{"id":3402,"date":"2020-10-31T02:11:40","date_gmt":"2020-10-30T23:11:40","guid":{"rendered":"https:\/\/sitecenneti.com\/kimya\/?p=3402"},"modified":"2025-01-07T21:03:29","modified_gmt":"2025-01-07T18:03:29","slug":"kimyasal-tepkimelerde-hesaplamalar","status":"publish","type":"post","link":"https:\/\/sitecenneti.com\/kimya\/tyt-kimya\/kimyanin-temel-kanunlari-ve-kimyasal-hesaplamalar\/kimyasal-tepkimelerde-hesaplamalar\/","title":{"rendered":"4. Kimyasal Tepkimelerde Hesaplamalar"},"content":{"rendered":"<div id=\"toc_container\" class=\"toc_transparent no_bullets\"><p class=\"toc_title\">\u0130&ccedil;indekiler<\/p><ul class=\"toc_list\"><li><a href=\"#Kimyasal_Hesaplamalar\">Kimyasal Hesaplamalar<\/a><ul><li><a href=\"#Kimyasal_Hesaplamalarda_Katsayilarin_Anlami\">Kimyasal Hesaplamalarda Katsay\u0131lar\u0131n Anlam\u0131<\/a><ul><li><a href=\"#Ogretici_Ornek\">\u00d6\u011fretici \u00d6rnek:<\/a><\/li><li><a href=\"#Ogretici_Ornek-2\">\u00d6\u011fretici \u00d6rnek:<\/a><\/li><li><a href=\"#Ogretici_Ornek-3\">\u00d6\u011fretici \u00d6rnek:<\/a><\/li><li><a href=\"#Ornek\">\u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#Katsayilar_Mutlaka_Olmali\">Katsay\u0131lar Mutlaka Olmal\u0131<\/a><ul><li><a href=\"#Ornek-2\">\u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#Katsayilari_Dogru_Kullanmak\">Katsay\u0131lar\u0131 Do\u011fru Kullanmak<\/a><ul><li><a href=\"#Ornek-3\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-4\">\u00d6rnek:<\/a><\/li><\/ul><\/li><\/ul><\/li><li><a href=\"#Soru_Tipleri\">Soru Tipleri<\/a><ul><li><a href=\"#1_Bir_Maddenin_Miktari_Verilir_Digeri_Sorulursa\">1. Bir Maddenin Miktar\u0131 Verilir Di\u011feri Sorulursa<\/a><ul><li><a href=\"#Ornek-5\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-6\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-7\">\u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#2_Karisim_Sorulari\">2. Kar\u0131\u015f\u0131m Sorular\u0131<\/a><ul><li><a href=\"#Ornek-8\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-9\">\u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#3_Mol_Agirligi_MA_Sorulari\">3. Mol A\u011f\u0131rl\u0131\u011f\u0131 (MA) Sorular\u0131<\/a><ul><li><a href=\"#Ornek-10\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-11\">\u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#4_Bilesik_Formulu_Bulma_Sorulari\">4. Bile\u015fik Form\u00fcl\u00fc Bulma Sorular\u0131<\/a><ul><li><a href=\"#Ornek-12\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-13\">\u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#5_Sinirlayici_Reaktif_Artan_Madde_Sorulari\">5. S\u0131n\u0131rlay\u0131c\u0131 Reaktif (Artan Madde) Sorular\u0131<\/a><ul><li><a href=\"#Ornek-14\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-15\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-16\">\u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#6_Yuzde_Verim_Sorulari\">6. Y\u00fczde Verim Sorular\u0131<\/a><ul><li><a href=\"#Ornek-17\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-18\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-19\">\u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#7_Saf_Olmayan_Madde_Sorulari\">7. Saf Olmayan Madde Sorular\u0131<\/a><ul><li><a href=\"#Ornek-20\">\u00d6rnek:<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/div>\n\n<ul class=\"wp-block-list\">\n<li><em><strong>Kimyasal Tepkimelerde Hesaplamalar<\/strong><\/em> dersi, bize, bir kimyasal tepkime denklemine bakarak, nas\u0131l hesap yapabilece\u011fimizi \u00f6\u011fretir.<\/li>\n\n\n\n<li>Bu konu, i\u00e7inde hesaplama bulunan b\u00fct\u00fcn kimya \u00fcnitelerinde kar\u015f\u0131m\u0131za \u00e7\u0131kacakt\u0131r. Bu y\u00fczden, \u00f6zellikle say\u0131sal d\u00fc\u015f\u00fcnen \u00f6\u011frencilerin dikkat etmesi gereken \u00f6nemli bir konudur.<\/li>\n\n\n\n<li>Bu dersin anla\u015f\u0131lmas\u0131 i\u00e7in; <em><strong>Mol Kavram\u0131<\/strong><\/em> ve <em><strong>Kimyasal Tepkime Denklemlerinin Denkle\u015ftirilmesi<\/strong><\/em> konusunun anla\u015f\u0131lm\u0131\u015f olmas\u0131 gerekir.<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group has-background\" style=\"background-color:#f2fefa\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p><em>Mol Kavram\u0131 <\/em>ve <em>Kimyasal Tepkime Denklemlerinin Denkle\u015ftirilmesi<\/em> ile ilgili bir sorun ya\u015f\u0131yorsan\u0131z, a\u015fa\u011f\u0131daki derslere t\u0131klayarak, eksi\u011finizi giderebilirsiniz:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><a href=\"https:\/\/sitecenneti.com\/kimya\/tyt-kimya\/kimyanin-temel-kanunlari-ve-kimyasal-hesaplamalar\/mol-kavrami\/\" target=\"_blank\" rel=\"noreferrer noopener\">Mol Kavram\u0131<\/a><\/li>\n\n\n\n<li><a href=\"https:\/\/sitecenneti.com\/kimya\/tyt-kimya\/kimyanin-temel-kanunlari-ve-kimyasal-hesaplamalar\/kimyasal-tepkimeler-ve-denklemler\/#Kimyasal_Tepkime_Denklemlerinin_Denklestirilmesi\">Kimyasal Tepkime Denklemlerinin Denkle\u015ftirilmesi<\/a><\/li>\n<\/ul>\n<\/div><\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><span id=\"Kimyasal_Hesaplamalar\">Kimyasal Hesaplamalar<\/span><\/h2>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Kimyasal hesaplamalar, tepkimelerdeki maddelerin;\n<ul class=\"wp-block-list\">\n<li>mol say\u0131lar\u0131n\u0131<\/li>\n\n\n\n<li>kimyasal t\u00fcrlerinin say\u0131s\u0131n\u0131<\/li>\n\n\n\n<li>k\u00fctlelerini<\/li>\n\n\n\n<li>hacimlerini hesaplama i\u015flemidir.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Kimyasal tepkimelerde, bu \u00f6zellikleri hesaplarken, daha \u00e7ok &#8220;mol kavram\u0131&#8221; kurallar\u0131ndan yararlan\u0131r\u0131z.<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group stcnnt-yazi-ici-reklam\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p>Bu bir reklamd\u0131r:<\/p>\n\n\n\n<script async=\"\" src=\"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\"><\/script>\n<ins class=\"adsbygoogle\" style=\"display:block; text-align:center;\" data-ad-layout=\"in-article\" data-ad-format=\"fluid\" data-ad-client=\"ca-pub-6366953309324763\" data-ad-slot=\"9738116384\"><\/ins>\n<script>\n     (adsbygoogle = window.adsbygoogle || []).push({});\n<\/script>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Kimyasal_Hesaplamalarda_Katsayilarin_Anlami\">Kimyasal Hesaplamalarda Katsay\u0131lar\u0131n Anlam\u0131<\/span><\/h3>\n\n\n\n<p>Kimyasal tepkimelerde hesaplama yaparken, tepkime denklemindeki katsay\u0131lar\u0131ndan \u015f\u00f6yle yararlan\u0131l\u0131r:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong><em>Kimyasal tepkimelerde katsay\u0131lar\u0131n oran\u0131; maddelerin mol say\u0131lar\u0131 aras\u0131ndaki oran\u0131 verir.<\/em><\/strong><\/li>\n<\/ol>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ogretici_Ornek\">\u00d6\u011fretici \u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-text-align-center\"><strong>4A&nbsp;+ 2B&nbsp;\u2192&nbsp;3C<\/strong><\/p>\n\n\n\n<p class=\"has-text-align-left\">Yukar\u0131daki tepkimenin katsay\u0131lar\u0131na bakarak \u015funlar\u0131 s\u00f6yleyebiliriz:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong><em>4 mol A<\/em><\/strong> maddesi ile <strong><em>2 mol B<\/em><\/strong> maddesi tepkimeye girer ve <strong><em>3 mol C<\/em><\/strong> olu\u015fur.<\/li>\n\n\n\n<li><strong><em>8 mol A<\/em><\/strong> maddesi ile <strong><em>4 mol B<\/em><\/strong> maddesi tepkimeye girer ve <strong><em>6 mol C<\/em><\/strong> olu\u015fur.<\/li>\n\n\n\n<li><strong><em>12 mol A<\/em><\/strong> maddesi ile <strong><em>6 mol B<\/em><\/strong> maddesi tepkimeye girer ve <strong><em>9 mol C<\/em><\/strong> maddesi olu\u015fur.<\/li>\n\n\n\n<li>&#8230;<\/li>\n<\/ul>\n<\/div><\/div>\n\n\n\n<ol start=\"2\" class=\"wp-block-list\">\n<li><strong><em>Kimyasal tepkimelerde katsay\u0131lar\u0131n oran\u0131; maddelerin kimyasal t\u00fcrlerinin say\u0131lar\u0131 aras\u0131ndaki oran\u0131 verir.<\/em><\/strong><\/li>\n<\/ol>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ogretici_Ornek-2\">\u00d6\u011fretici \u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-text-align-center\"><strong>4A&nbsp;+ 2B&nbsp;\u2192&nbsp;3C<\/strong><\/p>\n\n\n\n<p>Yukar\u0131daki tepkimenin katsay\u0131lar\u0131na bakarak \u015funlar\u0131 s\u00f6yleyebiliriz:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong><em>4 tane A<\/em><\/strong> ile <strong><em>2 tane B<\/em><\/strong> tepkimeye girer ve <strong><em>3 tane C<\/em><\/strong> olu\u015fur.<\/li>\n\n\n\n<li><strong><em>8 tane A<\/em><\/strong> ile <strong><em>4 tane B<\/em><\/strong> tepkimeye girer ve <strong><em>6 tane C<\/em><\/strong> olu\u015fur.<\/li>\n\n\n\n<li><strong><em>12 tane A<\/em><\/strong> ile <strong><em>6 tane B<\/em><\/strong> tepkimeye girer ve <strong><em>9 tane C<\/em><\/strong> olu\u015fur.<\/li>\n\n\n\n<li>&#8230;<\/li>\n<\/ul>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group stcnnt-yazi-ici-reklam\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p>Bu bir reklamd\u0131r:<\/p>\n\n\n\n<script async=\"\" src=\"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\"><\/script>\n<ins class=\"adsbygoogle\" style=\"display:block; text-align:center;\" data-ad-layout=\"in-article\" data-ad-format=\"fluid\" data-ad-client=\"ca-pub-6366953309324763\" data-ad-slot=\"9738116384\"><\/ins>\n<script>\n     (adsbygoogle = window.adsbygoogle || []).push({});\n<\/script>\n<\/div><\/div>\n\n\n\n<ol start=\"3\" class=\"wp-block-list\">\n<li><strong><em>Kimyasal tepkimelerde katsay\u0131lar\u0131n oran\u0131; ayn\u0131 ko\u015fullardaki gazlar\u0131n hacimleri aras\u0131ndaki oran\u0131 verir.