{"id":5022,"date":"2020-12-14T23:43:32","date_gmt":"2020-12-14T20:43:32","guid":{"rendered":"https:\/\/sitecenneti.com\/kimya\/?p=5022"},"modified":"2024-02-02T00:23:34","modified_gmt":"2024-02-01T21:23:34","slug":"1-tepkime-hizlari","status":"publish","type":"post","link":"https:\/\/sitecenneti.com\/kimya\/ayt-kimya\/kimyasal-tepkimelerde-hiz\/1-tepkime-hizlari\/","title":{"rendered":"1. Tepkime H\u0131zlar\u0131"},"content":{"rendered":"<div id=\"toc_container\" class=\"toc_transparent no_bullets\"><p class=\"toc_title\">\u0130&ccedil;indekiler<\/p><ul class=\"toc_list\"><li><a href=\"#Atom_ve_Molekullerin_Dunyasinda_Tepkimeler_Nasil_Gerceklesir\">Atom ve Molek\u00fcllerin D\u00fcnyas\u0131nda Tepkimeler Nas\u0131l Ger\u00e7ekle\u015fir?<\/a><ul><li><a href=\"#Carpisma_Teorisi\">\u00c7arp\u0131\u015fma Teorisi<\/a><ul><li><a href=\"#1_Esik_Enerjisi\">1. E\u015fik Enerjisi<\/a><\/li><li><a href=\"#Ornek\">\u00d6rnek:<\/a><\/li><li><a href=\"#2_Uygun_Geometride_Carpisma\">2. Uygun Geometride \u00c7arp\u0131\u015fma<\/a><\/li><li><a href=\"#Ogretici_Ornek\">\u00d6\u011fretici \u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-2\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-3\">\u00d6rnek:<\/a><\/li><\/ul><\/li><\/ul><\/li><li><a href=\"#Tepkime_Hizinin_Takibi\">Tepkime H\u0131z\u0131n\u0131n Takibi<\/a><ul><li><a href=\"#1_Hacim_Degisimiyle_Hiz_Takibi\">1. Hacim De\u011fi\u015fimiyle H\u0131z Takibi<\/a><ul><li><a href=\"#Ogretici_Ornek-2\">\u00d6\u011fretici \u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#2_Basinc_Degisimiyle_Hiz_Takibi\">2. Bas\u0131n\u00e7 De\u011fi\u015fimiyle H\u0131z Takibi<\/a><ul><li><a href=\"#Ogretici_Ornek-3\">\u00d6\u011fretici \u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-4\">\u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#3_Renk_Degisimiyle_Hiz_Takibi\">3. Renk De\u011fi\u015fimiyle H\u0131z Takibi<\/a><ul><li><a href=\"#Ogretici_Ornek-4\">\u00d6\u011fretici \u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#4_Iletkenlik_Degisimiyle_Hiz_Takibi\">4. \u0130letkenlik De\u011fi\u015fimiyle H\u0131z Takibi<\/a><ul><li><a href=\"#Ogretici_Ornek-5\">\u00d6\u011fretici \u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#5_Gaz_Cikis_Hiziyla_Hiz_Takibi\">5. Gaz \u00c7\u0131k\u0131\u015f H\u0131z\u0131yla H\u0131z Takibi<\/a><ul><li><a href=\"#Ogretici_Ornek-6\">\u00d6\u011fretici \u00d6rnek:<\/a><\/li><\/ul><\/li><\/ul><\/li><li><a href=\"#Tepkimedeki_Maddelerin_Olusma_ve_Harcanma_Hizlari\">Tepkimedeki Maddelerin Olu\u015fma ve Harcanma H\u0131zlar\u0131<\/a><ul><li><a href=\"#Tepkimelerdeki_Maddelerin_Ortalama_Hizlari\">Tepkimelerdeki Maddelerin Ortalama H\u0131zlar\u0131<\/a><ul><li><a href=\"#Ogretici_Ornek-7\">\u00d6\u011fretici \u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-5\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-6\">\u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#Tepkimenin_Ortalama_Hizi\">Tepkimenin Ortalama H\u0131z\u0131<\/a><ul><li><a href=\"#Ornek-7\">\u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#Maddelerin_Farkli_Birimlerle_Hizini_Hesaplama\">Maddelerin Farkl\u0131 Birimlerle H\u0131z\u0131n\u0131 Hesaplama<\/a><ul><li><a href=\"#Ornek-8\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-9\">\u00d6rnek:<\/a><\/li><\/ul><\/li><\/ul><\/li><li><a href=\"#Tepkimedeki_Maddelerin_Hizlari_Arasindaki_Iliski\">Tepkimedeki Maddelerin H\u0131zlar\u0131 Aras\u0131ndaki \u0130li\u015fki<\/a><ul><li><ul><li><a href=\"#Ogretici_Ornek-8\">\u00d6\u011fretici \u00d6rnek:<\/a><\/li><li><a href=\"#Ogretici_Ornek-9\">\u00d6\u011fretici \u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#Ornek-10\">\u00d6rnek:<\/a><\/li><li><a href=\"#Tepkimelerdeki_Maddelerin_Anlik_Hizlari\">Tepkimelerdeki Maddelerin Anl\u0131k H\u0131zlar\u0131<\/a><\/li><\/ul><\/li><li><a href=\"#Homojen_ve_Heterojen_Faz_Tepkimeleri\">Homojen ve Heterojen Faz Tepkimeleri<\/a><ul><li><a href=\"#I_Homojen_Faz_Tepkimeleri\">I. Homojen Faz Tepkimeleri<\/a><\/li><li><a href=\"#II_Heterojen_Faz_Tepkimeleri\">II. Heterojen Faz Tepkimeleri<\/a><\/li><\/ul><\/li><\/ul><\/div>\n\n<ul class=\"wp-block-list\">\n<li>&#8220;<strong><em>Tepkime h\u0131zlar\u0131<\/em><\/strong>&#8220;, tepkimelerin ba\u015flad\u0131ktan sonraki h\u0131zlar\u0131 ile ilgili bir kavramd\u0131r.<\/li>\n\n\n\n<li>Baz\u0131 tepkimeler \u00e7ok h\u0131zl\u0131 ger\u00e7ekle\u015firken, baz\u0131lar\u0131 \u00e7ok yava\u015ft\u0131r.\n<ul class=\"wp-block-list\">\n<li><strong><em>Hava yast\u0131klar\u0131n\u0131n a\u00e7\u0131lmas\u0131<\/em><\/strong> veya <strong><em>bombalar\u0131n patlamas\u0131<\/em><\/strong> gibi baz\u0131 kimyasal tepkimeler <strong><em>ba\u015flad\u0131klar\u0131 anda biterler.<\/em><\/strong><\/li>\n\n\n\n<li><strong><em>Plastiklerin bozunmas\u0131<\/em><\/strong>, baz\u0131 <strong><em>metallerin paslanmas\u0131<\/em><\/strong> gibi tepkimelerin ger\u00e7ekle\u015fip sonlanmas\u0131 ise, y\u0131llar hatta <strong><em>y\u00fczy\u0131llarca s\u00fcrebilir<\/em><\/strong>.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Tepkimelerin h\u0131z\u0131n\u0131 \u00f6l\u00e7ebilmek i\u00e7in; \u00f6nce tepkimenin ba\u015flamas\u0131 gerekir.<\/li>\n<\/ul>\n\n\n\n<p>\u015eimdi gelin, molek\u00fcller aleminde, bir kimyasal tepkimenin, nas\u0131l ba\u015flad\u0131\u011f\u0131n\u0131 ve ger\u00e7ekle\u015fti\u011fini anlamaya \u00e7al\u0131\u015fal\u0131m.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><span id=\"Atom_ve_Molekullerin_Dunyasinda_Tepkimeler_Nasil_Gerceklesir\">Atom ve Molek\u00fcllerin D\u00fcnyas\u0131nda Tepkimeler Nas\u0131l Ger\u00e7ekle\u015fir?<\/span><\/h2>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Tepkimeler, maddelerin <a href=\"https:\/\/sitecenneti.com\/kimya\/tyt-kimya\/kimyasal-turler-arasi-etkilesimler\/kimyasal-turler\/\">kimyasal t\u00fcrleri<\/a> aras\u0131nda ger\u00e7ekle\u015fir.\n<ul class=\"wp-block-list\">\n<li>Kimyasal t\u00fcrler demek; atomlar, molek\u00fcller veya iyonlar demektir.<\/li>\n\n\n\n<li>Yani; asl\u0131nda, kimyasal tepkimeler; atomlar veya molek\u00fcller veya iyonlar aras\u0131nda ger\u00e7ekle\u015fir.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>\u0130ki kimyasal t\u00fcr\u00fcn, nas\u0131l tepkimeye girdi\u011fi &#8220;<strong><em>\u00c7arp\u0131\u015fma Teorisi<\/em><\/strong>&#8221; ile a\u00e7\u0131klan\u0131r.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Carpisma_Teorisi\">\u00c7arp\u0131\u015fma Teorisi<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>\u00c7arp\u0131\u015fma teorisine g\u00f6re,<strong><em> kimyasal t\u00fcrlerin<\/em><\/strong>, bir tepkime verebilmesi i\u00e7in <strong><em>\u00e7arp\u0131\u015fmalar\u0131<\/em><\/strong> \u015fartt\u0131r.\n<ul class=\"wp-block-list\">\n<li>\u00c7arp\u0131\u015fmayan kimyasal t\u00fcrlerin, bir tepkime vermesi m\u00fcmk\u00fcn de\u011fildir.<\/li>\n\n\n\n<li>Fakat; kimyasal t\u00fcrlerin her \u00e7arp\u0131\u015fmas\u0131, bir kimyasal tepkime ile sonu\u00e7lanmaz.<\/li>\n\n\n\n<li>Tepkime ile sonu\u00e7lanan \u00e7arp\u0131\u015fmalara &#8220;<strong><span class=\"has-inline-color has-luminous-vivid-orange-color\">etkin \u00e7arp\u0131\u015fma<\/span><\/strong>&#8221; denir.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Etkin bir \u00e7arp\u0131\u015fman\u0131n ger\u00e7ekle\u015fmesi i\u00e7in, \u015fu <strong><em>iki ko\u015fulun yerine gelmesi gerekir<\/em><\/strong>. Bunlar \u015funlard\u0131r:<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><span id=\"1_Esik_Enerjisi\">1. E\u015fik Enerjisi<\/span><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Etkin bir \u00e7arp\u0131\u015fman\u0131n ger\u00e7ekle\u015fmesi i\u00e7in, kimyasal t\u00fcrlerin a\u015fmas\u0131 gereken minimum enerjiye <strong><span class=\"has-inline-color has-luminous-vivid-orange-color\">e\u015fik enerjisi <\/span><\/strong>denir.<\/li>\n\n\n\n<li>E\u015fik enerjisine ula\u015fmayan kimyasal t\u00fcrlerin, bir tepkimeye girmesi m\u00fcmk\u00fcn de\u011fildir.<\/li>\n\n\n\n<li>E\u015fik enerjisi, Potansiyel Enerji &#8211; T.K grafi\u011fini tepe noktas\u0131n\u0131n enerji de\u011feridir.<\/li>\n<\/ul>\n\n\n\n<ul class=\"wp-block-list\">\n<li>A\u015fa\u011f\u0131daki grafik; <span style=\"color:#431370\" class=\"has-inline-color\"><strong>X<sub>2<\/sub>&nbsp;+ Y<sub>2<\/sub>&nbsp;\u2192 2XY<\/strong><\/span> tepkimesine aittir. Bu grafik, bir \u00f6nceki \u00fcnitede, \u0394H<sup>o<\/sup> de\u011ferini hesaplamak i\u00e7in verdi\u011fimiz, Potansiyel Enerji-TK grafi\u011finin ta kendisidir.<\/li>\n<\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"450\" height=\"371\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Esik-Enerjisi.jpg\" alt=\"\u00c7arp\u0131\u015fma Teorisi - E\u015fik Enerjisi\" class=\"wp-image-5030\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Esik-Enerjisi.jpg 450w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Esik-Enerjisi-300x247.jpg 300w\" sizes=\"auto, (max-width: 450px) 100vw, 450px\" \/><figcaption class=\"wp-element-caption\">\u00c7arp\u0131\u015fma Teorisi &#8211; E\u015fik Enerjisi<\/figcaption><\/figure>\n<\/div>\n\n\n<p class=\"has-background\" style=\"background-color:#fff8f2\"><strong><em>E\u015fik enerjisini<\/em><\/strong>, <strong><em>a\u015f\u0131lmas\u0131 gereken bir da<\/em><\/strong>\u011f gibi d\u00fc\u015f\u00fcnebiliriz. Zaten, grafik te bir da\u011fa benziyor. Da\u011f\u0131n tepesi, e\u015fik enerjisini g\u00f6steren nokta olarak d\u00fc\u015f\u00fcn\u00fclebilir. Girenlerdeki maddelerin \u00fcr\u00fcnlere d\u00f6n\u00fc\u015febilmesi i\u00e7in bu da\u011f\u0131 a\u015fmas\u0131 gereklidir.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong><em>E\u015fik enerjisini<\/em><\/strong>, genellikle, maddeleri <strong><em>\u0131s\u0131tarak veririz<\/em><\/strong>.\n<ul class=\"wp-block-list\">\n<li>Mesela; ka\u011f\u0131t 230<sup>o<\/sup>C&#8217;ye geldi\u011finde, havadaki oksijenle yanar.