{"id":5945,"date":"2021-01-01T23:50:43","date_gmt":"2021-01-01T20:50:43","guid":{"rendered":"https:\/\/sitecenneti.com\/kimya\/?p=5945"},"modified":"2024-05-06T21:31:56","modified_gmt":"2024-05-06T18:31:56","slug":"1-indirgenme-yukseltgenme-tepkimelerinde-elektrik-akimi","status":"publish","type":"post","link":"https:\/\/sitecenneti.com\/kimya\/ayt-kimya\/kimya-ve-elektrik\/1-indirgenme-yukseltgenme-tepkimelerinde-elektrik-akimi\/","title":{"rendered":"1. \u0130ndirgenme-Y\u00fckseltgenme Tepkimelerinde Elektrik Ak\u0131m\u0131"},"content":{"rendered":"<div id=\"toc_container\" class=\"toc_transparent no_bullets\"><p class=\"toc_title\">\u0130&ccedil;indekiler<\/p><ul class=\"toc_list\"><li><a href=\"#Indirgenme-Yukseltgenme_Tepkimesi_Nedir\">\u0130ndirgenme-Y\u00fckseltgenme Tepkimesi Nedir?<\/a><ul><li><a href=\"#Indirgenme_Reduksiyon_Nedir\">\u0130ndirgenme (Red\u00fcksiyon) Nedir?<\/a><ul><li><a href=\"#Indirgenme_Yari_Tepkimeleri_IYT\">\u0130ndirgenme Yar\u0131 Tepkimeleri (\u0130YT)<\/a><\/li><\/ul><\/li><li><a href=\"#Yukseltgenme_Oksidasyon_Nedir\">Y\u00fckseltgenme (Oksidasyon) Nedir?<\/a><ul><li><a href=\"#Yukseltgenme_Yari_Tepkimeleri_YYT\">Y\u00fckseltgenme Yar\u0131 Tepkimeleri (YYT)<\/a><\/li><\/ul><\/li><li><a href=\"#Yari_Tepkimeleri_Denklestirme\">Yar\u0131 Tepkimeleri Denkle\u015ftirme<\/a><\/li><li><a href=\"#Ornek\">\u00d6rnek:<\/a><ul><li><a href=\"#Ornek-2\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-3\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-4\">\u00d6rnek:<\/a><\/li><\/ul><\/li><\/ul><\/li><li><a href=\"#Redoks_Indirgenme-Yukseltgenme_Tepkimeleri\">Redoks (\u0130ndirgenme-Y\u00fckseltgenme) Tepkimeleri<\/a><ul><li><a href=\"#Redoks_Tepkimelerini_Tanimak\">Redoks Tepkimelerini Tan\u0131mak<\/a><ul><li><a href=\"#Ornek-5\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-6\">\u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#Redoks_Tepkimelerinin_Denklestirilmesi\">Redoks Tepkimelerinin Denkle\u015ftirilmesi<\/a><ul><li><a href=\"#Ornek-7\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-8\">\u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#Indirgen_ve_Yukseltgen_Maddeler\">\u0130ndirgen ve Y\u00fckseltgen Maddeler<\/a><ul><li><a href=\"#Ornek-9\">\u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#Bazi_Indirgen_ve_Yukseltgen_Maddeler_ve_Ozellikleri\">Baz\u0131 \u0130ndirgen ve Y\u00fckseltgen Maddeler ve \u00d6zellikleri<\/a><\/li><\/ul><\/li><li><a href=\"#Redoks_Tepkimeleriyle_Elektrik_Enerjisi_Arasindaki_Iliski\">Redoks Tepkimeleriyle Elektrik Enerjisi Aras\u0131ndaki \u0130li\u015fki<\/a><ul><li><a href=\"#Ornek-10\">\u00d6rnek:<\/a><\/li><\/ul><\/li><\/ul><\/div>\n\n<h2 class=\"wp-block-heading\"><span id=\"Indirgenme-Yukseltgenme_Tepkimesi_Nedir\">\u0130ndirgenme-Y\u00fckseltgenme Tepkimesi Nedir?<\/span><\/h2>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-purple-color\">Elektrokimya<\/mark><\/strong>: Elektrik enerjisi ile kimyasal tepkimeler aras\u0131ndaki ili\u015fkiyi inceleyen kimya disiplinine <strong>elektrokimya<\/strong> denir.\n<ul class=\"wp-block-list\">\n<li>Kimya ve Elektrik = Elektrokimya<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Amac\u0131m\u0131z <strong>elektrik <\/strong>\u00fcretmekse bir <strong>indirgenme y\u00fckseltgenme tepkimesi<\/strong> ger\u00e7ekle\u015ftirmeliyiz.<\/li>\n\n\n\n<li><strong><em>\u0130ndirgenme-Y\u00fckseltgenme tepkimelerinde;<\/em><\/strong>\n<ul class=\"wp-block-list\">\n<li>Ya <strong><em>elektrik ak\u0131m\u0131<\/em><\/strong> olu\u015fur<\/li>\n\n\n\n<li>Ya da elektrik enerjisi harcan\u0131r.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>&#8220;<em>\u0130ndirgenme-y\u00fckseltgenme<\/em>&#8221; tepkimelerinde, ad\u0131ndan anla\u015f\u0131laca\u011f\u0131 \u00fczere, mutlaka:\n<ul class=\"wp-block-list\">\n<li>en az bir atom <strong>indirgenir <\/strong>(y\u00fck\u00fc azal\u0131r)<\/li>\n\n\n\n<li>en az bir atom da <strong>y\u00fckseltgenir <\/strong>(y\u00fck\u00fc artar).<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Bu tepkimelerde de b\u00fct\u00fcn tepkimelerde oldu\u011fu gibi:\n<ul class=\"wp-block-list\">\n<li>Toplam k\u00fctle ve<\/li>\n\n\n\n<li>Toplam y\u00fck korunur.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Bu tepkimeleri tan\u0131mak i\u00e7in tepkimedeki atomlar\u0131n <strong><em>y\u00fcklerini (y\u00fckseltgenme basamaklar\u0131n\u0131)<\/em><\/strong> hesaplamak gerekir.\n<ul class=\"wp-block-list\">\n<li>Atom <strong>y\u00fck\u00fc<\/strong> i\u00e7in \u015fu kavramlar da kullan\u0131labilir:\n<ul class=\"wp-block-list\">\n<li>Y\u00fckseltgenme basama\u011f\u0131 <\/li>\n\n\n\n<li>Oksidasyon basama\u011f\u0131<\/li>\n\n\n\n<li>De\u011ferlik<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group has-background\" style=\"background-color:#e7f6ff\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p><strong><em>Y\u00fckseltgenme basama\u011f\u0131 (y\u00fck) hesaplama<\/em><\/strong> ile ilgili eksi\u011fi olan arkada\u015flar, a\u015fa\u011f\u0131daki ba\u011flant\u0131ya t\u0131klayarak, bu eksiklerini kapatabilirler:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><a href=\"https:\/\/sitecenneti.com\/kimya\/ayt-kimya\/modern-atom-teorisi\/yukseltgenme-basamagi\/\" target=\"_blank\" rel=\"noreferrer noopener\">Y\u00fckseltgenme Basama\u011f\u0131<\/a><\/li>\n<\/ul>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Indirgenme_Reduksiyon_Nedir\">\u0130ndirgenme (Red\u00fcksiyon) Nedir?<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>\u0130ndirgenmenin di\u011fer ad\u0131 <strong>red\u00fcksiyon<\/strong>dur.<\/li>\n\n\n\n<li>\u0130ndirgenme tepkimelerinde atomun:\n<ul class=\"wp-block-list\">\n<li>Y\u00fck\u00fc azal\u0131r, yani \u00fcr\u00fcnlerdeki y\u00fck\u00fc daha k\u00fc\u00e7\u00fckt\u00fcr.\n<ul class=\"wp-block-list\">\n<li>Fe<sup>3+<\/sup> + e<sup>&#8211;<\/sup> \u2192 Fe<sup>2+<\/sup><\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Elektron al\u0131r.<\/li>\n\n\n\n<li>Yar\u0131 \u00e7ap\u0131 artar.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Sadece indirgenmenin ger\u00e7ekle\u015fti\u011fi tepkimelere <strong><em>indirgenme yar\u0131 tepkimesi (\u0130YT)<\/em><\/strong> de denir.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><span id=\"Indirgenme_Yari_Tepkimeleri_IYT\">\u0130ndirgenme Yar\u0131 Tepkimeleri (\u0130YT)<\/span><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>B\u00fct\u00fcn <em>indirgenme yar\u0131 tepkimelerinde<\/em> bir atom ya da molek\u00fcl (kimyasal t\u00fcr) elektron al\u0131r ve y\u00fck\u00fc azal\u0131r.<\/li>\n\n\n\n<li>Kimyasal t\u00fcr ka\u00e7 tane elektron ald\u0131ysa, y\u00fck\u00fc o kadar d\u00fc\u015fer.<\/li>\n\n\n\n<li>Al\u0131nan elektronlar tepkimenin girenler k\u0131sm\u0131ndad\u0131r.<\/li>\n\n\n\n<li>A\u015fa\u011f\u0131da bu olaya baz\u0131 \u00f6rnekler verilmi\u015ftir:\n<ul class=\"wp-block-list\">\n<li><strong>Al<sup>3+<\/sup> + 3e<sup>&#8211;<\/sup> \u2192 Al<\/strong><\/li>\n\n\n\n<li><strong>Fe<sup>3+<\/sup> + e<sup>&#8211;<\/sup> \u2192 Fe<sup>2+<\/sup><\/strong><\/li>\n\n\n\n<li><strong>Cl<sub>2<\/sub> + 2e<sup>&#8211;<\/sup> \u2192 2Cl<sup>1-<\/sup><\/strong><\/li>\n\n\n\n<li><strong>Cu<sup>2+<\/sup> + 2e<sup>&#8211;<\/sup> \u2192 Cu<\/strong><\/li>\n\n\n\n<li><strong>Ag<sup>+<\/sup> + e<sup>&#8211;<\/sup> \u2192 Ag<\/strong><\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Yukseltgenme_Oksidasyon_Nedir\">Y\u00fckseltgenme (Oksidasyon) Nedir?<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Y\u00fckseltgenmenin di\u011fer ad\u0131 <strong>red\u00fcksiyon<\/strong>dur.<\/li>\n\n\n\n<li>Y\u00fckseltgenme tepkimelerinde atomun:\n<ul class=\"wp-block-list\">\n<li>Y\u00fck\u00fc artar, yani \u00fcr\u00fcnlerdeki y\u00fck\u00fc daha b\u00fcy\u00fckt\u00fcr.\n<ul class=\"wp-block-list\">\n<li>Fe<sup>2+<\/sup> \u2192 Fe<sup>3+<\/sup> + e<sup>&#8211;<\/sup><\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Elektron verir.<\/li>\n\n\n\n<li>Yar\u0131 \u00e7ap\u0131 azal\u0131r.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Sadece y\u00fckseltgenmenin ger\u00e7ekle\u015fti\u011fi tepkimelere <strong><em>y\u00fckseltgenme yar\u0131 tepkimesi (YYT)<\/em><\/strong> de denir.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><span id=\"Yukseltgenme_Yari_Tepkimeleri_YYT\">Y\u00fckseltgenme Yar\u0131 Tepkimeleri (YYT)<\/span><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>B\u00fct\u00fcn <em>y\u00fckseltgenme yar\u0131 tepkimelerinde<\/em> bir atom ya da molek\u00fcl elektron verir.<\/li>\n\n\n\n<li>Kimyasal t\u00fcr ka\u00e7 tane elektron verdiyse, y\u00fck\u00fc o kadar artar.<\/li>\n\n\n\n<li>Verilen elektronlar tepkimenin \u00fcr\u00fcnler k\u0131sm\u0131ndad\u0131r.