<\/em><\/strong><\/li>\n<\/ol>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ogretici_Ornek-3\">\u00d6\u011fretici \u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-text-align-center\"><strong>4A<sub>(g)<\/sub>&nbsp;+ 2B<sub>(g)<\/sub>&nbsp;\u2192&nbsp;3C<sub>(g)<\/sub><\/strong><\/p>\n\n\n\n<p>Yukar\u0131daki tepkimenin katsay\u0131lar\u0131na bakarak \u015funlar\u0131 s\u00f6yleyebiliriz:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong><em>4 Litre A<\/em><\/strong> gaz\u0131 ile <strong><em>2 Litre B<\/em><\/strong> gaz\u0131 tepkimeye girer ve <strong><em>3 Litre C<\/em><\/strong> gaz\u0131 olu\u015fur.<\/li>\n\n\n\n<li><strong><em>8 Litre A<\/em><\/strong> gaz\u0131 ile <strong><em>4 Litre B<\/em><\/strong> gaz\u0131 tepkimeye girer ve <strong><em>6 Litre C<\/em><\/strong> gaz\u0131 olu\u015fur.<\/li>\n\n\n\n<li><strong><em>12 Litre A<\/em><\/strong> gaz\u0131 ile <strong><em>6 Litre B<\/em><\/strong> gaz\u0131 tepkimeye girer ve <strong><em>9 Litre C<\/em><\/strong> gaz\u0131 olu\u015fur.<\/li>\n\n\n\n<li>&#8230;<\/li>\n<\/ul>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group stcnnt-yazi-ici-reklam\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p>Bu bir reklamd\u0131r:<\/p>\n\n\n\n<script async=\"\" src=\"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\"><\/script>\n<ins class=\"adsbygoogle\" style=\"display:block; text-align:center;\" data-ad-layout=\"in-article\" data-ad-format=\"fluid\" data-ad-client=\"ca-pub-6366953309324763\" data-ad-slot=\"9738116384\"><\/ins>\n<script>\n     (adsbygoogle = window.adsbygoogle || []).push({});\n<\/script>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-text-align-center has-white-background-color has-background\" style=\"font-size:18px\">3H<sub>2<\/sub>&nbsp;+ N<sub>2<\/sub>&nbsp;\u2192&nbsp;2NH<sub>3<\/sub><\/p>\n\n\n\n<p><strong>Yukar\u0131daki tepkimeye g\u00f6re, 6 mol H<sub>2<\/sub> (Hidrojen) ka\u00e7 mol N<sub>2<\/sub> (Azot) ile tepkime verir?<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong><em>2 mol N<sub>2<\/sub><\/em><\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Tepkimede, H<sub>2<\/sub> elementinin katsay\u0131s\u0131 3, N<sub>2<\/sub> elementinin katsay\u0131s\u0131 g\u00f6r\u00fcnmedi\u011fine g\u00f6re 1 olmal\u0131d\u0131r. Bu durumda bu iki katsay\u0131 bize \u015funu demeye \u00e7al\u0131\u015f\u0131r:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#891532;font-size:18px\"><strong>3 mol<\/strong> H<sub>2<\/sub> ile <strong>1 mol<\/strong> N<sub>2<\/sub> tepkimeye girer.<\/p>\n\n\n\n<p>Demek ki; H<sub>2<\/sub> ile N<sub>2<\/sub> aras\u0131ndaki mol oran\u0131 buymu\u015f. Oran belliyse \u015fu orant\u0131 bizi, cevaba g\u00f6t\u00fcr\u00fcr:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#891532;font-size:18px\">Orant\u0131:<br><br><strong>3 mol<\/strong> H<sub>2<\/sub> ile <strong>1 mol<\/strong> N<sub>2<\/sub> tepkimeye girerse<br><strong>6 mol<\/strong> H<sub>2<\/sub> ile <strong>n mol<\/strong> N<sub>2<\/sub> tepkimeye girer<br><br>Bu bir do\u011fru orant\u0131d\u0131r. Do\u011fru orant\u0131n\u0131n e\u015fitli\u011fini kurarsak, n de\u011ferini buluruz:<br>3 . n = 6 . 1<br>n = 6 \/ 3<br>n = 2 mol<\/p>\n\n\n\n<p><em>Cevap: 2 mol N<sub>2<\/sub><\/em><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Katsayilar_Mutlaka_Olmali\">Katsay\u0131lar Mutlaka Olmal\u0131<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Kimyasal hesab\u0131n temelinde, tepkimedeki <strong><em>katsay\u0131lar <\/em><\/strong>yatar dedik.<\/li>\n\n\n\n<li>Demek ki, bir kimyasal tepkime ile ilgili hesap yapabilmek i\u00e7in, \u00f6ncelikle, tepkimedeki maddelerin <strong><em>katsay\u0131lar\u0131na <\/em><\/strong>bakmam\u0131z gerekiyor.<\/li>\n\n\n\n<li>Tepkimelerin katsay\u0131lar\u0131, ancak, tepkime <strong><em>denkle\u015ftirilmi\u015fse <\/em><\/strong>bellidir.<\/li>\n\n\n\n<li>Bu durumda, bir kimyasal tepkime denk de\u011filse, hesap yapmaya ba\u015flamadan \u00f6nce tepkimeyi <strong><em>denkle\u015ftirmemiz gerekir<\/em><\/strong>.<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group stcnnt-yazi-ici-reklam\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p>Bu bir reklamd\u0131r:<\/p>\n\n\n\n<script async=\"\" src=\"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\"><\/script>\n<ins class=\"adsbygoogle\" style=\"display:block; text-align:center;\" data-ad-layout=\"in-article\" data-ad-format=\"fluid\" data-ad-client=\"ca-pub-6366953309324763\" data-ad-slot=\"9738116384\"><\/ins>\n<script>\n     (adsbygoogle = window.adsbygoogle || []).push({});\n<\/script>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-2\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#6c6f71;font-size:18px\">H<sub>2<\/sub>&nbsp;+ N<sub>2<\/sub>&nbsp;\u2192&nbsp;NH<sub>3<\/sub><\/p>\n\n\n\n<p><strong>Yukar\u0131daki tepkimeye g\u00f6re, 8 mol NH<sub>3<\/sub> (Amonyak) olu\u015fmas\u0131 i\u00e7in ka\u00e7 mol H<sub>2<\/sub> (Hidrojen) kullan\u0131lmal\u0131d\u0131r?<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong>12 mol H<sub>2<\/sub><\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Verilen tepkime denkleminde katsay\u0131 g\u00f6remiyoruz. Demek ki tepkime denkle\u015ftirilmemi\u015f. Bu y\u00fczden, \u00f6nce tepkimeyi denkle\u015ftirmemiz gerekiyor. A\u015fa\u011f\u0131da, denklemin denkle\u015fmi\u015f hali verilmi\u015ftir:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#6c6f71;font-size:18px\">3H<sub>2<\/sub>&nbsp;+ N<sub>2<\/sub>&nbsp;\u2192&nbsp;2NH<sub>3<\/sub><\/p>\n\n\n\n<p>Bu tepkimeyi nas\u0131l denkle\u015ftirdi\u011fimizi \u00f6\u011frenmek i\u00e7in, \u015fu <a href=\"https:\/\/sitecenneti.com\/kimya\/tyt-kimya\/kimyanin-temel-kanunlari-ve-kimyasal-hesaplamalar\/kimyasal-tepkimeler-ve-denklemler\/#Ornek-5\" target=\"_blank\" rel=\"noreferrer noopener\">\u00f6rne\u011fe t\u0131klay\u0131n\u0131z.<\/a><\/p>\n\n\n\n<p>Denkle\u015fmi\u015f tepkimede, H<sub>2<\/sub> elementinin katsay\u0131s\u0131 3, NH<sub>3<\/sub> bile\u015fi\u011finin katsay\u0131s\u0131 2&#8217;dir. Bu durumda bu iki katsay\u0131 bize \u015funu demeye \u00e7al\u0131\u015f\u0131r:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#891532;font-size:18px\"><strong>3 mol<\/strong> H<sub>2<\/sub> den <strong>2 mol<\/strong> NH<sub>3<\/sub> olu\u015fur.<\/p>\n\n\n\n<p>Demek ki; H<sub>2<\/sub> ile NH<sub>3<\/sub> aras\u0131ndaki mol oran\u0131 buymu\u015f. Oran belliyse \u015fu orant\u0131 bizi, cevaba g\u00f6t\u00fcr\u00fcr:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#891532;font-size:18px\">Orant\u0131:<br><br><strong><strong>3 mol<\/strong> <\/strong>H<sub>2<\/sub> den<strong> <strong>2 mol<\/strong> <\/strong>NH<sub>3<\/sub> olu\u015fursa<br><strong><strong>n mol<\/strong> <\/strong>H<sub>2<\/sub> den<strong> <strong>8 mol<\/strong> <\/strong>NH<sub>3<\/sub> olu\u015fur.<br><br>Bu bir do\u011fru orant\u0131d\u0131r. Do\u011fru orant\u0131n\u0131n e\u015fitli\u011fini kurarsak, n de\u011ferini buluruz:<br>n . 2 = 3 . 8<br>n . 2 = 24<br>n = 12 mol<\/p>\n\n\n\n<p><em>Cevap: 12 mol H<sub>2<\/sub><\/em><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Katsayilari_Dogru_Kullanmak\">Katsay\u0131lar\u0131 Do\u011fru Kullanmak<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong><em>Kimyasal bir tepkimede katsay\u0131lar\u0131n oran\u0131<\/em><\/strong> her zaman, a\u015fa\u011f\u0131da verilen \u00f6zelliklerin <strong><em>oran\u0131n\u0131 <\/em><\/strong>verir:\n<ul class=\"wp-block-list\">\n<li>Mol oran\u0131<\/li>\n\n\n\n<li>Say\u0131 oran\u0131<\/li>\n\n\n\n<li>Sabit bas\u0131n\u00e7taki gazlar\u0131n hacim oran\u0131<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Katsay\u0131lar\u0131n oran\u0131, hi\u00e7 bir zaman, maddelerin k\u00fctleleri aras\u0131ndaki oran\u0131 vermez.<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-3\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#6c6f71;font-size:18px\">3H<sub>2(g)<\/sub>&nbsp;+ N<sub>2(g)<\/sub>&nbsp;\u2192&nbsp;2NH<sub>3(g)<\/sub><\/p>\n\n\n\n<p><strong>Yukar\u0131daki tepkimeye g\u00f6re, 12 litre N<sub>2<\/sub> (Azot) gaz\u0131n\u0131n tam tepkimesinden, ayn\u0131 \u015fartlarda, ka\u00e7 litre NH<sub>3<\/sub> gaz\u0131 olu\u015fur?<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong>24 Litre<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>&#8220;Litre&#8221; bir hacim birimidir. Bu soru da bir hacim sorusudur.<\/p>\n\n\n\n<p>Soruda ge\u00e7en &#8220;tam tepkimesinden&#8221; ifadesi, &#8220;hepsi tepkimeye girecek&#8221; anlam\u0131ndad\u0131r. Zaten biz de, hepsinin tepkimeye girdi\u011fini d\u00fc\u015f\u00fcnerek hesap yapacakt\u0131k.<\/p>\n\n\n\n<p>Tepkime denklemine dikkat edilirse, b\u00fct\u00fcn maddelerin gaz halde oldu\u011fu g\u00f6r\u00fclecektir. Ayn\u0131 ko\u015fullardaki gazlar\u0131n tepkimelerinde, katsay\u0131lar, tepkimedeki gazlar\u0131n hacim oranlar\u0131n\u0131 da veriyordu.<\/p>\n\n\n\n<p>N<sub>2<\/sub> gaz\u0131n\u0131n katsay\u0131s\u0131 1, NH<sub>3<\/sub> gaz\u0131n\u0131n katsay\u0131s\u0131 da 2&#8217;dir. Yani bu iki maddenin, hacimleri aras\u0131ndaki oran \u015fudur:<\/p>\n\n\n\n<p class=\"has-white-color has-vivid-red-background-color has-text-color has-background\"><strong>1 litre N<sub>2<\/sub><\/strong> gaz\u0131n\u0131n tepkimesinden <strong>2 Litre NH<sub>3<\/sub><\/strong> gaz\u0131 olu\u015fur.