<\/li>\n\n\n\n<li>Ka\u011f\u0131d\u0131 \u00e7akmak ya da kibrit yard\u0131m\u0131 ile, yakla\u015f\u0131k 230<sup>o<\/sup>C&#8217;ye kadar \u0131s\u0131tt\u0131\u011f\u0131m\u0131zda, gerekli e\u015fik enerjisini vermi\u015f oluruz.<\/li>\n\n\n\n<li>230<sup>o<\/sup>C&#8217;ye kadar \u0131s\u0131t\u0131lan ka\u011f\u0131t ve oksijen molek\u00fclleri, yeterli enerjiye ula\u015fm\u0131\u015f olur ve yanma tepkimesi ba\u015flar, aksi taktirde bir yanma olay\u0131 ger\u00e7ekle\u015fmez.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe loading=\"lazy\" title=\"Activation Energy\" width=\"1170\" height=\"658\" src=\"https:\/\/www.youtube.com\/embed\/9rR6OEQRFZQ?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" allowfullscreen><\/iframe>\n<\/div><figcaption class=\"wp-element-caption\">E\u015fik Enerjisi ve Kibritin Yanmas\u0131<\/figcaption><\/figure>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Tepkimedeki maddelerin, e\u015fik enerjisine ula\u015fmalar\u0131 i\u00e7in gereken enerjiye <strong><span class=\"has-inline-color has-luminous-vivid-orange-color\">aktifle\u015fme enerjisi<\/span><\/strong>, denir.<\/li>\n\n\n\n<li>Bir \u00e7ok tepkime, geri y\u00f6nde de ger\u00e7ekle\u015febilir, yani \u00fcr\u00fcnler de tepkimeye girerek girenlere d\u00f6n\u00fc\u015febilir.\n<ul class=\"wp-block-list\">\n<li>\u0130leri y\u00f6ndeki tepkimenin aktifle\u015fme enerjisine <strong><span class=\"has-inline-color has-luminous-vivid-orange-color\">ileri aktifle\u015fme enerjisi (E<sub>ai<\/sub>)<\/span><\/strong> denir.<\/li>\n\n\n\n<li>Geri y\u00f6ndeki tepkimenin aktifle\u015fme enerjisine <strong><span class=\"has-inline-color has-luminous-vivid-orange-color\">geri aktifle\u015fme enerjisi (E<sub>ag<\/sub>)<\/span><\/strong> denir.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>\u0130leri ve geri aktifle\u015fme enerjisi de\u011ferleri, Potansiyel Enerji-T.K grafi\u011fine bakarak hesaplanabilir.\n<ul class=\"wp-block-list\">\n<li>Grafi\u011fin <strong><em>\u00e7izildi\u011fi y\u00f6n ileri tepkime<\/em><\/strong> y\u00f6n\u00fcd\u00fcr.<\/li>\n\n\n\n<li>Grafi\u011fin sonundan ba\u015f\u0131na do\u011fru giden y\u00f6n geri tepkime y\u00f6n\u00fcd\u00fcr.<\/li>\n\n\n\n<li><strong><em>\u0130leri tepkimenin \u00fcr\u00fcnleri, geri tepkimenin girenleridir.<\/em><\/strong><\/li>\n\n\n\n<li>\u0130leri tepkimenin girenleri, geri tepkimenin \u00fcr\u00fcnleridir.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n<div class=\"wp-block-image stcnnt-no-bordered-img\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"450\" height=\"370\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Aktiflesme-Enerjisi.jpg\" alt=\"\u0130leri ve Geri Aktifle\u015fme Enerjileri\" class=\"wp-image-5031\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Aktiflesme-Enerjisi.jpg 450w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Aktiflesme-Enerjisi-300x247.jpg 300w\" sizes=\"auto, (max-width: 450px) 100vw, 450px\" \/><\/figure>\n<\/div>\n\n\n<ul class=\"wp-block-list\">\n<li>Bir tepkimenin <strong><em>ileri ve geri aktifle\u015fme enerjileri yard\u0131m\u0131 ile, tepkime \u0131s\u0131s\u0131 hesaplanabilir<\/em><\/strong>.\n<ul class=\"wp-block-list\">\n<li>Bunun i\u00e7in yapmam\u0131z gereken tek \u015fey ileri aktifle\u015fme enerjisinden geri aktifle\u015fme enerjisini \u00e7\u0131karmakt\u0131r:<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<p class=\"has-text-align-center has-background\" style=\"background-color:#edf8ff;font-size:19px\"><strong>\u0394H<sup>o<\/sup> = E<sub>ai<\/sub> &#8211; E<sub>ag<\/sub><\/strong><\/p>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p>A<sub>2<\/sub>&nbsp;+ B<sub>2<\/sub>&nbsp;\u2192 2AB &nbsp;&nbsp;&nbsp;&nbsp;\u0394H = +436 kj\/mol<\/p>\n\n\n\n<p>Yukar\u0131da verilen tepkimenin ileri aktifle\u015fme enerjisinin 790 kj\/mol oldu\u011fu biliniyor.<\/p>\n\n\n\n<p><strong>Buna g\u00f6re bu tepkimenin geri aktifle\u015fme enerjisi ka\u00e7 kj\/mol&#8217;d\u00fcr?<\/strong><\/p>\n\n\n\n<p>A) -354<br>B) 354<br>C) -1226<br>D) 1226<br>E) -790<\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-large-font-size\"><strong>B<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Aktifle\u015fme enerjileri ile \u0394H hesaplamak i\u00e7in \u015fu form\u00fcl kullan\u0131l\u0131r:<\/p>\n\n\n\n<p><strong>\u0394H = E<sub>ai<\/sub> &#8211; E<sub>ag<\/sub><\/strong><\/p>\n\n\n\n<p>Soruda verilenler \u015funlard\u0131r:<br>\u0394H = +436 kj\/mol<br>E<sub>ai<\/sub> = 790 kj\/mol<\/p>\n\n\n\n<p>Sorulan \u015fudur:<br>E<sub>ag<\/sub> = ? kj\/mol<\/p>\n\n\n\n<p>Verilenleri form\u00fclde yerine yazal\u0131m ve E<sub>ag<\/sub> de\u011ferini bulal\u0131m:<\/p>\n\n\n\n<p><strong>\u0394H = E<sub>ai<\/sub> &#8211; E<sub>ag<\/sub><\/strong><br>+436 = 790 &#8211; E<sub>ag<\/sub><br>E<sub>ag<\/sub> = 790 &#8211; 436<br>E<sub>ag<\/sub> = 354 kj\/mol<\/p>\n\n\n\n<p><strong>Cevap B \u015f\u0131kk\u0131d\u0131r.<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h4 class=\"wp-block-heading\"><span id=\"2_Uygun_Geometride_Carpisma\">2. Uygun Geometride \u00c7arp\u0131\u015fma<\/span><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Kimyasal t\u00fcrlerin, tepkimeye girebilmeleri i\u00e7in, belli bir e\u015fik enerjisin a\u015fmalar\u0131 gerekti\u011fini \u00f6\u011frendik.\n<ul class=\"wp-block-list\">\n<li>Fakat; <strong><em>e\u015fik enerjisini a\u015fmalar\u0131<\/em><\/strong>, iki kimyasal t\u00fcr\u00fcn, <strong><em>kesin<\/em><\/strong> olarak <strong><em>tepkimeye girecekleri anlam\u0131na gelmez<\/em><\/strong>.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong><em>Yeterli enerjiye sahip<\/em><\/strong> olan atom ya da molek\u00fcllerin, bir de <strong><em>uygun bir geometride \u00e7arp\u0131\u015fmalar\u0131 gerekir<\/em><\/strong>.\n<ul class=\"wp-block-list\">\n<li>Yani, olu\u015facak \u00fcr\u00fcnde, hangi atomlar birbirine ba\u011flanacaksa, o atomlar\u0131n birbirine \u00e7arpmas\u0131 gerekir.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Uygun geometride ve yeterli enerji ile \u00e7arp\u0131\u015fan kimyasal t\u00fcrler, \u00fcr\u00fcnlere d\u00f6n\u00fc\u015f\u00fcrse, <strong>etkin \u00e7arp\u0131\u015fma<\/strong> ger\u00e7ekle\u015fmi\u015f olur.\n<ul class=\"wp-block-list\">\n<li>Etkin bir \u00e7arp\u0131\u015fmada, \u00f6nce b\u00fct\u00fcn atomlar aras\u0131nda zay\u0131f etkile\u015fimler kurulur ve karars\u0131z bir molek\u00fcl olu\u015fur.<\/li>\n\n\n\n<li>Bu molek\u00fcle &#8220;<strong><span class=\"has-inline-color has-luminous-vivid-orange-color\">aktifle\u015fmi\u015f kompleks<\/span><\/strong>&#8221; denir.<\/li>\n\n\n\n<li>Aktifle\u015fmi\u015f kompleksteki ba\u011flar:\n<ul class=\"wp-block-list\">\n<li>\u00dcr\u00fcnleri olu\u015fturacak \u015fekilde k\u0131r\u0131l\u0131rsa tepkime ger\u00e7ekle\u015fmi\u015f olur ve \u00fcr\u00fcnler olu\u015fur.<\/li>\n\n\n\n<li>Yanl\u0131\u015f bir yerinden k\u0131r\u0131l\u0131rsa, \u00fcr\u00fcnler olu\u015fmaz ve tepkime ger\u00e7ekle\u015fmez.<\/li>\n\n\n\n<li>Yani, aktifle\u015fmi\u015f kompleksin olu\u015fmas\u0131 da, tepkimenin garanti ger\u00e7ekle\u015fti\u011fi anlam\u0131nda gelmez.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<p>A\u015fa\u011f\u0131daki \u015fekilde; <strong>X<sub>2<\/sub>&nbsp;+ Y<sub>2<\/sub>&nbsp;\u2192 2XY<\/strong> tepkimesine ait, etkin \u00e7arp\u0131\u015fma senaryosu \u00e7izilmi\u015ftir.<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"500\" height=\"196\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Etkin-Carpismai.jpg\" alt=\"Etkin \u00c7arp\u0131\u015fma\" class=\"wp-image-5035\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Etkin-Carpismai.jpg 500w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Etkin-Carpismai-300x118.jpg 300w\" sizes=\"auto, (max-width: 500px) 100vw, 500px\" \/><figcaption class=\"wp-element-caption\">Etkin \u00c7arp\u0131\u015fma<\/figcaption><\/figure>\n<\/div>\n\n\n<p>A\u015fa\u011f\u0131daki grafikte; <strong>X<sub>2<\/sub>&nbsp;+ Y<sub>2<\/sub>&nbsp;\u2192 2XY<\/strong> tepkimesine ait, etkin \u00e7arp\u0131\u015fma senaryosu g\u00f6sterilmi\u015ftir:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"450\" height=\"422\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Etkin-Carpisma-Aktiflesmis-Kopmleks.jpg\" alt=\"Etkin \u00c7arp\u0131\u015fma\" class=\"wp-image-5040\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Etkin-Carpisma-Aktiflesmis-Kopmleks.jpg 450w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Etkin-Carpisma-Aktiflesmis-Kopmleks-300x281.jpg 300w\" sizes=\"auto, (max-width: 450px) 100vw, 450px\" \/><figcaption class=\"wp-element-caption\">Etkin \u00c7arp\u0131\u015fma<\/figcaption><\/figure>\n<\/div>\n\n\n<ul class=\"wp-block-list\">\n<li>Uygun bir geometride olmayan \u00e7arp\u0131\u015fmalar, kimyasal t\u00fcrlerin enerjisi yeterli olsa bile, \u00fcr\u00fcnle sonu\u00e7lanmaz, tepkime ger\u00e7ekle\u015fmez.\n<ul class=\"wp-block-list\">\n<li>B\u00f6yle \u00e7arp\u0131\u015fmalara, <span class=\"has-inline-color has-luminous-vivid-orange-color\"><strong>etkin olmayan \u00e7arp\u0131\u015fmalar<\/strong><\/span> denir.