{"id":6478,"date":"2021-01-09T23:05:45","date_gmt":"2021-01-09T20:05:45","guid":{"rendered":"https:\/\/sitecenneti.com\/kimya\/?p=6478"},"modified":"2022-10-24T23:38:27","modified_gmt":"2022-10-24T20:38:27","slug":"5-elektroliz","status":"publish","type":"post","link":"https:\/\/sitecenneti.com\/kimya\/ayt-kimya\/kimya-ve-elektrik\/5-elektroliz\/","title":{"rendered":"5. Elektroliz"},"content":{"rendered":"<div id=\"toc_container\" class=\"toc_transparent no_bullets\"><p class=\"toc_title\">\u0130&ccedil;indekiler<\/p><ul class=\"toc_list\"><ul><li><a href=\"#Tek_Kapli_Elektroliz_Hucresi\">Tek Kapl\u0131 Elektroliz H\u00fccresi<\/a><\/li><li><a href=\"#Elektroliz_Olayinda_Neler_Olur\">Elektroliz Olay\u0131nda Neler Olur?<\/a><ul><li><a href=\"#Anot_Kutbu\">Anot Kutbu<\/a><\/li><li><a href=\"#Katot_Kutbu\">Katot Kutbu<\/a><\/li><\/ul><\/li><li><a href=\"#Ornek\">\u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#Faraday_Kanunlari\">Faraday Kanunlar\u0131<\/a><ul><li><a href=\"#1_Kanun\">1. Kanun<\/a><\/li><li><a href=\"#Ornek-2\">\u00d6rnek:<\/a><\/li><li><a href=\"#2_Kanun\">2. Kanun<\/a><ul><li><a href=\"#Hangi_Kapta_Daha_Cok_Element_Birikir\">Hangi Kapta Daha \u00c7ok Element Birikir?<\/a><\/li><\/ul><\/li><\/ul><\/li><li><a href=\"#Tuzlarin_Elektrolizi\">Tuzlar\u0131n Elektrolizi<\/a><ul><li><a href=\"#Ornek-3\">\u00d6rnek:<\/a><\/li><li><a href=\"#Suyun_Elektrolizi\">Suyun Elektrolizi<\/a><\/li><\/ul><\/li><\/ul><\/div>\n\n<ul class=\"wp-block-list\"><li><em><strong>Elektroliz olay\u0131<\/strong><\/em>, elektrik enerjisinin zoruyla bir redoks tepkimesinin ger\u00e7ekle\u015ftirilmesidir.<\/li><li>Elektroliz olay\u0131nda ger\u00e7ekle\u015fen redoks tepkimeleri <strong><em>istemsizdir<\/em><\/strong>.<\/li><li><strong><em>Elektrolitik h\u00fccreler<\/em><\/strong> de bir \u00e7e\u015fit elektroliz h\u00fccresidir.<\/li><\/ul>\n\n\n\n<div class=\"wp-block-group has-background\" style=\"background-color:#e2f4ff\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p>Elektrolitik H\u00fccreler ile ilgili detayl\u0131 bilgi i\u00e7in a\u015fa\u011f\u0131daki ba\u011flant\u0131y\u0131 t\u0131klayabilirsiniz.<\/p>\n\n\n\n<ul class=\"wp-block-list\"><li><a href=\"https:\/\/sitecenneti.com\/kimya\/ayt-kimya\/kimya-ve-elektrik\/3-elektrot-potansiyelleri-ve-elektrokimyasal-hucreler\/#II_Elektrolitik_Hucreler_Sarj_Duzenegi\">Elektrolitik H\u00fccreler (\u015earj D\u00fczene\u011fi)<\/a><\/li><\/ul>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Tek_Kapli_Elektroliz_Hucresi\">Tek Kapl\u0131 Elektroliz H\u00fccresi<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\"><li>Elektroliz sorular\u0131nda genellikle tek kapl\u0131 elektroliz h\u00fccreleri ile kar\u015f\u0131la\u015faca\u011f\u0131z.<\/li><li>Tek kapl\u0131 elektroliz h\u00fccrelerinde;<ul><li>elektrotlar, ayn\u0131 kab\u0131n i\u00e7ine konulur,<\/li><li>indirgenme ve y\u00fckseltgenme yar\u0131 tepkimeleri tek bir kapta ger\u00e7ekle\u015fir.<\/li><\/ul><\/li><\/ul>\n\n\n\n<p>A\u015fa\u011f\u0131da, NaCl s\u0131v\u0131s\u0131na ait bir elektroliz h\u00fccresi verilmi\u015ftir:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"200\" height=\"322\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari-Elektroliz-Kabi.jpg\" alt=\"Elektroliz H\u00fccresi\" class=\"wp-image-6502\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari-Elektroliz-Kabi.jpg 200w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari-Elektroliz-Kabi-186x300.jpg 186w\" sizes=\"auto, (max-width: 200px) 100vw, 200px\" \/><figcaption>Elektroliz H\u00fccresi<\/figcaption><\/figure>\n<\/div>\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Elektroliz_Olayinda_Neler_Olur\">Elektroliz Olay\u0131nda Neler Olur?<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\"><li>Tek kapl\u0131 elektroliz h\u00fccrelerinde; z\u0131t y\u00fckl\u00fc iyonlar birbirini \u00e7ekece\u011fi i\u00e7in, elektroliz edilen bile\u015fi\u011fin iyonlar\u0131, y\u00fcklerine g\u00f6re z\u0131t kutuplara giderler. Buna g\u00f6re;<\/li><\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><span id=\"Anot_Kutbu\">Anot Kutbu<\/span><\/h4>\n\n\n\n<p>Anot kutbunun her zaman pozitif (&#8220;+&#8221;) kutup oldu\u011funu unutmayal\u0131m.<\/p>\n\n\n\n<ul class=\"wp-block-list\"><li>\u00dcretecin art\u0131 kutbuna ba\u011fl\u0131 elektrottur.<\/li><li>Anot elektrota anyonlar (- y\u00fckl\u00fc iyonlar) gider.<\/li><li>Anota giden anyon y\u00fckseltgenir.<\/li><li>Anyonlar genellikle, ametal iyonlar\u0131d\u0131r.<\/li><li>Y\u00fckseltgenen anyonlar; y\u00fck\u00fcn\u00fc kaybeder ve element haline ge\u00e7er:<ul><li>2F<sup>&#8211;<\/sup> <strong>\u2192<\/strong> F<sub>2(g)<\/sub> + 2e<sup>&#8211;<\/sup><\/li><li>2Cl<sup>&#8211;<\/sup> <strong>\u2192<\/strong> Cl<sub>2(g)<\/sub> + 2e<sup>&#8211;<\/sup><\/li><li>2O<sup>2-<\/sup> <strong>\u2192<\/strong> O<sub>2(g)<\/sub> + 4e<sup>&#8211;<\/sup><\/li><\/ul><\/li><\/ul>\n\n\n\n<ul class=\"wp-block-list\"><li><strong><em>Anot kutbunda, birden fazla anyon varsa, \u00f6nce hangisinin y\u00fckseltgenece\u011fine a\u015fa\u011f\u0131dakilerden herhangi birini tespit ederek karar veririz:<\/em><\/strong><ul><li>Y\u00fckseltgenme potansiyeli daha b\u00fcy\u00fck olan anyon \u00f6nce y\u00fckseltgenir.<\/li><li>Veya elektron verme iste\u011fi daha b\u00fcy\u00fck olan anyon \u00f6nce y\u00fckseltgenir.