<\/p>\n\n\n\n<p>O zaman basit bir orant\u0131 ile, soruyu \u00e7\u00f6zebiliriz:<\/p>\n\n\n\n<p class=\"has-white-color has-vivid-red-background-color has-text-color has-background\">Orant\u0131:<br><br><strong>1 litre N<sub>2<\/sub><\/strong> gaz\u0131n\u0131n tepkimesinden <strong>2 Litre NH<sub>3<\/sub><\/strong> gaz\u0131 olu\u015fursa<br><strong>12 litre N<sub>2<\/sub><\/strong> gaz\u0131n\u0131n tepkimesinden <strong>V Litre NH<sub>3<\/sub><\/strong> gaz\u0131 olu\u015fursa<br><br>Bu bir do\u011fru orant\u0131d\u0131r. Do\u011fru orant\u0131n\u0131n e\u015fitli\u011fini kurarsak, n de\u011ferini buluruz:<br><br>1. V = 12 . 2<br>V = 24<\/p>\n\n\n\n<p><em>Cevap: 24 Litre<\/em><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group stcnnt-yazi-ici-reklam\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p>Bu bir reklamd\u0131r:<\/p>\n\n\n\n<script async=\"\" src=\"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\"><\/script>\n<ins class=\"adsbygoogle\" style=\"display:block; text-align:center;\" data-ad-layout=\"in-article\" data-ad-format=\"fluid\" data-ad-client=\"ca-pub-6366953309324763\" data-ad-slot=\"9738116384\"><\/ins>\n<script>\n     (adsbygoogle = window.adsbygoogle || []).push({});\n<\/script>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-4\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#6c6f71;font-size:18px\">3H<sub>2(g)<\/sub>&nbsp;+ N<sub>2(g)<\/sub>&nbsp;\u2192&nbsp;2NH<sub>3(g)<\/sub><\/p>\n\n\n\n<p><strong>Yukar\u0131daki tepkimeye g\u00f6re, 24 tane H<sub>2<\/sub> (Hidrojen) molek\u00fcl\u00fcn\u00fcn tam tepkimesinden, ka\u00e7 tane NH<sub>3<\/sub> (Amonyak) molek\u00fcl\u00fc olu\u015fur?<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\">16 tane<\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>&#8220;Tane&#8221; bir say\u0131 birimidir.<\/p>\n\n\n\n<p>Tepkimelerde, katsay\u0131lar, tepkimedeki kimyasal t\u00fcrlerin say\u0131ca oranlar\u0131n\u0131 da veriyordu.<\/p>\n\n\n\n<p>H<sub>2<\/sub> gaz\u0131n\u0131n katsay\u0131s\u0131 3, NH<sub>3<\/sub> gaz\u0131n\u0131n katsay\u0131s\u0131 da 2&#8217;dir. Yani bu iki maddenin, say\u0131lar\u0131 aras\u0131ndaki oran \u015fudur:<\/p>\n\n\n\n<p class=\"has-white-color has-vivid-red-background-color has-text-color has-background\"><strong>3 tane H<sub>2<\/sub><\/strong> molek\u00fcl\u00fcn\u00fcn tepkimesinden <strong>2 tane NH<sub>3<\/sub><\/strong> molek\u00fcl\u00fc olu\u015fur.<\/p>\n\n\n\n<p>O zaman basit bir orant\u0131 ile, soruyu \u00e7\u00f6zebiliriz:<\/p>\n\n\n\n<p class=\"has-white-color has-vivid-red-background-color has-text-color has-background\">Orant\u0131: <br><br><strong>3 tane H<sub>2<\/sub><\/strong> molek\u00fcl\u00fcnden <strong>2 tane NH<sub>3<\/sub><\/strong> olu\u015fursa<br><strong>24 tane H<sub>2<\/sub><\/strong> molek\u00fcl\u00fcnden <strong>x tane NH<sub>3<\/sub><\/strong> olu\u015fur<br><br>Bu bir do\u011fru orant\u0131d\u0131r. Do\u011fru orant\u0131n\u0131n e\u015fitli\u011fini kurarsak, x de\u011ferini buluruz:<br><br>3 . x = 24 . 2<br>x = 48\/3<br>x = 16 tane<\/p>\n\n\n\n<p><em>Cevap: 16 tane<\/em><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><span id=\"Soru_Tipleri\">Soru Tipleri<\/span><\/h2>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Kimyasal hesaplamalar ile ilgili soru tipleri ne olursa olsun, kullanaca\u011f\u0131m\u0131z kural ve form\u00fcller hep ayn\u0131d\u0131r:\n<ul class=\"wp-block-list\">\n<li><em>mol say\u0131s\u0131 kurallar\u0131<\/em><\/li>\n\n\n\n<li><em>katsay\u0131lar\u0131n oran\u0131.<\/em><\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<p>Kimyasal hesaplama sorular\u0131, genelde \u015fu tiplerde gelir:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"1_Bir_Maddenin_Miktari_Verilir_Digeri_Sorulursa\">1. Bir Maddenin Miktar\u0131 Verilir Di\u011feri Sorulursa<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Yukar\u0131da \u00e7\u00f6zd\u00fc\u011f\u00fcm\u00fcz sorular bu tip sorulard\u0131r.<\/li>\n\n\n\n<li>Bu tip sorularda, tepkimedeki maddelerden <strong><em>birinin miktar\u0131 verilir<\/em><\/strong>, <strong><em>di\u011ferinin miktar\u0131 sorulur<\/em><\/strong>.\n<ul class=\"wp-block-list\">\n<li>Bu sorular \u00e7\u00f6z\u00fcl\u00fcrken, verilen ve sorulan maddelerin <strong><em>katsay\u0131lar\u0131 aras\u0131ndaki orana bak\u0131l\u0131r<\/em><\/strong>. Bu orana g\u00f6re, sorulan maddenin miktar\u0131 hesaplan\u0131r.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-5\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#3f3f3f\">CH<sub>4(g)<\/sub>&nbsp;+ 2O<sub>2(g)<\/sub>&nbsp;<strong>\u2192&nbsp;<\/strong>&nbsp;CO<sub>2(g)<\/sub>&nbsp;+ 2H<sub>2<\/sub>O<sub>(g)<\/sub>&nbsp;+ \u0131s\u0131<\/p>\n\n\n\n<p><strong>Yukar\u0131daki tepkimeye g\u00f6re, 48 gram Metan (CH<sub>4<\/sub>) gaz\u0131 yand\u0131\u011f\u0131nda, ka\u00e7 mol su (H<sub>2<\/sub>O) buhar\u0131 olu\u015fur? (C: 12 g\/mol, H: 1 g\/mol)<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong>8 mol<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Metan gaz\u0131n\u0131n k\u00fctlesini kullanarak, suyun mol say\u0131s\u0131n\u0131 hesaplamam\u0131z gerekiyor.<\/p>\n\n\n\n<p>Tepkimedeki katsay\u0131lardan yararlanabilmek i\u00e7in, \u00f6nce, 48 gram CH<sub>4<\/sub> gaz\u0131n\u0131n mol say\u0131s\u0131n\u0131 hesaplayal\u0131m:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#178c61\"> 48 gram CH<sub>4<\/sub> gaz\u0131 i\u00e7in:<br><br>Mol a\u011f\u0131rl\u0131\u011f\u0131n\u0131 bulal\u0131m:<br>M<sub>A<\/sub> = C + 4.H<br>M<sub>A<\/sub> = 12 + 4.1<br>M<sub>A<\/sub> = 16 g\/mol<br><br>Mol say\u0131s\u0131n\u0131 bulal\u0131m:<br>n = m \/ M<sub>A<\/sub><br>n = 48 \/ 16<br>n = 3 mol<\/p>\n\n\n\n<p>Art\u0131k, 3 mol CH<sub>4<\/sub> (Metan) gaz\u0131ndan, ka\u00e7 mol H<sub>2<\/sub>O (su) gaz\u0131n\u0131n olu\u015faca\u011f\u0131n\u0131 bulmam\u0131z gerekiyor. Bu durumda yapabilece\u011fimiz tek \u015fey, bu iki maddenin katsay\u0131lar\u0131na bakmakt\u0131r: <\/p>\n\n\n\n<p>CH<sub>4<\/sub> gaz\u0131n\u0131n katsay\u0131s\u0131 1, H<sub>2<\/sub>O gaz\u0131n\u0131n katsay\u0131s\u0131 da 2&#8217;dir. Yani bu iki maddenin, say\u0131lar\u0131 aras\u0131ndaki oran \u015fudur:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#157351\"><strong>1 mol CH<sub>4<\/sub><\/strong> gaz\u0131ndan <strong>2 mol H<sub>2<\/sub>O<\/strong> olu\u015fur.<\/p>\n\n\n\n<p>O zaman basit bir orant\u0131 ile, soruyu \u00e7\u00f6zebiliriz:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#126b4a\">Orant\u0131: <br><br><strong>1 mol CH<sub>4<\/sub><\/strong> gaz\u0131ndan <strong>2 mol H<sub>2<\/sub>O<\/strong> olu\u015fursa<br><strong>3 mol CH<sub>4<\/sub><\/strong> gaz\u0131ndan <strong>x mol H<sub>2<\/sub>O<\/strong> olu\u015fur<br><br>Bu bir do\u011fru orant\u0131d\u0131r. Do\u011fru orant\u0131n\u0131n e\u015fitli\u011fini kurarsak, x de\u011ferini buluruz:<br><br>1 . x = 3 . 2<br>x = 6 mol<\/p>\n\n\n\n<p><em>Cevap: 8 mol<\/em><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group stcnnt-yazi-ici-reklam\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p>Bu bir reklamd\u0131r:<\/p>\n\n\n\n<script async=\"\" src=\"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\"><\/script>\n<ins class=\"adsbygoogle\" style=\"display:block; text-align:center;\" data-ad-layout=\"in-article\" data-ad-format=\"fluid\" data-ad-client=\"ca-pub-6366953309324763\" data-ad-slot=\"9738116384\"><\/ins>\n<script>\n     (adsbygoogle = window.adsbygoogle || []).push({});\n<\/script>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-6\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#3f3f3f\">CH<sub>4(g)<\/sub>&nbsp;+ 2O<sub>2(g)<\/sub>&nbsp;<strong>\u2192&nbsp;<\/strong>&nbsp;CO<sub>2(g)<\/sub>&nbsp;+ 2H<sub>2<\/sub>O<sub>(g)<\/sub>&nbsp;+ \u0131s\u0131<\/p>\n\n\n\n<p><strong>Yukar\u0131daki tepkimede, NK (Normal Ko\u015fullarda) 5,6 L CO<sub>2<\/sub><\/strong> <strong>(Karbon dioksit) gaz\u0131 olu\u015ftu\u011funa g\u00f6re, ka\u00e7 gram O<sub>2<\/sub> (Oksijen) gaz\u0131 harcanm\u0131\u015ft\u0131r? (O: 16 g\/mol)<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong>16 g<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>NK, <strong>5,6 L CO<sub>2<\/sub><\/strong> gaz\u0131 \u00fcretmek i\u00e7in, <strong>ka\u00e7 gram O<sub>2<\/sub><\/strong> gaz\u0131n\u0131n harcamak gerekti\u011fi soruluyor.<\/p>\n\n\n\n<p>Dikkat ettiyseniz, maddelerin ikisi de gaz ve ayn\u0131 ko\u015fullarda. Bu durumda, katsay\u0131lar\u0131, bu iki maddenin hacimleri aras\u0131ndaki oran\u0131 verir.<\/p>\n\n\n\n<p>CO<sub>2<\/sub> gaz\u0131n\u0131n katsay\u0131s\u0131 1, O<sub>2<\/sub> gaz\u0131n\u0131n katsay\u0131s\u0131 da 2&#8217;dir. Bu katsay\u0131lar\u0131n bize anlatmaya \u00e7al\u0131\u015ft\u0131\u011f\u0131 \u015fey \u015fudur:<\/p>\n\n\n\n<p class=\"has-white-color has-vivid-red-background-color has-text-color has-background\"><strong>1 litre CO<sub>2<\/sub><\/strong> gaz\u0131 i\u00e7in <strong>2 Litre O<sub>2<\/sub><\/strong> gaz\u0131 gerekir.<\/p>\n\n\n\n<p>O zaman basit bir orant\u0131 ile, harcanmas\u0131 gereken O<sub>2<\/sub> gaz\u0131n\u0131n hacmini bulunabilir:<\/p>\n\n\n\n<p class=\"has-white-color has-vivid-red-background-color has-text-color has-background\">Orant\u0131:<br><br><strong>1 litre CO<sub>2<\/sub><\/strong> gaz\u0131 i\u00e7in <strong>2 Litre O<sub>2<\/sub><\/strong> gaz\u0131 gerekiyorsa<br><strong>5,6 litre CO<sub>2<\/sub><\/strong> gaz\u0131 i\u00e7in <strong>V Litre O<sub>2<\/sub><\/strong> gaz\u0131 gerekir.