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<p>A\u015fa\u011f\u0131daki \u00e7arp\u0131\u015fmadan 2 tane XY molek\u00fcl\u00fc molek\u00fcl\u00fcn\u00fcn olu\u015fmas\u0131 m\u00fcmk\u00fcn de\u011fildir:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"400\" height=\"173\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Etkin-Olmayan-Carpisma.jpg\" alt=\"Etkin Olmayan \u00c7arp\u0131\u015fma\" class=\"wp-image-5043\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Etkin-Olmayan-Carpisma.jpg 400w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Etkin-Olmayan-Carpisma-300x130.jpg 300w\" sizes=\"auto, (max-width: 400px) 100vw, 400px\" \/><figcaption class=\"wp-element-caption\">Etkin Olmayan \u00c7arp\u0131\u015fma<\/figcaption><\/figure>\n<\/div>\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ogretici_Ornek\">\u00d6\u011fretici \u00d6rnek:<\/span><\/h4>\n\n\n\n<p>Gelin, \u015fu ana kadar \u00f6\u011frendi\u011fimiz kavramlar\u0131, endotermik ve ekzotermik tepkimelerin enerji grafikleri \u00fczerinde ayr\u0131 ayr\u0131 g\u00f6relim:<\/p>\n\n\n\n<p>A\u015fa\u011f\u0131da, ekzotermik <strong>A<sub>2<\/sub>&nbsp;+ B<sub>2<\/sub>&nbsp;\u2192 2AB + \u0131s\u0131<\/strong> tepkimesine ait, Potansiyel Enerji &#8211; Tepkime Koordinat\u0131 grafi\u011fi \u00fczerinden, \u00f6\u011frendi\u011fimiz kavramlar g\u00f6sterilmi\u015ftir:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"500\" height=\"418\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Aktiflesmis-kompleks-Ekzotermik-Tepkime.jpg\" alt=\"Ekzotermik Bir Tepkimenin Enerji -TK Grafi\u011fi\" class=\"wp-image-5045\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Aktiflesmis-kompleks-Ekzotermik-Tepkime.jpg 500w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Aktiflesmis-kompleks-Ekzotermik-Tepkime-300x251.jpg 300w\" sizes=\"auto, (max-width: 500px) 100vw, 500px\" \/><figcaption class=\"wp-element-caption\">Ekzotermik Bir Tepkimenin Enerji -TK Grafi\u011fi<\/figcaption><\/figure>\n<\/div>\n\n\n<p>A\u015fa\u011f\u0131da, endotermik <strong>2AB + \u0131s\u0131 \u2192 A<sub>2<\/sub>&nbsp;+ B<sub>2<\/sub>&nbsp;<\/strong> tepkimesine ait, Potansiyel Enerji &#8211; Tepkime Koordinat\u0131 grafi\u011fi \u00fczerinden, \u00f6\u011frendi\u011fimiz kavramlar g\u00f6sterilmi\u015ftir:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"504\" height=\"418\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Aktiflesmis-kompleks-Endotermik-Tepkime.jpg\" alt=\"Endotermik Tepkimenin Enerji-TK Grafi\u011fi\" class=\"wp-image-5047\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Aktiflesmis-kompleks-Endotermik-Tepkime.jpg 504w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Aktiflesmis-kompleks-Endotermik-Tepkime-300x249.jpg 300w\" sizes=\"auto, (max-width: 504px) 100vw, 504px\" \/><figcaption class=\"wp-element-caption\">Endotermik Tepkimenin Enerji-TK Grafi\u011fi<\/figcaption><\/figure>\n<\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-2\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-text-align-center\"><img loading=\"lazy\" decoding=\"async\" width=\"400\" height=\"289\" class=\"wp-image-11097\" style=\"width: 400px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Kimyasal-Tepkimelerde-Hiz-Soru-Cozumu-2.jpg\" alt=\"Kimyasal Tepkimelerde H\u0131z - Soru \u00c7\u00f6z\u00fcm\u00fc\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Kimyasal-Tepkimelerde-Hiz-Soru-Cozumu-2.jpg 399w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Kimyasal-Tepkimelerde-Hiz-Soru-Cozumu-2-300x217.jpg 300w\" sizes=\"auto, (max-width: 400px) 100vw, 400px\" \/><\/p>\n\n\n\n<p>Yukar\u0131daki grafik, bir kimyasal tepkimenin Potansiyel Enerji &#8211; Tepkime Koordinat\u0131 grafi\u011fidir.<\/p>\n\n\n\n<p><strong>Buna g\u00f6re, bu tepkime i\u00e7in a\u015fa\u011f\u0131daki sorular\u0131 cevaplay\u0131n\u0131z.<\/strong><\/p>\n\n\n\n<p>I) Tepkimenin e\u015fik enerjisi ka\u00e7t\u0131r?<br>II) Tepkimenin ileri aktifle\u015fme enerjisi (E<sub>ai<\/sub>) ka\u00e7t\u0131r?<br>III) Tepkimenin geri aktifle\u015fme enerjisi (E<sub>ag<\/sub>) ka\u00e7t\u0131r?<br>IV) Tepkimenin \u0394H de\u011feri ka\u00e7t\u0131r?<br>V) Geri tepkimenin ileri aktifle\u015fme enerjisi ka\u00e7t\u0131r?<\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\">I) 462 kj\/mol<br>II) 250 kj\/mol<br>III) 430 kj\/mol<br>IV) -180 kj\/mol<br>V) 430 kj\/mol<\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Potansiyel Enerji-Tepkime Koordinat\u0131 grafi\u011findeki b\u00f6lgelerin anlamlar\u0131n\u0131 hat\u0131rlayal\u0131m:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"400\" height=\"294\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Kimyasal-Tepkimelerde-Hiz-Soru-Cozumu-2-.jpg\" alt=\"Kimyasal Tepkimelerde H\u0131z - Soru \u00c7\u00f6z\u00fcm\u00fc\" class=\"wp-image-11098\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Kimyasal-Tepkimelerde-Hiz-Soru-Cozumu-2-.jpg 400w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Kimyasal-Tepkimelerde-Hiz-Soru-Cozumu-2--300x221.jpg 300w\" sizes=\"auto, (max-width: 400px) 100vw, 400px\" \/><\/figure>\n<\/div>\n\n\n<p>Bu durumda, sorulan de\u011ferler \u015f\u00f6yle hesaplanabilir:<\/p>\n\n\n\n<p>I) E\u015fik enerjisi, tepkimenin tepe noktas\u0131d\u0131r: 462 kj\/mol<\/p>\n\n\n\n<p>II) E<sub>ai<\/sub> = 462 &#8211; 212 = 250 kj\/mol<\/p>\n\n\n\n<p>III) E<sub>ag<\/sub> = 462 &#8211; 32 = 430 kj\/mol<\/p>\n\n\n\n<p>IV) \u0394H = E<sub>ai<\/sub> &#8211; E<sub>ag<\/sub><br>\u0394H = 250 &#8211; 430 = &#8211; 180 kj\/mol<\/p>\n\n\n\n<p>V) \u0130leri tepkimenin <strong><em>geri aktifle\u015fme enerjisi<\/em><\/strong> geri tepkimenin <strong><em>ileri aktifle\u015fme enerjisi<\/em><\/strong> demektir.<br>Yani; geri tepkimenin ileri aktifle\u015fme enerjisi = 430 kj\/mol olmal\u0131d\u0131r.<\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-3\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p><strong>Bir kimyasal tepkimede a\u015fa\u011f\u0131daki olaylardan hangisi ger\u00e7ekle\u015firse, etkin bir \u00e7arp\u0131\u015fma ger\u00e7ekle\u015fmi\u015f demektir?<\/strong><\/p>\n\n\n\n<p>A) Girenlerin yeterli enerjiye sahip olmas\u0131<br>B) Girenlerin uygun geometride \u00e7arp\u0131\u015fmas\u0131<br>C) Girenlerin yeterli enerjide ve uygun geometride \u00e7ap\u0131\u015fmas\u0131<br>D) Aktifle\u015fmi\u015f kompleksin olu\u015fmas\u0131<br>E) Aktifle\u015fmi\u015f kompleksin uygun yerinden k\u0131r\u0131lmas\u0131<\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-large-font-size\"><strong>E<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Bir kimyasal tepkimede, etkin \u00e7arp\u0131\u015fman\u0131n ger\u00e7ekle\u015fmesi demek, tepkimenin ger\u00e7ekle\u015fmesi ve \u00fcr\u00fcnlerin olu\u015fmas\u0131 demektir.<\/p>\n\n\n\n<p>Yeterli enerji ile ve uygun geometride \u00e7arp\u0131\u015fan molek\u00fcller, \u00f6nce aktifle\u015fmi\u015f kompleks molek\u00fcl\u00fcn\u00fc olu\u015fturur.<\/p>\n\n\n\n<p>Olu\u015fan aktifle\u015fmi\u015f kompleks molek\u00fcl\u00fc uygun yerinden k\u0131r\u0131l\u0131rsa \u00fcr\u00fcnler olu\u015fur; k\u0131r\u0131lmazsa girenler geri olu\u015fur.<\/p>\n\n\n\n<p><em>Bu y\u00fczden E \u015f\u0131kk\u0131 do\u011frudur.<\/em><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><span id=\"Tepkime_Hizinin_Takibi\">Tepkime H\u0131z\u0131n\u0131n Takibi<\/span><\/h2>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Kimyasal tepkimeler ger\u00e7ekle\u015ftik\u00e7e; baz\u0131 \u015feyler de\u011fi\u015fir.<\/li>\n\n\n\n<li>H\u0131zl\u0131 ger\u00e7ekle\u015fen tepkimelerde bu de\u011fi\u015fimler h\u0131zl\u0131 olur, yava\u015f ger\u00e7ekle\u015fen tepkimelerde yava\u015f olur.\n<ul class=\"wp-block-list\">\n<li>Mesela, elbiselerin solmas\u0131 tepkimesinde, renk de\u011fi\u015fimini takip ederek, tepkimenin h\u0131z\u0131n\u0131 g\u00f6rebiliriz.\n<ul class=\"wp-block-list\">\n<li>Elbiselerin solmas\u0131 y\u0131larca s\u00fcrebilmektedir. Bu y\u00fczden solma tepkimesi y\u0131llarca devam eden yava\u015f bir tepkimedir diyebiliriz.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Havai fi\u015fe\u011fin patlay\u0131p tamamen s\u00f6nmesi tepkimesinde de k\u0131v\u0131lc\u0131mlar\u0131n olu\u015fma ve s\u00f6nme h\u0131z\u0131na bakarak, tepkime h\u0131z\u0131n\u0131 takip edebiliriz.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Tepkime h\u0131zlar\u0131n\u0131 takip etmenin bir \u00e7ok yolu vard\u0131r. \u00c7\u00fcnk\u00fc tepkimelerde maddelerin de\u011fi\u015fen bir \u00e7ok \u00f6zelli\u011fi vard\u0131r. Bu \u00f6zelliklerin de\u011fi\u015fme h\u0131z\u0131na bakarak tepkimelerin h\u0131zlar\u0131n\u0131 anlayabiliriz.<\/li>\n\n\n\n<li>Tepkime h\u0131z\u0131n\u0131 takip etmek i\u00e7in kullan\u0131labilecek baz\u0131 \u00f6zellikler \u015funlard\u0131r:\n<ol class=\"wp-block-list\">\n<li>Hacim de\u011fi\u015fimi<\/li>\n\n\n\n<li>Bas\u0131n\u00e7 de\u011fi\u015fimi<\/li>\n\n\n\n<li>Renk de\u011fi\u015fimi<\/li>\n\n\n\n<li>\u0130letkenlik de\u011fi\u015fimi<\/li>\n\n\n\n<li>Gaz \u00e7\u0131k\u0131\u015f h\u0131z\u0131<\/li>\n<\/ol>\n<\/li>\n<\/ul>\n\n\n\n<p>Farkl\u0131 tepkimelerin h\u0131zlar\u0131n\u0131 takip etmek i\u00e7in farkl\u0131 \u00f6zelliklerden yararlan\u0131labilir. A\u015fa\u011f\u0131da tepkime h\u0131z\u0131n\u0131 takip etmek i\u00e7in kullan\u0131lan baz\u0131 yollar verilmi\u015ftir.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"1_Hacim_Degisimiyle_Hiz_Takibi\">1. Hacim De\u011fi\u015fimiyle H\u0131z Takibi<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Hacim de\u011fi\u015fimi ile h\u0131z takibi yap\u0131labilen tepkimelerde, <strong>gazlara <\/strong>dikkat edilir.\n<ul class=\"wp-block-list\">\n<li>Girenlerdeki gazlar\u0131n toplam say\u0131s\u0131 ile \u00fcr\u00fcnlerdeki gazlar\u0131n toplam say\u0131s\u0131 farkl\u0131 olmal\u0131d\u0131r ki hacim de\u011fi\u015febilsin.\n<ul class=\"wp-block-list\">\n<li><strong>Mesela<\/strong>:\n<ul class=\"wp-block-list\">\n<li>3 tane gaz molek\u00fcl\u00fc 2 tane gaz molek\u00fcl\u00fcne d\u00f6n\u00fc\u015f\u00fcyorsa bu tepkimede hacim azal\u0131r:\n<ul class=\"wp-block-list\">\n<li><strong>3A<sub>(g)<\/sub> \u2192 2B<sub>(g)<\/sub><\/strong><\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>3 tane gaz molek\u00fcl\u00fc 4 tane gaz molek\u00fcl\u00fcne d\u00f6n\u00fc\u015f\u00fcyorsa bu tepkimede hacim artar:\n<ul class=\"wp-block-list\">\n<li><strong>3A<sub>(g)<\/sub> \u2192 4B<sub>(g)<\/sub><\/strong><\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>3 tane gaz molek\u00fcl\u00fc 3 tane gaz molek\u00fcl\u00fcne d\u00f6n\u00fc\u015f\u00fcyorsa bu tepkimede hacim de\u011fi\u015fmez:\n<ul class=\"wp-block-list\">\n<li><strong>3A<sub>(g)<\/sub> \u2192 3B<sub>(g)<\/sub><\/strong><\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<p><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Hacim de\u011fi\u015fimi ile h\u0131z takibi yapabilmek i\u00e7in:\n<ul class=\"wp-block-list\">\n<li>Tepkimede en az bir tane gaz olmal\u0131<\/li>\n\n\n\n<li>Tepkime sabit bas\u0131n\u00e7 alt\u0131nda (ideal pistonlu kapta ya da elastik balonda) ger\u00e7ekle\u015fmelidir.