<\/li>\n\n\n\n<li>A\u015fa\u011f\u0131da, bu olaya baz\u0131 \u00f6rnekler verilmi\u015ftir:\n<ul class=\"wp-block-list\">\n<li><strong>Al \u2192 Al<sup>3+<\/sup> + 3e<sup>&#8211;<\/sup><\/strong><\/li>\n\n\n\n<li><strong>Fe<sup>2+<\/sup> \u2192 Fe<sup>3+<\/sup> + e<sup>&#8211;<\/sup><\/strong><\/li>\n\n\n\n<li><strong>2Cl<sup>1-<\/sup> \u2192 Cl<sub>2<\/sub> + 2e<sup>&#8211;<\/sup><\/strong><\/li>\n\n\n\n<li><strong>Cu \u2192 Cu<sup>2+<\/sup> + 2e<sup>&#8211;<\/sup><\/strong><\/li>\n\n\n\n<li><strong>Ag \u2192 Ag<sup>+<\/sup> + e<sup>&#8211;<\/sup><\/strong><\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Yari_Tepkimeleri_Denklestirme\">Yar\u0131 Tepkimeleri Denkle\u015ftirme<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>B\u00fct\u00fcn tepkime denklemleri gibi, indirgenme ve y\u00fckseltgenme yar\u0131 tepkimelerine ait denklemler de denkle\u015fmi\u015f olmal\u0131d\u0131r.<\/li>\n\n\n\n<li>Yar\u0131 tepkimeler denkle\u015ftirilirken a\u015fa\u011f\u0131daki kurallara dikkat edilir:\n<ul class=\"wp-block-list\">\n<li>Yar\u0131 tepkimenin giren ve \u00fcr\u00fcnlerindeki <strong><em>atom say\u0131lar\u0131 e\u015fitlenir.<\/em><\/strong><\/li>\n\n\n\n<li>Sonra atomun y\u00fck\u00fcndeki artma veya azalmaya g\u00f6re <em><strong>al\u0131nan-verilen elektron say\u0131s\u0131 hesaplan\u0131r.<\/strong><\/em><\/li>\n\n\n\n<li>Atomun katsay\u0131s\u0131 ile ald\u0131\u011f\u0131 verdi\u011fi elektron \u00e7arp\u0131l\u0131r ve bulunan say\u0131da elektron denklemin uygun taraf\u0131na eklenir.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-constrained wp-block-group-is-layout-constrained\">\n<h3 class=\"wp-block-heading\"><span id=\"Ornek\">\u00d6rnek:<\/span><\/h3>\n\n\n\n<p><strong>Mesela klor atomunun -1 grip n\u00f6t\u00fcr bir klor molek\u00fcl\u00fcne d\u00f6n\u00fc\u015ft\u00fc\u011f\u00fc yar\u0131 tepkimeyi denkle\u015ftirelim:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Tarif edilen tepkimenin denklemi \u015f\u00f6yle olmal\u0131d\u0131r:\n<ul class=\"wp-block-list\">\n<li><strong>Cl<sup>1-<\/sup> \u2192 Cl<sub>2<\/sub><\/strong><\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Cl<sup>1-<\/sup> \u2192 Cl<sub>2<\/sub><\/strong> tepkimesinde Cl atomu -1 den s\u0131f\u0131ra y\u00fckseltgenmi\u015ftir.\n<ul class=\"wp-block-list\">\n<li>O zaman bu tepkime bir y\u00fckseltgenme yar\u0131 tepkimesidir.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Tepkimeyi denkle\u015ftirmek i\u00e7in \u00f6nce atom say\u0131lar\u0131n\u0131 e\u015fitleriz:\n<ul class=\"wp-block-list\">\n<li>2 tane Cl \u00e7\u0131kt\u0131ysa 2 tane girmek zorundad\u0131r:\n<ul class=\"wp-block-list\">\n<li><strong>2Cl<sup>1-<\/sup> \u2192 Cl<sub>2<\/sub><\/strong><\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Sonra elektron say\u0131s\u0131n\u0131 buluruz:\n<ul class=\"wp-block-list\">\n<li>-1 den s\u0131f\u0131ra bir basamak y\u00fckselen atom 1 elektron verir. Bu tepkimeyi 2 tane Cl atomu verdi\u011finden ki\u015fi ba\u015f\u0131 1 elektrondan toplam 2 elektron verilir. Denklemin son hali \u015f\u00f6yle olur:\n<ul class=\"wp-block-list\">\n<li><strong>2Cl<sup>1-<\/sup> \u2192 Cl<sub>2<\/sub> + 2e<sup>&#8211;<\/sup><\/strong><\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/div><\/div>\n\n\n\n<ul class=\"wp-block-list\">\n<li>B\u00fct\u00fcn kimyasal tepkimelerde oldu\u011fu gibi, <em>indirgenme ve y\u00fckseltgenme yar\u0131 tepkimelerinde<\/em> de <strong><em>girenlerin toplam y\u00fck\u00fc, \u00fcr\u00fcnlerin toplam y\u00fck\u00fcne mutlaka e\u015fittir.<\/em><\/strong>\n<ul class=\"wp-block-list\">\n<li>Y\u00fckleri toplarken, her bir elektronun -1 y\u00fckl\u00fc oldu\u011funu unutmamal\u0131y\u0131z.<\/li>\n\n\n\n<li>Yazd\u0131\u011f\u0131m\u0131z, yar\u0131 tepkimenin do\u011fru olup olmad\u0131\u011f\u0131na y\u00fck e\u015fitli\u011fini test ederek anlayabiliriz.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-2\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p><strong>Demir atomunun 0&#8217;dan, +2&#8217;ye y\u00fckseltgendi\u011fi yar\u0131 tepkimeyi yaz\u0131n\u0131z.<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center\" style=\"font-size:22px\"><strong><strong><strong><strong>Fe \u2192 Fe<sup>2+<\/sup> <strong><strong>+ 2e<sup>&#8211;<\/sup><\/strong><\/strong><\/strong><\/strong><\/strong><\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Demir n\u00f6t\u00fcr girip +2 \u00e7\u0131k\u0131yorsa tepkime denklemi \u015f\u00f6yle olur:<\/p>\n\n\n\n<p><strong>Fe \u2192 Fe<sup>2+<\/sup><\/strong><\/p>\n\n\n\n<p>Demirin y\u00fck\u00fc 2 basamak artm\u0131\u015f, yani 2 tane elektron vermi\u015f. Verilen elektron girenlere yaz\u0131l\u0131r:<\/p>\n\n\n\n<p><strong><strong><strong>Fe \u2192 Fe<sup>2+<\/sup> + 2e<sup>&#8211;<\/sup><\/strong><\/strong><\/strong><\/p>\n\n\n\n<p>Bir de toplam y\u00fcklere bakarak, yar\u0131 tepkimenin sa\u011flamas\u0131n\u0131 yapal\u0131m:<\/p>\n\n\n\n<p>Tepkimenin girenler k\u0131sm\u0131ndaki atomun y\u00fck\u00fc:<br><strong>0<\/strong><\/p>\n\n\n\n<p>Tepkimenin \u00fcr\u00fcnler k\u0131sm\u0131ndaki iyonun ve 2 tane elektronun toplam y\u00fck\u00fc:<br><strong><strong>+2 &#8211; 2<\/strong> = 0<\/strong><\/p>\n\n\n\n<p>Girenlerde k\u0131sm\u0131ndaki y\u00fck toplam ve \u00fcr\u00fcnler k\u0131sm\u0131nda y\u00fck toplam\u0131 e\u015fit oldu\u011fundan bu yar\u0131 tepkime denktir.<\/p>\n\n\n\n<p><strong><em>Cevap: <strong><strong><strong><strong><strong>Fe \u2192 Fe<sup>2+<\/sup> + 2e<sup>&#8211;<\/sup><\/strong><\/strong><\/strong><\/strong><\/strong><\/em><\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group stcnnt-yazi-ici-reklam\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p>Bu bir reklamd\u0131r:<\/p>\n\n\n\n<script async=\"\" src=\"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\"><\/script>\n<ins class=\"adsbygoogle\" style=\"display:block; text-align:center;\" data-ad-layout=\"in-article\" data-ad-format=\"fluid\" data-ad-client=\"ca-pub-6366953309324763\" data-ad-slot=\"9738116384\"><\/ins>\n<script>\n     (adsbygoogle = window.adsbygoogle || []).push({});\n<\/script>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-3\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p>Bir indirgenme-y\u00fckseltgenme tepkimesine kat\u0131lan al\u00fcminyum atomu, tepkimeye +3 y\u00fckl\u00fc bir katyon olarak girmi\u015f, n\u00f6t\u00fcr olarak \u00e7\u0131km\u0131\u015ft\u0131r.<\/p>\n\n\n\n<p><strong>Buna g\u00f6re, al\u00fcminyumun yar\u0131 tepkimesi nas\u0131l olmal\u0131d\u0131r?<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center\" style=\"font-size:22px\"><strong><strong><strong>Al<sup>3+<\/sup> + 3e<sup>&#8211;<\/sup> \u2192 Al<\/strong><\/strong><\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Soruda verilenlere g\u00f6re:<\/p>\n\n\n\n<p>Al\u00fcminyum;<br>&#8212; girenler k\u0131sm\u0131nda +3 y\u00fckl\u00fc olacak,<br>&#8212; \u00fcr\u00fcnler k\u0131sm\u0131nda da y\u00fcks\u00fcz olacakt\u0131r.<\/p>\n\n\n\n<p><strong><strong>Al<sup>3+<\/sup> \u2192 Al<\/strong><\/strong><\/p>\n\n\n\n<p>Tepkimede al\u00fcminyumun y\u00fck\u00fc azalm\u0131\u015ft\u0131r. O zaman bu tepkime bir indirgenme tepkimesidir. \u0130ndirgenen her atom gibi al\u00fcminyum da elektron alm\u0131\u015ft\u0131r.<\/p>\n\n\n\n<p>Y\u00fck\u00fc 3 basamak indi\u011fi i\u00e7in 3 elektron alm\u0131\u015ft\u0131r.<\/p>\n\n\n\n<p>O zaman, tepkimenin girenler k\u0131sm\u0131na 3 tane elektron eklemeliyiz:<\/p>\n\n\n\n<p><strong><strong>Al<sup>3+<\/sup> + 3e<sup>&#8211;<\/sup> \u2192 Al<\/strong><\/strong><\/p>\n\n\n\n<p>\u0130ndirgenme yar\u0131 tepkimesini bulduk ve soruyu \u00e7\u00f6zm\u00fc\u015f olduk. Fakat, i\u00e7imiz rahat etsin diye sa\u011flamas\u0131n\u0131 yapal\u0131m.<\/p>\n\n\n\n<p>Tepkimenin girenler k\u0131sm\u0131nda toplam y\u00fck:<br><strong>+3 + (-3) = 0<\/strong><\/p>\n\n\n\n<p>Tepkimenin \u00fcr\u00fcnler k\u0131sm\u0131nda toplam y\u00fck:<br><strong>0<\/strong><\/p>\n\n\n\n<p>Girenlerin ve \u00fcr\u00fcnlerin toplam y\u00fck\u00fc e\u015fit ise her \u015fey yolunda demektir.<\/p>\n\n\n\n<p><strong><em>Cevap: <strong><strong>Al<sup>3+<\/sup> + 3e<sup>&#8211;<\/sup> \u2192 Al<\/strong><\/strong><\/em><\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group stcnnt-yazi-ici-reklam\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p>Bu bir reklamd\u0131r:<\/p>\n\n\n\n<script async=\"\" src=\"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\"><\/script>\n<ins class=\"adsbygoogle\" style=\"display:block; text-align:center;\" data-ad-layout=\"in-article\" data-ad-format=\"fluid\" data-ad-client=\"ca-pub-6366953309324763\" data-ad-slot=\"9738116384\"><\/ins>\n<script>\n     (adsbygoogle = window.adsbygoogle || []).push({});\n<\/script>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-4\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p>Bir yanma tepkimesinde, O<sub>2<\/sub> elementi -2 y\u00fcklenmi\u015ftir.<\/p>\n\n\n\n<p><strong>Buna g\u00f6re, oksijen elementinin yar\u0131 tepkimesi nas\u0131l olmal\u0131d\u0131r?