<br><br>Bu bir do\u011fru orant\u0131d\u0131r. Do\u011fru orant\u0131n\u0131n e\u015fitli\u011fini kurarsak, V de\u011ferini buluruz:<br><br>1. V = 5,6 . 2<br>V = 11,2 L<\/p>\n\n\n\n<p>Demek ki 5,6 L CO<sub>2<\/sub> gaz\u0131 \u00fcretmek i\u00e7in, NK, 11,2 L O<sub>2<\/sub> gaz\u0131 gerekiyormu\u015f. Gereken oksijen gaz\u0131n\u0131n miktar\u0131n\u0131 bulduk fakat Litre olarak bulduk yani, hacmini bulduk. Soru, oksijen gaz\u0131n\u0131n k\u00fctlesini soruyor. O zaman Normal Ko\u015fullardaki bir gaz\u0131n, k\u00fctlesini nas\u0131l bulaca\u011f\u0131m\u0131z g\u00f6relim:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#178c61\"> NK, 11,2 Litre O<sub>2<\/sub> gaz\u0131 i\u00e7in:<br><br>Mol say\u0131s\u0131n\u0131 bulal\u0131m:<br>n = V \/ 22,4<br>n = 11,2 \/ 22,4<br>n = 0,5 mol<br><br>Mol a\u011f\u0131rl\u0131\u011f\u0131n\u0131 bulal\u0131m (Sorunun sonundaki parantezden):<br>M<sub>A<\/sub> = 2.O<br>M<sub>A<\/sub> = 2.16<br>M<sub>A<\/sub> = 32 g\/mol<br><br>K\u00fctlesini bulal\u0131m:<br>m = n . M<sub>A<\/sub><br>m = 0,5 . 32<br>m = 16 gram<\/p>\n\n\n\n<p><em>Cevap: 16 g<\/em><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group stcnnt-yazi-ici-reklam\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p>Bu bir reklamd\u0131r:<\/p>\n\n\n\n<script async=\"\" src=\"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\"><\/script>\n<ins class=\"adsbygoogle\" style=\"display:block; text-align:center;\" data-ad-layout=\"in-article\" data-ad-format=\"fluid\" data-ad-client=\"ca-pub-6366953309324763\" data-ad-slot=\"9738116384\"><\/ins>\n<script>\n     (adsbygoogle = window.adsbygoogle || []).push({});\n<\/script>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-7\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#515355\">2Al<sub>(k)<\/sub> + 6HCl<sub>(suda)<\/sub> <strong>\u2192<\/strong> 2AlCl<sub>3(suda)<\/sub> + 3H<sub>2(g)<\/sub><\/p>\n\n\n\n<p>tepkimesine g\u00f6re, olu\u015fan H<sub>2<\/sub> gaz\u0131n\u0131n normal ko\u015fullarda (NK) hacmi 6,72 litredir.<\/p>\n\n\n\n<p><strong>Buna g\u00f6re tepkimede ka\u00e7 tane Al atomu harcanm\u0131\u015ft\u0131r?<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong>12,04 . 10<sup>22<\/sup> tane<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>NK, <strong>6,72 L H<sub>2<\/sub><\/strong> gaz\u0131 \u00fcretmek i\u00e7in, <strong>ka\u00e7 tane Al<\/strong> atomu harcamak gerekti\u011fi soruluyor.<\/p>\n\n\n\n<p>Dikkat ettiyseniz, H<sub>2<\/sub> gaz halinde bir madde Al metali kat\u0131 halde bir madde. Bu durumda, katsay\u0131lar\u0131n\u0131 kullanarak Al miktar\u0131n\u0131 bulmak i\u00e7in mol say\u0131s\u0131ndan ba\u015fka \u00e7are yok.<\/p>\n\n\n\n<p>Hemen, NK 6,72 Litre H<sub>2<\/sub> gaz\u0131n\u0131n mol say\u0131s\u0131n\u0131 hesaplayal\u0131m:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#14845b\">NK, 6,72 Litre H<sub>2<\/sub> gaz\u0131 i\u00e7in:<br><br>Mol say\u0131s\u0131n\u0131 bulal\u0131m:<br>n = V \/ 22,4<br>n = 6,72 \/ 22, 4<br>n = 0,3 mol<\/p>\n\n\n\n<p>Art\u0131k katsay\u0131lar\u0131na bakarak, Al ve H<sub>2<\/sub> gaz\u0131 aras\u0131na bir oran kurabilirim ve Al metalinin mol say\u0131s\u0131n\u0131 bulabilirim.<\/p>\n\n\n\n<p>Tepkimede, Al metalinin katsay\u0131s\u0131 2, H<sub>2<\/sub> gaz\u0131n\u0131n katsay\u0131s\u0131 da 3 verilmi\u015ftir. Bu oran kullan\u0131larak, a\u015fa\u011f\u0131daki gibi bir orant\u0131 kurulabilir ve Al metalinin mol say\u0131s\u0131 bulunabilir:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#14845b\"><strong>2 mol Al<\/strong> metalinden <strong>3 mol H<sub>2<\/sub><\/strong> gaz\u0131 olu\u015fuyorsa<br><strong>n mol Al<\/strong> metalinden <strong>0,3 mol H<sub>2<\/sub><\/strong> gaz\u0131 olu\u015fur.<br><br>Bu bir do\u011fru orant\u0131d\u0131r. Do\u011fru orant\u0131n\u0131n e\u015fitli\u011fini kurarsak, n de\u011ferini buluruz:<br>n . 3 = 2 . 0,3<br>n = 0,6 \/ 3<br>n = 0,2 mol<\/p>\n\n\n\n<p>Demek kim Al miktar\u0131 0,2 mol olmal\u0131d\u0131r. O zaman 0,2 mol Al metalinde ka\u00e7 tane atom oldu\u011funu bulursak, sorunun cevab\u0131 bulunmu\u015f olacakt\u0131r:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#14845b\">0,2 mol Al metalindeki atom say\u0131s\u0131:<br><br><strong>1 mol Al<\/strong> metalinde<strong> 6,02.10<sup>23<\/sup> tane<\/strong> atom varsa<br><strong>0,2 mol Al<\/strong> metalinde<strong> x tane<\/strong> atom varsa<br><br>Bu bir do\u011fru orant\u0131d\u0131r. Do\u011fru orant\u0131n\u0131n e\u015fitli\u011fini kurarsak, x de\u011ferini buluruz:<br>1 . x = 0,2 . <strong>6,02.10<sup>23<\/sup><\/strong><br>x = 2. 10<sup>-1<\/sup> . <strong>6,02.10<sup>23<\/sup><\/strong><br>n = 12,04 . 10<sup>22<\/sup> tane<\/p>\n\n\n\n<p><em>Cevap: 12,04 . 10<sup>22<\/sup> tane<\/em><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"2_Karisim_Sorulari\">2. Kar\u0131\u015f\u0131m Sorular\u0131<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Bir kar\u0131\u015f\u0131mda, kimsenin tepkimesi kimseyi ilgilendirmez.<\/li>\n\n\n\n<li>Kar\u0131\u015f\u0131mdaki maddelerin tepkimelerini ayr\u0131 ayr\u0131 yazmal\u0131y\u0131z.<\/li>\n\n\n\n<li>Kar\u0131\u015f\u0131mdaki her bir maddenin tepkimesi i\u00e7in, ayr\u0131 ayr\u0131, yukar\u0131da \u00f6\u011frendi\u011fimiz kurallar\u0131 kullan\u0131r\u0131z.<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-8\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p>CH<sub>4<\/sub> ile C<sub>2<\/sub>H<sub>6<\/sub> gazlar\u0131ndan olu\u015fan bir kar\u0131\u015f\u0131m\u0131n, 5 mol\u00fc tamamen yan\u0131yor ve bu kar\u0131\u015f\u0131m\u0131n yanmas\u0131ndan toplam 8 mol CO<sub>2<\/sub> gaz\u0131 olu\u015fuyor.<\/p>\n\n\n\n<p><strong>Buna g\u00f6re bu kar\u0131\u015f\u0131mdaki, CH<sub>4<\/sub> ile C<sub>2<\/sub>H<sub>6<\/sub> gazlar\u0131n\u0131n k\u00fctleleri ka\u00e7ar gramd\u0131r? (C: 12 g\/mol, H: 1 g\/mol)<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong>32 g CH<sub>4<\/sub><\/strong><\/p>\n\n\n\n<p class=\"has-text-align-center has-medium-font-size\"><strong>90 g C<sub>2<\/sub>H<sub>6<\/sub><\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Kimsenin tepkimesi kimseyi ilgilendirmez. \u00d6nce kar\u0131\u015f\u0131mdaki iki maddenin ayr\u0131 ayr\u0131 yanma tepkimelerini bulal\u0131m:<\/p>\n\n\n\n<p>CH<sub>4<\/sub> ve C<sub>2<\/sub>H<sub>6<\/sub> bile\u015fikleri, organik bile\u015fiklerdir. Organik bile\u015fikler yan\u0131nca, her zaman CO<sub>2<\/sub> ve H<sub>2<\/sub>O olu\u015fur:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#157552\">CH<sub>4<\/sub> ve C<sub>2<\/sub>H<sub>6<\/sub> gazlar\u0131n\u0131n yanma tepkimeleri:<br><br>CH<sub>4<\/sub> + 2O<sub>2<\/sub> <strong>\u2192<\/strong> CO<sub>2<\/sub> + 2H<sub>2<\/sub>O<br>C<sub>2<\/sub>H<sub>6<\/sub> + 7\/2O<sub>2<\/sub> <strong>\u2192<\/strong> 2CO<sub>2<\/sub> + 3H<sub>2<\/sub>O<\/p>\n\n\n\n<p>CH<sub>4<\/sub> ve C<sub>2<\/sub>H<sub>6<\/sub> bile\u015fiklerinin toplam 5 mol oldu\u011fu verilmi\u015f. O zaman \u015f\u00f6yle bir yol se\u00e7elim:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#157552\">Kar\u0131\u015f\u0131mdaki<br>CH<sub>4<\/sub> = x mol olsun<br>C<sub>2<\/sub>H<sub>6<\/sub> = y mol olsun<\/p>\n\n\n\n<p>Kar\u015f\u0131m\u0131 toplam 5 mol oldu\u011funa g\u00f6re:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#157552\">x + y = 5<\/p>\n\n\n\n<p>olacakt\u0131r.<\/p>\n\n\n\n<p>Katsay\u0131lar yard\u0131m\u0131 ile, x mol CH<sub>4<\/sub> gaz\u0131ndan ve y mol C<sub>2<\/sub>H<sub>6<\/sub> gaz\u0131ndan, toplam ne kadar CO<sub>2<\/sub> gaz\u0131 olu\u015ftu\u011funu bulabiliriz. Buldu\u011fumuz toplam da yine x ve y cinsinden olacakt\u0131r ve de\u011feri de 8&#8217;e e\u015fit olmak zorundad\u0131r. \u00c7\u00fcnk\u00fc bu iki tepkimede, 8 mol CO<sub>2<\/sub> olu\u015ftu\u011fu soruda belirtilmi\u015f.<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#1d694d\">x mol CH<sub>4<\/sub>  gaz\u0131ndan olu\u015fan CO<sub>2<\/sub> gaz\u0131n\u0131n mol say\u0131s\u0131:<br><br>CH<sub>4<\/sub> + 2O<sub>2<\/sub> <strong>\u2192<\/strong> CO<sub>2<\/sub> + 2H<sub>2<\/sub>O<br><br>CH<sub>4<\/sub> ve CO<sub>2<\/sub> gazlar\u0131n\u0131n katsay\u0131lar\u0131 e\u015fittir. O zaman i\u015flem yapmaya gerek kalmaz. Yani;<br><br>x mol CH<sub>4<\/sub> gaz\u0131ndan, <strong>x mol CO<sub>2<\/sub> <\/strong>gaz\u0131 olu\u015fur.<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#1d694d\">y mol C<sub>2<\/sub>H<sub>6<\/sub> gaz\u0131ndan olu\u015fan CO<sub>2<\/sub> gaz\u0131n\u0131n mol say\u0131s\u0131:<br><br>C<sub>2<\/sub>H<sub>6<\/sub> + 7\/2O<sub>2<\/sub> <strong>\u2192<\/strong> 2CO<sub>2<\/sub> + 3H<sub>2<\/sub>O<br><br>C<sub>2<\/sub>H<sub>6<\/sub> gaz\u0131n\u0131n katsay\u0131s\u0131 1; CO<sub>2<\/sub> gaz\u0131n\u0131n katsay\u0131s\u0131 2&#8217;dir. O zaman \u015f\u00f6yle bir orant\u0131 ile CO2 gaz\u0131n\u0131 ka\u00e7 y olu\u015faca\u011f\u0131n\u0131 bulabiliriz:<br><br>1 mol C<sub>2<\/sub>H<sub>6<\/sub> gaz\u0131ndan, 2 mol CO<sub>2<\/sub> gaz\u0131 olu\u015fursa<br>y mol C<sub>2<\/sub>H<sub>6<\/sub> gaz\u0131ndan, ? mol CO<sub>2<\/sub> gaz\u0131 olu\u015fur<br><br>Do\u011fru orant\u0131 e\u015fitli\u011fi kurarak, ? de\u011ferinin ka\u00e7 y oldu\u011funu bulal\u0131m:<br>1 . ? = y . 