<\/li>\n\n\n\n<li>Sabit hacimli kaplarda ger\u00e7ekle\u015fen tepkimelerde, hacim de\u011fi\u015femeyece\u011fi i\u00e7in, tepkime h\u0131z\u0131n\u0131 hacim de\u011fi\u015fimini takip ederek anlamak m\u00fcmk\u00fcn de\u011fildir.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ogretici_Ornek-2\">\u00d6\u011fretici \u00d6rnek:<\/span><\/h4>\n\n\n\n<p>A\u015fa\u011f\u0131daki tepkime, pistonlu veya balonlu bir kapta ger\u00e7ekle\u015firse, tepkime h\u0131z\u0131, hacim art\u0131\u015f\u0131 ile takip edilebilir:<\/p>\n\n\n\n<p class=\"has-text-align-center has-background\" style=\"background-color:#eff9ff\"><strong>Zn<sub>(k)<\/sub> + 2HCl<sub>(suda)<\/sub> \u2192&nbsp; ZnCl<sub>2(suda)<\/sub> + H<sub>2(g)<\/sub><\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Yukardaki tepkimenin girenler k\u0131sm\u0131nda hi\u00e7 gaz yoktur, \u00fcr\u00fcnler k\u0131sm\u0131nda bir tane gaz vard\u0131r.<\/li>\n\n\n\n<li>Bu y\u00fczden, bu tekime ger\u00e7ekle\u015ftik\u00e7e gaz miktar\u0131 artar.\n<ul class=\"wp-block-list\">\n<li>Gaz artt\u0131k\u00e7a da hacim artar.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Tepkime h\u0131zl\u0131 ger\u00e7ekle\u015firse hacim h\u0131zl\u0131 artar, yava\u015f ger\u00e7ekle\u015firse yava\u015f artar.<\/li>\n\n\n\n<li>Bu y\u00fczden bu tepkimenin h\u0131z\u0131n\u0131 hacim de\u011fi\u015fimine bakarak anlayabiliriz.<\/li>\n<\/ul>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"2_Basinc_Degisimiyle_Hiz_Takibi\">2. Bas\u0131n\u00e7 De\u011fi\u015fimiyle H\u0131z Takibi<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Bir tepkimenin h\u0131z\u0131, <strong><em>hacim de\u011fi\u015fimi ile takip edilebiliyorsa, bas\u0131n\u00e7 de\u011fi\u015fimi ile de takip edilebilir.<\/em><\/strong>\n<ul class=\"wp-block-list\">\n<li>Bunun i\u00e7in tepkimenin, sabit hacimli bir kapta ger\u00e7ekle\u015fmesi yeterlidir.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ogretici_Ornek-3\">\u00d6\u011fretici \u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-text-align-center has-background\" style=\"background-color:#ebf7ff\"><strong>N<sub>2(g)<\/sub> + 3H<sub>2(g)<\/sub> \u2192&nbsp; 2NH<sub>3(g)<\/sub><\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Yukardaki tepkimede, toplam 4 tane gazdan 2 tane gaz olu\u015fuyor.<\/li>\n\n\n\n<li>Yani, tepkime ger\u00e7ekle\u015ftik\u00e7e gaz miktar\u0131 azal\u0131yor.<\/li>\n\n\n\n<li>Sabit hacimde iken, bu tepkime ger\u00e7ekle\u015ftik\u00e7e, gaz miktar\u0131 ve gaz bas\u0131nc\u0131 azalacakt\u0131r.<\/li>\n\n\n\n<li>Tepkime ne kadar h\u0131zl\u0131 ise bu olaylar o kadar h\u0131zl\u0131 olacakt\u0131r.<\/li>\n<\/ul>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-4\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-text-align-center has-background\" style=\"background-color:#ebf7ff\"><strong>H<sub>2(g)<\/sub> + Cl<sub>2(g)<\/sub> \u2192&nbsp; 2HCl<sub>(g)<\/sub> + \u0131s\u0131<\/strong><\/p>\n\n\n\n<p><strong>Yukar\u0131daki tepkime i\u00e7in a\u015fa\u011f\u0131dakilerden hangisi yanl\u0131\u015ft\u0131r?<\/strong><\/p>\n\n\n\n<p>A) Bir sentez tepkimesidir.<br>B) Tepkime h\u0131z\u0131 hacim de\u011fi\u015fimi ile takip edilebilir.<br>C) Ekzotermik bir tepkimedir.<br>D) \u00dcr\u00fcnlerin enerjisi daha azd\u0131r.<br>E) E<sub>ag<\/sub> de\u011feri E<sub>ai<\/sub> de\u011ferinden daha b\u00fcy\u00fckt\u00fcr.<\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-large-font-size\"><strong>B<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center\"><strong>H<sub>2(g)<\/sub> + Cl<sub>2(g)<\/sub> \u2192&nbsp; 2HCl<sub>(g)<\/sub> + \u0131s\u0131<\/strong><\/p>\n\n\n\n<p>A) &#8211; Do\u011fru<br>Tepkimede iki madde birle\u015fmi\u015f ve bir bile\u015fik olu\u015fmu\u015ftur. Bu y\u00fczen bir tepkime bir olu\u015fma (sentez) tepkimesidir.<\/p>\n\n\n\n<p>B) &#8211; Yanl\u0131\u015f<br>Girenlerde de 2 tane gaz, \u00fcr\u00fcnlerde de 2 tane gaz vard\u0131r. Harcanan ve olu\u015fan gaz say\u0131s\u0131 e\u015fit oldu\u011fu i\u00e7in, bu tepkimenin h\u0131z\u0131 bas\u0131n\u00e7 veya hacim de\u011fi\u015fimi ile takip edilemez.<\/p>\n\n\n\n<p>C) &#8211; Do\u011fru<br>Is\u0131 \u00fcr\u00fcnlerde oldu\u011fu i\u00e7in tepkime ekzotermiktir.<\/p>\n\n\n\n<p>D) &#8211; Do\u011fru<br>Ekzotermik tepkimelerde \u00fcr\u00fcnlerin enerjisi daha azd\u0131r.<\/p>\n\n\n\n<p>E) &#8211; Do\u011fru<br>A\u015fa\u011f\u0131daki grafik, ekzotermik bir tepkimenin enerji grafi\u011fidir.<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"500\" height=\"418\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Aktiflesmis-kompleks-Ekzotermik-Tepkime.jpg\" alt=\"Ekzotermik Bir Tepkimenin Enerji -TK Grafi\u011fi\" class=\"wp-image-5045\" style=\"width:291px;height:243px\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Aktiflesmis-kompleks-Ekzotermik-Tepkime.jpg 500w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Aktiflesmis-kompleks-Ekzotermik-Tepkime-300x251.jpg 300w\" sizes=\"auto, (max-width: 500px) 100vw, 500px\" \/><figcaption class=\"wp-element-caption\">Ekzotermik Bir Tepkimenin Enerji -TK Grafi\u011fi<\/figcaption><\/figure>\n<\/div>\n\n\n<p>Grafikten de anla\u015f\u0131ld\u0131\u011f\u0131 gibi, ekzotermik tepkimelerde E<sub>ag<\/sub> de\u011feri daha b\u00fcy\u00fckt\u00fcr.<\/p>\n\n\n\n<p><strong><em>Cevap B<\/em><\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"3_Renk_Degisimiyle_Hiz_Takibi\">3. Renk De\u011fi\u015fimiyle H\u0131z Takibi<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Tepkimeye<strong><em> girenler ve \u00fcr\u00fcnler ayn\u0131 renkte de\u011filse<\/em><\/strong>, renk de\u011fi\u015fimi, tepkime h\u0131z\u0131 hakk\u0131nda fikir verir.<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ogretici_Ornek-4\">\u00d6\u011fretici \u00d6rnek:<\/span><\/h4>\n\n\n\n<p>A\u015fa\u011f\u0131daki tepkime, ne kadar h\u0131zl\u0131 ise kahverengi renk, o kadar h\u0131zl\u0131 kaybolacakt\u0131r:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"400\" height=\"80\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Hiz-Takibi-.jpg\" alt=\"Renk De\u011fi\u015fimi ile H\u0131z Takibi\" class=\"wp-image-5082\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Hiz-Takibi-.jpg 400w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Hiz-Takibi--300x60.jpg 300w\" sizes=\"auto, (max-width: 400px) 100vw, 400px\" \/><figcaption class=\"wp-element-caption\">Renk De\u011fi\u015fimi ile H\u0131z Takibi<\/figcaption><\/figure>\n<\/div><\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"4_Iletkenlik_Degisimiyle_Hiz_Takibi\">4. \u0130letkenlik De\u011fi\u015fimiyle H\u0131z Takibi<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>\u00dcr\u00fcnler ile girenlerin elektrik iletkenli\u011fi farkl\u0131 ise, tepkime ger\u00e7ekle\u015ftik\u00e7e iletkenlik de de\u011fi\u015fecektir. B\u00f6yle tepkimelerin h\u0131z\u0131, iletkenlik de\u011fi\u015fimi ile \u00f6l\u00e7\u00fclebilir.<\/li>\n\n\n\n<li>Elektri\u011fi ileten maddeler \u015funlard\u0131r:\n<ul class=\"wp-block-list\">\n<li>Kat\u0131 ve s\u0131v\u0131 metaller:\n<ul class=\"wp-block-list\">\n<li>Na, Ca, Mg, Al&#8230;.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Karbonun grafit formu (C<sub>(grafit)<\/sub>)<\/li>\n\n\n\n<li>Suda \u00e7\u00f6z\u00fcnm\u00fc\u015f iyonlar:\n<ul class=\"wp-block-list\">\n<li>Na<sup>+<\/sup><sub>(suda)<\/sub>,<\/li>\n\n\n\n<li>SO<sub>4<\/sub><sup>2-<\/sup>(suda)<\/li>\n\n\n\n<li>Cl<sup>&#8211;<\/sup><sub>(suda)<\/sub><\/li>\n\n\n\n<li>&#8230;..<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>S\u0131v\u0131 haldeki tuzlar:\n<ul class=\"wp-block-list\">\n<li>NaCl<sub>(s)<\/sub><\/li>\n\n\n\n<li>CaBr<sub>2(s)<\/sub><\/li>\n\n\n\n<li>BaSO<sub>4(s)<\/sub><\/li>\n\n\n\n<li>&#8230;.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ogretici_Ornek-5\">\u00d6\u011fretici \u00d6rnek:<\/span><\/h4>\n\n\n\n<p>A\u015fa\u011f\u0131daki tepkime ne kadar h\u0131zl\u0131 ise, iletkenlik o kadar h\u0131zl\u0131 azalacakt\u0131r:<\/p>\n\n\n\n<p class=\"has-text-align-left has-background\" style=\"background-color:#f3faff\"><strong>Ag<sup>+<\/sup><sub>(suda)<\/sub> + Cl<sup>&#8211;<\/sup><sub>(suda)<\/sub> \u2192&nbsp; AgCl<sub>(k)<\/sub><\/strong><\/p>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"5_Gaz_Cikis_Hiziyla_Hiz_Takibi\">5. Gaz \u00c7\u0131k\u0131\u015f H\u0131z\u0131yla H\u0131z Takibi<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Bir kimyasal tepkimenin sadece \u00fcr\u00fcnlerinde gaz varsa, bu tepkimenin h\u0131z\u0131, gaz \u00e7\u0131k\u0131\u015f h\u0131z\u0131 ile \u00f6l\u00e7\u00fclebilir.<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ogretici_Ornek-6\">\u00d6\u011fretici \u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-text-align-left has-background\" style=\"background-color:#f3faff\"><strong>Ca<sub>(k)<\/sub> + HCl<sub>(suda)<\/sub> \u2192&nbsp; CaCl<sub>2(suda)<\/sub> + H<sub>2(g)<\/sub><\/strong><\/p>\n\n\n\n<p>Yukar\u0131daki tepkime, ne kadar h\u0131zl\u0131 ger\u00e7ekle\u015firse o kadar h\u0131zl\u0131 bir gaz \u00e7\u0131k\u0131\u015f\u0131 olur.<\/p>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group has-background\" style=\"background-color:#f2fffa\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<ul class=\"wp-block-list\">\n<li>H\u0131zlar\u0131 takip edildi\u011finde g\u00f6r\u00fclecektir ki, <strong><em>b\u00fct\u00fcn tepkimeler h\u0131zl\u0131 ba\u015flar, zamanla yava\u015flar.<\/em><\/strong><\/li>\n\n\n\n<li>Bir kimyasal tepkimenin en h\u0131zl\u0131 oldu\u011fu an, ba\u015flad\u0131\u011f\u0131 and\u0131r.