<\/li><li>Veya daha pasif olan ametal \u00f6nce y\u00fckseltgenir.<\/li><li>Bir anyon y\u00fckseltgenirse; y\u00fck\u00fcn\u00fc kaybeder ve n\u00f6t\u00fcr bir ametal elementi haline ge\u00e7er (O<sub>2<\/sub>, F<sub>2<\/sub>, Cl<sub>2<\/sub> gibi). Bu hi\u00e7 bir ametalin ho\u015funa giden bir olay de\u011fildir. Bu y\u00fczden, aktif olan ametaller, bu olayda geri dururlar, \u00f6nce pasif ametaller y\u00fckseltgenir.<ul><li>7A grubu ametalleri<\/li><li>O<sup>-2<\/sup> iyonu<\/li><li>OH<sup>&#8211;<\/sup> iyonu; aktif anyonlar oldu\u011fundan, y\u00fckseltgenme s\u0131ras\u0131nda son s\u0131ralarda olacaklard\u0131r.<\/li><\/ul><\/li><\/ul><\/li><\/ul>\n\n\n\n<ul class=\"wp-block-list\"><li>\u00d6rne\u011fin NaCl s\u0131v\u0131s\u0131n\u0131n elektrolizinde, <em>anot kutbunda (+)<\/em>, tuzun anyonu (-) olan <strong>Cl<sup>&#8211;<\/sup><\/strong> iyonu y\u00fckseltgenir. Y\u00fckseltgenme yar\u0131 tepkimesi \u015f\u00f6yledir:<ul><li>2Cl<sup>&#8211;<\/sup> <strong>\u2192<\/strong> Cl<sub>2(g)<\/sub> + 2e<sup>&#8211;<\/sup><\/li><\/ul><\/li><\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><span id=\"Katot_Kutbu\">Katot Kutbu<\/span><\/h4>\n\n\n\n<p>Katot kutbunun her zaman negatif (&#8220;-&#8220;) kutup oldu\u011funu unutmayal\u0131m.<\/p>\n\n\n\n<ul class=\"wp-block-list\"><li>\u00dcretecin eksi kutbuna ba\u011fl\u0131 elektrottur.<\/li><li>Katot elektrota katyonlar (+ y\u00fckl\u00fc iyonlar) gider.<\/li><li>Katota giden katyon indirgenir.<\/li><li>Katyonlar genellikle metal iyonlar\u0131d\u0131r.<\/li><li>\u0130ndirgenen katyonlar; y\u00fck\u00fcn\u00fc kaybeder ve element haline ge\u00e7er.<\/li><\/ul>\n\n\n\n<ul class=\"wp-block-list\"><li>Katot kutbunda, birden fazla katyon varsa, \u00f6nce hangisinin indirgenece\u011fine, a\u015fa\u011f\u0131dakilerden herhangi birini tespit ederek karar veririz:<ul><li>\u0130ndirgenme potansiyeli daha b\u00fcy\u00fck metal \u00f6nce indirgenir.<\/li><li>Veya, elektron alma iste\u011fi daha b\u00fcy\u00fck olan metal \u00f6nce indirgenir.<\/li><li>Veya, daha pasif olan metal \u00f6nce indirgenir.<\/li><li>Bir metalin katyonu indirgenirse; y\u00fck\u00fcn\u00fc kaybeder ve n\u00f6t\u00fcr bir metal elementi haline ge\u00e7er. Bu hi\u00e7 bir metalin ho\u015funa giden bir olay de\u011fildir. Bu y\u00fczden, aktif olan metaller, bu olayda geri dururlar, \u00f6nce pasif metaller indirgenir. 1A ve 2A grubu metalleri, aktif metaller oldu\u011fundan, indirgenme s\u0131ras\u0131nda sona s\u0131ralarda olacaklard\u0131r.<\/li><\/ul><\/li><\/ul>\n\n\n\n<ul class=\"wp-block-list\"><li>\u00d6rne\u011fin NaCl s\u0131v\u0131s\u0131n\u0131n elektrolizinde, <em>katot (-) kutbunda<\/em>, Na<sup>+<\/sup> iyonu indirgenir. \u00c7\u00fcnk\u00fc bu iyon tuzun katyonudur. \u0130ndirgenme yar\u0131 tepkimesi \u015f\u00f6yledir:<ul><li>Na<sup>+<\/sup> + e<sup>&#8211;<\/sup> <strong>\u2192<\/strong> Na<sub>(k)<\/sub><\/li><\/ul><\/li><\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h3 class=\"wp-block-heading\"><span id=\"Ornek\">\u00d6rnek:<\/span><\/h3>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"200\" height=\"311\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari-Soru-Cozumu-4.jpg\" alt=\"Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlar\u0131-Soru-\u00c7\u00f6z\u00fcm\u00fc-4\" class=\"wp-image-6536\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari-Soru-Cozumu-4.jpg 200w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari-Soru-Cozumu-4-193x300.jpg 193w\" sizes=\"auto, (max-width: 200px) 100vw, 200px\" \/><\/figure>\n<\/div>\n\n\n<p>Yukar\u0131da; NaCl<sub>(s)<\/sub>, KBr<sub>(s)<\/sub> ve FeCl<sub>3(s)<\/sub> s\u0131v\u0131lar\u0131n\u0131n bulundu\u011fu bir elektroliz kab\u0131 verilmi\u015ftir.<\/p>\n\n\n\n<p><strong>Buna g\u00f6re bu kap ile ilgili olarak a\u015fa\u011f\u0131daki sorular\u0131 cevapland\u0131r\u0131n\u0131z.<\/strong> (Elektron verme e\u011filimleri K &gt; Na &gt; Fe &gt; Br<sup>\u2013<\/sup> &gt; Cl<sup>\u2013<\/sup> dir.)<\/p>\n\n\n\n<p>I) Anot ve katotta tepkimeye girecek iyonlar\u0131 belirtiniz.<br>II) Anotta ve katotta hangi iyonlar \u00f6ncelikle elektroliz olur?<br>III) Anotta ve katotta ilk olarak ger\u00e7ekle\u015fecek tepkimeleri yaz\u0131n\u0131z.<\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p><em>I)<br>Anota giden iyonlar: Cl<sup>&#8211;<\/sup> ve Br<sup>&#8211;<\/sup><br>Katoda giden iyonlar: Na<sup>+<\/sup>, K<sup>+<\/sup> ve Fe<sup>3+<\/sup><br>II)<br>Anotta \u00f6nce Br<sup>&#8211;<\/sup> iyonu y\u00fckseltgenir, sonra Cl<sup>&#8211;<\/sup> iyonu y\u00fckseltgenir.<br>Katotta, \u00f6nce Fe<sup>3+<\/sup> iyonu indirgenir, sonra Na<sup>+<\/sup> ve en son da K<sup>+<\/sup> iyonu indirgenir.