<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center\" style=\"font-size:22px\"><strong><strong><strong>O<sub>2<\/sub> <strong>+ 4e<sup>&#8211;<\/sup><\/strong><\/strong><\/strong><\/strong> <strong><strong><strong>\u2192 2O<sup>2-<\/sup><\/strong><\/strong><\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Yanma tepkimelerinde, Oksijen, girenler k\u0131sm\u0131nda ve O<sub>2<\/sub> molek\u00fcl\u00fc \u015feklindedir.<\/p>\n\n\n\n<p>Sorudan anla\u015f\u0131ld\u0131\u011f\u0131na g\u00f6re \u00fcr\u00fcnlerde de -2 y\u00fckl\u00fc olmaktad\u0131r. O zaman \u015fu denklemi yazabilir:<\/p>\n\n\n\n<p><strong><strong>O<sub>2<\/sub> \u2192 O<sup>2-<\/sup><\/strong><\/strong><\/p>\n\n\n\n<p>\u00d6nce atom say\u0131s\u0131n\u0131 halledelim:<br> &#8212; 2 tane O atomu girdiyse 2 tane \u00e7\u0131kmal\u0131d\u0131r:<\/p>\n\n\n\n<p><strong><strong>O<sub>2<\/sub> \u2192 2O<sup>2-<\/sup><\/strong><\/strong><\/p>\n\n\n\n<p>Oksijen s\u0131f\u0131r girmi\u015f -2 \u00e7\u0131km\u0131\u015f. Y\u00fck\u00fc 2 basamak azalm\u0131\u015f, yani oksijen atomu 2 elektron alm\u0131\u015f.<\/p>\n\n\n\n<p>Tepkimede 2 oksijen atomu var. 1 tane O atomu 2 elektron ald\u0131ysa, 2 tanesi 4 elektron al\u0131r:<\/p>\n\n\n\n<p><strong><strong><strong>O<sub>2<\/sub> + 4e<sup>&#8211;<\/sup><\/strong><\/strong> <strong><strong>\u2192 2O<sup>2-<\/sup><\/strong><\/strong><\/strong><\/p>\n\n\n\n<p><strong><em>Cevap: <strong><strong><strong><strong>O<sub>2<\/sub> + 4e<sup>&#8211;<\/sup><\/strong><\/strong> <strong><strong>\u2192 2O<sup>2-<\/sup><\/strong><\/strong><\/strong><\/strong><\/em><\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<p><\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><span id=\"Redoks_Indirgenme-Yukseltgenme_Tepkimeleri\">Redoks (\u0130ndirgenme-Y\u00fckseltgenme) Tepkimeleri<\/span><\/h2>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"300\" height=\"145\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Redoks-Reduksiyon-Oksidasyon-Indirgenme-Yukseltgenme-Tepkimeleri-.jpg\" alt=\"Redoks Kelimesinin Anlam\u0131\" class=\"wp-image-6003\"\/><figcaption class=\"wp-element-caption\">Redoks Kelimesinin Anlam\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Red<\/strong>oks kelimesindeki, &#8220;Red&#8221;, &#8220;<em>red\u00fcksiyon&#8221; kavram\u0131ndan<\/em> gelir; &#8220;Oks&#8221;, &#8220;<em>oksidasyon&#8221; kavram\u0131ndan<\/em> gelir.<\/li>\n\n\n\n<li>Redoks tepkimelerinde , hem indirgenme hem de y\u00fckseltgenme tepkimeleri ge\u00e7ekle\u015fir.\n<ul class=\"wp-block-list\">\n<li>Bir redoks tepkimesi, indirgenme ve y\u00fckseltgenme yar\u0131 tepkimelerinin birle\u015fimidir.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Redoks tepkimelerinde, <strong><em>al\u0131nan ve verilen elektron say\u0131lar\u0131 her zaman e\u015fittir.<\/em><\/strong>\n<ul class=\"wp-block-list\">\n<li>Bu y\u00fczden <strong><em>elektronlar sadele\u015fir ve tepkime denkleminde g\u00f6r\u00fcnmez.<\/em><\/strong><\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Redoks_Tepkimelerini_Tanimak\">Redoks Tepkimelerini Tan\u0131mak<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Redoks tepkimelerini tan\u0131man\u0131n iki yolu vard\u0131r:\n<ol class=\"wp-block-list\">\n<li>Ezberden tan\u0131mak<\/li>\n\n\n\n<li>Y\u00fckseltgenme basama\u011f\u0131 (y\u00fck) hesaplayarak tan\u0131mak<\/li>\n<\/ol>\n<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Redoks Tepkimelerini Ezbere Tan\u0131mak:<\/strong>\n<ul class=\"wp-block-list\">\n<li>Bir element bile\u015fi\u011fe d\u00f6n\u00fc\u015f\u00fcyorsa ortal\u0131kta e<sup>&#8211;<\/sup> yoksa, tepkime bir redoks tepkimesidir.\n<ul class=\"wp-block-list\">\n<li>Yanma tepkimeleri<\/li>\n\n\n\n<li>Metal-asit tepkimeleri<\/li>\n\n\n\n<li>Metal-baz tepkimeleri<\/li>\n\n\n\n<li>Ametal-asit tepkimeleri<\/li>\n\n\n\n<li>Ametal-baz tepkimeleri<\/li>\n\n\n\n<li>Metal-su tepkimeleri<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<ol class=\"wp-block-list\" start=\"2\">\n<li><strong>Y\u00fck Hesaplayarak Redoks Tepkimelerini Tan\u0131mak:<\/strong>\n<ul class=\"wp-block-list\">\n<li>Tepkimedeki b\u00fct\u00fcn atomlar\u0131n teker teker y\u00fckleri (y\u00fckseltgenme basamaklar\u0131) hesaplan\u0131r.<\/li>\n\n\n\n<li>Y\u00fckseltgenen ve indirgenen atomlar varsa, tepkime bir redoks tepkimesidir.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<p>Y\u00fckseltgenme basama\u011f\u0131 hesaplarken, hat\u0131rlamam\u0131z gereken temel kurallar \u015funlard\u0131r:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>Elementlerin y\u00fck\u00fc zaten verilmi\u015ftir. Verilmemi\u015fse s\u0131f\u0131rd\u0131r.<\/li>\n\n\n\n<li>Bile\u015fiklerde ve k\u00f6k iyonlarda, herkesin bir y\u00fck\u00fc vard\u0131r fakat hi\u00e7 biri g\u00f6r\u00fcnmez.<\/li>\n\n\n\n<li>Bile\u015fiklerde, b\u00fct\u00fcn atomlar\u0131n toplam y\u00fck\u00fc s\u0131f\u0131rd\u0131r.<\/li>\n\n\n\n<li>K\u00f6k iyonlarda, b\u00fct\u00fcn atomlar\u0131n toplam y\u00fck\u00fc iyonun y\u00fck\u00fcne e\u015fittir.<\/li>\n\n\n\n<li>Yapmam\u0131z gereken, bildi\u011fimiz atomlar\u0131n y\u00fck\u00fcn\u00fc yazmak, bilmedi\u011fimizi hesaplamakt\u0131r.<\/li>\n\n\n\n<li>Bilmedi\u011fimiz y\u00fckleri hesaplamak i\u00e7in, bile\u015fikteki veya iyondaki herkesin y\u00fck\u00fc toplan\u0131r ve toplam y\u00fcke e\u015fitlenir.<\/li>\n<\/ol>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-5\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-white-background-color has-background\"><strong>CH<sub>4<\/sub> + 2O<sub>2<\/sub> \u2192 CO<sub>2<\/sub> + 2H<sub>2<\/sub>O<\/strong><\/p>\n\n\n\n<p>Yukar\u0131da verilen tepkime i\u00e7in a\u015fa\u011f\u0131daki sorular\u0131 yan\u0131tlay\u0131n\u0131z.<\/p>\n\n\n\n<p><strong>a) Tepkimedeki b\u00fct\u00fcn atomlar\u0131n y\u00fckseltgenme basamaklar\u0131n\u0131 hesaplay\u0131n\u0131z.<\/strong><br><strong>b) Tepkimenin bir redoks tepkimesi oldu\u011funu ispatlay\u0131n\u0131z.<\/strong><br><strong>c) \u0130ndirgenme ve y\u00fckseltgenme yar\u0131 tepkimelerini yaz\u0131n\u0131z.<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p><em>a)<\/em><br><em>C<sup>-4<\/sup>H<sup>+1<\/sup><sub>4<\/sub> + 2O<sup>0<\/sup><sub>2<\/sub> \u2192 C<sup>+4<\/sup>O<sup>-2<\/sup><sub>2<\/sub> + 2H<sup>+2<\/sup><sub>2<\/sub>O<sup>-2<\/sup><\/em><\/p>\n\n\n\n<p><em>b)<br>C atomu; -4&#8217;ten +4&#8217;e y\u00fckseltgenmi\u015f.<br>0 atomu; 0&#8217;dan -2&#8217;ye indirgenmi\u015ftir.<br>\u0130ndirgenme ve y\u00fckseltgenme olaylar\u0131 ger\u00e7ekle\u015fti\u011fi i\u00e7in bu tepkime bir redoks tepkimesidir.<\/em><\/p>\n\n\n\n<p><em>c)<br>\u0130YT: 0<sub>2<\/sub> + 4e<sup>&#8211;<\/sup> \u2192 2O<sup>-2<\/sup><br>YYT: C<sup>-4<\/sup> \u2192 C<sup>+4<\/sup> + 8e<sup>&#8211;<\/sup><\/em><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"stcnnt-no-bordered-img\"><strong><strong>CH<sub>4<\/sub> + 2O<sub>2<\/sub> \u2192 CO<sub>2<\/sub> + 2H<sub>2<\/sub>O<\/strong><\/strong><br><br><strong>a)<\/strong><br>Tepkimedeki her bir maddenin y\u00fckseltgenme basama\u011f\u0131n\u0131 ayr\u0131 ayr\u0131 hesaplamam\u0131z gerekiyor.<br><br>Y\u00fck bulurken, hat\u0131rlamam\u0131z gereken temel kurallar \u015funlard\u0131r:<br>&#8211; Elementlerin y\u00fck\u00fc zaten verilmi\u015ftir. Verilmemi\u015fse s\u0131f\u0131rd\u0131r.<br>&#8211; Bile\u015fiklerde, herkesin bir y\u00fck\u00fc vard\u0131r fakat hi\u00e7 biri g\u00f6r\u00fcnmez.<br>&#8211; Bile\u015fiklerde, b\u00fct\u00fcn atomlar\u0131n toplam y\u00fck\u00fc s\u0131f\u0131rd\u0131r.<br>&#8211; K\u00f6k iyonlarda, b\u00fct\u00fcn atomlar\u0131n toplam y\u00fck\u00fc iyonun y\u00fck\u00fcne e\u015fittir.<br>&#8211; Yapmam\u0131z gereken, bildi\u011fimiz atomlar\u0131n y\u00fck\u00fcn\u00fc yazmak, bilmedi\u011fimizi hesaplamakt\u0131r.<br><br><strong>CH<sub>4<\/sub><\/strong><br>&#8211; H atomunun y\u00fck\u00fc ezbere bilinmelidir: +1<br>&#8211; C atomunun y\u00fck\u00fcne x diyelim ve hesaplayal\u0131m.<br><strong>(C<sup>x<\/sup> H<sup>+1<\/sup> <strong>H<sup>+1<\/sup><\/strong><\/strong> <strong>H<sup>+1<\/sup><\/strong> <strong>H<sup>+1<\/sup>)<sup>0<\/sup><\/strong><br><strong>x + 1 + 1 + 1 + 1 = 0<br>x + 4 = 0<br>x = -4<\/strong><br><br><strong>O<sub>2<\/sub><\/strong><br>O<sub>2<\/sub><sup>0<\/sup>: Elementlerin y\u00fck\u00fc zaten bellidir. Y\u00fckleri yoksa s\u0131f\u0131rd\u0131r.<br><strong>(O<sup>x<\/sup> O<sup>x<\/sup>)<sup>0<\/sup><\/strong><br><strong>x + x = 0<br>x = 0<\/strong><br><br><strong>CO<sub>2<\/sub><\/strong><br>&#8211; O atomunun y\u00fck\u00fc ezbere bilinmelidir: -2<br>&#8211; C atomunun y\u00fck\u00fcne x diyelim ve hesaplayal\u0131m.<br><strong>(C<sup>x<\/sup> O<sup>-2<\/sup> O<strong><sup>-2<\/sup><\/strong>)<sup>0<\/sup><\/strong><br><strong>x &#8211; 2 &#8211;  2 = 0<br>x &#8211; 4 = 0<br>x = +4<\/strong><br><br><strong>H<sub>2<\/sub>O<\/strong><br>&#8211; H ve O atomlar\u0131n\u0131n y\u00fck\u00fc ezbere bilinmelidir.