<\/li>\n<\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"290\" height=\"265\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Kimyasal-Tepkimelerde-Hiz-2.jpg\" alt=\"Tepkime H\u0131z\u0131n\u0131n Zamanla De\u011fi\u015fimi\" class=\"wp-image-11166\"\/><figcaption class=\"wp-element-caption\">Tepkime H\u0131z\u0131n\u0131n Zamanla De\u011fi\u015fimi<\/figcaption><\/figure>\n<\/div><\/div><\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><span id=\"Tepkimedeki_Maddelerin_Olusma_ve_Harcanma_Hizlari\">Tepkimedeki Maddelerin Olu\u015fma ve Harcanma H\u0131zlar\u0131<\/span><\/h2>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Kimyasal tepkimeler ger\u00e7ekle\u015ftik\u00e7e,\n<ul class=\"wp-block-list\">\n<li>tepkimeye <strong><em>giren maddelerin miktar\u0131 azal\u0131r<\/em><\/strong>,<\/li>\n\n\n\n<li><strong><em>\u00fcr\u00fcnlerdeki maddelerin miktar\u0131 artar.<\/em><\/strong><\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>H\u0131zl\u0131 ger\u00e7ekle\u015fen bir kimyasal tepkimede, girenler h\u0131zl\u0131 bir \u015fekilde t\u00fckenir, \u00fcr\u00fcnler h\u0131zl\u0131 bir \u015fekilde \u00fcretilir.<\/li>\n\n\n\n<li>Ayn\u0131 \u015fekilde yava\u015f ger\u00e7ekle\u015fen bir tepkimede de, maddelerin miktar\u0131 yava\u015f bir \u015fekilde de\u011fi\u015fecektir.<\/li>\n<\/ul>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong><em>Tepkimelerin h\u0131z\u0131<\/em><\/strong>, tepkimedeki her hangi bir <strong><em>maddenin miktar\u0131n\u0131n zamanla de\u011fi\u015fme h\u0131z\u0131na<\/em><\/strong> bak\u0131larak da hesaplanabilir.\n<ul class=\"wp-block-list\">\n<li>Bir tepkimedeki maddelerin, zamanla de\u011fi\u015fme h\u0131zlar\u0131na, <strong><span class=\"has-inline-color has-luminous-vivid-orange-color\">tepkime h\u0131z\u0131<\/span><\/strong> denir.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<p>Tepkimedeki herhangi <strong><em>bir maddenin h\u0131z\u0131n\u0131<\/em><\/strong> hesaplamak i\u00e7in, a\u015fa\u011f\u0131daki <strong><em>form\u00fcl <\/em><\/strong>kullan\u0131labilir:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"143\" height=\"90\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Maddelerin-Hizi.jpg\" alt=\"Tepkimedeki Maddelerin H\u0131z\u0131\" class=\"wp-image-5060\"\/><figcaption class=\"wp-element-caption\">Tepkimedeki Maddelerin H\u0131z\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<p>Form\u00fcldeki sembollerin anlamlar\u0131 \u015f\u00f6yledir:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>r<\/strong>: Maddenin h\u0131z\u0131d\u0131r. Bazen &#8220;r&#8221; yerine &#8220;\u03d1&#8221; sembol\u00fc de kullan\u0131l\u0131r.<\/li>\n\n\n\n<li><strong>\u0394C<\/strong>: Maddenin <strong><em>deri\u015fimindeki (konsantrasyonundaki) de\u011fi\u015fim<\/em><\/strong>\n<ul class=\"wp-block-list\">\n<li><strong><em>\u0394C = C<sub>son<\/sub> &#8211; C<sub>ilk<\/sub><\/em><\/strong><br>\u015feklinde hesaplan\u0131r. H\u0131z hesaplan\u0131rken, deri\u015fim birimi olarak genellikle <strong><em>Molarite (M)<\/em><\/strong> kullan\u0131l\u0131r.<\/li>\n\n\n\n<li><strong><em>K\u00f6\u015feli parantez Molaritesi demektir:<\/em><\/strong><br>[N<sub>2<\/sub>] = Azotun molaritesi<br>[Na<sup>+<\/sup>] = Na<sup>+<\/sup> iyonunun molaritesi<br>[NH<sub>3<\/sub>] = NH<sub>3<\/sub> bile\u015fi\u011finin molaritesi<br>[H<sub>2<\/sub>] = Hidrojenin molaritesi<br><\/li>\n\n\n\n<li><strong><em>&#8220;\u0394&#8221; i\u015fareti, de\u011fi\u015fim demektir:<br><\/em><\/strong>Molarite de\u011fi\u015fimleri de \u015f\u00f6yle ifade edilir:<br>\u0394[H<sub>2<\/sub>] = [H<sub>2<\/sub>]<sub>son<\/sub> &#8211; [H<sub>2<\/sub>]<sub>ilk<\/sub><br>\u0394[NH<sub>3<\/sub>] = [NH<sub>3<\/sub>]<sub>son<\/sub> &#8211; [NH<sub>3<\/sub>]<sub>ilk<\/sub><br>\u0394[Na<sup>+<\/sup>] = [Na<sup>+<\/sup>]<sub>son<\/sub> &#8211; [Na<sup>+<\/sup>]<sub>ilk<\/sub><br>&#8230;<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>\u0394t<\/strong>:  Ge\u00e7en s\u00fcre<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Tepkimelerdeki_Maddelerin_Ortalama_Hizlari\">Tepkimelerdeki Maddelerin Ortalama H\u0131zlar\u0131<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong><span class=\"has-inline-color has-luminous-vivid-orange-color\">Ortalama h\u0131z<\/span><\/strong>, bir maddenin birim zamanda de\u011fi\u015fen molaritesi olarak ifade edilebilir.<\/li>\n\n\n\n<li>Bir tepkimedeki her bir maddenin bir ortalama h\u0131z\u0131 vard\u0131r.<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ogretici_Ornek-7\">\u00d6\u011fretici \u00d6rnek:<\/span><\/h4>\n\n\n\n<p>\u00d6rnek olarak NH<sub>3<\/sub> (Amonyak) bile\u015fi\u011finin olu\u015fum tepkimesini inceleyelim:<\/p>\n\n\n\n<p class=\"has-text-align-center has-background\" style=\"background-color:#ebf7ff\"><strong>N<sub>2<\/sub> + 3H<sub>2<\/sub> \u2192&nbsp; 2NH<sub>3<\/sub><\/strong><\/p>\n\n\n\n<p>Molaritelerindeki de\u011fi\u015fim \u00fczerinden, tepkimedeki her \u00fc\u00e7 maddenin de teker teker ortalama h\u0131z ba\u011f\u0131nt\u0131s\u0131n\u0131 yazal\u0131m:<\/p>\n\n\n\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-9d6595d7 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\"><div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"216\" height=\"90\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Maddelerin-Hizi-1.jpg\" alt=\"N2'nin H\u0131z\u0131\" class=\"wp-image-5068\"\/><figcaption class=\"wp-element-caption\">N<sub>2<\/sub>&#8216;nin Ortalama Harcanma H\u0131z\u0131<\/figcaption><\/figure>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\"><div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"216\" height=\"87\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Maddelerin-Hizi-2.jpg\" alt=\"H2'nin H\u0131z\u0131\" class=\"wp-image-5067\"\/><figcaption class=\"wp-element-caption\">H<sub>2<\/sub>&#8216;nin Ortalama Harcanma H\u0131z\u0131<\/figcaption><\/figure>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\"><div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"220\" height=\"86\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Maddelerin-Hizi-3.jpg\" alt=\"NH3 Bile\u015fi\u011finin H\u0131z\u0131\" class=\"wp-image-5066\"\/><figcaption class=\"wp-element-caption\">NH<sub>3<\/sub> Bile\u015fi\u011finin Ortalama Olu\u015fma H\u0131z\u0131<\/figcaption><\/figure>\n<\/div><\/div>\n<\/div>\n\n\n\n<p class=\"has-background\" style=\"background-color:#f3fbff\">Yukar\u0131daki form\u00fclde, dilersek; r<sub>N2<\/sub>, r<sub>H2<\/sub> ve r<sub>NH3<\/sub> ifadeleri yerine &#8220;<strong>r<sub>ort<\/sub><\/strong>&#8221; da yazabiliriz.<br>&#8220;<strong>r<sub>ort<\/sub><\/strong>&#8220;, ortalama h\u0131z demektir.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Dikkat edilirse; tepkimeye <strong><em>giren maddelerin<\/em><\/strong> h\u0131z form\u00fcllerinde &#8220;<strong><span class=\"has-inline-color has-luminous-vivid-orange-color\">eksi<\/span><\/strong>&#8221; i\u015fareti vard\u0131r.\n<ul class=\"wp-block-list\">\n<li>Bu eksi i\u015fareti, &#8220;<strong><em>harcanma h\u0131z\u0131<\/em><\/strong>&#8221; anlam\u0131na gelir.<\/li>\n\n\n\n<li>Harcanma h\u0131z\u0131 negatiftir, \u00e7\u00fcnk\u00fc; <strong><em>girenlerin deri\u015fimi zamanla azal\u0131r<\/em><\/strong>, bu da de\u011fi\u015fimin negatif olmas\u0131na sebep olur.<\/li>\n\n\n\n<li>Form\u00fcldeki eksi i\u015fareti, bu negatifi tekrar pozitif yapmak i\u00e7indir.<\/li>\n\n\n\n<li>Giren maddelerin, molarite de\u011fi\u015fimlerini pozitif al\u0131rsak, bu eksi i\u015faretine gerek kalmaz.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-5\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-text-align-center has-background\" style=\"background-color:#eff9ff;font-size:18px\"><strong>N<sub>2<\/sub> + 3H<sub>2<\/sub> \u2192&nbsp; 2NH<sub>3<\/sub><\/strong><\/p>\n\n\n\n<p>Yukar\u0131da verilen tepkime, 2,4 M H<sub>2<\/sub> gaz\u0131 ile ba\u015flam\u0131\u015ft\u0131r. Tepkime ba\u015flad\u0131ktan 20 saniye sonra, kaptaki H<sub>2<\/sub> gaz\u0131n\u0131n deri\u015fimi 0,4 M olarak \u00f6l\u00e7\u00fcl\u00fcyor.<\/p>\n\n\n\n<p><strong>Buna g\u00f6re, bu tepkimenin ilk 20 saniyesinde, H<sub>2<\/sub> gaz\u0131n\u0131n ortalama harcanma h\u0131z\u0131 ka\u00e7 M\/s&#8217;dir.<\/strong><\/p>\n\n\n\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-9d6595d7 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\" style=\"flex-basis:20%\">\n<p>A) 1<\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\" style=\"flex-basis:20%\">\n<p>B) 10<sup>-1<\/sup><\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\" style=\"flex-basis:20%\">\n<p>C) 10<sup>-2<\/sup><\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\" style=\"flex-basis:20%\">\n<p>D) 10<sup>-3<\/sup><\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\" style=\"flex-basis:20%\">\n<p>E) 10<sup>-4<\/sup><\/p>\n<\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong>B<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#1e5a44\">Soruda, H<sub>2<\/sub> gaz\u0131n\u0131n 20 saniyelik s\u00fcre i\u00e7indeki ortalama h\u0131z\u0131 (r<sub>H2<\/sub>) sorulmaktad\u0131r.