2<br>? = <strong>2y mol CO<sub>2<\/sub><\/strong><\/p>\n\n\n\n<p>Tepkimelerin birinden x mol, di\u011ferinden 2y mol CO<sub>2<\/sub> gaz\u0131 olu\u015fmu\u015ftur. Bu iki de\u011ferin toplam\u0131 8 yapmal\u0131d\u0131r:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#0c6645\">x + 2y = 8<\/p>\n\n\n\n<p>Sorunun ba\u015f\u0131nda da buldu\u011fumuz e\u015fitli\u011fi de hat\u0131rlarsak, elimizde iki bilinmeyenli iki tane e\u015fitlik olur:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#0c6645\">x + y = 5<br>x + 2y = 8<\/p>\n\n\n\n<p>Bundan sonras\u0131 matematik bilgimize kalm\u0131\u015ft\u0131r. Bu iki denklemden x ve y \u015f\u00f6yle hesaplan\u0131r:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#0c6645\">x + y = 5<br>x + 2y = 8 \/ (Bunu -1 ile \u00e7arparsak x gider y kal\u0131r)<br><br>x + y = 5<br>&#8211; x &#8211; 2y = -8<br><br>\u015eimdi ikisini, alt alta toplayal\u0131m, x gider, a\u015fa\u011f\u0131daki e\u015fitlik elde edilir:<br><br>-y = -3<br>yani:<br>y = 3 mol<br><br>y bulundu\u011funa g\u00f6re, ilk e\u015fitli\u011fi yazal\u0131m, y&#8217;nin de\u011ferini de yerine koyal\u0131m ve x de\u011ferini bulal\u0131m:<br><br>x + y = 5<br>x + 3 = 5<br>x = 5 &#8211; 3<br>x = 2 mol<\/p>\n\n\n\n<p>Demek ki, kar\u015f\u0131mdaki maddelerin mol say\u0131lar\u0131 \u015f\u00f6yle olacakm\u0131\u015f:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#1b694d\">CH<sub>4<\/sub> : 2 mol<br>C<sub>2<\/sub>H<sub>6<\/sub> : 3 mol<\/p>\n\n\n\n<p>Mol say\u0131lar\u0131 bilindi\u011fine g\u00f6re, art\u0131k, k\u00fctlelerini hesaplamak da m\u00fcmk\u00fcnd\u00fcr.<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#1b694d\">2 mol CH<sub>4<\/sub> gaz\u0131n\u0131 k\u00fctlesi:<br><br>Mol a\u011f\u0131rl\u0131\u011f\u0131n\u0131 bulal\u0131m:<br>M<sub>A<\/sub> = C + 4.H<br>M<sub>A<\/sub> = 12 + 4.1<br>M<sub>A<\/sub> = 16 g\/mol<br><br>K\u00fctlesini bulal\u0131m:<br>m = n . M<sub>A<\/sub><br>m = 2 . 16<br>m = 32 gram<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#1b694d\">3 mol C<sub>2<\/sub>H<sub>6<\/sub> gaz\u0131n\u0131 k\u00fctlesi:<br><br>Mol a\u011f\u0131rl\u0131\u011f\u0131n\u0131 bulal\u0131m:<br>M<sub>A<\/sub> = 2.C + 6.H<br>M<sub>A<\/sub> = 2.12 + 6.1<br>M<sub>A<\/sub> = 30 g\/mol<br><br>K\u00fctlesini bulal\u0131m:<br>m = n . M<sub>A<\/sub><br>m = 3 . 30<br>m = 90 gram<\/p>\n\n\n\n<p><em>Cevap: 32 g CH<sub>4<\/sub>, 90 g C<sub>2<\/sub>H<sub>6<\/sub><\/em><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group stcnnt-yazi-ici-reklam\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p>Bu bir reklamd\u0131r:<\/p>\n\n\n\n<script async=\"\" src=\"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\"><\/script>\n<ins class=\"adsbygoogle\" style=\"display:block; text-align:center;\" data-ad-layout=\"in-article\" data-ad-format=\"fluid\" data-ad-client=\"ca-pub-6366953309324763\" data-ad-slot=\"9738116384\"><\/ins>\n<script>\n     (adsbygoogle = window.adsbygoogle || []).push({});\n<\/script>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-9\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p>Zn ile Ag\u02bcden olu\u015fan 160 graml\u0131k kar\u0131\u015f\u0131m, yeterince HCl ile tepkimeye girince NKA\u2019da 44,8 L H<sub>2<\/sub> gaz\u0131 a\u00e7\u0131\u011fa \u00e7\u0131kt\u0131\u011f\u0131na g\u00f6re;<\/p>\n\n\n\n<p><strong>a) Kar\u0131\u015f\u0131mdaki g\u00fcm\u00fc\u015f\u00fcn k\u00fctlesi ka\u00e7 gramd\u0131r?<br>b) Kar\u0131\u015f\u0131mdaki g\u00fcm\u00fc\u015f\u00fcn k\u00fctlece y\u00fczdesi nedir? (Zn: 65 g\/mol)<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong>a) 30 gram<\/strong><\/p>\n\n\n\n<p class=\"has-text-align-center has-medium-font-size\"><strong>b) % 18,75<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Bu soruda, Ag (G\u00fcm\u00fc\u015f) metalinin bir yar\u0131 soy metal oldu\u011funu ve HCl (Hidroklorik asit) ile tepkime vermeyece\u011fini hat\u0131rlamam\u0131z gerekiyor.<\/p>\n\n\n\n<p>Bu durumda, olu\u015fan H<sub>2<\/sub> gaz\u0131n\u0131n tamam\u0131 Zn (\u00c7inko) ile HCl tepkimesinden olu\u015fmu\u015ftur. Bu tepkimeye ge\u00e7meden \u00f6nce, olu\u015fan H<sub>2<\/sub> gaz\u0131n\u0131n mol say\u0131s\u0131n\u0131 bulal\u0131m:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#147551\">N\u015eA (Normal \u015eartlar Alt\u0131nda), 44,8 Litre H<sub>2<\/sub> gaz\u0131n\u0131n mol say\u0131s\u0131:<br><br>n = V \/ 22,4<br>n = 44,8 \/ 22,4<br><strong>n = 2 mol H<sub>2<\/sub> gaz\u0131<\/strong><\/p>\n\n\n\n<p>Zn ile HCl tepkimesi bir <a href=\"https:\/\/sitecenneti.com\/kimya\/tyt-kimya\/asitler-bazlar-ve-tuzlar\/asitlerin-ve-bazlarin-tepkimeleri\/#3_Asit-Metal_Tepkimeleri\">Asit- Aktif Metal  Tepkimesidir<\/a>. Bu tepkimeden, tuz ve H<sub>2<\/sub> gaz\u0131 olu\u015fmaktad\u0131r. Tepkime denklemi \u015f\u00f6yle olacakt\u0131r:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#187a56;font-size:18px\">Zn + 2HCl <strong>\u2192<\/strong> ZnCl<sub>2<\/sub> + H<sub>2<\/sub><\/p>\n\n\n\n<p>Katsay\u0131lara dikkat edersek, H2 gaz\u0131n\u0131n katsay\u0131s\u0131 ile Zn metalinin katsay\u0131s\u0131 e\u015fittir. Yani, bu iki maddenin, bu tepkimede, mol oranlar\u0131 ayn\u0131d\u0131r. O zaman \u015funu diyebiliriz:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#147551\">2 mol H<sub>2<\/sub> gaz\u0131n\u0131n olu\u015fmas\u0131 i\u00e7in <strong>2 mol Zn<\/strong> gerekir.<\/p>\n\n\n\n<p>Demek ki elimizde 2 mol Zn varm\u0131\u015f. Hemen k\u00fctlesini hesaplayal\u0131m:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#147551\"> <strong>2 mol Zn<\/strong> metalinin k\u00fctlesi:<br><br>m = n . M<sub>A<\/sub><br>m = 2 . 65<br>m = 130 gram<\/p>\n\n\n\n<p><strong>a)<\/strong><br>Demek ki, 160 graml\u0131k Zn-Ag kar\u0131\u015f\u0131m\u0131nda 130 gram Zn varm\u0131\u015f. O zaman, kar\u0131\u015f\u0131mdaki Ag k\u00fctlesi:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#147551\"> 160 &#8211; 130 = 30 gram<\/p>\n\n\n\n<p><em>Cevap: 30 gram<\/em><\/p>\n\n\n\n<p><strong>b)<\/strong><br>Basit bir orant\u0131 ile 160 graml\u0131k kar\u0131\u015f\u0131mda, Ag metalinin k\u00fctlece y\u00fczdesini bulabiliriz:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#147551\"> 160 gram kar\u0131\u015f\u0131mda 30 gram Ag varsa<br>100 gram kar\u0131\u015f\u0131mda x gram Ag vard\u0131r.<br><br>Do\u011fru orant\u0131n\u0131n e\u015fitli\u011fini kurarsak, x de\u011ferin bulabiliriz:<br>160 . x = 100 . 30<br>x = 3000 \/ 160<br>x = 18,75<\/p>\n\n\n\n<p>Cevap: % 18,75<\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"3_Mol_Agirligi_MA_Sorulari\">3. Mol A\u011f\u0131rl\u0131\u011f\u0131 (M<sub>A<\/sub>) Sorular\u0131<\/span><\/h3>\n\n\n\n<p class=\"has-text-align-center has-background\" style=\"background-color:#f1faff\">Mol say\u0131s\u0131 form\u00fcl\u00fcnden:<br><br><strong>M<sub>A<\/sub> = m \/ n<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Bu tip sorularda, tepkimedeki bir bile\u015fi\u011fin ya da elementin <strong><em>mol a\u011f\u0131rl\u0131\u011f\u0131n\u0131<\/em> <em>(M<sub>A<\/sub>)<\/em><\/strong> bulmam\u0131z gerekecek.<\/li>\n\n\n\n<li>Bunu i\u00e7in bir \u015fekilde, bu maddenin <strong><em>mol say\u0131s\u0131na<\/em><\/strong> ve <em><strong>k\u00fctlesine <\/strong><\/em>ula\u015fmaya ba\u015farmal\u0131y\u0131z \u00e7\u00fcnk\u00fc; yukar\u0131da da g\u00f6r\u00fcld\u00fc\u011f\u00fc gibi, k\u00fctlesini mol say\u0131s\u0131na b\u00f6l\u00fcnce, maddenin<strong><em> mol a\u011f\u0131rl\u0131\u011f\u0131 bulunur<\/em><\/strong>.<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group stcnnt-yazi-ici-reklam\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p>Bu bir reklamd\u0131r:<\/p>\n\n\n\n<script async=\"\" src=\"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\"><\/script>\n<ins class=\"adsbygoogle\" style=\"display:block; text-align:center;\" data-ad-layout=\"in-article\" data-ad-format=\"fluid\" data-ad-client=\"ca-pub-6366953309324763\" data-ad-slot=\"9738116384\"><\/ins>\n<script>\n     (adsbygoogle = window.adsbygoogle || []).push({});\n<\/script>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-10\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p>X + 2HBr <strong>\u2192<\/strong> XBr<sub>2<\/sub> + H<sub>2(g)<\/sub><\/p>\n\n\n\n<p>Yukar\u0131daki tepkimeye g\u00f6re, 16 gram X yeterince HBr ile tepkimeye girdi\u011finde NKA\u2019da 0,4 mol H<sub>2<\/sub> gaz\u0131 a\u00e7\u0131\u011fa \u00e7\u0131k\u0131yor.<\/p>\n\n\n\n<p><strong>Buna g\u00f6re X elementinin atom k\u00fctlesi ka\u00e7t\u0131r?<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong>40 g\/mol<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Atom k\u00fctlesi veya Mol a\u011f\u0131rl\u0131\u011f\u0131 (M<sub>A<\/sub>) ayn\u0131 anlamdad\u0131r. X elementinin k\u00fctlesi verilmi\u015f, Mol a\u011f\u0131rl\u0131\u011f\u0131 soruluyor. Mol a\u011f\u0131rl\u0131\u011f\u0131n\u0131 hesaplamak i\u00e7in ihtiyac\u0131m\u0131z olanlar k\u00fctle ve mol say\u0131s\u0131d\u0131r. K\u00fctle biliniyorsa, bize d\u00fc\u015fen X elementinin mol say\u0131s\u0131n\u0131 bulmakt\u0131r.<\/p>\n\n\n\n<p>Olu\u015fan H<sub>2<\/sub> gaz\u0131n\u0131n mol say\u0131s\u0131 verilmi\u015f. Katsay\u0131lar\u0131 kullanarak, X elementinin mol say\u0131s\u0131na ge\u00e7elim:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#14845b\">X + 2HBr <strong>\u2192<\/strong> XBr<sub>2<\/sub> + H<sub>2(g)<\/sub><br><br>Tepkimede, X elementi ile H<sub>2<\/sub> gaz\u0131n\u0131n katsay\u0131lar\u0131 e\u015fittir. Bu durumda, 0,4 mol H<sub>2<\/sub> gaz\u0131 olu\u015ftuysa, <strong>0,4 mol X <\/strong>elementi harcanm\u0131\u015f demektir.