<br>III)<br>Anot: 2Br<sup>&#8211;<\/sup> \u2192 Br<sub>2(g)<\/sub> + 2e<sup>&#8211;<\/sup><br>Katot: Fe<sup>3+<\/sup> + 3e<sup>&#8211;<\/sup> \u2192 Fe<sub>(k)<\/sub><\/em><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>I)<br>Kaptaki bile\u015fiklerin katyonlar\u0131n\u0131 (&#8220;+&#8221;) ve anyonlar\u0131n\u0131 (&#8220;-&#8220;) g\u00f6relim:<br>&#8211; <strong>NaCl bile\u015finin iyonlar\u0131: Na<sup>+<\/sup> ve Cl<sup>&#8211;<\/sup><\/strong><br>&#8211; <strong>NaBr bile\u015fi\u011finin iyonlar\u0131: K<sup>+<\/sup> ve Br<sup>&#8211;<\/sup><\/strong><br>&#8211; <strong>FeCl<sub>3<\/sub> bile\u015fi\u011finin iyonlar\u0131: Fe<sup>3+<\/sup> ve Cl<sup>&#8211;<\/sup><\/strong><br><br>Bu iyonlar, kendileri ile z\u0131t y\u00fckl\u00fc olan kutba gidecek ve orada elektroliz olacakt\u0131r:<br><img loading=\"lazy\" decoding=\"async\" width=\"150\" height=\"246\" class=\"wp-image-6540\" style=\"width: 150px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari-Soru-Cozumu-5.jpg\" alt=\"Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlar\u0131-Soru-\u00c7\u00f6z\u00fcm\u00fc-5\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari-Soru-Cozumu-5.jpg 190w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari-Soru-Cozumu-5-183x300.jpg 183w\" sizes=\"auto, (max-width: 150px) 100vw, 150px\" \/><br>Anyonlar anotta tepkimeye girer ve y\u00fckseltgenir.<br>Katyonlar katotta tepkimeye girer ve indirgenir.<br>Sonu\u00e7ta:<br><strong>Anota giden iyonlar: Cl<sup>&#8211;<\/sup> ve Br<sup>&#8211;<\/sup><\/strong><br><strong>Katoda giden iyonlar: Na<sup>+<\/sup>, K<sup>+<\/sup> ve Fe<sup>3+<\/sup><\/strong><br><br><span style=\"color:#2c3401\" class=\"has-inline-color\">II)<br>&#8211; Anotta: Elektron verme e\u011filimi en fazla olan \u00f6nce y\u00fckseltgenir.<br>&#8211; Katotta: Elektron alma e\u011filimi en fazla olan \u00f6nce y\u00fckseltgenir.<br><br>Soruda; herkesin <em>elektron verme e\u011filimi<\/em> s\u0131ras\u0131 \u015f\u00f6yle verilmi\u015f:<br><strong>K &gt; Na &gt; Fe &gt; Br<sup>\u2013<\/sup> &gt; Cl<sup>\u2013<\/sup><\/strong><br><br><strong>O zaman:<\/strong><br>Anotta bekleyenlerin elektron verme e\u011filimi \u015f\u00f6yledir:<br><strong>Br<sup>\u2013<\/sup> &gt; Cl<sup>\u2013<\/sup><\/strong><br>Demek ki; anotta \u00f6nce Br<sup>&#8211;<\/sup> iyonu y\u00fckseltgenir, sonra Cl<sup>&#8211;<\/sup> iyonu y\u00fckseltgenir.<br><br>Katotta bekleyenlerin elektron verme e\u011filimi \u015f\u00f6yledir:<br><strong>K &gt; Na &gt; Fe<\/strong><br>Elektron alma e\u011filimi, elektron verme e\u011filiminin tam tersidir. O zamana katotta bekleyenlerin elektron alma e\u011filimi \u015f\u00f6yledir:<br><strong>Fe<\/strong> &gt; <strong>Na<\/strong> &gt; <strong>K<\/strong><br>Demek ki; katotta, \u00f6nce Fe<sup>3+<\/sup> iyonu indirgenir, sonra Na<sup>+<\/sup> ve en son da K<sup>+<\/sup> iyonu indirgenir.<\/span><br><br>III) <br>Anotta; elektron vermeye daha hevesli oldu\u011fu i\u00e7in; \u00f6nce <strong>Br<sup>\u2013<\/sup><\/strong> iyonu y\u00fckseltgenir. <strong>Br<sup>\u2013<\/sup><\/strong> iyonunun y\u00fckseltgenme yar\u0131 tepkimesi \u015f\u00f6yledir:<br><strong>2Br<sup>&#8211;<\/sup> \u2192 Br<sub>2(g)<\/sub> + 2e<sup>&#8211;<\/sup><\/strong><br><br>Katotta; elektron almaya daha hevesli oldu\u011fu i\u00e7in, \u00f6nce Fe<sup>3+<\/sup> iyonu indirgenir. Fe<sup>3+<\/sup> iyonunun indirgenme yar\u0131 tepkimesi \u015f\u00f6yledir:<br><strong>Fe<sup>3+<\/sup> + 3e<sup>&#8211;<\/sup> \u2192 Fe<sub>(k)<\/sub><\/strong><\/p>\n\n\n\n<p>Cevap:<br><em>I)<br>Anota giden iyonlar: Cl<sup>&#8211;<\/sup> ve Br<sup>&#8211;<\/sup><br>Katoda giden iyonlar: Na<sup>+<\/sup>, K<sup>+<\/sup> ve Fe<sup>3+<\/sup><br>II)<br>Anotta \u00f6nce Br<sup>&#8211;<\/sup> iyonu y\u00fckseltgenir, sonra Cl<sup>&#8211;<\/sup> iyonu y\u00fckseltgenir.<br>Katotta, \u00f6nce Fe<sup>3+<\/sup> iyonu indirgenir, sonra Na<sup>+<\/sup> ve en son da K<sup>+<\/sup> iyonu indirgenir.<br>III)<br>Anot: 2Br<sup>&#8211;<\/sup> \u2192 Br<sub>2(g)<\/sub> + 2e<sup>&#8211;<\/sup><br>Katot: Fe<sup>3+<\/sup> + 3e<sup>&#8211;<\/sup> \u2192 Fe<sub>(k)<\/sub><\/em><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><span id=\"Faraday_Kanunlari\">Faraday Kanunlar\u0131<\/span><\/h2>\n\n\n\n<ul class=\"wp-block-list\"><li>Elektroliz olay\u0131nda verilen elektrik enerjisi sayesinde, anot ve katotta yar\u0131 tepkimeler ger\u00e7ekle\u015fir.<\/li><li>Bu tepkimeler sonucunda; anot ve katot kutbunda elementler birikir.<\/li><li>Biriken elementlerin miktar\u0131n\u0131 hesaplamak i\u00e7in Faraday Kanunlar\u0131 kullan\u0131l\u0131r.<\/li><\/ul>\n\n\n\n<p>Faraday Kanunlar\u0131 iki tanedir:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"1_Kanun\">1. Kanun<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\"><li>Elektroliz devresinden ne kadar \u00e7ok elektrik y\u00fck\u00fc ge\u00e7erse anot ve katotta biriken madde miktar\u0131 da o kadar \u00e7ok olur.<\/li><li>Devreden ge\u00e7en elektrik y\u00fck\u00fc 1 Faraday (F) oldu\u011funda; devreden 96500 C y\u00fck ve 1 mol elektron ge\u00e7mi\u015f demektir:<\/li><\/ul>\n\n\n\n<p class=\"has-text-align-center\"><strong>1 mol e<sup>&#8211;<\/sup> = 96500 C = 1F<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\"><li>Bu kanuna g\u00f6re; bir elektroliz kab\u0131nda kutuplarda biriken element k\u00fctlesi (m) \u015f\u00f6yle hesaplan\u0131r:<\/li><\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"200\" height=\"86\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Faraday-Kanunlari.jpg\" alt=\"Faraday Kanunlar\u0131\" class=\"wp-image-6488\"\/><figcaption>Faraday Kanunlar\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<p>Form\u00fcldeki sembollerin anlamlar\u0131 \u015f\u00f6yledir:<\/p>\n\n\n\n<ul class=\"wp-block-list\"><li>m: Anot ya da katotta biriken elementin gram olarak k\u00fctlesi.