<br>Tepkimenin girenler taraf\u0131ndaki her maddede oldu\u011fu gibi H<sub>2<\/sub> elementinin de ortalama h\u0131z\u0131 \u015f\u00f6yle bulunur:<br><br><img loading=\"lazy\" decoding=\"async\" width=\"150\" height=\"60\" class=\"wp-image-5067\" style=\"width: 150px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Maddelerin-Hizi-2.jpg\" alt=\"H2'nin H\u0131z\u0131\"><br><br>Soruda, H2&#8217;nin deri\u015fiminin ba\u015flang\u0131\u00e7ta 2,4 M, sonu\u00e7ta ise 0,4 M oldu\u011fu s\u00f6ylenmi\u015f. O zaman \u0394[H<sub>2<\/sub>] de\u011ferini bulal\u0131m:<br>[H<sub>2<\/sub>]<sub>ilk<\/sub> = 2,4 M<br>[H<sub>2<\/sub>]<sub>son<\/sub> = 0,4 M<br>\u0394[H<sub>2<\/sub>] = [H<sub>2<\/sub>]<sub>son<\/sub> &#8211; [H<sub>2<\/sub>]<sub>ilk<\/sub><br>\u0394[H<sub>2<\/sub>] = 0,4 &#8211; 2,4<br>\u0394[H<sub>2<\/sub>] = -2M<br><br>Ge\u00e7en s\u00fcre de 20 saniye olarak verilmi\u015f. Yani:<br>\u0394t = 20 s<br><br>O zaman H<sub>2<\/sub> i\u00e7in, ortalama h\u0131z \u015f\u00f6yle hesaplan\u0131r:<br>r<sub>H2<\/sub> = &#8211; \u0394[H<sub>2<\/sub>] \/ \u0394t<br>r<sub>H2<\/sub> = &#8211; (-2 \/ 20)<br>r<sub>H2<\/sub> = 2 \/ 20 = 1 \/ 10 =  0,1 = 10<sup>-1<\/sup> M\/s<\/p>\n\n\n\n<p><em>Cevap: B<\/em><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-6\">\u00d6rnek:<\/span><\/h4>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"400\" height=\"297\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Soru-Cozumu.jpg\" alt=\"Tepkime H\u0131z\u0131 Soru \u00c7\u00f6z\u00fcm\u00fc\" class=\"wp-image-5087\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Soru-Cozumu.jpg 400w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Soru-Cozumu-300x223.jpg 300w\" sizes=\"auto, (max-width: 400px) 100vw, 400px\" \/><\/figure>\n<\/div>\n\n\n<p>Yukar\u0131daki grafik, bir kimyasal tepkimedeki maddelerin, zamana kar\u015f\u0131 molarite de\u011fi\u015fimini g\u00f6stermektedir.<\/p>\n\n\n\n<p>Buna g\u00f6re, bu tepkime i\u00e7in a\u015fa\u011f\u0131daki sorular\u0131 cevaplay\u0131n\u0131z.<\/p>\n\n\n\n<p><strong>a) X<sub>2<\/sub> maddesinin ilk 10 saniyedeki ortalama harcanma h\u0131z\u0131 ka\u00e7 M\/s&#8217;dir?<br>b) XY bile\u015fi\u011finin ilk 10 saniyedeki ortalama olu\u015fma h\u0131z\u0131 ka\u00e7 M\/s&#8217;dir?<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong>a) r<sub>X2<\/sub> = 0,5 M\/s<br>b) r<sub>XY<\/sub> = 1 M\/s<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#13523b\">Grafi\u011fe yak\u0131ndan bakal\u0131m:<br><br><img loading=\"lazy\" decoding=\"async\" width=\"300\" height=\"223\" class=\"wp-image-5087\" style=\"width: 300px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Soru-Cozumu.jpg\" alt=\"Tepkime H\u0131z\u0131 Soru \u00c7\u00f6z\u00fcm\u00fc\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Soru-Cozumu.jpg 400w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Soru-Cozumu-300x223.jpg 300w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><br><br>a)<br>Grafi\u011fe dikkat edersek, X<sub>2<\/sub> maddesinin deri\u015fimi azal\u0131yor. Yani; X<sub>2<\/sub> maddesi tepkimenin girenlerindedir. O zaman X<sub>2<\/sub> maddesinin ortalama harcanma h\u0131z\u0131:<br><br><img loading=\"lazy\" decoding=\"async\" width=\"150\" height=\"66\" class=\"wp-image-5097\" style=\"width: 150px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Soru-Cozumu-2.jpg\" alt=\"Tepkime H\u0131z\u0131 Soru \u00c7\u00f6z\u00fcm\u00fc\"><br><br>form\u00fcl\u00fc ile bulunur. Grafi\u011fe g\u00f6re, 10 saniye i\u00e7indeki molarite de\u011fi\u015fimi:<br><br><strong>\u0394[X<sub>2<\/sub>] = 3 &#8211; 8 = &#8211; 5 M<\/strong><br><br>oluyor. O zaman, molarite de\u011fi\u015fimini ve ge\u00e7en s\u00fcreyi form\u00fclde yerine yazal\u0131m ve ortalama harcanma h\u0131z\u0131n\u0131 bulal\u0131m:<br><br>r<sub>X2<\/sub> = &#8211; \u0394[X<sub>2<\/sub>] \/ \u0394t<br>r<sub>X2<\/sub> = &#8211; (-5) \/ 10 = 5 \/ 10<br>r<sub>X2<\/sub> = 0,5 M\/s<br><br>b)<br>Grafi\u011fe dikkat edersek, XY maddesinin deri\u015fimi zamanla art\u0131yor. Yani; XY bile\u015fi\u011fi tepkimenin \u00fcr\u00fcnlerindedir. O zaman, XY maddesinin ortalama olu\u015fma h\u0131z\u0131:<br><br><img loading=\"lazy\" decoding=\"async\" width=\"150\" height=\"67\" class=\"wp-image-5099\" style=\"width: 150px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Soru-Cozumu-3.jpg\" alt=\"Tepkime H\u0131z\u0131 Ortalama H\u0131z Soru \u00c7\u00f6z\u00fcm\u00fc\"><br><br>form\u00fcl\u00fc ile bulunur. Grafi\u011fe g\u00f6re, 10 saniye i\u00e7indeki molarite de\u011fi\u015fimi:<br><br><strong>\u0394[XY] = 10 &#8211; 0 = 10 M<\/strong><br><br>oluyor. O zaman, molarite de\u011fi\u015fimini ve ge\u00e7en s\u00fcreyi form\u00fclde yerine yazal\u0131m ve ortalama olu\u015fma h\u0131z\u0131n\u0131 bulal\u0131m:<br><br>r<sub>XY<\/sub> = \u0394[XY] \/ \u0394t<br>r<sub>XY<\/sub> = 10 \/ 10<br>r<sub>XY<\/sub> = 1 M\/s<\/p>\n\n\n\n<p><em>Cevap:<br>a) r<sub>X2<\/sub> = 0,5 M\/s<br>b) r<sub>XY<\/sub> = 1 M\/s<\/em><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Tepkimenin_Ortalama_Hizi\">Tepkimenin Ortalama H\u0131z\u0131<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Tepkimedeki herhangi <strong><em>bir maddenin ortalama h\u0131z\u0131n\u0131, katsay\u0131s\u0131na b\u00f6lersek<\/em><\/strong>, tepkimenin ortalama h\u0131z\u0131n\u0131 bulmu\u015f oluruz.<\/li>\n\n\n\n<li>Bir tepkimenin ortalama h\u0131z\u0131na r<sub>ort<\/sub> dersek, form\u00fcl \u015f\u00f6yle olur:<\/li>\n<\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"300\" height=\"67\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkimenin-Ortalama-Hizi-.jpg\" alt=\"Tepkimenin Ortalama H\u0131z\u0131\" class=\"wp-image-5100\"\/><figcaption class=\"wp-element-caption\">Tepkimenin Ortalama H\u0131z\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<ul class=\"wp-block-list\">\n<li>Yani; bir tepkimenin h\u0131z\u0131, katsay\u0131s\u0131 1 olan maddenin h\u0131z\u0131 demektir.<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-7\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-text-align-center has-white-background-color has-background\"><strong>N<sub>2<\/sub> + 3H<sub>2<\/sub> \u2192&nbsp; 2NH<sub>3<\/sub><\/strong><\/p>\n\n\n\n<p>Yukar\u0131da verilen tepkime, 14,4 M H<sub>2<\/sub> gaz\u0131 ile ba\u015flam\u0131\u015ft\u0131r. Tepkime ba\u015flad\u0131ktan 20 saniye sonra, kaptaki H<sub>2<\/sub> gaz\u0131n\u0131n deri\u015fimi 2,4 M olarak \u00f6l\u00e7\u00fcl\u00fcyor.<\/p>\n\n\n\n<p><strong>Buna g\u00f6re, bu tepkimenin ilk 20 saniyedeki ortalama h\u0131z\u0131 ka\u00e7 M\/s&#8217;dir.<\/strong><\/p>\n\n\n\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-9d6595d7 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\" style=\"flex-basis:20%\">\n<p>A) 10<sup>-1<\/sup><\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\" style=\"flex-basis:20%\">\n<p>B) 2.10<sup>-1<\/sup><\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\" style=\"flex-basis:20%\">\n<p>C) 4.10<sup>-1<\/sup><\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\" style=\"flex-basis:20%\">\n<p>D) 6.10<sup>-1<\/sup><\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\" style=\"flex-basis:20%\">\n<p>E) 8.10<sup>-1<\/sup><\/p>\n<\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong>B<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#1e5a44\">Soruda, tepkimenin ortalama h\u0131z\u0131 soruluyor ve H<sub>2<\/sub> gaz\u0131n\u0131n 20 saniyelik s\u00fcre i\u00e7indeki ortalama h\u0131z\u0131n\u0131 (r<sub>H2<\/sub>) hesaplayabilecek bilgi veriliyor.<br><br>O zaman, H<sub>2<\/sub> gaz\u0131n\u0131n ortalama h\u0131z\u0131n\u0131, katsay\u0131s\u0131na b\u00f6lerek, tepkimenin ortalama h\u0131z\u0131n\u0131 bulabiliriz.<br><br>Tepkime denklemine bakarsak, H<sub>2<\/sub>&#8216;nin katsay\u0131s\u0131n\u0131n 3 oldu\u011funu g\u00f6rebiliriz. Bu durumda, tepkime i\u00e7in ortalama h\u0131z denklemi \u015f\u00f6yle olacakt\u0131r:<br><br><strong>r<sub>ort<\/sub> = r<sub>H2<\/sub> \/ 3<\/strong><br><br>Gelin, <strong>r<sub>H2<\/sub><\/strong> de\u011ferini bulal\u0131m:<br><br>Tepkimenin girenler taraf\u0131ndaki her maddede oldu\u011fu gibi H<sub>2<\/sub> elementinin de ortalama h\u0131z\u0131 \u015f\u00f6yle bulunur:<br><br><img loading=\"lazy\" decoding=\"async\" width=\"150\" height=\"60\" class=\"wp-image-5067\" style=\"width: 150px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkime-Hizi-Maddelerin-Hizi-2.jpg\" alt=\"H2'nin H\u0131z\u0131\"><br><br>Soruda, H2&#8217;nin deri\u015fiminin ba\u015flang\u0131\u00e7ta 2,4 M, sonu\u00e7ta ise 0,4 M oldu\u011fu s\u00f6ylenmi\u015f. O zaman \u0394[H<sub>2<\/sub>] de\u011ferini bulal\u0131m:<br>[H<sub>2<\/sub>]<sub>ilk<\/sub> = 14,4 M<br>[H<sub>2<\/sub>]<sub>son<\/sub> = 2,4 M<br>\u0394[H<sub>2<\/sub>] = [H<sub>2<\/sub>]<sub>son<\/sub> &#8211; [H<sub>2<\/sub>]<sub>ilk<\/sub><br>\u0394[H<sub>2<\/sub>] = 2,4 &#8211; 14,4<br>\u0394[H<sub>2<\/sub>] = -12M<br><br>Ge\u00e7en s\u00fcre de 20 saniye olarak verilmi\u015f. Yani:<br>\u0394t = 20 s<br><br>O zaman H<sub>2<\/sub>&#8216;nin ortalama h\u0131z\u0131 \u015f\u00f6yle hesaplan\u0131r:<br>r<sub>ort<\/sub> = &#8211; \u0394[H<sub>2<\/sub>] \/ \u0394t<br>r<sub>ort<\/sub> = &#8211; (-12 \/ 20) = 12 \/ 20<br>r<sub>ort<\/sub> = 3 \/ 5 = 0,6 =  6 x 10<sup>-1<\/sup> M\/s<br><br>Tepkimenin h\u0131z\u0131 soruldu\u011fu i\u00e7in, H<sub>2<\/sub>&#8216;nin h\u0131z\u0131n\u0131 kat say\u0131s\u0131na yani 3&#8217; b\u00f6lmeliyiz:<br>r<sub>tepkime<\/sub> = 6&#215;10<sup>-1<\/sup> \/ 3<br>r<sub>tepkime<\/sub> = 2&#215;10<sup>-1<\/sup><\/p>\n\n\n\n<p><em>Cevap: <\/em>B<\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Maddelerin_Farkli_Birimlerle_Hizini_Hesaplama\">Maddelerin Farkl\u0131 Birimlerle H\u0131z\u0131n\u0131 Hesaplama<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Ortalama h\u0131z hesaplan\u0131rken, molarite de\u011fi\u015fimi d\u0131\u015f\u0131nda \u015fu \u00f6zellikler de kullan\u0131labilir:\n<ul class=\"wp-block-list\">\n<li>mol say\u0131s\u0131 de\u011fi\u015fimi<\/li>\n\n\n\n<li>hacim de\u011fi\u015fimi<\/li>\n\n\n\n<li>k\u00fctle de\u011fi\u015fimi<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<ul class=\"wp-block-list\">\n<li>H\u0131z\u0131n nas\u0131l hesaplanaca\u011f\u0131n\u0131, sorunun sonunda sorulan h\u0131z birimine dikkat ederek, anlayabiliriz.<\/li>\n\n\n\n<li>Maddenin h\u0131z\u0131 a\u015fa\u011f\u0131daki birimlerde sorulabilir:\n<ul class=\"wp-block-list\">\n<li><strong>mol\/s veya mol.s<sup>-1<\/sup><\/strong> : Mol say\u0131s\u0131ndaki artma ya da azalmay\u0131 ge\u00e7en saniyeye b\u00f6lerek h\u0131z bulunacak.<\/li>\n\n\n\n<li><strong>mol\/dak veya mol.dak<sup>-1<\/sup><\/strong> : Mol say\u0131s\u0131ndaki artma ya da azalmay\u0131 ge\u00e7en dakikaya b\u00f6lerek h\u0131z bulunacak.