<br><strong>(H<sup>+1<\/sup> <strong>H<sup>+1<\/sup><\/strong> O<sup>-2<\/sup>)<sup>0<\/sup><\/strong><br><br>\u015eimdi, tepkime denklemini, herkesin y\u00fckseltgenme basama\u011f\u0131n\u0131 \u00fczerine yazarak g\u00f6sterelim:<br><img loading=\"lazy\" decoding=\"async\" width=\"450\" height=\"50\" class=\"wp-image-5987\" style=\"width: 450px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Redoks-Reduksiyon-Oksidasyon-Indirgenme-Yukseltgenme-Tepkimeleri-Soru-Cozumu-3.jpg\" alt=\"Redoks-Red\u00fcksiyon-Oksidasyon-\u0130ndirgenme-Y\u00fckseltgenme-Tepkimeleri-Soru-\u00c7\u00f6z\u00fcm\u00fc-3\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Redoks-Reduksiyon-Oksidasyon-Indirgenme-Yukseltgenme-Tepkimeleri-Soru-Cozumu-3.jpg 450w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Redoks-Reduksiyon-Oksidasyon-Indirgenme-Yukseltgenme-Tepkimeleri-Soru-Cozumu-3-300x33.jpg 300w\" sizes=\"auto, (max-width: 450px) 100vw, 450px\" \/><br><br><strong>b) <\/strong><br>Dikkat edersek, tepkimede, indirgenen ve y\u00fckseltgenen atomlar\u0131 oldu\u011funu g\u00f6rebiliriz:<br><img loading=\"lazy\" decoding=\"async\" width=\"450\" height=\"151\" class=\"wp-image-5988\" style=\"width: 450px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Redoks-Reduksiyon-Oksidasyon-Indirgenme-Yukseltgenme-Tepkimeleri-Soru-Cozumu-4.jpg\" alt=\"Redoks-Red\u00fcksiyon-Oksidasyon-\u0130ndirgenme-Y\u00fckseltgenme-Tepkimeleri-Soru-\u00c7\u00f6z\u00fcm\u00fc-4\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Redoks-Reduksiyon-Oksidasyon-Indirgenme-Yukseltgenme-Tepkimeleri-Soru-Cozumu-4.jpg 500w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Redoks-Reduksiyon-Oksidasyon-Indirgenme-Yukseltgenme-Tepkimeleri-Soru-Cozumu-4-300x101.jpg 300w\" sizes=\"auto, (max-width: 450px) 100vw, 450px\" \/><br><br><strong>C atomu; -4&#8217;ten +4&#8217;e y\u00fckseltgenmi\u015f.<\/strong><br><strong>0 atomu; 0&#8217;dan -2&#8217;ye indirgenmi\u015ftir.<\/strong><br>\u0130ndirgenme ve y\u00fckseltgenme olaylar\u0131 ger\u00e7ekle\u015fti\u011fi i\u00e7in bu tepkime bir redoks tepkimesidir.<br><br><strong>c)<\/strong><br>Bu redoks tepkimesinde ger\u00e7ekle\u015fen <strong>indirgenme yar\u0131 tepkimesi<\/strong> \u015fudur:<br><strong>0<sub>2<\/sub> + 4e<sup>&#8211;<\/sup> \u2192 2O<sup>-2<\/sup><\/strong> (\u00f6nce atomlar\u0131n say\u0131s\u0131n\u0131 e\u015fitledik, sonra al\u0131nan elektron say\u0131s\u0131n\u0131 hesaplad\u0131k.)<br><br><strong>Y\u00fckseltgenme yar\u0131 tepkimesi<\/strong> ise \u015f\u00f6yledir:<br><strong>C<sup>-4<\/sup> \u2192 C<sup>+4<\/sup> + 8e<sup>&#8211;<\/sup><\/strong><\/p>\n\n\n\n<p><em><strong>Cevap<\/strong>:<br><\/em><strong><em>a)<\/em><br><em>C<sup><span class=\"has-inline-color has-vivid-red-color\">-4<\/span><\/sup>H<sup><span class=\"has-inline-color has-vivid-red-color\">+1<\/span><\/sup><sub>4<\/sub> + 2O<sup><span class=\"has-inline-color has-vivid-red-color\">0<\/span><\/sup><sub>2<\/sub> \u2192 C<sup><span class=\"has-inline-color has-vivid-red-color\">+4<\/span><\/sup>O<sup><span class=\"has-inline-color has-vivid-red-color\">-2<\/span><\/sup><sub>2<\/sub> + 2H<sup><span class=\"has-inline-color has-vivid-red-color\">+2<\/span><\/sup><sub>2<\/sub>O<sup><span class=\"has-inline-color has-vivid-red-color\">-2<\/span><\/sup><\/em><br><em><br>b)<br>C atomu; -4&#8217;ten +4&#8217;e y\u00fckseltgenmi\u015f.<br>0 atomu; 0&#8217;dan -2&#8217;ye indirgenmi\u015ftir.<br>\u0130ndirgenme ve y\u00fckseltgenme olaylar\u0131 ger\u00e7ekle\u015fti\u011fi i\u00e7in bu tepkime bir redoks tepkimesidir.<\/em><br><em><br>c)<br>\u0130YT: 0<sub>2<\/sub> + 4e<sup>&#8211;<\/sup> \u2192 2O<sup>-2<\/sup><br>YYT: C<sup>-4<\/sup> \u2192 C<sup>+4<\/sup> + 8e<sup>&#8211;<\/sup><\/em><\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group stcnnt-yazi-ici-reklam\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p>Bu bir reklamd\u0131r:<\/p>\n\n\n\n<script async=\"\" src=\"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\"><\/script>\n<ins class=\"adsbygoogle\" style=\"display:block; text-align:center;\" data-ad-layout=\"in-article\" data-ad-format=\"fluid\" data-ad-client=\"ca-pub-6366953309324763\" data-ad-slot=\"9738116384\"><\/ins>\n<script>\n     (adsbygoogle = window.adsbygoogle || []).push({});\n<\/script>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-6\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-white-background-color has-background\"><strong>3P + 5HNO<sub>3<\/sub> + 2H<sub>2<\/sub>O \u2192 3H<sub>3<\/sub>PO<sub>4<\/sub> + 5NO<\/strong><\/p>\n\n\n\n<p>Yukar\u0131da verilen tepkime i\u00e7in a\u015fa\u011f\u0131daki sorular\u0131 yan\u0131tlay\u0131n\u0131z.<\/p>\n\n\n\n<p><strong>a) Tepkimedeki b\u00fct\u00fcn atomlar\u0131n y\u00fckseltgenme basamaklar\u0131n\u0131 hesaplay\u0131n\u0131z.<\/strong><br><strong>b) Tepkimenin bir redoks tepkimesi oldu\u011funu ispatlay\u0131n\u0131z.<\/strong><br><strong>c) \u0130ndirgenme ve y\u00fckseltgenme yar\u0131 tepkimelerini yaz\u0131n\u0131z.<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p><strong><em>a)<\/em><br><em>3P<sup><span class=\"has-inline-color has-vivid-red-color\">0<\/span><\/sup> + 5H<sup><span class=\"has-inline-color has-vivid-red-color\">+1<\/span><\/sup>N<sup><span class=\"has-inline-color has-vivid-red-color\">+5<\/span><\/sup>O<sup><span class=\"has-inline-color has-vivid-red-color\">-2<\/span><\/sup><sub>3<\/sub> + 2H<sup><span class=\"has-inline-color has-vivid-red-color\">+1<\/span><\/sup><sub>2<\/sub>O<sup><span class=\"has-inline-color has-vivid-red-color\">-2<\/span><\/sup> \u2192 3H<sup><span class=\"has-inline-color has-vivid-red-color\">+1<\/span><\/sup><sub>3<\/sub>P<sup><span class=\"has-inline-color has-vivid-red-color\">+5<\/span><\/sup>O<sup><span class=\"has-inline-color has-vivid-red-color\">-2<\/span><\/sup><sub>4<\/sub> + 5N<sup><span class=\"has-inline-color has-vivid-red-color\">+2<\/span><\/sup>O<sup><span class=\"has-inline-color has-vivid-red-color\">-2<\/span><\/sup><\/em><br><em><br>b)<br>P atomu; 0&#8217;dan +5&#8217;y\u00fckseltgenmi\u015f.<br>N atomu; +5&#8217;den +2&#8217;ye indirgenmi\u015ftir.<\/em><br><em>Hem indirgenme hem de y\u00fckseltgenme oldu\u011fu i\u00e7in tepkime redoks tepkimesidir.<\/em><br><em><br>c)<br>\u0130YT: N<sup>+5<\/sup> + 3e<sup>&#8211;<\/sup> \u2192 N<sup>+2<\/sup><br>YYT: P \u2192 P<sup>+5<\/sup> + 5e<sup>&#8211;<\/sup><\/em><\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"stcnnt-no-bordered-img\"><strong>3P + 5HNO<sub>3<\/sub> + 2H<sub>2<\/sub>O \u2192 3H<sub>3<\/sub>PO<sub>4<\/sub> + 5NO<\/strong><br><br><strong>a)<\/strong><br>Tepkimedeki her bir maddenin y\u00fckseltgenme basama\u011f\u0131n\u0131 ayr\u0131 ayr\u0131 hesaplamam\u0131z gerekiyor.<br><br>Y\u00fck bulurken, hat\u0131rlamam\u0131z gereken temel kurallar \u015funlard\u0131r:<br>&#8211; Elementlerin y\u00fck\u00fc zaten verilmi\u015ftir. Verilmemi\u015fse s\u0131f\u0131rd\u0131r.<br>&#8211; Bile\u015fiklerde, herkesin bir y\u00fck\u00fc vard\u0131r fakat hi\u00e7 biri g\u00f6r\u00fcnmez.<br>&#8211; Bile\u015fiklerde, b\u00fct\u00fcn atomlar\u0131n toplam y\u00fck\u00fc s\u0131f\u0131rd\u0131r.<br>&#8211; K\u00f6k iyonlarda, b\u00fct\u00fcn atomlar\u0131n toplam y\u00fck\u00fc iyonun y\u00fck\u00fcne e\u015fittir.<br>&#8211; Yapmam\u0131z gereken, bildi\u011fimiz atomlar\u0131n y\u00fck\u00fcn\u00fc yazmak, bilmedi\u011fimizi hesaplamakt\u0131r.<br><br><strong>P<\/strong><br>P<sup>0<\/sup>: Elementlerin y\u00fck\u00fc zaten bellidir. Y\u00fckleri yoksa s\u0131f\u0131rd\u0131r.<br><br><strong>HNO<sub>3<\/sub><\/strong><br>&#8211; H ve O atomlar\u0131n\u0131n y\u00fck\u00fc ezbere bilinmelidir.<br>&#8211; N atomunun y\u00fck\u00fcne x diyelim ve hesaplayal\u0131m.<br><br><strong>(H<sup>+1<\/sup> N<sup>x<\/sup> O<sup>-2<\/sup> O<sup>-2<\/sup> O<sup>-2<\/sup>)<sup>0<\/sup><\/strong><br><strong>+1 + x -2 -2 -2 = 0<br>x = 6-1<br>x = +5<\/strong><br><br><strong>H<sub>2<\/sub>O<\/strong><br>&#8211; H ve O atomlar\u0131n\u0131n y\u00fck\u00fc ezbere bilinmelidir.<br><br><strong>(H<sup>+1<\/sup> <strong>H<sup>+1<\/sup><\/strong> O<sup>-2<\/sup>)<sup>0<\/sup><\/strong><br><br><strong>H<sub>3<\/sub>PO<sub>4<\/sub><\/strong><br>&#8211; H ve O atomlar\u0131n\u0131n y\u00fck\u00fc ezbere bilinmelidir.<br>&#8211; P atomunun y\u00fck\u00fcne x diyelim ve hesaplayal\u0131m.<br><br><strong>(H<sup>+1<\/sup> <strong>H<sup>+1<\/sup><\/strong><\/strong> <strong>H<sup>+1<\/sup><\/strong> <strong>P<sup>x<\/sup> O<sup>-2<\/sup> O<sup>-2<\/sup> O<sup>-2<\/sup> <strong>O<sup>-2<\/sup><\/strong>)<sup>0<\/sup><\/strong><br><strong>+3 + x &#8211; 8 = 0<br>x = 8 &#8211; 3<br>x = +5<\/strong><br><br><strong>NO<\/strong><br>&#8211; O atomunun y\u00fck\u00fc ezbere bilinmelidir.<br>&#8211; N atomunun y\u00fck\u00fcne x diyelim ve hesaplayal\u0131m.