<\/p>\n\n\n\n<p>Mol say\u0131s\u0131 ve k\u00fctlesi belli ise MA \u015f\u00f6yle hesaplan\u0131r:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#14845b\">0,4 mol, 16 gram X elementinin M<sub>A<\/sub> de\u011feri:<br><br>M<sub>A<\/sub> = m \/ n<br>M<sub>A<\/sub> = 16 \/ 0,4<br>M<sub>A<\/sub> = 40 g\/mol<\/p>\n\n\n\n<p><em>Cevap: 40 g\/mol<\/em><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group stcnnt-yazi-ici-reklam\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p>Bu bir reklamd\u0131r:<\/p>\n\n\n\n<script async=\"\" src=\"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\"><\/script>\n<ins class=\"adsbygoogle\" style=\"display:block; text-align:center;\" data-ad-layout=\"in-article\" data-ad-format=\"fluid\" data-ad-client=\"ca-pub-6366953309324763\" data-ad-slot=\"9738116384\"><\/ins>\n<script>\n     (adsbygoogle = window.adsbygoogle || []).push({});\n<\/script>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-11\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#4b4c4d\">X(OH)<sub>2(k)<\/sub> + 2HNO<sub>3(suda)<\/sub> <strong>\u2192<\/strong> X(NO<sub>3<\/sub>)<sub>2(suda)<\/sub> + 2H<sub>2<\/sub>O<sub>(s)<\/sub><\/p>\n\n\n\n<p>tepkimesine g\u00f6re 23,2 gram X(OH)<sub>2<\/sub> yeterince HNO<sub>3<\/sub> ile tepkimeye girdi\u011finde 14,4 gram H<sub>2<\/sub>O olu\u015fuyor.<\/p>\n\n\n\n<p><strong>Buna g\u00f6re X elementinin mol k\u00fctlesini hesaplay\u0131n\u0131z. (H: 1 g\/mol, O: 16 g\/mol)<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong>24 g\/mol<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#393f44\">Suyun mol say\u0131s\u0131n\u0131 bulursak, katsay\u0131lar\u0131n yad\u0131m\u0131 ile X(OH)<sub>2<\/sub> kats\u0131n\u0131n da mol say\u0131s\u0131n\u0131 buluruz:<br><br>14,4 g suyun mol say\u0131s\u0131:<br>m = 14,4 g<br>M<sub>A<\/sub> = 2.1 + 16 = 18 g\/mol<br>n = ?<br>n = m \/ M<sub>A<\/sub><br>n = 14,4 \/ 18<br>n = 0,8 mol<br><br>Katsay\u0131lar\u0131ndan:<br>1 mol X(OH)<sub>2<\/sub> kat\u0131s\u0131ndan 2 mol H<sub>2<\/sub>O olu\u015fuyorsa<br>n mol X(OH)<sub>2<\/sub> kat\u0131s\u0131ndan 0,8 mol H<sub>2<\/sub>O olu\u015fur.<br><br>Do\u011fru orant\u0131y\u0131 \u00e7\u00f6zelim:<br>1 . 0,8 = n . 2<br>n = 0,4 mol X(OH)<sub>2<\/sub><br><br>Soruda k\u00fctlesi verilmi\u015f, biz de mol say\u0131s\u0131n bulduk. Art\u0131k, X(OH)<sub>2<\/sub> bile\u015fi\u011finin MA de\u011ferini bulabiliriz:<br>M<sub>A<\/sub> = m \/ n<br>M<sub>A<\/sub> = 23,2 \/ 0,4<br>M<sub>A<\/sub> = 232 \/ 4<br>M<sub>A<\/sub> = 58<br><br>Demek ki X(OH)<sub>2<\/sub> bile\u015fi\u011findeki b\u00fct\u00fcn atomlar\u0131n Mol A\u011f\u0131rl\u0131klar\u0131n\u0131n toplam\u0131 58 yap\u0131yor:<br><br>X + 2.O + 2.H = 58<br><br>Hidrojen (H) ve Oksijen (O) atomlar\u0131n\u0131n mol a\u011f\u0131rl\u0131klar\u0131 soruda verilmi\u015fti:<br>X + 2.16 + 2.1 = 58<br>X + 34 = 58<br>X = 58 &#8211; 34<br>X = 24 g\/mol<\/p>\n\n\n\n<p><em>Cevap: 24 g\/mol<\/em><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"4_Bilesik_Formulu_Bulma_Sorulari\">4. Bile\u015fik Form\u00fcl\u00fc Bulma Sorular\u0131<\/span><\/h3>\n\n\n\n<p>Bile\u015fik form\u00fcl\u00fc bulma sorular\u0131 iki \u00e7e\u015fittir:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>Tepkime Denkleminden Bile\u015fik Form\u00fcl\u00fc Bulma Sorular\u0131\n<ul class=\"wp-block-list\">\n<li>Bu tip sorularda, bir tepkime denklemi verilir yada kurulur. Tepkime bir \u015fekilde e\u015fitlenir. E\u015fit olan tepkimedeki atom say\u0131lar\u0131 da e\u015fit olmal\u0131d\u0131r. Bu kural d\u00fc\u015f\u00fcn\u00fclerek form\u00fcldeki say\u0131lar bulunur.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Mol Say\u0131lar\u0131ndan Bile\u015fik Form\u00fcl\u00fc Bulma Sorular\u0131\n<ul class=\"wp-block-list\">\n<li>Bile\u015fikteki b\u00fct\u00fcn atomlar\u0131n ayr\u0131 ayr\u0131 mol say\u0131lar\u0131 bulunur. Bulunan mol say\u0131lar\u0131, en k\u00fc\u00e7\u00fck tam say\u0131lara \u00e7evrilerek atomlar\u0131n alt\u0131na yaz\u0131l\u0131r. Bu \u015fekilde bile\u015fi\u011fin kaba form\u00fcl\u00fc elde edilir.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-12\">\u00d6rnek:<\/span><\/h4>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"350\" height=\"345\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Hesaplamalar-Formul-Bulma-Problemleri.jpg\" alt=\"Form\u00fcl Bulma Sorular\u0131\" class=\"wp-image-3666\" style=\"width:322px;height:317px\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Hesaplamalar-Formul-Bulma-Problemleri.jpg 350w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Hesaplamalar-Formul-Bulma-Problemleri-300x296.jpg 300w\" sizes=\"auto, (max-width: 350px) 100vw, 350px\" \/><\/figure>\n<\/div>\n\n\n<p>Yukar\u0131daki grafik, bir kimyasal tepkimeye ait hacim-zaman grafi\u011fidir. Tepkimedeki maddelerin hepsinin gaz oldu\u011fu bilinmektedir.<\/p>\n\n\n\n<p><strong>Bu gazlar, ayn\u0131 ko\u015fullarda oldu\u011funa g\u00f6re, X<sub>a<\/sub>Y<sub>b<\/sub> gaz\u0131n\u0131n form\u00fcl\u00fc nedir?<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong>X<sub>3<\/sub>Y<sub>2<\/sub><\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Tepkimeye giren maddelerin miktar\u0131 zamanla azal\u0131r, \u00fcr\u00fcnlerin miktar\u0131 zamanla artar. Bu basit kural\u0131 kullanarak, grafikteki maddelerin hangisinin giren, hangisinin \u00fcr\u00fcn oldu\u011fu anla\u015f\u0131l\u0131r.<\/p>\n\n\n\n<p>Grafikte miktar\u0131 azalan maddeler, yani tepkimeye girenler \u015funlard\u0131r:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>X<sub>2<\/sub> ve Y<sub>2<\/sub><\/li>\n<\/ul>\n\n\n\n<p>Grafikte miktar\u0131 artan madde bir tanedir, yani tepkimede bir \u00fcr\u00fcn vard\u0131r; o da \u015funlard\u0131r:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>X<sub>a<\/sub>Y<sub>b<\/sub><\/li>\n<\/ul>\n\n\n\n<p>Girenler ve \u00fcr\u00fcnler belli oldu\u011funa g\u00f6re tepkime denklemi \u015f\u00f6yle olmal\u0131d\u0131r:<\/p>\n\n\n\n<p class=\"has-text-color has-background\" style=\"color:#f9f1db;background-color:#8f420b;font-size:18px\">X<sub>2<\/sub> + Y<sub>2<\/sub> \u2192 X<sub>a<\/sub>Y<sub>b<\/sub><\/p>\n\n\n\n<p>S\u0131ra geldi, katsay\u0131lar\u0131na. Grafikteki bilgilerden, katsay\u0131lar da bulunabilir. \u00c7\u00fcnk\u00fc, tepkimedeki maddeler gaz halinde verilmi\u015f ve ayn\u0131 ko\u015fullarda olduklar\u0131 s\u00f6ylenmi\u015ftir. B\u00f6yle gazlar\u0131n katsay\u0131lar\u0131, hacim oranlar\u0131d\u0131r. Yani, herkesin tepkimede harcanan ve olu\u015fan hacimlerini bulursak, katsay\u0131lar\u0131n\u0131 da bulmu\u015f oluruz:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#4b5053\">X<sub>2<\/sub> gaz\u0131n\u0131n, tepkimede harcanan hacmi:<br>40 &#8211; 10 = 30 birim<br><br>Y<sub>2<\/sub> gaz\u0131n\u0131n, tepkimede harcanan hacmi:<br>20 &#8211; 0 = 20 birim<br><br>X<sub>a<\/sub>Y<sub>b<\/sub> gaz\u0131n\u0131n, tepkimede olu\u015fan hacmi:<br>20 &#8211; 0 = 20 birim<\/p>\n\n\n\n<p>Buldu\u011fumuz hacim de\u011ferlerini katsay\u0131 olarak \u00f6nlerine yazarsak, tepkime denklemi \u015f\u00f6yle olur:<\/p>\n\n\n\n<p class=\"has-text-color has-background\" style=\"color:#f9f1db;background-color:#8f420b;font-size:18px\"><strong><span style=\"color:#f5ee76\" class=\"has-inline-color\">30<\/span><\/strong>X<sub>2<\/sub> + <strong><span style=\"color:#faf370\" class=\"has-inline-color\">20<\/span><\/strong>Y<sub>2<\/sub> \u2192 <strong><span style=\"color:#fdfb75\" class=\"has-inline-color\">20<\/span><\/strong>X<sub>a<\/sub>Y<sub>b<\/sub><\/p>\n\n\n\n<p>Katsay\u0131lar sadele\u015febilir:<\/p>\n\n\n\n<p class=\"has-text-color has-background\" style=\"color:#f9f1db;background-color:#8f420b;font-size:18px\">3X<sub>2<\/sub> + 2Y<sub>2<\/sub> \u2192 2X<sub>a<\/sub>Y<sub>b<\/sub><\/p>\n\n\n\n<p>Katsay\u0131lar belli oldu\u011funa g\u00f6re, girenlerdeki atomlar ile \u00fcr\u00fcnlerdeki atomlar\u0131n say\u0131s\u0131 e\u015fit demektir.<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#196144\">Girenlere bakt\u0131\u011f\u0131m\u0131zda 3X<sub>2<\/sub> &#8216;de:<br>3 . 2 = 6 tane X atomu g\u00f6r\u00fcyoruz.<br><br>O zaman \u00fcr\u00fcnlerdeki 2X<sub>a<\/sub>Y<sub>b<\/sub> bile\u015fi\u011finde de 6 tane X atomu olmal\u0131d\u0131r. Bu durumda:<br>2 . a = 6<br>a = 3 olmal\u0131d\u0131r.<br><br>Girenlerdeki 2Y<sub>2<\/sub> &#8216;de:<br>2 . 2 = 4 tane Y atom vard\u0131r.<br><br>O zaman \u00fcr\u00fcnlerdeki 2X<sub>a<\/sub>Y<sub>b<\/sub> bile\u015fi\u011finde de 4 tane Y atomu olmal\u0131d\u0131r. Bu durumda:<br>2 . b = 4<br>b = 2 olmal\u0131d\u0131r.<br><br>a=3, b=2 ise X<sub>a<\/sub>Y<sub>b<\/sub> bile\u015fi\u011finin form\u00fcl\u00fc \u015fudur:<br><strong>X<sub>3<\/sub>Y<sub>2<\/sub><\/strong><\/p>\n\n\n\n<p><em>Cevap: X<sub>3<\/sub>Y<sub>2<\/sub><\/em><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group stcnnt-yazi-ici-reklam\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p>Bu bir reklamd\u0131r:<\/p>\n\n\n\n<script async=\"\" src=\"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\"><\/script>\n<ins class=\"adsbygoogle\" style=\"display:block; text-align:center;\" data-ad-layout=\"in-article\" data-ad-format=\"fluid\" data-ad-client=\"ca-pub-6366953309324763\" data-ad-slot=\"9738116384\"><\/ins>\n<script>\n     (adsbygoogle = window.adsbygoogle || []).push({});\n<\/script>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-13\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p>C, H, ve O elementlerinden olu\u015fan bir bile\u015fi\u011fin 9,2 gram\u0131nda; 4,8 gram C, 1,2 gram da H elementi vard\u0131r.