<\/li>\n\n\n\n<li><strong>Litre\/s veya L.s<sup>-1<\/sup><\/strong> : Litre olarak hacimdeki artma ya azalmay\u0131 ge\u00e7en saniyeye b\u00f6lerek h\u0131z bulunacak.<\/li>\n\n\n\n<li>&#8230;<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-8\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-text-align-center has-white-background-color has-background\"><strong>2Na<sub>(k)<\/sub> + H<sub>2<\/sub>O<sub>(s)<\/sub> \u2192&nbsp; Na<sub>2<\/sub>O<sub>(k)<\/sub>  + H<sub>2(g)<\/sub><\/strong><\/p>\n\n\n\n<p>Yukar\u0131daki tepkime denklemine g\u00f6re; 100 saniyede, 4 mol Na kat\u0131s\u0131 t\u00fckenmektedir.<\/p>\n\n\n\n<p><strong>Buna g\u00f6re, ayn\u0131 s\u00fcre i\u00e7inde, H<sub>2<\/sub> gaz\u0131n\u0131n ortalama olu\u015fma h\u0131z\u0131 ka\u00e7 mol.s<sup>-1<\/sup>&#8216;dir<\/strong>?<\/p>\n\n\n\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-9d6595d7 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\" style=\"flex-basis:20%\">\n<p>A) 10<sup>-2<\/sup><\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\" style=\"flex-basis:20%\">\n<p>B) 2.10<sup>-2<\/sup><\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\" style=\"flex-basis:20%\">\n<p>C) 4.10<sup>-2<\/sup><\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\" style=\"flex-basis:20%\">\n<p>D) 6.10<sup>-2<\/sup><\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\" style=\"flex-basis:20%\">\n<p>E) 8.10<sup>-2<\/sup><\/p>\n<\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong>B<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#496676\">H2 gaz\u0131n\u0131n ortalama olu\u015fma h\u0131z\u0131;<br><strong>mol.s<sup>-1<\/sup><\/strong><br>biriminde sorulmu\u015f. Bu birimin anlam\u0131na g\u00f6re, h\u0131z\u0131, H<sub>2<\/sub> gaz\u0131n\u0131n mol say\u0131s\u0131ndaki de\u011fi\u015fimi ge\u00e7en saniyeye b\u00f6lerek bulmam\u0131z gerekiyor.<br><br>Tepkime denklemine bak\u0131l\u0131rsa, Na kat\u0131s\u0131 ile H<sub>2<\/sub> gaz\u0131n\u0131n katsay\u0131lar\u0131 oran\u0131 s\u0131ras\u0131 ile 2:1 olarak g\u00f6r\u00fcl\u00fcr. Buna g\u00f6re:<br><br><strong>4 mol Na kat\u0131s\u0131ndan 2 mol H<sub>2<\/sub> gaz\u0131 olu\u015fur.<br><\/strong><br>Demek ki, H<sub>2<\/sub> gaz\u0131n\u0131n mol say\u0131s\u0131ndaki art\u0131\u015f 2 mol, ge\u00e7en s\u00fcre de 100 saniyedir. O zaman H<sub>2<\/sub> gaz\u0131n\u0131n ortalama olu\u015fma h\u0131z\u0131 \u015f\u00f6yledir:<br><br><strong>r<sub>H2<\/sub> = 2 mol \/ 100 s = 2.10<sup>-2<\/sup> mol.s<sup>-1<\/sup><\/strong><\/p>\n\n\n\n<p><em>Cevap: B<\/em><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-9\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-text-align-left stcnnt-no-bordered-img\"><img loading=\"lazy\" decoding=\"async\" width=\"400\" height=\"305\" class=\"wp-image-11183\" style=\"width: 400px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Kimyasal-Tepkimelerde-Hiz-Soru-Cozumu-4.jpg\" alt=\"Kimyasal Tepkimelerde H\u0131z - Soru \u00c7\u00f6z\u00fcm\u00fc\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Kimyasal-Tepkimelerde-Hiz-Soru-Cozumu-4.jpg 397w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Kimyasal-Tepkimelerde-Hiz-Soru-Cozumu-4-300x229.jpg 300w\" sizes=\"auto, (max-width: 400px) 100vw, 400px\" \/><\/p>\n\n\n\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-9d6595d7 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\" style=\"flex-basis:20%\">\n<p>A) 1<\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\" style=\"flex-basis:20%\">\n<p>B) 2<\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\" style=\"flex-basis:20%\">\n<p>C) 3<\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\" style=\"flex-basis:20%\">\n<p>D) 4<\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\" style=\"flex-basis:20%\">\n<p>E) 5<\/p>\n<\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\">D<\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Soru bizden mol\/dak olarak h\u0131z isteniyor.<br>O zaman, grafi\u011fi verilen maddenin yani C<sub>2<\/sub>H<sub>4<\/sub> gaz\u0131n\u0131n, mol\/dakika olarak h\u0131z\u0131n\u0131 bulal\u0131m.<br>Katsay\u0131lardan CO<sub>2<\/sub> gaz\u0131na ge\u00e7elim.<\/p>\n\n\n\n<p>Grafi\u011fe bakarsak, 15 saniyede 14 gram C<sub>2<\/sub>H<sub>4<\/sub> gaz\u0131n\u0131n t\u00fckendi\u011fini g\u00f6r\u00fcr\u00fcz.<\/p>\n\n\n\n<p><strong>C<sub>2<\/sub>H<sub>4<\/sub> gaz\u0131n\u0131n mol say\u0131s\u0131:<br><\/strong>C<sub>2<\/sub>H<sub>4<\/sub> gaz\u0131n\u0131n mol a\u011f\u0131rl\u0131\u011f\u0131 (M<sub>A<\/sub>) de\u011feri: 2.12 + 4.1 = 28 g\/mol<br>Bu durumda 28 gram C<sub>2<\/sub>H<sub>4<\/sub> gaz\u0131 1 mold\u00fcr.<br>O zaman 14 gram C<sub>2<\/sub>H<sub>4<\/sub> gaz\u0131 0,5 mold\u00fcr.<\/p>\n\n\n\n<p><strong>C<sub>2<\/sub>H<sub>4<\/sub> gaz\u0131n\u0131n dakikas\u0131:<br><\/strong>60 saniye 1 dakika ise,<br>15 saniye 0,25 dakikad\u0131r.<\/p>\n\n\n\n<p><strong>C<sub>2<\/sub>H<sub>4<\/sub> ortalama h\u0131z\u0131:<br><\/strong>r<sub>ort<\/sub> = 0,5mol \/ 0,25dak = 2 mol\/dak<\/p>\n\n\n\n<p><strong>CO<sub>2<\/sub> gaz\u0131n\u0131n ortalama h\u0131z\u0131:<br><\/strong>Tepkime denklemine bakt\u0131\u011f\u0131m\u0131zda, CO<sub>2<\/sub> gaz\u0131n\u0131n katsay\u0131s\u0131, C<sub>2<\/sub>H<sub>4<\/sub> gaz\u0131ndan 2 kat daha b\u00fcy\u00fckt\u00fcr.<br>Bu y\u00fczden h\u0131z\u0131 da 2 kat daha b\u00fcy\u00fck olmal\u0131d\u0131r.<br>CO<sub>2<\/sub> gaz\u0131 i\u00e7in ortalama h\u0131z:<br><strong>r<sub>ort<\/sub> = 2&#215;2 = 4 mol\/dak<\/strong><\/p>\n\n\n\n<p><em>Cevap D \u015f\u0131kk\u0131d\u0131r.<br><\/em><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><span id=\"Tepkimedeki_Maddelerin_Hizlari_Arasindaki_Iliski\">Tepkimedeki Maddelerin H\u0131zlar\u0131 Aras\u0131ndaki \u0130li\u015fki<\/span><\/h2>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Bir kimyasal tepkimdeki her <strong><em>bir maddenin h\u0131z\u0131, katsay\u0131s\u0131 ile do\u011fru orant\u0131l\u0131d\u0131r<\/em><\/strong>.\n<ul class=\"wp-block-list\">\n<li>Yani katsay\u0131s\u0131 en b\u00fcy\u00fck olan maddenin h\u0131z\u0131, en b\u00fcy\u00fck; katsay\u0131s\u0131 en k\u00fc\u00e7\u00fck olan maddenin h\u0131z\u0131 ise en k\u00fc\u00e7\u00fckt\u00fcr.<\/li>\n\n\n\n<li>Tepkimedeki maddelerden birinin h\u0131z\u0131n\u0131 biliyorsak, katsay\u0131lar\u0131n oran\u0131n\u0131 kullanarak, di\u011fer maddelerin de h\u0131z\u0131n\u0131 bulabiliriz.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group has-background\" style=\"background-color:#f2fde8\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p><strong>UYARI!<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Katsay\u0131lar\u0131n oranlar\u0131:<\/strong>\n<ul class=\"wp-block-list\">\n<li><em><strong>K\u00fctle i\u00e7in kullan\u0131lmaz<\/strong><\/em>.<\/li>\n\n\n\n<li>Mol i\u00e7in kullan\u0131labilir.<\/li>\n\n\n\n<li>Gazlar\u0131n hacminde ve molaritesinde kullan\u0131labilir.<\/li>\n\n\n\n<li>Ayn\u0131 \u00e7\u00f6zeltide \u00e7\u00f6z\u00fcnm\u00fc\u015f maddelerin molaritesinde kullan\u0131labilir.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ogretici_Ornek-8\">\u00d6\u011fretici \u00d6rnek:<\/span><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>N<sub>2<\/sub> + 3H<sub>2<\/sub> \u2192&nbsp; 2NH<sub>3<\/sub><\/strong> tepkimesi ger\u00e7ekle\u015firken:\n<ul class=\"wp-block-list\">\n<li><strong>N<sub>2<\/sub><\/strong> nin ortalama harcanma h\u0131z\u0131 V ise<\/li>\n\n\n\n<li><strong>H<sub>2<\/sub><\/strong> nin ortalama harcanma h\u0131z\u0131 3V&#8217;dir,<\/li>\n\n\n\n<li><strong>NH<sub>3<\/sub><\/strong>&#8216;\u00fcn ortalama olu\u015fma h\u0131z\u0131 da 2V&#8217;dir.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/div><\/div>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Bir kimyasal tepkimedeki <strong><em>maddelerin h\u0131zlar\u0131n\u0131 birbirine e\u015fitlememiz gerekirse<\/em><\/strong>:\n<ul class=\"wp-block-list\">\n<li>Her maddenin h\u0131z\u0131n\u0131 katsay\u0131s\u0131na b\u00f6leriz. B\u00f6ylece, herkesin h\u0131z\u0131 e\u015fit olur.<\/li>\n\n\n\n<li>Veya katsay\u0131lar\u0131 payda e\u015fitler gibi e\u015fitleriz. Bu e\u015fitli\u011fi, h\u0131zlar aras\u0131ndaki e\u015fitlik olarak kullan\u0131l\u0131r\u0131z.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ogretici_Ornek-9\">\u00d6\u011fretici \u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-text-align-center\"><strong>N<sub>2<\/sub> + 3H<sub>2<\/sub> \u2192&nbsp; 2NH<sub>3<\/sub><\/strong><\/p>\n\n\n\n<p>Yukar\u0131da verilen tepkime denklemine g\u00f6re, tepkimedeki maddelerin h\u0131zlar\u0131 aras\u0131ndaki ili\u015fki \u015f\u00f6yledir:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"250\" height=\"73\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkimedeki-Maddelerin-Ortalama-Hizi-2.jpg\" alt=\"Tepkimedeki Maddelerin H\u0131zlar\u0131 Aras\u0131ndaki \u0130li\u015fki\" class=\"wp-image-5106\"\/><figcaption class=\"wp-element-caption\">Tepkimedeki Maddelerin H\u0131zlar\u0131 Aras\u0131ndaki \u0130li\u015fki<\/figcaption><\/figure>\n<\/div>\n\n\n<ul class=\"wp-block-list\">\n<li>Yukar\u0131daki e\u015fitlikte, girenlerdeki maddelerin h\u0131z\u0131n\u0131n \u00f6n\u00fcne, &#8220;eksi&#8221; i\u015fareti koymay\u0131 unutmad\u0131k. Eksi i\u015fareti bize, maddelerin harcand\u0131\u011f\u0131n\u0131 s\u00f6yler.<\/li>\n\n\n\n<li>Yukar\u0131daki e\u015fitlik 6 ile geni\u015fletilirse, a\u015fa\u011f\u0131daki e\u015fitlik elde edilir. Yani, dilersek, yukar\u0131daki e\u015fitli\u011fi \u015f\u00f6yle de ifade edebiliriz:<\/li>\n<\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"300\" height=\"49\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkimedeki-Maddelerin-Ortalama-Hizi.jpg\" alt=\"Tepkimedeki Maddeler Aras\u0131ndaki \u0130li\u015fki\" class=\"wp-image-5110\"\/><figcaption class=\"wp-element-caption\">Tepkimedeki Maddeler Aras\u0131ndaki \u0130li\u015fki<\/figcaption><\/figure>\n<\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h3 class=\"wp-block-heading\"><span id=\"Ornek-10\">\u00d6rnek:<\/span><\/h3>\n\n\n\n<p class=\"has-text-align-center has-white-background-color has-background\"><strong>4NO<sub>2<\/sub> + O<sub>2<\/sub> \u2192&nbsp; 2N<sub>2<\/sub>O<sub>5<\/sub><\/strong><\/p>\n\n\n\n<p>tepkimesinde, O<sub>2<\/sub>&#8216;nin ortalama harcanma h\u0131z\u0131 0,024 mol\/L.s&#8217;dir. Buna g\u00f6re;<\/p>\n\n\n\n<p><strong>a) NO<sub>2<\/sub>&#8216;nin ortalama harcanma h\u0131z\u0131n\u0131 hesaplay\u0131n\u0131z.