<br><br><strong>(N<sup>x<\/sup> <strong>O<sup>-2<\/sup><\/strong>)<sup>0<\/sup><\/strong><br><strong>x &#8211; 2 = 0<br>x = +2<\/strong><br><br>\u015eimdi, tepkime denklemini, herkesin y\u00fck\u00fcn\u00fc \u00fczerine yazarak g\u00f6sterelim:<br><img loading=\"lazy\" decoding=\"async\" width=\"500\" height=\"33\" class=\"wp-image-5978\" style=\"width: 500px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Redoks-Reduksiyon-Oksidasyon-Indirgenme-Yukseltgenme-Tepkimeleri-Soru-Cozumu-2.jpg\" alt=\"Redoks-Red\u00fcksiyon-Oksidasyon-\u0130ndirgenme-Y\u00fckseltgenme-Tepkimeleri-Soru-\u00c7\u00f6z\u00fcm\u00fc-2\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Redoks-Reduksiyon-Oksidasyon-Indirgenme-Yukseltgenme-Tepkimeleri-Soru-Cozumu-2.jpg 700w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Redoks-Reduksiyon-Oksidasyon-Indirgenme-Yukseltgenme-Tepkimeleri-Soru-Cozumu-2-300x20.jpg 300w\" sizes=\"auto, (max-width: 500px) 100vw, 500px\" \/><br><br><strong>b) <\/strong><br>Dikkat edersek, tepkimede, indirgenen ve y\u00fckseltgenen atomlar\u0131 oldu\u011funu g\u00f6rebiliriz:<br><img loading=\"lazy\" decoding=\"async\" width=\"500\" height=\"128\" class=\"wp-image-5980\" style=\"width: 500px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Redoks-Reduksiyon-Oksidasyon-Indirgenme-Yukseltgenme-Tepkimeleri-Soru-Cozumu-1-.jpg\" alt=\"Redoks-Red\u00fcksiyon-Oksidasyon-\u0130ndirgenme-Y\u00fckseltgenme-Tepkimeleri-Soru-\u00c7\u00f6z\u00fcm\u00fc-1\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Redoks-Reduksiyon-Oksidasyon-Indirgenme-Yukseltgenme-Tepkimeleri-Soru-Cozumu-1-.jpg 700w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Redoks-Reduksiyon-Oksidasyon-Indirgenme-Yukseltgenme-Tepkimeleri-Soru-Cozumu-1--300x77.jpg 300w\" sizes=\"auto, (max-width: 500px) 100vw, 500px\" \/><br><br>P atomu; 0&#8217;dan +5&#8217;y\u00fckseltgenmi\u015f.<br>N atomu; +5&#8217;den +2&#8217;ye indirgenmi\u015ftir.<br>\u0130ndirgenme ve y\u00fckseltgenme olaylar\u0131 ger\u00e7ekle\u015fti\u011fi i\u00e7in bu tepkime bir redoks tepkimesidir.<br><br><strong>c)<\/strong><br>Bu redoks tepkimesinde ger\u00e7ekle\u015fen <strong>indirgenme yar\u0131 tepkimesi<\/strong> \u015fudur:<br><strong>N<sup>+5<\/sup> + 3e<sup>&#8211;<\/sup> \u2192 N<sup>+2<\/sup><\/strong><br><br><strong>Y\u00fckseltgenme yar\u0131 tepkimesi<\/strong> ise \u015f\u00f6yledir:<br><strong>P \u2192 P<sup>+5<\/sup> + 5e<sup>&#8211;<\/sup><\/strong><\/p>\n\n\n\n<p><em><strong>Cevap<\/strong>:<\/em><\/p>\n\n\n\n<p><strong><em>a)<\/em><br><em>3P<sup><span class=\"has-inline-color has-vivid-red-color\">0<\/span><\/sup> + 5H<sup><span class=\"has-inline-color has-vivid-red-color\">+1<\/span><\/sup>N<sup><span class=\"has-inline-color has-vivid-red-color\">+5<\/span><\/sup>O<sup><span class=\"has-inline-color has-vivid-red-color\">-2<\/span><\/sup><sub>3<\/sub> + 2H<sup><span class=\"has-inline-color has-vivid-red-color\">+1<\/span><\/sup><sub>2<\/sub>O<sup><span class=\"has-inline-color has-vivid-red-color\">-2<\/span><\/sup> \u2192 3H<sup><span class=\"has-inline-color has-vivid-red-color\">+1<\/span><\/sup><sub>3<\/sub>P<sup><span class=\"has-inline-color has-vivid-red-color\">+5<\/span><\/sup>O<sup><span class=\"has-inline-color has-vivid-red-color\">-2<\/span><\/sup><sub>4<\/sub> + 5N<sup><span class=\"has-inline-color has-vivid-red-color\">+2<\/span><\/sup>O<sup><span class=\"has-inline-color has-vivid-red-color\">-2<\/span><\/sup><\/em><br><em><br>b)<br>P atomu; 0&#8217;dan +5&#8217;y\u00fckseltgenmi\u015f.<br>N atomu; +5&#8217;den +2&#8217;ye indirgenmi\u015ftir.<\/em><br><em>Hem indirgenme hem de y\u00fckseltgenme oldu\u011fu i\u00e7in tepkime redoks tepkimesidir.<\/em><br><em><br>c)<br>\u0130YT: N<sup>+5<\/sup> + 3e<sup>&#8211;<\/sup> \u2192 N<sup>+2<\/sup><br>YYT: P \u2192 P<sup>+5<\/sup> + 5e<sup>&#8211;<\/sup><\/em><\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Redoks_Tepkimelerinin_Denklestirilmesi\">Redoks Tepkimelerinin Denkle\u015ftirilmesi<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Bir redoks tepkimesini klasik y\u00f6ntemlerle de denkle\u015ftirebiliriz.<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group has-background\" style=\"background-color:#e2ffea\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p>Klasik y\u00f6ntemle, kimyasal tepkimelerin nas\u0131l denkle\u015ftirildi\u011fini hat\u0131rlamak i\u00e7in a\u015fa\u011f\u0131daki ba\u011flant\u0131ya t\u0131klayabilirsiniz:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><a href=\"https:\/\/sitecenneti.com\/kimya\/tyt-kimya\/kimyanin-temel-kanunlari-ve-kimyasal-hesaplamalar\/kimyasal-tepkimeler-ve-denklemler\/#Kimyasal_Tepkime_Denklemlerinin_Denklestirilmesi\" target=\"_blank\" rel=\"noreferrer noopener\">Kimyasal Tepkime Denklemlerinin Denkle\u015ftirilmesi<\/a><\/li>\n<\/ul>\n<\/div><\/div>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Redoks tepkimelerini, klasik yoldan denkle\u015ftirmek genellikle zordur. Bu y\u00fczden kendilerine ait denkle\u015ftirme y\u00f6ntemleri vard\u0131r.<\/li>\n\n\n\n<li>Redoks tepkimelerini denkle\u015ftirme i\u015flemi, s\u0131ras\u0131yla, a\u015fa\u011f\u0131daki kurallar\u0131 uygulayarak ger\u00e7ekle\u015ftirilir:\n<ol class=\"wp-block-list\">\n<li>Tepkimedeki b\u00fct\u00fcn atomlar\u0131n y\u00fckleri bulunur.<\/li>\n\n\n\n<li>\u0130ndirgenen ve y\u00fckseltgenen atomlar tespit edilir ve indirgenme ve y\u00fckseltgenme yar\u0131 tepkimeleri yaz\u0131l\u0131r.<\/li>\n\n\n\n<li>Yar\u0131 tepkimeler, uygun say\u0131larla geni\u015fletilerek, al\u0131nan ve verilen elektron say\u0131lar\u0131 e\u015fitlenir.<\/li>\n\n\n\n<li>Al\u0131nan-verilen elektron say\u0131lar\u0131 e\u015fitlendikten sonra, yar\u0131 tepkimelerdeki iyonlar\u0131n katsay\u0131lar\u0131, tepkimedeki bile\u015fiklerinin \u00f6n\u00fcne ta\u015f\u0131n\u0131r.<\/li>\n\n\n\n<li>Tepkimedeki di\u011fer maddelerin katsay\u0131lar\u0131, klasik y\u00f6ntemle hesaplan\u0131r.<\/li>\n<\/ol>\n<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-7\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-white-background-color has-background\"><strong>P + HNO<sub>3<\/sub> + H<sub>2<\/sub>O \u2192 H<sub>3<\/sub>PO<sub>4<\/sub> + NO<\/strong><\/p>\n\n\n\n<p><strong>Yukar\u0131da verilen tepkimeyi denkle\u015ftiriniz.<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center\">3<strong>P + 5HNO<sub>3<\/sub> + 2H<sub>2<\/sub>O \u2192 3H<sub>3<\/sub>PO<sub>4<\/sub> + 5NO<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"stcnnt-no-bordered-img\">Tepkimeyi tekrar g\u00f6relim:<br><br><strong>P + HNO<sub>3<\/sub> + H<sub>2<\/sub>O \u2192 H<sub>3<\/sub>PO<sub>4<\/sub> + NO<\/strong><br><br>\u015eans\u0131n\u0131 denemek isteyenler, klasik y\u00f6ntemle denkle\u015ftirmeye \u00e7al\u0131\u015fabilir. Fakat, bu tepkime, bir ametal-asit tepkimesidir ve redokstur.<br><br>\u015eimdi ad\u0131m ad\u0131m redoks kurallar\u0131n\u0131 uygulayal\u0131m ve tepkimeyi denkle\u015ftirelim:<br><br><strong>1- Tepkimedeki b\u00fct\u00fcn atomlar\u0131n y\u00fckleri bulunur<\/strong>:<br><br><strong>P<\/strong><br>P<sup>0<\/sup>: Elementlerin y\u00fck\u00fc zaten bellidir. Y\u00fckleri yoksa s\u0131f\u0131rd\u0131r.<br><br><strong>HNO<sub>3<\/sub><\/strong><br>&#8211; H ve O atomlar\u0131n\u0131n y\u00fck\u00fc ezbere bilinmelidir.<br>&#8211; N atomunun y\u00fck\u00fcne x diyelim ve hesaplayal\u0131m.<br><strong>(H<sup>+1<\/sup> N<sup>x<\/sup> O<sup>-2<\/sup> O<sup>-2<\/sup> O<sup>-2<\/sup>)<sup>0<\/sup><\/strong><br><strong>+1 + x -2 -2 -2 = 0<br>x = 6-1<br>x = +5<\/strong><br><br><strong>H<sub>2<\/sub>O<\/strong><br>&#8211; H ve O atomlar\u0131n\u0131n y\u00fck\u00fc ezbere bilinmelidir.<br><strong>(H<sup>+1<\/sup> <strong>H<sup>+1<\/sup><\/strong> O<sup>-2<\/sup>)<sup>0<\/sup><\/strong><br><br><strong>H<sub>3<\/sub>PO<sub>4<\/sub><\/strong><br>&#8211; H ve O atomlar\u0131n\u0131n y\u00fck\u00fc ezbere bilinmelidir.<br>&#8211; P atomunun y\u00fck\u00fcne x diyelim ve hesaplayal\u0131m.<br><strong>(H<sup>+1<\/sup> <strong>H<sup>+1<\/sup><\/strong><\/strong> <strong>H<sup>+1<\/sup><\/strong> <strong>P<sup>x<\/sup> O<sup>-2<\/sup> O<sup>-2<\/sup> O<sup>-2<\/sup> <strong>O<sup>-2<\/sup><\/strong>)<sup>0<\/sup><\/strong><br><strong>+3 + x &#8211; 8 = 0<br>x = 8 &#8211; 3<br>x = +5<\/strong><br><br><strong>NO<\/strong><br>&#8211; O atomunun y\u00fck\u00fc ezbere bilinmelidir.<br>&#8211; N atomunun y\u00fck\u00fcne x diyelim ve hesaplayal\u0131m.