<\/p>\n\n\n\n<p><strong>Buna g\u00f6re bu bile\u015fi\u011fin kaba form\u00fcl\u00fc nedir? (C: 12 g\/mol, H: 1 g\/mol, O: 16 g\/mol)<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong>C<sub>2<\/sub>H<sub>6<\/sub>O<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Bile\u015fikteki elementlere bakarsak, bile\u015fi\u011fin form\u00fcl\u00fc \u015funa benzemeli: C<sub>?<\/sub>H<sub>?<\/sub>O<sub>?<\/sub><\/p>\n\n\n\n<p>Form\u00fcldeki atomlar\u0131n alt\u0131nda ka\u00e7 oldu\u011funu bulmak i\u00e7in, her atomun mol say\u0131s\u0131n\u0131 bulmam\u0131z, buldu\u011fumuz say\u0131lar k\u00fcs\u00fcrl\u00fc ise tam say\u0131ya \u00e7evirmemiz, sadele\u015fiyorlar ise de sadele\u015ftirmemiz yeterli olacakt\u0131r. Hayda ba\u015flayal\u0131m:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#2e3134\">Bile\u015fikte 3 tane element var: C, H ve O. Hepsinin toplam k\u00fctlesi 9,2 gram verilmi\u015f.<br><br>C&#8217;nin k\u00fctlesi: 4,8 gram<br>H&#8217;nin k\u00fctlesi: 1,2 gram<br><br>Bile\u015fikteki O (Oksijen) k\u00fctlesi verilmemi\u015f ama, toplam k\u00fctleden C ve H&#8217;yi \u00e7\u0131kar\u0131rsak, geriye kalan k\u00fctle Oksijenin k\u00fctlesidir:<br><br>O&#8217;nun k\u00fctlesi: 9,2 &#8211; 4,8 &#8211; 1,2 = 3,2 g Oksijen<\/p>\n\n\n\n<p>Herkesin mol say\u0131s\u0131n\u0131 bulal\u0131m:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#3a3333\">Bile\u015fikteki C&#8217;nin mol say\u0131s\u0131:<br>n = m \/ M<sub>A<\/sub><br>n = 4,8 \/ 12<br>n = 0,4 mol<br><br>Bile\u015fikteki H&#8217;nin mol say\u0131s\u0131:<br>n = m \/ M<sub>A<\/sub><br>n = 1,2 \/ 1<br>n = 1,2 mol<br><br>Bile\u015fikteki O&#8217;nun mol say\u0131s\u0131:<br>n = m \/ M<sub>A<\/sub><br>n = 3,2 \/ 16<br>n = 0,2 mol<\/p>\n\n\n\n<p>Herkesin mol say\u0131s\u0131n\u0131 bile\u015fik form\u00fcl\u00fcnde, sa\u011f-alt k\u00f6\u015fesine yazal\u0131m:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#373333\">C<sub>0,4<\/sub>H<sub>1,2<\/sub>O<sub>0,2<\/sub><br><br>Form\u00fcldeki bu say\u0131lar\u0131, tam say\u0131lara \u00e7evirip sadele\u015ftirirsek, bile\u015fi\u011fin kaba form\u00fcl\u00fc ortaya \u00e7\u0131kar. Bunun i\u00e7in \u00f6nce, hepsini 10 ile \u00e7arpal\u0131m:<br>C<sub>4<\/sub>H<sub>12<\/sub>O<sub>2<\/sub><br><br>\u015eimdi hepsini iki ile sadele\u015ftirelim ve kaba form\u00fcl\u00fc bulmu\u015f olal\u0131m:<br>C<sub>2<\/sub>H<sub>6<\/sub>O<\/p>\n\n\n\n<p><em>Cevap: C<sub>2<\/sub>H<sub>6<\/sub>O<\/em><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"5_Sinirlayici_Reaktif_Artan_Madde_Sorulari\">5. S\u0131n\u0131rlay\u0131c\u0131 Reaktif (Artan Madde) Sorular\u0131<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Artan madde sorular\u0131nda, tepkimeye giren en az iki maddenin miktarlar\u0131 verilir. Fakat, katsay\u0131lara g\u00f6re hesapland\u0131\u011f\u0131nda, maddelerin biri di\u011ferine fazla gelir.\n<ul class=\"wp-block-list\">\n<li>Fazla gelen madde, di\u011fer madde bitti\u011fi i\u00e7in artacakt\u0131r.<\/li>\n\n\n\n<li>Artan maddelerin oldu\u011fu tepkimelerde, tamamen biten maddeye <strong>s\u0131n\u0131rlay\u0131c\u0131 bile\u015fen <\/strong>veya <strong>s\u0131n\u0131rlay\u0131c\u0131 reaktif<\/strong> denir.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-14\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-white-color has-vivid-red-background-color has-text-color has-background\" style=\"font-size:18px\">N<sub>2(g)<\/sub> + 3H<sub>2(g)<\/sub> \u2192 2NH<sub>3(g)<\/sub><\/p>\n\n\n\n<p>Ayn\u0131 ko\u015fullardaki, 15&#8217;er Litre N<sub>2<\/sub> ve H<sub>2<\/sub> gaz\u0131 yukar\u0131daki denkleme g\u00f6re tepkimeye giriyor.<\/p>\n\n\n\n<p><strong>Tepkime tam verimle ger\u00e7ekle\u015fti\u011fine g\u00f6re, artan gaz\u0131n ve olu\u015fan NH<sub>3<\/sub> gaz\u0131n\u0131n hacmini hesaplay\u0131n\u0131z.<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong>10 L N<sub>2<\/sub> artar<br>10 L NH<sub>3<\/sub> olu\u015fur.<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Ayn\u0131 ko\u015fullardaki, 15 L N<sub>2<\/sub> ve 15 L H<sub>2<\/sub> gaz\u0131n\u0131n, a\u015fa\u011f\u0131daki denkleme g\u00f6re, tam verimle tepkimeye girmesi isteniyor.<\/p>\n\n\n\n<p>Katsay\u0131lar\u0131na bakarak, tepkime denkleminin alt\u0131nda \u015fu hesaplar\u0131 yapabiliriz:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"500\" height=\"296\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Tepkimelerde-Hesaplamalar-Artan-Madde-Sorulari-Cozumu.jpg\" alt=\"Artan Madde sorular\u0131 b\u00f6yle \u00e7\u00f6z\u00fclebilir.\" class=\"wp-image-9014\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Tepkimelerde-Hesaplamalar-Artan-Madde-Sorulari-Cozumu.jpg 500w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Tepkimelerde-Hesaplamalar-Artan-Madde-Sorulari-Cozumu-300x178.jpg 300w\" sizes=\"auto, (max-width: 500px) 100vw, 500px\" \/><figcaption class=\"wp-element-caption\">Artan Madde sorular\u0131 b\u00f6yle \u00e7\u00f6z\u00fclebilir.<\/figcaption><\/figure>\n<\/div>\n\n\n<p>&#8211; <strong>Ba\u015flang\u0131\u00e7<\/strong>: Ba\u015flang\u0131\u00e7 miktarlar\u0131 soruda verilen miktarlard\u0131r.<br>&#8211; <strong>Tepkime<\/strong>: Ba\u015flang\u0131\u00e7 miktarlar\u0131, katsay\u0131lar\u0131n oran\u0131na g\u00f6re tepkimeye sokulur. Tam verimli tepkimelerde, girenlerdeki maddelerden, en az biri s\u0131f\u0131rlan\u0131ncaya kadar tepkime ger\u00e7ekle\u015fir.<br>Girenlerim miktar\u0131 eksilir (-), \u00fcr\u00fcnlerin miktar\u0131 artar (+).<br>&#8211; <strong>Sonu\u00e7<\/strong>: Ba\u015flang\u0131\u00e7 ile tepkimede harcanan veya olu\u015fan miktar\u0131n toplam\u0131d\u0131r.<\/p>\n\n\n\n<p><em>Cevap: 10 L N<sub>2<\/sub> artar, 10 L NH<sub>3<\/sub> olu\u015fur.<\/em><\/p>\n\n\n\n<p><strong>\u00c7\u00f6z\u00fcm 2<\/strong>:<\/p>\n\n\n\n<p class=\"has-white-color has-vivid-red-background-color has-text-color has-background\" style=\"font-size:18px\">N<sub>2(g)<\/sub> + 3H<sub>2(g)<\/sub> \u2192 2NH<sub>3(g)<\/sub><\/p>\n\n\n\n<p>Ayn\u0131 ko\u015fullardaki gazlar\u0131n, katsay\u0131lar\u0131, hacim oranlar\u0131n\u0131 da veriyordu. Tepkimenin katsay\u0131lar\u0131na bakt\u0131\u011f\u0131m\u0131zda, 1 L N<sub>2<\/sub> ile 3 L H<sub>2<\/sub> gaz\u0131n\u0131n tepkimeye girdi\u011fini anl\u0131yoruz.<\/p>\n\n\n\n<p>H<sub>2<\/sub> gaz\u0131n\u0131n oran\u0131 daha b\u00fcy\u00fck oldu\u011fu i\u00e7in, \u00f6nce o t\u00fckenecektir. Bu durumda, basit bir orant\u0131 ile, N2 gaz\u0131n\u0131n da ne kadar t\u00fckenece\u011fini bulabiliriz:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#414649\">1 L N<sub>2<\/sub> gaz\u0131 3 L H<sub>2<\/sub> gaz\u0131 tepkimeye giriyorsa<br>V L N<sub>2<\/sub> gaz\u0131 15 L H<sub>2<\/sub> gaz\u0131 ile tepkimeye girer<br><br>Bu bir do\u011fru orant\u0131d\u0131r. Denklemini kurarsak, V hacmini bulabiliriz:<br>V . 3 = 1 . 15<br>V = 5 L N<sub>2<\/sub> gaz\u0131<br><br>Yani, 5 L N<sub>2<\/sub> gaz\u0131 t\u00fckenir. O zaman, ba\u015flang\u0131\u00e7ta 15 L al\u0131nd\u0131\u011f\u0131 i\u00e7in:<br>15 &#8211; 5 = 10 L N<sub>2<\/sub> gaz\u0131 artar.<\/p>\n\n\n\n<p>Olu\u015fan NH<sub>3<\/sub> gaz\u0131 miktar\u0131n\u0131, ister tepkimeye kat\u0131lan H<sub>2<\/sub>&#8216;den, isterse N<sub>2<\/sub> gaz\u0131ndan yola \u00e7\u0131karak bulabiliriz. Ben N<sub>2<\/sub> gaz\u0131n\u0131n hacminden yola \u00e7\u0131karak bulmak istiyorum.<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#3b4044\">N<sub>2<\/sub>&#8216;nin katsay\u0131 1, NH<sub>3<\/sub> bile\u015fi\u011finin ise 2&#8217;dir. N<sub>2<\/sub> gaz\u0131ndan 5 L harcanm\u0131\u015ft\u0131r. Bu durumda olu\u015fan NH<sub>3<\/sub> gaz\u0131 i\u00e7in basit bir orant\u0131 kurabiliriz:<br><br>1 L N<sub>2<\/sub> gaz\u0131ndan 2 L NH<sub>3<\/sub> gaz\u0131 olu\u015fursa<br>5 L N<sub>2<\/sub> gaz\u0131ndan V L NH<sub>3<\/sub> gaz\u0131 olu\u015fur.<br><br>Bu bir do\u011fru orant\u0131d\u0131r. Denklemini kurarsak, V hacmini bulabiliriz:<br>1 . V = 5 . 2<br>V = 10 L NH<sub>3<\/sub> gaz\u0131<\/p>\n\n\n\n<p><em>Cevap: 10 L N<sub>2<\/sub> artar, 10 L NH<sub>3<\/sub> olu\u015fur.<\/em><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group stcnnt-yazi-ici-reklam\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p>Bu bir reklamd\u0131r:<\/p>\n\n\n\n<script async=\"\" src=\"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\"><\/script>\n<ins class=\"adsbygoogle\" style=\"display:block; text-align:center;\" data-ad-layout=\"in-article\" data-ad-format=\"fluid\" data-ad-client=\"ca-pub-6366953309324763\" data-ad-slot=\"9738116384\"><\/ins>\n<script>\n     (adsbygoogle = window.adsbygoogle || []).push({});\n<\/script>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-15\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p>132 gram C<sub>3<\/sub>H<sub>8<\/sub> ile 10 mol O<sub>2<\/sub> gaz\u0131 kar\u0131\u015f\u0131m\u0131n\u0131n, tam verimle yanmas\u0131 sonucu, ka\u00e7 mol CO<sub>2<\/sub> gaz\u0131 elde edilir.<\/p>\n\n\n\n<p><strong>Buna g\u00f6re, bu tepkimede, hangi maddeden ka\u00e7 gram artar? (C: 12 g\/mol, H:1 g\/mol, O: 16 g\/mol)<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong>6 mol CO<sub>2<\/sub> olu\u015fur<br>44 gram C<sub>3<\/sub>H<sub>8<\/sub> maddesi artar.