<\/li><li>M<sub>A<\/sub>: Biriken elementin mol a\u011f\u0131rl\u0131\u011f\u0131<\/li><li>n: Elementin ald\u0131\u011f\u0131 ya da verdi\u011fi elektron say\u0131s\u0131<\/li><li>Q: Devreden ge\u00e7en y\u00fck miktar\u0131. Birimi Coloumb&#8217;dur. Bir devreden ge\u00e7en ak\u0131m ve bu ak\u0131m\u0131n\u0131 ka\u00e7 saniye ge\u00e7ti\u011fi biliniyorsa, y\u00fck miktar\u0131, a\u015fa\u011f\u0131daki form\u00fclle hesaplanabilir:<ul><li><strong>Q = I . t<\/strong><\/li><li>I: Devreden ge\u00e7en elektrik ak\u0131m\u0131 (Birimi Amper&#8217;dir.)<\/li><li>t: Saniye olarak ak\u0131m\u0131n verildi\u011fi s\u00fcredir.<\/li><\/ul><\/li><\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h3 class=\"wp-block-heading\"><span id=\"Ornek-2\">\u00d6rnek:<\/span><\/h3>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"220\" height=\"295\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari-Soru-Cozumu.jpg\" alt=\"Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlar\u0131-Soru-\u00c7\u00f6z\u00fcm\u00fc\" class=\"wp-image-6525\"\/><\/figure>\n<\/div>\n\n\n<p>Yukar\u0131da verilen \u015fekil, s\u0131v\u0131 NaCl tuzunun elektrolizine aittir.<\/p>\n\n\n\n<p><strong>Buna g\u00f6re, bu olay ile ilgili olarak, a\u015fa\u011f\u0131da verilen yarg\u0131lardan hangileri do\u011frudur?<\/strong>(Na: 23 g\/mol, Cl: 35 g\/mol)<\/p>\n\n\n\n<p>I) Kapta ger\u00e7ekle\u015fen tepkimenin denklemi \u015f\u00f6yledir:<br>2Na<sup>+<\/sup><sub>(suda)<\/sub> + 2Cl<sup>\u2013<\/sup><sub>(suda)<\/sub> \u2192 2Na<sub>(k)<\/sub> + Cl<sub>2(g)<\/sub><br>II) Devreden 9650 C&#8217;luk ak\u0131m ge\u00e7erse, katota 2,3 gram Na metali birikir.<br>III) Devreden 4F ak\u0131m ge\u00e7erse, anotta 2 mol Cl<sub>2<\/sub> gaz\u0131 olu\u015fur.<br>IV) Devreden 1,93 Amperlik ak\u0131m, 16 dakika ve 40 saniye boyunca ge\u00e7erse, katotta biriken element k\u00fctlesi 4,6 gram olur.<\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\">I) Do\u011fru<br>II) Do\u011fru<br>III) Do\u011fru<br>IV) Yanl\u0131\u015f<\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p><span class=\"has-inline-color has-vivid-purple-color\"><strong>I) &#8211; Do\u011fru<br><\/strong><\/span>Elektroliz tepkimesi anot ve katotta ger\u00e7ekle\u015fen yar\u0131 tepkimelerin toplam\u0131d\u0131r.<br><br>Anotta, tuzun anyonu y\u00fckseltgenir:<br><span class=\"has-inline-color has-vivid-purple-color\"><strong>Anot (YYT): 2Cl<sup>&#8211;<\/sup> \u2192 Cl<sub>2(g)<\/sub> + 2e<sup>&#8211;<\/sup><\/strong><\/span><br><br>Katotta tuzun katyonu indirgenir:<br><span class=\"has-inline-color has-vivid-purple-color\"><strong>Katot (\u0130YT): Na<sup>+<\/sup> + e<sup>&#8211;<\/sup> \u2192 Na<sub>(k)<\/sub><\/strong><\/span><br><br>Elektroliz tepkimesini bulmak i\u00e7in, bu iki tepkimenin toplanmas\u0131 gerekir. Tabi yar\u0131 tepkimelerin toplanmas\u0131 i\u00e7in de elektronlar\u0131n e\u015fitlenmesi gerekir. Yani; \u00f6nce, katot tepkimesini 2 ile \u00e7arp\u0131p, yar\u0131 tepkiemleri \u00f6yle toplamal\u0131y\u0131z.<br><strong>Anot (YYT): 2Cl<sup>&#8211;<\/sup> \u2192 Cl<sub>2(g)<\/sub> + <span style=\"color:#f9cfda\" class=\"has-inline-color\">2e<sup>&#8211;<\/sup><\/span><\/strong><br><strong>Katot (\u0130YT): 2Na<sup>+<\/sup> +<span style=\"color:#ffe5ec\" class=\"has-inline-color\"> 2e<sup>&#8211;<\/sup><\/span> \u2192 2Na<sub>(k)<\/sub><\/strong><br><br>Elektroliz tepkimesi:<br><strong>2Na<sup>+<\/sup> + <strong>2Cl<sup>&#8211;<\/sup><\/strong>\u2192 2Na<sub>(k)<\/sub> + <strong>Cl<sub>2(g)<\/sub><\/strong><\/strong><br>veya<br><strong>2Na<strong>Cl<sub>(s)<\/sub> <\/strong>\u2192 2Na<sub>(k)<\/sub> + <strong>Cl<sub>2(g)<\/sub><\/strong><\/strong><br><br><span class=\"has-inline-color has-vivid-purple-color\"><strong>II) &#8211; Do\u011fru<\/strong><\/span><br>Bir elektroliz kab\u0131nda devreden ge\u00e7en y\u00fck miktar\u0131 biliniyor ise, anot ve katotta biriken elementin k\u00fctlesi Faraday\u0131n 1. Kanunu ile bulunabilir:<br><img loading=\"lazy\" decoding=\"async\" width=\"150\" height=\"65\" class=\"wp-image-6488\" style=\"width: 150px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Faraday-Kanunlari.jpg\" alt=\"Faraday Kanunlar\u0131\"><br>Katot tepkimesini hat\u0131rlayal\u0131m:<br><strong>Na<sup>+<\/sup> + e<sup>&#8211;<\/sup> \u2192 Na<sub>(k)<\/sub><\/strong><br>&#8211; Tepkimeden anl\u0131yoruz ki al\u0131nan elektron say\u0131s\u0131 yani &#8220;n&#8221; de\u011feri 1&#8217;dir.<br>&#8211; Q de\u011feri, soruda 9650 C verilmi\u015f.<br>&#8211; M<sub>A<\/sub> de\u011feri 23 verilmi\u015f.<br>Verilenleri yerine yazal\u0131m ve &#8220;m&#8221; de\u011ferini bulal\u0131m:<br><img loading=\"lazy\" decoding=\"async\" width=\"150\" height=\"174\" class=\"wp-image-6528\" style=\"width: 150px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari-Soru-Cozumu-1.jpg\" alt=\"Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlar\u0131-Soru-\u00c7\u00f6z\u00fcm\u00fc-1\"><br><br>2. Yol:<br>Devreden ge\u00e7en y\u00fck biliniyorsa, devreden ka\u00e7 mol elektron ge\u00e7ti\u011fi de hesaplanabilir:<br><br><strong>96500 C &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;1 mol e<sup>&#8211;<\/sup> demekse<br>9650 C &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;n mol e<sup>&#8211;<\/sup> demektir.<\/strong><br><br>Do\u011fru orant\u0131 denklemini \u00e7\u00f6zerek n de\u011ferini bulal\u0131m:<br><strong>n . 