<br><strong>(N<sup>x<\/sup> <strong>O<sup>-2<\/sup><\/strong>)<sup>0<\/sup><\/strong><br><strong>x &#8211; 2 = 0<br>x = +2<\/strong><br><br><strong>2- \u0130ndirgenen ve y\u00fckseltgenen atomlar tespit edilir ve indirgenme ve y\u00fckseltgenme yar\u0131 tepkimeleri yaz\u0131l\u0131r:<\/strong><br><br>\u015eimdi, tepkime denklemini, herkesin y\u00fck\u00fcn\u00fc \u00fczerine yazarak g\u00f6sterelim:<br><img loading=\"lazy\" decoding=\"async\" width=\"500\" height=\"40\" class=\"wp-image-6015\" style=\"width: 500px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Redoks-Reduksiyon-Oksidasyon-Indirgenme-Yukseltgenme-Tepkimeleri-4.jpg\" alt=\"Redoks-Red\u00fcksiyon-Oksidasyon-\u0130ndirgenme-Y\u00fckseltgenme-Tepkimeleri-4\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Redoks-Reduksiyon-Oksidasyon-Indirgenme-Yukseltgenme-Tepkimeleri-4.jpg 600w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Redoks-Reduksiyon-Oksidasyon-Indirgenme-Yukseltgenme-Tepkimeleri-4-300x24.jpg 300w\" sizes=\"auto, (max-width: 500px) 100vw, 500px\" \/><br><br>Dikkat edersek, tepkimede, indirgenen ve y\u00fckseltgenen atomlar\u0131 oldu\u011funu g\u00f6rebiliriz:<br><img loading=\"lazy\" decoding=\"async\" width=\"500\" height=\"135\" class=\"wp-image-6017\" style=\"width: 500px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Redoks-Reduksiyon-Oksidasyon-Indirgenme-Yukseltgenme-Tepkimeleri-5.jpg\" alt=\"Redoks-Red\u00fcksiyon-Oksidasyon-\u0130ndirgenme-Y\u00fckseltgenme-Tepkimeleri-5\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Redoks-Reduksiyon-Oksidasyon-Indirgenme-Yukseltgenme-Tepkimeleri-5.jpg 600w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Redoks-Reduksiyon-Oksidasyon-Indirgenme-Yukseltgenme-Tepkimeleri-5-300x81.jpg 300w\" sizes=\"auto, (max-width: 500px) 100vw, 500px\" \/><br><br>P atomu; 0&#8217;dan +5&#8217;y\u00fckseltgenmi\u015f.<br>N atomu; +5&#8217;den +2&#8217;ye indirgenmi\u015ftir.<br><br>Bu redoks tepkimesinde ger\u00e7ekle\u015fen, indirgenme ve y\u00fckseltgenme yar\u0131 tepkimeleri \u015funlard\u0131r:<br><br><strong>N<sup>+5<\/sup> + 3e<sup>&#8211;<\/sup> \u2192 N<sup>+2<\/sup><\/strong> (\u0130TY)<br><strong>P \u2192 P<sup>+5<\/sup> + 5e<sup>&#8211;<\/sup> (YYT)<\/strong><br><br><strong>3- Yar\u0131 tepkimeler, uygun say\u0131larla geni\u015fletilerek, al\u0131nan ve verilen elektron say\u0131lar\u0131 e\u015fitlenir:<\/strong><br><br>Yar\u0131 tepkimelere bakt\u0131\u011f\u0131m\u0131zda, al\u0131nan elektron say\u0131s\u0131 3, verilen elektron say\u0131s\u0131 ise 5&#8217;dir. Yapmam\u0131z gereken \u015fey, bu iki say\u0131s\u0131 e\u015fitlemek i\u00e7in, payda e\u015fitler gibi tepkimeleri geni\u015fletmektir:<br><br><span style=\"background-color:rgba(0, 0, 0, 0);color:#ffffaf\" class=\"has-inline-color\">5x<\/span> <strong>N<sup>+5<\/sup> + 3e<sup>&#8211;<\/sup> \u2192 N<sup>+2<\/sup><\/strong> (\u0130TY)<br><span style=\"background-color:rgba(0, 0, 0, 0);color:#ffffaf\" class=\"has-inline-color\">3x<\/span> <strong>P \u2192 P<sup>+5<\/sup> + 5e<sup>&#8211;<\/sup> (YYT)<\/strong><br>Sonu\u00e7ta; al\u0131nan-verilen say\u0131s\u0131 e\u015fit olacakt\u0131r:<br>5<strong>N<sup>+5<\/sup> + 15e<sup>&#8211;<\/sup> \u2192 5N<sup>+2<\/sup><\/strong> (\u0130TY)<br>3<strong>P \u2192 3P<sup>+5<\/sup> + 15e<sup>&#8211;<\/sup> (YYT)<\/strong><br><br><strong>4- Al\u0131nan-verilen elektron say\u0131lar\u0131 e\u015fitlendikten sonra, yar\u0131 tepkimelerdeki iyonlar\u0131n katsay\u0131lar\u0131, tepkimedeki bile\u015fiklerinin \u00f6n\u00fcne ta\u015f\u0131n\u0131r<\/strong>:<br><br>Yar\u0131 tepkimelerde; <strong>5<strong>N<sup>+5<\/sup><\/strong><\/strong>, <strong>5N<sup>+2<\/sup>, <\/strong>3<strong>P<\/strong> ve <strong>3P<sup>+5<\/sup><\/strong> iyonlar\u0131n\u0131n katsay\u0131lar\u0131n\u0131 tepkimede, i\u00e7inde bulunduklar\u0131 maddelere ta\u015f\u0131yal\u0131m.<br><br><strong>3P + 5HNO<sub>3<\/sub> + H<sub>2<\/sub>O \u2192 3H<sub>3<\/sub>PO<sub>4<\/sub> + 5NO<br><\/strong><br><strong>5- Tepkimedeki di\u011fer maddelerin katsay\u0131lar\u0131, klasik y\u00f6ntemle hesaplan\u0131r:<\/strong><br><br>3<strong>P + 5HNO<sub>3<\/sub> + <span style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-purple-color\">H<sub>2<\/sub>O<\/span> \u2192 3H<sub>3<\/sub>PO<sub>4<\/sub> + 5NO<\/strong><br>Geldi\u011fimiz a\u015famada, <strong>H<sub>2<\/sub>O<\/strong> hari\u00e7 di\u011fer maddelerin katsay\u0131lar\u0131 ortaya \u00e7\u0131km\u0131\u015ft\u0131r. O zaman <strong>H<sub>2<\/sub>O<\/strong> bile\u015fi\u011finin katsay\u0131lar\u0131n\u0131, klasik yoldan bulal\u0131m.<br><br>\u00dcr\u00fcnlere bakarsak;<br>&#8211; toplam 17 adet O atomu g\u00f6r\u00fcr\u00fcz.<br>O zaman girenlerde de;<br>&#8211; toplam 17 adet O atomu olmal\u0131d\u0131r.<br><br><strong>H<sub>2<\/sub>O<\/strong> bile\u015fi\u011finin katsay\u0131s\u0131 2 olursa, girenlerdeki O atomu say\u0131s\u0131 da toplam 17 olur.<br><br>3<strong>P + 5HNO<sub>3<\/sub> + <span style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-luminous-vivid-orange-color\">2<\/span>H<sub>2<\/sub>O \u2192 3H<sub>3<\/sub>PO<sub>4<\/sub> + 5NO<\/strong><br><br>Dilerseniz; <strong>H<sub>2<\/sub>O<\/strong> bile\u015fi\u011finin katsay\u0131s\u0131n\u0131 bulmak i\u00e7in, H atomlar\u0131n\u0131 da sayabilirsiniz.<\/p>\n\n\n\n<p><em><strong>Cevap<\/strong>:<\/em><\/p>\n\n\n\n<p class=\"has-text-align-center\">3<strong>P + 5HNO<sub>3<\/sub> + 2H<sub>2<\/sub>O \u2192 3H<sub>3<\/sub>PO<sub>4<\/sub> + 5NO<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group stcnnt-yazi-ici-reklam\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p>Bu bir reklamd\u0131r:<\/p>\n\n\n\n<script async=\"\" src=\"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\"><\/script>\n<ins class=\"adsbygoogle\" style=\"display:block; text-align:center;\" data-ad-layout=\"in-article\" data-ad-format=\"fluid\" data-ad-client=\"ca-pub-6366953309324763\" data-ad-slot=\"9738116384\"><\/ins>\n<script>\n     (adsbygoogle = window.adsbygoogle || []).push({});\n<\/script>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-8\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-white-background-color has-background\"><strong>Cu + HNO<sub>3<\/sub> \u2192 Cu(NO<sub>3<\/sub>)<sub>2<\/sub> + NO + H<sub>2<\/sub>O<\/strong><\/p>\n\n\n\n<p><strong>Yukar\u0131daki tepkimeyi denkle\u015ftiriniz.<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong>3Cu + 8HNO<sub>3<\/sub> \u2192 3Cu(NO<sub>3<\/sub>)<sub>2<\/sub> + 2NO + 4H<sub>2<\/sub>O<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"stcnnt-no-bordered-img\">Tepkimeyi tekrar g\u00f6relim:<br><br><strong><strong>Cu + HNO<sub>3<\/sub> \u2192 Cu(NO<sub>3<\/sub>)<sub>2<\/sub> + NO + H<sub>2<\/sub>O<\/strong><\/strong><br><br>\u015eans\u0131n\u0131 denemek isteyenler, klasik y\u00f6ntemle denkle\u015ftirmeye \u00e7al\u0131\u015fabilir. Fakat, bu tepkime, bir metal-asit tepkimesidir ve redokstur.<br><br>\u015eimdi ad\u0131m ad\u0131m redoks kurallar\u0131n\u0131 uygulayal\u0131m ve tepkimeyi denkle\u015ftirelim:<br><br><strong>1- Tepkimedeki b\u00fct\u00fcn atomlar\u0131n y\u00fckleri bulunur<\/strong>:<br><br><strong>Cu<\/strong><br>Cu<sup>0<\/sup>: Elementlerin y\u00fck\u00fc zaten bellidir. Y\u00fckleri yoksa s\u0131f\u0131rd\u0131r.<br><br><strong>HNO<sub>3<\/sub><\/strong><br>&#8211; H ve O atomlar\u0131n\u0131n y\u00fck\u00fc ezbere bilinmelidir.<br>&#8211; N atomunun y\u00fck\u00fcne x diyelim ve hesaplayal\u0131m.<br><strong>(H<sup>+1<\/sup> N<sup>x<\/sup> O<sup>-2<\/sup> O<sup>-2<\/sup> O<sup>-2<\/sup>)<sup>0<\/sup><\/strong><br><strong>+1 + x -2 -2 -2 = 0<br>x = 6-1<br>x = +5<\/strong><br><br><strong><strong>Cu(NO<sub>3<\/sub>)<sub>2<\/sub><\/strong><\/strong><br>&#8211; Bile\u015fikteki \u00e7aprazlamay\u0131 g\u00f6rebilirsek, Cu atomunun +2, NO<sub>3<\/sub> iyonunun -1 oldu\u011funu anlar\u0131z.<br>&#8211; NO<sub>3<\/sub><sup>-1<\/sup> iyonundaki b\u00fct\u00fcn atomlar\u0131n toplam y\u00fck\u00fc -1 olmal\u0131d\u0131r.<br>&#8211; \u0130yondaki O atomunun y\u00fck\u00fc ezbere bilinmelidir: -2<br>&#8211; \u0130yondaki N atomunun y\u00fck\u00fcne x dersek, x de\u011ferini \u015f\u00f6yle hesaplayabiliriz:<br><strong>(N<sup>x<\/sup> O<sup>-2<\/sup>  O<sup>-2<\/sup> O<sup>-2<\/sup>)<sup>-1<\/sup><br>x &#8211; 2 &#8211; 2 &#8211; 2 = -1<br>x &#8211; 6 = -1<br>x = 6 &#8211; 1<br>x = +5<\/strong><br><br><strong>NO<\/strong><br>&#8211; O atomunun y\u00fck\u00fc ezbere bilinmelidir.<br>&#8211; N atomunun y\u00fck\u00fcne x diyelim ve hesaplayal\u0131m.<br><strong>(N<sup>x<\/sup> <strong>O<sup>-2<\/sup><\/strong>)<sup>0<\/sup><\/strong><br><strong>x &#8211; 2 = 0<br>x = +2<\/strong><br> <br><strong>H<sub>2<\/sub>O<\/strong><br>&#8211; H ve O atomlar\u0131n\u0131n y\u00fck\u00fc ezbere bilinmelidir.