<br>b) N<sub>2<\/sub>O<sub>5<\/sub>&#8216;in ortalama olu\u015fma h\u0131z\u0131n\u0131 hesaplay\u0131n\u0131z.<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong>a) 0,096 mol\/L.s<br>b) 0,048 mol\/L.s<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#035385\">Tepkimedeki maddelerin h\u0131zlar\u0131 aras\u0131nda bir e\u015fitlik kurabiliriz. Bunun i\u00e7in, her maddenin ortalama h\u0131z\u0131n\u0131 katsay\u0131s\u0131na b\u00f6lmek yeterli olacakt\u0131r.<br><br>Bu tepkimede; NO<sub>2<\/sub> (Azot dioksit), O<sub>2<\/sub> (Oksijen) ve N<sub>2<\/sub>O<sub>5<\/sub> (Diazot pentaoksit)  maddelerinin ortalama h\u0131zlar\u0131 a\u015fa\u011f\u0131daki e\u015fitlik \u015f\u00f6yledir:<br><br><img loading=\"lazy\" decoding=\"async\" width=\"250\" height=\"70\" class=\"wp-image-5117\" style=\"width: 250px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkimedeki-Maddelerin-Ortalama-Hiz-Iliskisi.jpg\" alt=\"Tepkimedeki Maddelerin H\u0131zlar\u0131 Aras\u0131ndaki \u0130li\u015fki\"><br><br><strong>a)<\/strong><br><br><strong>-r<sub>NO2<\/sub> (NO2&#8217;nin harcanma h\u0131z\u0131)&#8217;n\u0131n hesaplanmas\u0131<br><\/strong><br>O<sub>2<\/sub>&#8216;nin ortalama harcanma h\u0131z\u0131, 0,024 M\/s olarak verilmi\u015ftir, yani <strong>-r<sub>O2<\/sub><\/strong> biliniyor. O<sub>2<\/sub> ve NO<sub>2 <\/sub>maddelerin ortalama h\u0131zlar\u0131 aras\u0131ndaki ili\u015fki \u015f\u00f6yledir:<br><br><img loading=\"lazy\" decoding=\"async\" width=\"150\" height=\"66\" class=\"wp-image-5118\" style=\"width: 150px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkimedeki-Maddelerin-Ortalama-Hiz-Iliskisi-.jpg\" alt=\"Tepkimedeki Maddelerin H\u0131zlar\u0131 Aras\u0131ndaki \u0130li\u015fki\"><br><br>E\u015fitlikte, i\u00e7ler d\u0131\u015flar \u00e7arp\u0131m\u0131 yaparsak:<br><br><strong>-r<sub>NO2<\/sub> = 4 . -r<sub>O2<\/sub><\/strong><br><br>e\u015fitli\u011fini elde ederiz. Bu e\u015fitlikte, O<sub>2<\/sub>&#8216;nin ortalama harcanma h\u0131z\u0131n\u0131 yerine yazal\u0131m ve NO<sub>2<\/sub>&#8216;nin harcanma h\u0131z\u0131n\u0131 bulal\u0131m:<br><br><strong>-r<sub>NO2<\/sub> = 4 . 0,024<\/strong><br><strong>-r<sub>NO2<\/sub> = 0,096 M\/s veya 0,096 mol\/L.s<\/strong><br><br>olarak bulunur.<br><br><br><strong>b)<\/strong><br><br><strong>r<sub>N2O5<\/sub><strong>  (N<sub>2<\/sub>O<sub>5<\/sub>&#8216;in olu\u015fma h\u0131z\u0131)&#8217;n\u0131n hesaplanmas\u0131<\/strong><\/strong><br><br>O<sub>2<\/sub>&#8216;nin ortalama harcanma h\u0131z\u0131 (-r<sub>O2<\/sub>), 0,024 M\/s olarak verildi\u011fi i\u00e7in, bu de\u011fer yad\u0131m\u0131 ile N2O5&#8217;nin ortalama olu\u015fma h\u0131z\u0131n\u0131 bulabiliriz. O<sub>2<\/sub> ve N<sub>2<\/sub>O<sub>5<\/sub> maddelerin ortalama h\u0131zlar\u0131 aras\u0131ndaki ili\u015fki \u015f\u00f6yledir:<br><br><img loading=\"lazy\" decoding=\"async\" width=\"150\" height=\"61\" class=\"wp-image-5121\" style=\"width: 150px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/12\/Tepkimedeki-Maddelerin-Ortalama-Hiz-Iliskisi-Soru-.jpg\" alt=\"Tepkime H\u0131z\u0131 Soru \u00c7\u00f6z\u00fcm\u00fc\"><br><br>E\u015fitlikte, i\u00e7ler d\u0131\u015flar \u00e7arp\u0131m\u0131 yaparsak:<br><br><strong>2 . (-r<sub>O2<\/sub>) = r<sub>N2O5<\/sub><\/strong><br><br>e\u015fitli\u011fini elde ederiz. Bu e\u015fitlikte, O<sub>2<\/sub>&#8216;nin ortalama harcanma h\u0131z\u0131n\u0131 yerine yazal\u0131m ve NO<sub>2<\/sub>&#8216;nin harcanma h\u0131z\u0131n\u0131 bulal\u0131m:<br><br><strong><strong>2 . (0,024) = r<sub>N2O5<\/sub><\/strong><\/strong><br><strong><strong><strong>r<sub>N2O5<\/sub><\/strong><\/strong> = 0,048 M\/s veya 0,048 mol\/L.s<\/strong><br><br>olarak bulunur.<\/p>\n\n\n\n<p><em>Cevap:<br>a) 0,096 mol\/L.s<br>b) 0,048 mol\/L.s<\/em><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group has-background\" style=\"background-color:#edffe0\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h3 class=\"wp-block-heading\"><span id=\"Tepkimelerdeki_Maddelerin_Anlik_Hizlari\">Tepkimelerdeki Maddelerin Anl\u0131k H\u0131zlar\u0131<\/span><\/h3>\n\n\n\n<p class=\"has-text-align-left\">&#8220;Anl\u0131k H\u0131z&#8221; kavram\u0131, AYT kimyas\u0131ndan \u00e7\u0131kar\u0131lm\u0131\u015ft\u0131r. Fakat, baz\u0131 testlerde kar\u015f\u0131m\u0131za \u00e7\u0131karsa \u015fa\u015f\u0131rmamak i\u00e7in, k\u0131saca bilmekte fayda vard\u0131r.<\/p>\n\n\n\n<p>Ortalama h\u0131z i\u00e7in, belli bir zaman aral\u0131\u011f\u0131ndaki h\u0131zlar\u0131n ortalamas\u0131d\u0131r, demi\u015ftik. Anl\u0131k h\u0131z ise; belli bir andaki h\u0131zd\u0131r.<\/p>\n\n\n\n<p>Bir tepkimenin h\u0131z\u0131, farkl\u0131 anlarda farkl\u0131 de\u011ferler alabilir. Genellikle, tepkimeler h\u0131zl\u0131 bir \u015fekilde ba\u015flarlar, zamanla yava\u015flarlar. Belli bir s\u00fcre sonra da, tepkime ya biter, ya da dengeye ula\u015f\u0131r. Bir tepkimenin dengeye ula\u015fmas\u0131n\u0131n ne demek oldu\u011fundan bir sonraki \u00fcnitede bahsedece\u011fiz.<\/p>\n\n\n\n<p>Bir maddenin anl\u0131k h\u0131z\u0131n\u0131 hesaplamak i\u00e7in, bu maddenin, <em>h\u0131z-zaman<\/em> grafi\u011fine ihtiyac\u0131m\u0131z vard\u0131r. H\u0131z-zaman grafi\u011finde, hangi andaki h\u0131z\u0131 merak ediyorsak, o andaki h\u0131z de\u011ferine bir te\u011fet \u00e7izmeliyiz. \u00c7izdi\u011fimiz te\u011fetin e\u011fimi, bize o maddenin o andaki h\u0131z\u0131n\u0131 verecektir.<\/p>\n<\/div><\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><span id=\"Homojen_ve_Heterojen_Faz_Tepkimeleri\">Homojen ve Heterojen Faz Tepkimeleri<\/span><\/h2>\n\n\n\n<p>Tepkimeler, girenlerin ve \u00fcr\u00fcnlerin fiziksel hallerine g\u00f6re ikiye ayr\u0131l\u0131r:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>Homojen Faz Tepkimeleri<\/li>\n\n\n\n<li>Heterojen Faz Tepkimeleri<\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"I_Homojen_Faz_Tepkimeleri\">I. Homojen Faz Tepkimeleri<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Tepkimedeki <strong><em>\u00fcr\u00fcnler ve girenler hep birlikte homojen bir kar\u0131\u015f\u0131m olu\u015fturuyorlar<\/em><\/strong> ise; tepkime bir homojen faz tepkimesidir.<\/li>\n\n\n\n<li>Gazlar, her zaman homojen kar\u0131\u015f\u0131rlar, bu y\u00fczden, tamamen gazlardan olu\u015fan tepkimeler homojen faz tepkimeleridir:\n<ul class=\"wp-block-list\">\n<li>CH<sub>4(g)<\/sub>&nbsp;+ 2O<sub>2(g)<\/sub>&nbsp;<strong>\u2192&nbsp;<\/strong>&nbsp;CO<sub>2(g)<\/sub>&nbsp;+ 2H<sub>2<\/sub>O<sub>(g)<\/sub>&nbsp;<\/li>\n\n\n\n<li>N<sub>2(g)<\/sub> + 3H<sub>2(g)<\/sub> \u2192&nbsp; 2NH<sub>3(g)<\/sub><\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Tepkimedeki b\u00fct\u00fcn maddeler suda \u00e7\u00f6z\u00fcnm\u00fc\u015f halde ise, tepkime bir homojen faz tepkimesidir. (Tepkimede H<sub>2<\/sub>O<sub>(s)<\/sub>&#8216;n\u0131n olmas\u0131, bu t\u00fcr tepkimelerin homojen olmas\u0131na engel de\u011fildir):\n<ul class=\"wp-block-list\">\n<li>HCl<sub>(suda)<\/sub>&nbsp;+ NaOH<sub>(suda)<\/sub>&nbsp;<strong>\u2192&nbsp;<\/strong>&nbsp;NaCl<sub>(suda)<\/sub>&nbsp;+ 2H<sub>2<\/sub>O<sub>(s)<\/sub>&nbsp;<\/li>\n\n\n\n<li>Fe<sup>3+<\/sup><sub>(suda)<\/sub> + SCN<sup>&#8211;<\/sup><sub>(suda)<\/sub> \u2192&nbsp; FeSCN<sup>2+<\/sup><sub>(suda)<\/sub><\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"II_Heterojen_Faz_Tepkimeleri\">II. Heterojen Faz Tepkimeleri<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Tepkimedeki <strong><em>\u00fcr\u00fcnler ve girenler hep birlikte heterojen bir kar\u0131\u015f\u0131m olu\u015fturuyorlar ise<\/em><\/strong>; tepkime bir heterojen faz tepkimesidir.<\/li>\n\n\n\n<li>Tepkimede; farkl\u0131 fazlarda maddeler varsa, bu tepkimler heterojen tepkimelerdir:\n<ul class=\"wp-block-list\">\n<li>Ca<sub>(k)<\/sub> + HCl<sub>(suda)<\/sub> \u2192&nbsp; CaCl<sub>2(suda)<\/sub> + H<sub>2(g)<\/sub><\/li>\n\n\n\n<li>Ag<sup>+<\/sup><sub>(suda)<\/sub> + Cl<sup>&#8211;<\/sup><sub>(suda)<\/sub> \u2192&nbsp; AgCl<sub>(k)<\/sub><\/li>\n\n\n\n<li>Na<sub>2<\/sub>O<sub>(k)<\/sub> + H<sub>2<\/sub>O<sub>(s)<\/sub> \u2192&nbsp; 2NaOH<sub>(suda)<\/sub><\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<p><\/p>\n","protected":false},"excerpt":{"rendered":"<p>&#8220;Tepkime H\u0131zlar\u0131&#8221; dersi, bir AYT konusu olan &#8220;Kimyasal Tepkimelerde H\u0131z&#8221; \u00fcnitesinin ilk b\u00f6l\u00fcm\u00fcd\u00fcr. Bu derste, &#8220;Tepkime H\u0131zlar&#8221; konusu, basit ve anla\u015f\u0131l\u0131r bir dille anlat\u0131lm\u0131\u015ft\u0131r.<\/p>\n","protected":false},"author":1,"featured_media":5023,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[163],"tags":[165],"class_list":["post-5022","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-kimyasal-tepkimelerde-hiz","tag-tepkime-hizlari"],"_links":{"self":[{"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/posts\/5022","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/comments?post=5022"}],"version-history":[{"count":3,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/posts\/5022\/revisions"}],"predecessor-version":[{"id":31126,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/posts\/5022\/revisions\/31126"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/media\/5023"}],"wp:attachment":[{"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/media?parent=5022"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/categories?post=5022"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/tags?post=5022"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}