96500 = 1 . 9650<br>n = 0,1 mol<\/strong><br><br>Yar\u0131 tepkimeye bakt\u0131\u011f\u0131m\u0131zda, Na kat\u0131s\u0131 ile elektronun katsay\u0131s\u0131 e\u015fittir:<br><strong>Na<sup>+<\/sup> + e<sup>&#8211;<\/sup> \u2192 Na<sub>(k)<\/sub><\/strong><br><br>Bu y\u00fczden; 0,1 mol elektrondan 0,1 mol Na kat\u0131s\u0131 olu\u015fur. 0,1 mol Na kat\u0131s\u0131n\u0131n k\u00fctlesi:<br><strong>m = n . M<sub>A<\/sub><br>m = 0,1 . 23<br>m = 2,3 g olur.<\/strong><br><br><span class=\"has-inline-color has-vivid-purple-color\"><strong>III) &#8211; Do\u011fru<br><\/strong><\/span>Faraday&#8217;\u0131n 1. kanunu ile olu\u015fan Cl<sub>2<\/sub> k\u00fctlesinin bulabiliriz:<br><img loading=\"lazy\" decoding=\"async\" width=\"150\" height=\"65\" class=\"wp-image-6488\" style=\"width: 150px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Faraday-Kanunlari.jpg\" alt=\"Faraday Kanunlar\u0131\"><br><br>&#8211; 96500 C demek 1F demektir.<br>&#8211; Q de\u011feri 4F olarak verilmi\u015f.<br>&#8211; Cl<sub>2<\/sub> gaz\u0131n\u0131n yar\u0131 tepkimesine bakarsak elektron say\u0131s\u0131n\u0131n 2 oldu\u011funu anlar\u0131z:<br><strong>2Cl<sup>&#8211;<\/sup> \u2192 Cl<sub>2(g)<\/sub> + 2e<sup>&#8211;<\/sup><\/strong><br>&#8211; Cl atomunun mol a\u011f\u0131rl\u0131\u011f\u0131 35 oldu\u011fu i\u00e7in Cl<sub>2<\/sub> gaz\u0131n\u0131n mol a\u011f\u0131rl\u0131\u011f\u0131:<br><strong>M<sub>A<\/sub> = 35 + 35 = 70 g\/mol<\/strong> d\u00fcr.<br>\u015eimdi, bu de\u011ferleri form\u00fclde yerine yazal\u0131m ve &#8220;m&#8221; de\u011ferini bulal\u0131m:<br><img loading=\"lazy\" decoding=\"async\" width=\"130\" height=\"101\" class=\"wp-image-6531\" style=\"width: 130px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari-Soru-Cozumu-2.jpg\" alt=\"Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlar\u0131-Soru-\u00c7\u00f6z\u00fcm\u00fc-2\"><br><br><strong><span class=\"has-inline-color has-vivid-purple-color\">IV) &#8211; Yanl\u0131\u015f<\/span><\/strong><br>Devreden ge\u00e7en amper ile saniyeyi \u00e7arparsak, bu devreden ge\u00e7en y\u00fck (Q) miktar\u0131n\u0131 bulabiliriz:<br><strong>Q = I . t<\/strong><br><br><strong>I = 1,93 A<\/strong> olarak verilmi\u015f.<br>16 dakika ve 40 saniye:<br><strong>(16 . 60) + 40 = 1000 saniye<\/strong><br>yapar. O zaman y\u00fck \u015fu kadar olur:<br>Q = 1,93 . 1000<br>Q = 1930 C<br><br>Katot, negatif kutup oldu\u011fundan, katota giden iyon Na<sup>+<\/sup> katyonu olacakt\u0131r.<br>Faraday\u0131n 1. kanunu yard\u0131m\u0131 ile, katotta biriken Na metalinin k\u00fctlesi bulunabilir:<br><img loading=\"lazy\" decoding=\"async\" width=\"150\" height=\"65\" class=\"wp-image-6488\" style=\"width: 150px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Faraday-Kanunlari.jpg\" alt=\"Faraday Kanunlar\u0131\"><br><br>Soruda; Na i\u00e7in MA de\u011feri 23 verilmi\u015f. Yar\u0131 tepkimesine bakt\u0131\u011f\u0131m\u0131zda, al\u0131nan elektron say\u0131s\u0131n\u0131 (n) 1 olarak g\u00f6r\u00fcr\u00fcz. B\u00fct\u00fcn bu de\u011ferleri yerine yazarsak, &#8220;m&#8221; de\u011feri bulunabilir:<br><img loading=\"lazy\" decoding=\"async\" width=\"170\" height=\"134\" class=\"wp-image-6534\" style=\"width: 170px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari-Soru-Cozumu-3.jpg\" alt=\"Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlar\u0131-Soru-\u00c7\u00f6z\u00fcm\u00fc-3\"><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"2_Kanun\">2. Kanun<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\"><li>Faraday&#8217;\u0131n 2 kanunu, seri ba\u011fl\u0131 elektroliz h\u00fccreleri ile ilgilidir.<\/li><\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"400\" height=\"328\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari.jpg\" alt=\"Seri Ba\u011fl\u0131 Elektroliz Kaplar\u0131\" class=\"wp-image-6497\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari.jpg 400w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari-300x246.jpg 300w\" sizes=\"auto, (max-width: 400px) 100vw, 400px\" \/><figcaption>Seri Ba\u011fl\u0131 Elektroliz H\u00fccreleri<\/figcaption><\/figure>\n<\/div>\n\n\n<ul class=\"wp-block-list\"><li>Seri ba\u011fl\u0131 elektroliz devrelerinde, kaplar\u0131n her birinden e\u015fit say\u0131da elektron ge\u00e7er.<\/li><li>Bu y\u00fczden, elektroliz kaplar\u0131n\u0131n her bir kutbundan ge\u00e7en:<ul><li>Elektron say\u0131s\u0131<\/li><li>Y\u00fck miktar\u0131<\/li><li>Elektronlar\u0131n mol say\u0131s\u0131 e\u015fittir.<\/li><\/ul><\/li><li>Ge\u00e7en y\u00fck ile, biriken elementlerin e\u015fde\u011fer k\u00fctleleri do\u011fru orant\u0131l\u0131d\u0131r.