<br><strong>(H<sup>+1<\/sup> <strong>H<sup>+1<\/sup><\/strong> O<sup>-2<\/sup>)<sup>0<\/sup><\/strong><br><br><strong>2- \u0130ndirgenen ve y\u00fckseltgenen atomlar tespit edilir ve indirgenme ve y\u00fckseltgenme yar\u0131 tepkimeleri yaz\u0131l\u0131r:<\/strong><br><br>\u015eimdi, tepkime denklemini, herkesin y\u00fck\u00fcn\u00fc \u00fczerine yazarak g\u00f6sterelim:<br><img loading=\"lazy\" decoding=\"async\" width=\"500\" height=\"40\" class=\"wp-image-6030\" style=\"width: 500px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Redoks-Reduksiyon-Oksidasyon-Indirgenme-Yukseltgenme-Tepkimeleri-6.jpg\" alt=\"Redoks-Red\u00fcksiyon-Oksidasyon-\u0130ndirgenme-Y\u00fckseltgenme-Tepkimeleri-6\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Redoks-Reduksiyon-Oksidasyon-Indirgenme-Yukseltgenme-Tepkimeleri-6.jpg 600w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Redoks-Reduksiyon-Oksidasyon-Indirgenme-Yukseltgenme-Tepkimeleri-6-300x24.jpg 300w\" sizes=\"auto, (max-width: 500px) 100vw, 500px\" \/><br><br>Dikkat edersek, tepkimede, indirgenen ve y\u00fckseltgenen atomlar\u0131 oldu\u011funu g\u00f6rebiliriz:<br><img loading=\"lazy\" decoding=\"async\" width=\"500\" height=\"126\" class=\"wp-image-6031\" style=\"width: 500px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Redoks-Reduksiyon-Oksidasyon-Indirgenme-Yukseltgenme-Tepkimeleri-7.jpg\" alt=\"Redoks-Red\u00fcksiyon-Oksidasyon-\u0130ndirgenme-Y\u00fckseltgenme-Tepkimeleri-7\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Redoks-Reduksiyon-Oksidasyon-Indirgenme-Yukseltgenme-Tepkimeleri-7.jpg 600w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Redoks-Reduksiyon-Oksidasyon-Indirgenme-Yukseltgenme-Tepkimeleri-7-300x76.jpg 300w\" sizes=\"auto, (max-width: 500px) 100vw, 500px\" \/><br><br>Cu atomu; 0&#8217;dan +2&#8217;ye y\u00fckseltgenmi\u015f.<br>N atomu; +5&#8217;den +2&#8217;ye indirgenmi\u015ftir.<br><br>Bu redoks tepkimesinde ger\u00e7ekle\u015fen, indirgenme ve y\u00fckseltgenme yar\u0131 tepkimeleri \u015funlard\u0131r:<br><br><strong>Cu \u2192 Cu<sup>+2<\/sup> + 2e<sup>&#8211;<\/sup> (YYT)<\/strong><br><strong>N<sup>+5<\/sup> + 3e<sup>&#8211;<\/sup> \u2192 N<sup>+2<\/sup> (\u0130TY)<\/strong><br><br><strong>3- Yar\u0131 tepkimeler, uygun say\u0131larla geni\u015fletilerek, al\u0131nan ve verilen elektron say\u0131lar\u0131 e\u015fitlenir:<\/strong><br><br>Yar\u0131 tepkimelere bakt\u0131\u011f\u0131m\u0131zda, al\u0131nan elektron say\u0131s\u0131 3, verilen elektron say\u0131s\u0131 ise 5&#8217;dir. Yapmam\u0131z gereken \u015fey, bu iki say\u0131s\u0131 e\u015fitlemek i\u00e7in, payda e\u015fitler gibi tepkimeleri geni\u015fletmektir:<br><br><strong><span style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-luminous-vivid-orange-color\">2x<\/span> N<sup>+5<\/sup> + 3e<sup>&#8211;<\/sup> \u2192 N<sup>+2<\/sup> (\u0130TY)<\/strong><br><span style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-luminous-vivid-orange-color\">3x<\/span> <strong><strong>Cu \u2192 Cu<sup>+2<\/sup> + 2e<sup>&#8211;<\/sup> (YYT)<\/strong><\/strong><br>Sonu\u00e7ta; al\u0131nan-verilen say\u0131s\u0131 e\u015fit olacakt\u0131r:<br><strong>2N<sup>+5<\/sup> + <span style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-luminous-vivid-amber-color\">6e<sup>&#8211;<\/sup> <\/span>\u2192 2N<sup>+2<\/sup> (\u0130TY)<\/strong><br><strong>3Cu \u2192 3Cu<sup>+2<\/sup> + <span style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-luminous-vivid-amber-color\">6e<sup>&#8211;<\/sup> <\/span>(YYT)<\/strong><br><br><strong>4- Al\u0131nan-verilen elektron say\u0131lar\u0131 e\u015fitlendikten sonra, yar\u0131 tepkimelerdeki iyonlar\u0131n katsay\u0131lar\u0131, tepkimedeki bile\u015fiklerinin \u00f6n\u00fcne ta\u015f\u0131n\u0131r<\/strong>:<br><br>Yar\u0131 tepkimelerde; <strong>2<strong>N<sup>+5<\/sup><\/strong><\/strong>, <strong>2N<sup>+2<\/sup>, <\/strong>3<strong>Cu<\/strong> ve <strong>3Cu<sup>+2<\/sup><\/strong> iyonlar\u0131n\u0131n katsay\u0131lar\u0131n\u0131 tepkimede, i\u00e7inde bulunduklar\u0131 maddelere ta\u015f\u0131yal\u0131m.<br><br>Yaln\u0131z, N<sup>+5<\/sup> iyonu, hem <strong>HNO<sub>3<\/sub><\/strong> bile\u015fi\u011finde hem de <strong>Cu(NO<sub>3<\/sub>)<sub>2<\/sub><\/strong> bile\u015fi\u011finde oldu\u011fu i\u00e7in, bu iyonun katsay\u0131s\u0131n\u0131 g\u00f6rmezden gelece\u011fiz.<br><br><strong>3Cu + HNO<sub>3<\/sub> \u2192 3Cu(NO<sub>3<\/sub>)<sub>2<\/sub> + 2NO + H<sub>2<\/sub>O<br><\/strong><br><strong>5- Tepkimedeki di\u011fer maddelerin katsay\u0131lar\u0131, klasik y\u00f6ntemle hesaplan\u0131r:<\/strong><br><br><strong>3Cu + <span style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-purple-color\">HNO<sub>3<\/sub> <\/span>\u2192 3Cu(NO<sub>3<\/sub>)<sub>2<\/sub> + 2NO + <span style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-purple-color\">H<sub>2<\/sub>O<\/span><\/strong><br><br>\u00dcr\u00fcnlerde, toplam <strong><span style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-luminous-vivid-orange-color\">8<\/span><\/strong> tane N atomu oldu\u011fu i\u00e7in <strong>HNO<sub>3<\/sub><\/strong> bile\u015fi\u011finin katsay\u0131s\u0131 8 olmal\u0131d\u0131r:<br><br><strong>3Cu + <span style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-luminous-vivid-orange-color\">8<\/span>HNO<sub>3<\/sub> \u2192 3Cu(NO<sub>3<\/sub>)<sub>2<\/sub> + 2NO + <span style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-purple-color\">H<sub>2<\/sub>O<\/span><\/strong><br><br><strong>H<sub>2<\/sub>O<\/strong> bile\u015fi\u011finin katsay\u0131lar\u0131n\u0131, Oksijenleri sayarak bulal\u0131m:<br><br>Girenlere bakarsak;<br>&#8211; toplam 24 adet O atomu g\u00f6r\u00fcr\u00fcz.<br>O zaman \u00fcr\u00fcnlerde de;<br>&#8211; toplam 24 adet O atomu olmal\u0131d\u0131r.<br><br><strong>H<sub>2<\/sub>O<\/strong> bile\u015fi\u011finin katsay\u0131s\u0131 4 olursa, \u00fcr\u00fcnlerdeki O atomu say\u0131s\u0131 da toplam 24 olur.<br><br><strong>3Cu + 8HNO<sub>3<\/sub> \u2192 3Cu(NO<sub>3<\/sub>)<sub>2<\/sub> + 2NO + <span style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-luminous-vivid-orange-color\">4<\/span>H<sub>2<\/sub>O<\/strong><br><br>Dilerseniz; <strong>H<sub>2<\/sub>O<\/strong> bile\u015fi\u011finin katsay\u0131s\u0131n\u0131 bulmak i\u00e7in, H atomlar\u0131n\u0131 da sayabilirsiniz.<\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Indirgen_ve_Yukseltgen_Maddeler\">\u0130ndirgen ve Y\u00fckseltgen Maddeler<\/span><\/h3>\n\n\n\n<p>&#8220;\u0130ndirgenme&#8221;, &#8220;y\u00fckseltgenme&#8221;, &#8220;indirgen&#8221; ve &#8220;y\u00fckseltgen&#8221; kavramlar\u0131n\u0131 anlamak i\u00e7in basit bir benzetme yapal\u0131m:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"500\" height=\"337\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/esit-kollu-bakkal-terazisi-sitecenneti.jpg\" alt=\"Bakkal Terazisi - E\u015fit Kollu Terazi\" class=\"wp-image-2174\" style=\"width:300px;height:undefinedpx\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/esit-kollu-bakkal-terazisi-sitecenneti.jpg 500w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/esit-kollu-bakkal-terazisi-sitecenneti-300x202.jpg 300w\" sizes=\"auto, (max-width: 500px) 100vw, 500px\" \/><figcaption class=\"wp-element-caption\">Bakkal Terazisi &#8211; E\u015fit Kollu Terazi<\/figcaption><\/figure>\n<\/div>\n\n\n<ul class=\"wp-block-list\">\n<li>Bakkal terazisinin bir kefesi y\u00fckselirse, kar\u015f\u0131s\u0131ndaki kefe a\u015fa\u011f\u0131 iner. Bu olaya daha yak\u0131ndan bakarsak;\n<ul class=\"wp-block-list\">\n<li>Y\u00fckselen kefe, kar\u015f\u0131s\u0131ndakini a\u015fa\u011f\u0131 indirir.<\/li>\n\n\n\n<li>A\u015fa\u011f\u0131 inen kefe de kar\u015f\u0131s\u0131ndaki y\u00fckseltir.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Bu olay\u0131 redoks tepkimelerine uyarlarsak:\n\n\n\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Y\u00fckseltgenen<\/strong> madde; kar\u015f\u0131s\u0131ndaki maddenin indirgenmesini sa\u011flad\u0131\u011f\u0131 i\u00e7in <strong>indirgen<\/strong> \u00f6zellik g\u00f6sterir.\n<ul class=\"wp-block-list\">\n<li>Y\u00fckseltgenen atomun olu\u015fturdu\u011fu madde <strong>y\u00fckseltgenme \u00fcr\u00fcn\u00fcd\u00fcr.<\/strong><\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>\u0130ndirgenen<\/strong> madde; kar\u015f\u0131s\u0131ndaki maddenin y\u00fckseltgenmesini sa\u011flad\u0131\u011f\u0131 i\u00e7in <strong>y\u00fckseltgen<\/strong> \u00f6zellik g\u00f6sterir.\n<ul class=\"wp-block-list\">\n<li>\u0130ndirgenene atomun olu\u015fturdu\u011fu madde <strong>indirgenme \u00fcr\u00fcn\u00fcd\u00fcr<\/strong>.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-9\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-white-background-color has-background\"><strong><strong>Cu<sup>+2<\/sup> + Fe \u2192 Cu + Fe<sup>+2<\/sup><\/strong><\/strong><\/p>\n\n\n\n<p><strong>Yukar\u0131daki tepkime i\u00e7in a\u015fa\u011f\u0131daki maddeleri bulunuz.<\/strong><\/p>\n\n\n\n<p><strong>I) Y\u00fckseltgenen<br>II) \u0130ndirgenen<br>III) Y\u00fckseltgen<br>IV) \u0130ndirgen<br>V) \u0130ndirgenme \u00fcr\u00fcn\u00fc<br>VI) Y\u00fckseltgenme \u00fcr\u00fcn\u00fc<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p><strong>I) Y\u00fckseltgenen: Fe<br>II) \u0130ndirgenen: Cu<sup>+2<\/sup><br>III) Y\u00fckseltgen: <strong>Cu<sup>+2<\/sup><\/strong><br>IV) \u0130ndirgen: Fe<br>V) \u0130ndirgenme \u00fcr\u00fcn\u00fc: Cu<br>VI) Y\u00fckseltgenme \u00fcr\u00fcn\u00fc: Fe<sup>2+<\/sup><\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Tepkimeye yak\u0131ndan bakal\u0131m:<\/p>\n\n\n\n<p><strong><strong>Cu<sup>+2<\/sup> + Fe \u2192 Cu + Fe<sup>+2<\/sup><\/strong><\/strong><\/p>\n\n\n\n<p>Tepkimede Cu elementi, +2 iken 0&#8217;a indirgenmi\u015ftir. \u0130ndirgenen madde, kar\u015f\u0131s\u0131ndaki maddeyi y\u00fckseltir, yani; y\u00fckseltgen \u00f6zellik g\u00f6sterir.