<\/li><li>Bir elektroliz kab\u0131nda kutuplardan birinde biriken elementin k\u00fctlesi biliniyorsa, di\u011fer kutuplarda biriken elementlerin k\u00fctleleri de hesaplanabilir:<\/li><\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"250\" height=\"94\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari-Seri-Bagli-Elektroliz-Kaplari.jpg\" alt=\"Seri Ba\u011fl\u0131 Elektroliz Kaplar\u0131\" class=\"wp-image-6513\"\/><figcaption>Seri Ba\u011fl\u0131 Elektroliz Kaplar\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<p>Form\u00fcldeki sembollerin anlamlar\u0131 \u015f\u00f6yledir:<\/p>\n\n\n\n<ul class=\"wp-block-list\"><li>m<sub>1<\/sub>: Birinci kab\u0131n anot ya da katodunda biriken element miktar\u0131<\/li><li>m<sub>2<\/sub>: \u0130kinci kab\u0131n anot ya da katodunda biriken element miktar\u0131<\/li><li>e<sub>1<\/sub>: Birinci kab\u0131n anot ya da katodunda biriken elementin ald\u0131\u011f\u0131-verdi\u011fi elektron say\u0131s\u0131<\/li><li>e<sub>2<\/sub>: \u0130kinci kab\u0131n anot ya da katodunda biriken elementin ald\u0131\u011f\u0131-verdi\u011fi elektron say\u0131s\u0131<\/li><li>M<sub>A1<\/sub>: Birinci kab\u0131n anot ya da katodunda biriken elementin mol a\u011f\u0131rl\u0131\u011f\u0131<\/li><li>M<sub>A2<\/sub>: \u0130kinci kab\u0131n anot ya da katodunda biriken elementin mol a\u011f\u0131rl\u0131\u011f\u0131<\/li><\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><span id=\"Hangi_Kapta_Daha_Cok_Element_Birikir\">Hangi Kapta Daha \u00c7ok Element Birikir?<\/span><\/h4>\n\n\n\n<ul class=\"wp-block-list\"><li>Seri ba\u011fl\u0131 elektroliz kaplar\u0131nda, kutuplarda ve e\u015fit s\u00fcrede biriken elementlerden <strong>e\u015fde\u011fer k\u00fctlesi<\/strong> daha b\u00fcy\u00fck olan elementin k\u00fctlesi daha b\u00fcy\u00fckt\u00fcr.<\/li><li>Bir elementin, e\u015fde\u011fer k\u00fctlesi \u015f\u00f6yle hesaplan\u0131r:<\/li><\/ul>\n\n\n\n<p class=\"has-text-align-center\"><img loading=\"lazy\" decoding=\"async\" width=\"250\" height=\"73\" class=\"wp-image-6565\" style=\"width: 250px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari-Seri-Bagli-Elektroliz-Kaplari-Esdeger-Kutle-Gram.jpg\" alt=\"Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlar\u0131-Seri-Ba\u011fl\u0131-Elektroliz-Kaplar\u0131-E\u015fde\u011fer-K\u00fctle-Gram\"><\/p>\n\n\n\n<ul class=\"wp-block-list\"><li><strong>M<sub>A<\/sub><\/strong>: Elementin mol a\u011f\u0131rl\u0131\u011f\u0131<\/li><li><strong>e<sup>&#8211;<\/sup><\/strong>: Elementin ald\u0131\u011f\u0131 veya verdi\u011fi elektron say\u0131s\u0131d\u0131r. Metaller i\u00e7in bu de\u011fer, metalin y\u00fck\u00fcne e\u015fittir.<\/li><\/ul>\n\n\n\n<h2 class=\"wp-block-heading\"><span id=\"Tuzlarin_Elektrolizi\">Tuzlar\u0131n Elektrolizi<\/span><\/h2>\n\n\n\n<ul class=\"wp-block-list\"><li>Tuzlar kat\u0131 halde iken elektri\u011fi iletmezler ve elektroliz olamazlar.<\/li><li>Bir tuzun elektroliz edilmesi i\u00e7in; ya s\u0131v\u0131 halde olmas\u0131 ya da suda \u00e7\u00f6z\u00fcnm\u00fc\u015f olmas\u0131 gerekir.<\/li><li>Elektrik enerjisi verilerek, tuz bile\u015fi\u011fi elementlerine ayr\u0131\u015ft\u0131r\u0131labilir.<\/li><\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h3 class=\"wp-block-heading\"><span id=\"Ornek-3\">\u00d6rnek:<\/span><\/h3>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"400\" height=\"224\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari-Seri-Bagli-Elektroliz-Kaplari-Soru-Cozumu-1.jpg\" alt=\"Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlar\u0131-Seri-Ba\u011fl\u0131-Elektroliz-Kaplar\u0131-Soru-\u00c7\u00f6z\u00fcm\u00fc-1\" class=\"wp-image-6556\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari-Seri-Bagli-Elektroliz-Kaplari-Soru-Cozumu-1.jpg 400w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari-Seri-Bagli-Elektroliz-Kaplari-Soru-Cozumu-1-300x168.jpg 300w\" sizes=\"auto, (max-width: 400px) 100vw, 400px\" \/><\/figure>\n<\/div>\n\n\n<p>\u015eekildeki \u00f6zde\u015f kaplarda, grafit elektrotlar kullan\u0131larak; XCl, YF<sub>2<\/sub> ve ZBr<sub>3<\/sub> eriyikleri elektroliz edilmektedir.<\/p>\n\n\n\n<p><strong>Bu elektroliz d\u00fczene\u011fi i\u00e7in a\u015fa\u011f\u0131daki sorular\u0131 cevapland\u0131r\u0131n\u0131z.<\/strong> (X: 23 g\/mol, Y: 40 g\/mol, Z: 27 g\/mol)<\/p>\n\n\n\n<p>I) Bu elektroliz d\u00fczene\u011finde, ayn\u0131 s\u00fcrede, katotlarda biriken elementlerin k\u00fctleleri aras\u0131ndaki ili\u015fki nedir?<br>II) Ortadaki kab\u0131n katot kutbunda, 24 gram madde element olu\u015ftu\u011fu anda, di\u011fer kaplar\u0131n katotlar\u0131nda ka\u00e7ar gram madde birikir?<br>III) XCl s\u0131v\u0131s\u0131n\u0131n bulundu\u011fu kapta, 2,3 gram X metali birikirse, ortadaki kab\u0131n anotundan ka\u00e7 mol elektron ge\u00e7mi\u015f olur?<\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong><em>I) X &gt; Y &gt; Z<\/em><\/strong><\/p>\n\n\n\n<p class=\"has-text-align-center has-medium-font-size\"><strong><em>II)<\/em> <em>m<sub>x<\/sub> = 27,6<\/em><br><em>m<sub>z<\/sub> = 10,8<\/em><\/strong><\/p>\n\n\n\n<p class=\"has-text-align-center has-medium-font-size\"><strong><em>III) 0,1 mol elektron<\/em><\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p><strong>I)<\/strong><br>Seri ba\u011fl\u0131 elektroliz h\u00fccrelerinde, her hangi bir kutupta, e\u015fit s\u00fcrede biriken elementlerden e\u015fde\u011fer k\u00fctlesi daha b\u00fcy\u00fck olan\u0131n k\u00fctlesi daha \u00e7oktur.<br><br>Katotlarda, katyonlar yani metal iyonlar\u0131 birikir. Bile\u015fiklerdeki her bir metal iyonunun e\u015fde\u011fer k\u00fctlesini s\u0131ralarsak, biriken metal miktar\u0131n\u0131 da s\u0131ralam\u0131\u015f oluruz.<br><br><strong>E\u015fde\u011fer k\u00fctleler:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"190\" height=\"55\" class=\"wp-image-6565\" style=\"width: 190px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari-Seri-Bagli-Elektroliz-Kaplari-Esdeger-Kutle-Gram.jpg\" alt=\"Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlar\u0131-Seri-Ba\u011fl\u0131-Elektroliz-Kaplar\u0131-E\u015fde\u011fer-K\u00fctle-Gram\"><br>Metaller i\u00e7in e<sup>&#8211;<\/sup> de\u011feri, metalin y\u00fck\u00fcne e\u015fittir.<br><br><strong>Bile\u015fiklerdeki metal iyonlar\u0131n\u0131n y\u00fck\u00fcn\u00fc bulal\u0131m:<\/strong><br>XCl bile\u015fi\u011finde X<sup>+<\/sup> ve Cl<sup>&#8211;<\/sup> iyonlar\u0131ndan olu\u015fur.<br>YF<sub>2<\/sub> bile\u015fi\u011finde Y<sup>2+<\/sup> ve F<sup>&#8211;<\/sup> iyonlar\u0131ndan olu\u015fur.<br>ZBr<sub>3<\/sub> bile\u015fi\u011finde Z<sup>3+<\/sup> ve Br<sup>&#8211;<\/sup> iyonlar\u0131ndan olu\u015fur.<br><br><strong>Her bir metalin e\u015fde\u011fer k\u00fctlesini bulal\u0131m:<\/strong><br>X<sup>+<\/sup> iyonunun e\u015fde\u011feri k\u00fctlesi = 23 \/ 1 = 23<br>Y<sup>2+<\/sup> iyonunun e\u015fde\u011feri k\u00fctlesi = 40 \/ 2 = 20<br>Z<sup>3+<\/sup> iyonunun e\u015fde\u011feri k\u00fctlesi = 27 \/ 3 = 9<br><br>E\u015fde\u011fer k\u00fctlelerin s\u0131ras\u0131, ayn\u0131 s\u00fcrede biriken metallerin k\u00fctlelerinin de s\u0131ralamas\u0131 demektir.<br>X &gt; Y &gt; Z<br><br><strong>II)<\/strong><br>Seri ba\u011fl\u0131 elektroliz kaplar\u0131nda, kaplar\u0131n kutuplar\u0131nda biriken elementlerin k\u00fctleleri aras\u0131nda a\u015fa\u011f\u0131daki ili\u015fki vard\u0131r:<br><img loading=\"lazy\" decoding=\"async\" width=\"180\" height=\"68\" class=\"wp-image-6513\" style=\"width: 180px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari-Seri-Bagli-Elektroliz-Kaplari.jpg\" alt=\"Seri Ba\u011fl\u0131 Elektroliz Kaplar\u0131\"><br><br>Ortadaki kab\u0131n katotunda (&#8220;-&#8221; kutup) kaptaki Y<sup>2+<\/sup> iyonu birikmi\u015ftir.<br><br><strong>Biriken X metalinin k\u00fctlesini bulal\u0131m:<br><\/strong><br>XCl kab\u0131n\u0131n katotunda ise, X<sup>+<\/sup> iyonu birikir.<br><br>Biriken Y<sup>2+<\/sup> ve X<sup>+<\/sup> iyonlar\u0131 i\u00e7in yukar\u0131daki form\u00fcl\u00fc uygularsak X<sup>+<\/sup> iyonunun k\u00fctlesini bulabiliriz. Form\u00fclde gerekenleri bulal\u0131m:<br><br>X metalinin M<sub>A<\/sub> de\u011feri = 23 g\/mol verilmi\u015f.<br>Y metalinin M<sub>A<\/sub> de\u011feri = 40 g\/mol verilmi\u015f.<br><br>Bir \u00f6nceki soruda bu iki iyonun y\u00fcklerini bulmu\u015ftuk. Metallerin y\u00fckleri, form\u00fcldeki e<sup>&#8211;<\/sup> de\u011ferine e\u015fittir:<br>X<sup>+<\/sup> i\u00e7in e<sup>&#8211;<\/sup> de\u011feri = 1<br>Y<sup>2+<\/sup> i\u00e7in e<sup>&#8211;<\/sup> de\u011feri = 2<br><br>Bu de\u011ferleri, form\u00fclde yerine koyal\u0131m ve katotta biriken X metalinin k\u00fctlesini (m<sub>x<\/sub>) bulal\u0131m:<br><img loading=\"lazy\" decoding=\"async\" width=\"180\" height=\"155\" class=\"wp-image-6568\" style=\"width: 180px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari-Seri-Bagli-Elektroliz-Kaplari-Esdeger-Kutle-Gram-Soru-Cozumu-1.jpg\" alt=\"Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlar\u0131-Seri-Ba\u011fl\u0131-Elektroliz-Kaplar\u0131-E\u015fde\u011fer-K\u00fctle-Gram-Soru-\u00c7\u00f6z\u00fcm\u00fc-1\"><br><br><strong>Biriken Z metalinin k\u00fctlesini bulal\u0131m:<br><\/strong><br>ZCl<sub>3<\/sub> kab\u0131n\u0131n katotunda ise, Z<sup>3+<\/sup> iyonu birikir.<br><br>Biriken Y<sup>2+<\/sup> ve Z<sup>3+<\/sup> iyonlar\u0131 i\u00e7in yukar\u0131daki form\u00fcl\u00fc uygularsak Z<sup>3+<\/sup> iyonunun k\u00fctlesini bulabiliriz. Form\u00fclde gerekenleri bulal\u0131m:<br><br>Z metalinin M<sub>A<\/sub> de\u011feri = 27 g\/mol verilmi\u015f.<br>Y metalinin M<sub>A<\/sub> de\u011feri = 40 g\/mol verilmi\u015f.<br><br>Metallerin bile\u015fikteki y\u00fckleri, form\u00fcldeki e<sup>&#8211;<\/sup> de\u011ferine e\u015fittir:<br>Z<sup>3+<\/sup> i\u00e7in e<sup>&#8211;<\/sup> de\u011feri = 3<br>Y<sup>2+<\/sup> i\u00e7in e<sup>&#8211;<\/sup> de\u011feri = 2<br><br>Bu de\u011ferleri, form\u00fclde yerine koyal\u0131m ve katotta biriken Z metalinin k\u00fctlesini (m<sub>Z<\/sub>) bulal\u0131m:<br><img loading=\"lazy\" decoding=\"async\" width=\"200\" height=\"172\" class=\"wp-image-6573\" style=\"width: 200px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari-Seri-Bagli-Elektroliz-Kaplari-Esdeger-Kutle-Gram-Soru-Cozumu-2.jpg\" alt=\"Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlar\u0131-Seri-Ba\u011fl\u0131-Elektroliz-Kaplar\u0131-E\u015fde\u011fer-K\u00fctle-Gram-Soru-\u00c7\u00f6z\u00fcm\u00fc-2\"><br><br>III)<br>XCl kab\u0131nda; X metali, bile\u015fikteki X<sup>+<\/sup> iyonundan olu\u015fur ve katot kutbunda olu\u015fur.<br><br>Faraday\u0131n 1. kanunu ile, 2,3 gram X metalinin birikmesi i\u00e7in, kutuptan ge\u00e7mesi gereken y\u00fck\u00fc bulabiliriz:<br><img loading=\"lazy\" decoding=\"async\" width=\"150\" height=\"173\" class=\"wp-image-6577\" style=\"width: 150px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlari-Seri-Bagli-Elektroliz-Kaplari-Esdeger-Kutle-Gram-Soru-Cozumu-3.jpg\" alt=\"Kimya-ve-Elektrik-Elektroliz-Faraday-Kanunlar\u0131-Seri-Ba\u011fl\u0131-Elektroliz-Kaplar\u0131-E\u015fde\u011fer-K\u00fctle-Gram-Soru-\u00c7\u00f6z\u00fcm\u00fc-3\"><br><br>Devreden 1 mol elektron ge\u00e7seydi 96500 C y\u00fck ge\u00e7mi\u015f olurdu. Buradan hareketle \u015f\u00f6yle bir orant\u0131 kurabiliriz:<br><br><strong>96500 C &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;1 mol e<sup>&#8211;<\/sup> demekse<br>9650 C &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;n mol e<sup>&#8211;<\/sup> demektir.