<\/p>\n\n\n\n<p>Fe elementi ise; 0&#8217;dan +2&#8217;ye y\u00fckseltgenmi\u015ftir. Y\u00fckseltgenen madde, kar\u015f\u0131s\u0131ndaki maddeyi indirger, yani indirgen \u00f6zellik g\u00f6sterir.<\/p>\n\n\n\n<p>Fe atomunun y\u00fckseltgenmesi sonucu Fe<sup>2+<\/sup> iyonu olu\u015fmu\u015ftur. Bu y\u00fczden Fe<sup>2+<\/sup> bir y\u00fckseltgenme \u00fcr\u00fcn\u00fcd\u00fcr.<\/p>\n\n\n\n<p>Cu<sup>2+<\/sup> iyonunun indirgenmesi sonucunda Cu metali olu\u015fmu\u015ftur. Bu y\u00fczden Cu metali bir indirgenme \u00fcr\u00fcn\u00fcd\u00fcr.<\/p>\n\n\n\n<p>Sonu\u00e7 olarak cevaplar \u015f\u00f6yledir:<br><strong>I) Y\u00fckseltgenen: Fe<br>II) \u0130ndirgenen: Cu<sup>+2<\/sup><br>III) Y\u00fckseltgen: <strong>Cu<sup>+2<\/sup><\/strong><br>IV) \u0130ndirgen: Fe<br>V) \u0130ndirgenme \u00fcr\u00fcn\u00fc: Cu<br>VI) Y\u00fckseltgenme \u00fcr\u00fcn\u00fc: Fe<sup>2+<\/sup><\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Bazi_Indirgen_ve_Yukseltgen_Maddeler_ve_Ozellikleri\">Baz\u0131 \u0130ndirgen ve Y\u00fckseltgen Maddeler ve \u00d6zellikleri<\/span><\/h3>\n\n\n\n<p>Ba\u015fl\u0131ca indirgen ve y\u00fckseltgen maddeler \u015funlar\u0131d\u0131r:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"600\" height=\"434\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Yukseltgen-ve-indirgen-Maddeler.jpg\" alt=\"Ba\u015fl\u0131ca Y\u00fckseltgen ve \u0130ndirgenler\" class=\"wp-image-6046\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Yukseltgen-ve-indirgen-Maddeler.jpg 600w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2021\/01\/Yukseltgen-ve-indirgen-Maddeler-300x217.jpg 300w\" sizes=\"auto, (max-width: 600px) 100vw, 600px\" \/><figcaption class=\"wp-element-caption\">Ba\u015fl\u0131ca Y\u00fckseltgen ve \u0130ndirgenler<\/figcaption><\/figure>\n<\/div>\n\n\n<h2 class=\"wp-block-heading\"><span id=\"Redoks_Tepkimeleriyle_Elektrik_Enerjisi_Arasindaki_Iliski\">Redoks Tepkimeleriyle Elektrik Enerjisi Aras\u0131ndaki \u0130li\u015fki<\/span><\/h2>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Elektrik, bir \u00e7e\u015fit enerjidir.<\/li>\n\n\n\n<li>Elektrik ak\u0131m\u0131, elektronlar\u0131n bir iletken telde hareket etmesi ile olu\u015fur.<\/li>\n\n\n\n<li>Redoks tepkimelerinde, bir madde elektron verir di\u011fer madde elektron al\u0131r.<\/li>\n\n\n\n<li>Elektron al\u0131\u015f-veri\u015fi ger\u00e7ekle\u015fti\u011fi i\u00e7in, redoks tepkimeleri ile elektrik enerjisi \u00fcretilebilir.<\/li>\n\n\n\n<li><strong><em>Kendili\u011finden ger\u00e7ekle\u015fen (istemli) redoks tepkimeleri, kimyasal ba\u011flardaki enerjiyi, elektrik enerjisine d\u00f6n\u00fc\u015ft\u00fcr\u00fcr.<\/em><\/strong>\n<ul class=\"wp-block-list\">\n<li>\u0130stemli tepkimeler, ba\u015flat\u0131ld\u0131ktan sorna kendi kendine devem edebilenlerdir.<\/li>\n\n\n\n<li>\u0130stemli redoks tepkimelerinde, elektron alan ve veren maddeler <strong><em>ayn\u0131 kab\u0131n i\u00e7inde olursa<\/em><\/strong>, <strong><em>elektrik ak\u0131m\u0131 olu\u015fmadan<\/em><\/strong> elektron al\u0131\u015f-veri\u015fi ger\u00e7ekle\u015fir.<\/li>\n\n\n\n<li>\u0130stemli redoks tepkimelerinde; indirgenme yar\u0131 tepkimesini ve y\u00fckseltgenme yar\u0131 tepkimesini <strong><em>ayr\u0131 kaplarda ger\u00e7ekle\u015ftirirsek<\/em><\/strong>; kaplar aras\u0131nda da gerekli ba\u011flant\u0131lar\u0131 kurarsak bir <strong><em>elektrik ak\u0131m\u0131 elde ederiz.<\/em><\/strong><\/li>\n\n\n\n<li>Piller, bataryalar ve ak\u00fcler; istemli redoks tepkimeleri ile elektrik \u00fcreterek, bir\u00e7ok makine ve cihaza elektrik enerjisi verirler:\n<ul class=\"wp-block-list\">\n<li>Uzaktan kumandalar<\/li>\n\n\n\n<li>Cep telefonlar\u0131<\/li>\n\n\n\n<li>Tablet bilgisayarlar<\/li>\n\n\n\n<li>Diz\u00fcst\u00fc bilgisayarlar<\/li>\n\n\n\n<li>Elektrikli arabalar<\/li>\n\n\n\n<li>Pilli oyuncaklar<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Elektrik enerji alarak ger\u00e7ekle\u015fen redoks tepkimeleri, elektrik enerjisini kimyasal enerjiye d\u00f6n\u00fc\u015ft\u00fcren tepkimelerdir. A\u015fa\u011f\u0131daki olaylarda, elektrik ak\u0131m\u0131 ile istemsiz redoks tepkimeleri ger\u00e7ekle\u015ftirir:<ul><li>Telefonun, tabletin, diz\u00fcst\u00fc bilgisayar\u0131n&#8230; \u015farj edilmesi<\/li><\/ul>\n<ul class=\"wp-block-list\">\n<li>Ak\u00fclerin doldurulmas\u0131<\/li>\n\n\n\n<li>Bile\u015fiklerin elektrolizi <\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h3 class=\"wp-block-heading\"><span id=\"Ornek-10\">\u00d6rnek:<\/span><\/h3>\n\n\n\n<p>I) CH<sub>4<\/sub> + 2O<sub>2<\/sub> <strong><strong>\u2192<\/strong><\/strong> CO<sub>2<\/sub> + 2H<sub>2<\/sub>O<br>II) NaCl<sub>(k)<\/sub> <strong><strong>\u2192<\/strong><\/strong> Na<sup>+<\/sup><sub>(suda)<\/sub> + Cl<sup>&#8211;<\/sup><sub>(suda)<\/sub><br>III) Al + 3HCl <strong><strong>\u2192<\/strong><\/strong> AlCl<sub>3<\/sub> + <sup>3<\/sup>\/<sub>2<\/sub>H<sub>2<\/sub><br>IV) HCl + NaOH <strong><strong>\u2192<\/strong><\/strong> NaCl + H<sub>2<\/sub>O<\/p>\n\n\n\n<p><strong>Yukar\u0131da verilen tepkimelerden hangileri uygun ko\u015fullar sa\u011fland\u0131\u011f\u0131nda elektrik enerjisi \u00fcretmek i\u00e7in kullan\u0131labilir?<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-large-font-size\">I ve III<\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Elektrik \u00fcretebilen kimyasal tepkimeler redoks tepkimeleridir. Bu y\u00fczden verilen tepkimelerde, redoks olanlar\u0131 aramal\u0131y\u0131z.<\/p>\n\n\n\n<p>Soruda verilen tepkimeler, ezbere bilinmesi gereken tepkime t\u00fcrlerdir. Y\u00fckseltgenme basama\u011f\u0131 hesaplamaya gerek yoktur.<\/p>\n\n\n\n<p>I) CH<sub>4<\/sub> + 2O<sub>2<\/sub> <strong><strong>\u2192<\/strong><\/strong> CO<sub>2<\/sub> + 2H<sub>2<\/sub>O<br>Yanma tepkimesidir. <strong><em>Yanma <\/em><\/strong>tepkimeleri her zaman <strong><em>redokstur<\/em><\/strong>.<\/p>\n\n\n\n<p><br>II) NaCl<sub>(k)<\/sub> <strong><strong>\u2192<\/strong><\/strong> Na<sup>+<\/sup><sub>(suda)<\/sub> + Cl<sup>&#8211;<\/sup><sub>(suda)<\/sub><br>Tuzlar\u0131n suda <strong><em>\u00e7\u00f6z\u00fcnmesi redoks de\u011fildir.<\/em><\/strong><\/p>\n\n\n\n<p><br>III) Al + 3HCl <strong><strong>\u2192<\/strong><\/strong> AlCl<sub>3<\/sub> + <sup>3<\/sup>\/<sub>2<\/sub>H<sub>2<\/sub><br><strong><em>Metal-asit<\/em><\/strong> tepkimesidir ve her zaman <strong><em>redokstur<\/em><\/strong>.<\/p>\n\n\n\n<p><br>IV) HCl + NaOH <strong><strong>\u2192<\/strong><\/strong> NaCl + H<sub>2<\/sub>O<br>Asit-baz tepkimesidir. <strong><em>Asit-baz<\/em><\/strong> tepkimeleri <strong><em>redoks de\u011fildir.<\/em><\/strong><\/p>\n\n\n\n<p><strong><em>Cevap: I ve III<\/em><\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<p><\/p>\n\n\n\n<div class=\"wp-block-group stcnnt-yazi-ici-reklam\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p>Bu bir reklamd\u0131r:<\/p>\n\n\n\n<script async=\"\" src=\"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\"><\/script>\n<ins class=\"adsbygoogle\" style=\"display:block; text-align:center;\" data-ad-layout=\"in-article\" data-ad-format=\"fluid\" data-ad-client=\"ca-pub-6366953309324763\" data-ad-slot=\"9738116384\"><\/ins>\n<script>\n     (adsbygoogle = window.adsbygoogle || []).push({});\n<\/script>\n<\/div><\/div>\n","protected":false},"excerpt":{"rendered":"<p>&#8220;\u0130ndirgenme-Y\u00fckseltgenme Tepkimelerinde Elektrik Ak\u0131m\u0131&#8221; dersi, bir AYT Konusu olan &#8220;Kimya ve Elektrik&#8221; \u00fcnitesinin ilk b\u00f6l\u00fcm\u00fcd\u00fcr. Bu derste, &#8220;\u0130ndirgenme-Y\u00fckseltgenme Tepkimelerinde Elektrik Ak\u0131m\u0131&#8221; konusu, basit ve anla\u015f\u0131l\u0131r bir dille anlat\u0131lm\u0131\u015ft\u0131r.<\/p>\n","protected":false},"author":1,"featured_media":5950,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[174],"tags":[176],"class_list":["post-5945","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-kimya-ve-elektrik","tag-indirgenme-yukseltgenme-tepkimelerinde-elektrik-akimi"],"_links":{"self":[{"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/posts\/5945","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/comments?post=5945"}],"version-history":[{"count":2,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/posts\/5945\/revisions"}],"predecessor-version":[{"id":32789,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/posts\/5945\/revisions\/32789"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/media\/5950"}],"wp:attachment":[{"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/media?parent=5945"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/categories?post=5945"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/tags?post=5945"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}