<\/strong><br><br>Do\u011fru orant\u0131 denklemini \u00e7\u00f6zerek n de\u011ferini bulal\u0131m:<br><strong>n . 96500 = 1 . 9650<br>n = 0,1 mol<\/strong> elektron<br><br>Seri ba\u011fl\u0131 elektroliz kaplar\u0131nda, bir kutuptan ka\u00e7 mol elektron ge\u00e7erse, b\u00fct\u00fcn kutuplardan o kadar elektron ge\u00e7er. Bu y\u00fczden;<br><br><strong>Ortadaki kab\u0131n anotundan 0,1 mol elektron elektron ge\u00e7er.<\/strong><\/p>\n\n\n\n<p><em>Cevap:<br>I) X &gt; Y &gt; Z<br>II)<\/em> <em>m<sub>x<\/sub> = 27,6<\/em><br><em>m<sub>z<\/sub> = 10,8<\/em><br><em>III) 0,1 mol elektron<\/em><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Suyun_Elektrolizi\">Suyun Elektrolizi<\/span><\/h3>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Suyun-Elektrolizi-.jpg\" alt=\"Kimya-ve-Elektrik-Elektroliz-Suyun-Elektrolizi-\" class=\"wp-image-6585\" width=\"265\" height=\"340\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Suyun-Elektrolizi-.jpg 300w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Suyun-Elektrolizi--233x300.jpg 233w\" sizes=\"auto, (max-width: 265px) 100vw, 265px\" \/><figcaption>Suyun Elektrolizi<\/figcaption><\/figure>\n<\/div>\n\n\n<ul class=\"wp-block-list\"><li>Elektroliz i\u015fleminin kullan\u0131m alanlar\u0131ndan biri de suyun elektrolizidir.<\/li><li>Saf su elektroliz bir s\u0131v\u0131 de\u011fildir, yani saf suyun elektrik iletkenli\u011fi \u00e7ok d\u00fc\u015f\u00fckt\u00fcr. Bu y\u00fczden saf su elektroliz edilirken, elektrik iletkenli\u011fi kazanmas\u0131 i\u00e7in, i\u00e7inde bir miktar asit (deri\u015fik H<sub>2<\/sub>SO<sub>4<\/sub>) \u00e7\u00f6z\u00fcl\u00fcr.<\/li><li>Suyun elektrolizi sonucunda anot kutbunda oksijen gaz\u0131 (O<sub>2(g)<\/sub>), katot kutbunda ise hidrojen gaz\u0131 (H<sub>2(g)<\/sub>) birikir.<\/li><li>Suyun elektrolizinde, katotta biriken hidrojen gaz\u0131n\u0131n hacmi, anotta biriken oksijen gaz\u0131n\u0131n hacminin iki kat\u0131d\u0131r.<\/li><li>Suyun elektrolizi olay\u0131nda anot ve katot tepkimeleri \u015f\u00f6yledir:<\/li><\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"650\" height=\"113\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Suyun-Elektroliz-Tepkimesi-.jpg\" alt=\"Suyun Elektroliz Tepkimesi\" class=\"wp-image-6590\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Suyun-Elektroliz-Tepkimesi-.jpg 650w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimya-ve-Elektrik-Elektroliz-Suyun-Elektroliz-Tepkimesi--300x52.jpg 300w\" sizes=\"auto, (max-width: 650px) 100vw, 650px\" \/><figcaption>Suyun Elektroliz Tepkimesi<\/figcaption><\/figure>\n<\/div>\n\n\n<ul class=\"wp-block-list\"><li>Elektroliz tepkimesinden anl\u0131yoruz ki, suyun elektrolizi i\u00e7in kullan\u0131lan \u00fcretecin, 2,06 Volttan daha y\u00fcksek bir elektrik enerjisi uygulamas\u0131 gerekir.<\/li><li>Suyun elektrolizi i\u00e7in haz\u0131rlanm\u0131\u015f \u00f6zel bir d\u00fczenek te vard\u0131r. &#8220;<strong><em>Hoffman Voltametresi<\/em><\/strong>&#8221; ad\u0131ndaki bu d\u00fczenek ile elde edilen hidrojen ve oksijen gazlar\u0131n\u0131n d\u00fczenekten al\u0131nmas\u0131 da kolayd\u0131r.<\/li><\/ul>\n\n\n\n<p>A\u015fa\u011f\u0131daki resim, bir Hoffman Voltametresine aittir:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"300\" height=\"318\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimyasallardan-Elektroliz-Hoffman-Voltmetresi.jpg\" alt=\"Elektroliz - Hoffman Voltmetresi\" class=\"wp-image-6479\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimyasallardan-Elektroliz-Hoffman-Voltmetresi.jpg 300w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Kimyasallardan-Elektroliz-Hoffman-Voltmetresi-283x300.jpg 283w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><figcaption>Suyun Elektrolizi &#8211; Hoffman Voltametresi<\/figcaption><\/figure>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>&#8220;Elektroliz&#8221; dersi, bir AYT Kimya konusu olan &#8220;Kimya ve Elektrik&#8221; \u00fcnitesinin 5. b\u00f6l\u00fcm\u00fcd\u00fcr. Bu derste, &#8220;Elektroliz&#8221; konusu, sade ve anla\u015f\u0131l\u0131r bir dille a\u00e7\u0131klanm\u0131\u015ft\u0131r.<\/p>\n","protected":false},"author":1,"featured_media":6479,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[174],"tags":[180],"class_list":["post-6478","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-kimya-ve-elektrik","tag-elektroliz"],"_links":{"self":[{"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/posts\/6478","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/comments?post=6478"}],"version-history":[{"count":1,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/posts\/6478\/revisions"}],"predecessor-version":[{"id":23776,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/posts\/6478\/revisions\/23776"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/media\/6479"}],"wp:attachment":[{"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/media?parent=6478"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/categories?post=6478"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/tags?post=6478"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}