<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>\u00d6nce tepkimeyi yazal\u0131m. C<sub>3<\/sub>H<sub>8<\/sub> bile\u015fi\u011fi organik bir bile\u015fiktir. Organik bile\u015fikler yanarsa, CO<sub>2<\/sub> ve H<sub>2<\/sub>O olu\u015fur. Yani tepkime, denkle\u015fmi\u015f haliyle \u015f\u00f6yle olur:<\/p>\n\n\n\n<p class=\"has-white-color has-vivid-red-background-color has-text-color has-background\" style=\"font-size:18px\">C<sub>3<\/sub>H<sub>8<\/sub> + 5O<sub>2<\/sub> \u2192 3CO<sub>2<\/sub> + 4H<sub>2<\/sub>O<\/p>\n\n\n\n<p>\u015eimdi de C<sub>3<\/sub>H<sub>8<\/sub> maddesinin mol say\u0131s\u0131n\u0131 bulal\u0131m:<\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#4b4f52\">132 gram C<sub>3<\/sub>H<sub>8<\/sub> maddesinin mol say\u0131s\u0131:<br>M<sub>A<\/sub> = 3.12 + 8.1<br>M<sub>A<\/sub> = 44 g\/mol<br>n = m \/ M<sub>A<\/sub><br>n = 132 \/ 44<br>n = 3 mol<\/p>\n\n\n\n<p><strong>Ba\u015flang\u0131\u00e7<\/strong>:<br>Ba\u015flang\u0131\u00e7ta, 3 mol C<sub>3<\/sub>H<sub>8<\/sub> ve 10 mol O<sub>2<\/sub> var. Katsay\u0131lar\u0131na bakarsak:<\/p>\n\n\n\n<p class=\"has-white-color has-vivid-red-background-color has-text-color has-background\" style=\"font-size:18px\">C<sub>3<\/sub>H<sub>8<\/sub> + 5O<sub>2<\/sub> \u2192 3CO<sub>2<\/sub> + 4H<sub>2<\/sub>O<\/p>\n\n\n\n<p><strong>Tepkimede<\/strong>:<br>&#8211; <strong><em>Katsay\u0131lara g\u00f6re<\/em><\/strong>, 1 mol C<sub>3<\/sub>H<sub>8<\/sub> i\u00e7in 5 mol O<sub>2<\/sub> gerekiyorsa,<br>&#8212; O zaman <strong><em>2 mol<\/em><\/strong> C<sub>3<\/sub>H<sub>8<\/sub> i\u00e7in <em><strong>10 mol<\/strong><\/em> O<sub>2<\/sub> gerekir.<br>&#8212; Demek ki 10 mol O<sub>2<\/sub> i\u00e7in, 2 mol C<sub>3<\/sub>H<sub>8<\/sub> yeterli.<br>&#8212;- O zaman 1 mol C<sub>3<\/sub>H<sub>8<\/sub> artar.<br>Gelin bu hesab\u0131 daha d\u00fczenli bir \u015fekilde yapal\u0131m:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"650\" height=\"332\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Tepkimelerde-Hesaplamalar-Artan-Madde-Sorulari-Cozumu-2.jpg\" alt=\"Artan Madde sorular\u0131 b\u00f6yle de de \u00e7\u00f6z\u00fcl\u00fcr.\" class=\"wp-image-9016\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Tepkimelerde-Hesaplamalar-Artan-Madde-Sorulari-Cozumu-2.jpg 650w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Tepkimelerde-Hesaplamalar-Artan-Madde-Sorulari-Cozumu-2-300x153.jpg 300w\" sizes=\"auto, (max-width: 650px) 100vw, 650px\" \/><figcaption class=\"wp-element-caption\">Artan Madde sorular\u0131 b\u00f6yle de de \u00e7\u00f6z\u00fcl\u00fcr.<\/figcaption><\/figure>\n<\/div>\n\n\n<p class=\"has-white-color has-vivid-red-background-color has-text-color has-background\">Artan madde 1 mol C<sub>3<\/sub>H<sub>8<\/sub> olmu\u015ftur. C<sub>3<\/sub>H<sub>8<\/sub> maddesinin mol a\u011f\u0131rl\u0131\u011f\u0131n\u0131 (M<sub>A<\/sub>) bulal\u0131m:<br>M<sub>A<\/sub> = (3.12) + (8.1) = 36 + 8 = 44 g\/mol<br><br>Mol a\u011f\u0131rl\u0131\u011f\u0131 zaten 1 mol\u00fcn ka\u00e7 gram oldu\u011fun g\u00f6steriyor. Demek ki 44 gram C<sub>3<\/sub>H<sub>8<\/sub> maddesi artm\u0131\u015ft\u0131r.<\/p>\n\n\n\n<p><em>Cevap: 6 mol CO<sub>2<\/sub> olu\u015fur; 44 gram C<sub>3<\/sub>H<sub>8<\/sub> maddesi artar.<\/em><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group stcnnt-yazi-ici-reklam\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p>Bu bir reklamd\u0131r:<\/p>\n\n\n\n<script async=\"\" src=\"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\"><\/script>\n<ins class=\"adsbygoogle\" style=\"display:block; text-align:center;\" data-ad-layout=\"in-article\" data-ad-format=\"fluid\" data-ad-client=\"ca-pub-6366953309324763\" data-ad-slot=\"9738116384\"><\/ins>\n<script>\n     (adsbygoogle = window.adsbygoogle || []).push({});\n<\/script>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-16\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p>E\u015fit k\u00fctledeki magnezyum ve oksijen tepkimesinden 20 gram magnezyum oksit elde edilmektedir.<\/p>\n\n\n\n<p><strong>Buna g\u00f6re, bu tepkimde, ba\u015flang\u0131\u00e7ta al\u0131nan magnezyum ve oksijen miktarlar\u0131 ve artan elementin miktar\u0131 nedir?  (O: 16 g\/mol, Mg: 24 g\/mol)<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong>Ba\u015flang\u0131\u00e7ta 12&#8217;\u015fer gram Mg ve O<sub>2<\/sub> al\u0131nm\u0131\u015f<\/strong><br><strong>O<sub>2<\/sub>&#8216;nin 4 gram\u0131 artm\u0131\u015ft\u0131r.<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>&#8211; Soruda tarif etti\u011fine g\u00f6re; Magnezyum (Mg), Oksijen (O<sub>2<\/sub>) elementi ile yanarak, Magnezyum oksit (MgO) bile\u015fi\u011fini olu\u015fturuyor.<br>&#8212; Yani \u015f\u00f6yle bir tepkime ger\u00e7ekle\u015fiyor:<\/p>\n\n\n\n<p class=\"has-white-color has-vivid-red-background-color has-text-color has-background\" style=\"font-size:18px\">2Mg + O<sub>2<\/sub> \u2192 2MgO<\/p>\n\n\n\n<p>&#8211; Katsay\u0131lara bakt\u0131\u011f\u0131m\u0131zda, 2 mol Mg ile 1 mol O<sub>2<\/sub> tepkimeye giriyor ve 2 mol MgO bile\u015fi\u011fi olu\u015fuyor.<br>&#8211; Parantez i\u00e7inde verilen de\u011ferlere bakt\u0131\u011f\u0131m\u0131zda;<br>&#8212; Mg elementini mol a\u011f\u0131rl\u0131\u011f\u0131; 24 gram<br>&#8212; O<sub>2<\/sub> elementinin mol a\u011f\u0131rl\u0131\u011f\u0131: 16 + 16 = 32  gram<br>&#8212; MgO bile\u015fi\u011finin mol a\u011f\u0131rl\u0131\u011f\u0131: 24 + 16 = 40 gramd\u0131r.<br><br>&#8211; O zaman, tepkimedeki maddelerin, kat say\u0131lar kadar molleri:<br>&#8212; 2 mol Mg elementi 48 gram,<br>&#8212; 1 mol O<sub>2<\/sub> elementi ise 32 gram,<br>&#8212; 2 mol MgO bile\u015fi\u011fi ise 40 gram geliyor.<br>&#8211; O zaman, tepkimedeki maddelerin k\u00fctleleri aras\u0131na \u015f\u00f6yle bir ili\u015fki var demektir:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"550\" height=\"210\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Tepkimelerde-Hesaplamalar-Artan-Madde-Sorulari-Cozumu-4.jpg\" alt=\"Artan Madde sorusu \u00e7\u00f6z\u00fcm\u00fc\" class=\"wp-image-9026\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Tepkimelerde-Hesaplamalar-Artan-Madde-Sorulari-Cozumu-4.jpg 550w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Tepkimelerde-Hesaplamalar-Artan-Madde-Sorulari-Cozumu-4-300x115.jpg 300w\" sizes=\"auto, (max-width: 550px) 100vw, 550px\" \/><figcaption class=\"wp-element-caption\">Artan Madde sorusu \u00e7\u00f6z\u00fcm\u00fc<\/figcaption><\/figure>\n<\/div>\n\n\n<p>&#8211; Soruda, olu\u015fan MgO bile\u015fi\u011finin 20 gram oldu\u011fu verilmi\u015f.<br>&#8212; Buldu\u011fumuz k\u00fctle oran\u0131ndaki MgO k\u00fctlesi 80 gram oldu. Fakat bizden 20 gram isteniyor.<br>&#8212; O zaman k\u00fctle oran\u0131ndaki miktarlar\u0131n hepsini 4&#8217;e b\u00f6lersek, 20 gram MgO bile\u015fi\u011fi ve bu bile\u015fi\u011fi olu\u015fturmak i\u00e7in gerekli Mg ve O<sub>2<\/sub> miktarlar\u0131n\u0131 elde etmi\u015f oluruz:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"550\" height=\"266\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Tepkimelerde-Hesaplamalar-Artan-Madde-Sorulari-Cozumu-3.jpg\" alt=\"Artan Madde sorusu \u00e7\u00f6z\u00fcm\u00fc\" class=\"wp-image-9024\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Tepkimelerde-Hesaplamalar-Artan-Madde-Sorulari-Cozumu-3.jpg 550w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Tepkimelerde-Hesaplamalar-Artan-Madde-Sorulari-Cozumu-3-300x145.jpg 300w\" sizes=\"auto, (max-width: 550px) 100vw, 550px\" \/><figcaption class=\"wp-element-caption\">Artan Madde sorusu \u00e7\u00f6z\u00fcm\u00fc<\/figcaption><\/figure>\n<\/div>\n\n\n<p>&#8211; Demek ki 20 gram MgO bile\u015fi\u011fi olu\u015fturmak i\u00e7in; 12 gram Mg, 8 gram O<sub>2<\/sub> elementi gerekiyor.<\/p>\n\n\n\n<p>&#8211; Ba\u015flang\u0131\u00e7ta e\u015fit miktarda iseler ve biri bitti ise (tam verim) ikisinin de 12 gram olmaktan ba\u015fka \u015fans\u0131 yoktur.<\/p>\n\n\n\n<p>&#8211; Bu durumda, 12 Mg tamamen bitmi\u015f, 12 gram O<sub>2<\/sub>&#8216;nin 8 gram\u0131 bitmi\u015f:<br>12 &#8211; 8 = 4 gram O<sub>2<\/sub> artm\u0131\u015ft\u0131r.<\/p>\n\n\n\n<p><em>Cevap: Ba\u015flang\u0131\u00e7ta 12&#8217;\u015fer gram Mg ve O<sub>2<\/sub> al\u0131nm\u0131\u015f, O<sub>2<\/sub>&#8216;nin 4 gram\u0131 artm\u0131\u015ft\u0131r.<\/em><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"6_Yuzde_Verim_Sorulari\">6. Y\u00fczde Verim Sorular\u0131<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Tam verimle<\/strong> ger\u00e7ekle\u015fen tepkimelerde, tepkimeye giren <strong><em>maddelerin <\/em><\/strong>en az <strong><em>biri s\u0131f\u0131rlan\u0131r<\/em><\/strong>. Yani, tepkime <strong><em>sonuna kadar<\/em><\/strong> ger\u00e7ekle\u015fir.<\/li>\n\n\n\n<li>\u00dcr\u00fcnlerin miktar\u0131 da, s\u0131f\u0131rlanan (<strong><em>s\u0131n\u0131rlay\u0131c\u0131 bile\u015fenin<\/em><\/strong>) miktar\u0131na g\u00f6re hesaplanan kadard\u0131r.<\/li>\n\n\n\n<li>Bu \u015fekilde, girenlerden en az birinin t\u00fckendi\u011fi tepkimeler, <strong><em>%100 verimle<\/em><\/strong> ger\u00e7ekle\u015fir.<\/li>\n<\/ul>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Fakat <strong><em>ger\u00e7ekte<\/em><\/strong>, bir \u00e7ok tepkime, <strong><em>tam verimle ger\u00e7ekle\u015fmez<\/em><\/strong>. Yani, bir \u00e7ok tepkimede, tam verime g\u00f6re hesaplad\u0131\u011f\u0131m\u0131zdan daha az \u00fcr\u00fcn olu\u015fur. B\u00f6yle tepkimelerde, verim %100 de\u011fildir.<\/li>\n\n\n\n<li>Bir tepkimede, <strong><em>hesaplanan <\/em><\/strong>\u00fcr\u00fcn miktar\u0131na <strong>teorik (kuramsal) verim<\/strong>, tepkimede olu\u015fan <strong><em>ger\u00e7ek \u00fcr\u00fcn<\/em><\/strong> miktar\u0131na da <strong>ger\u00e7ek verim<\/strong> denir.<\/li>\n\n\n\n<li>Yani teorik verim, beklenen \u00fcr\u00fcn miktar\u0131d\u0131r; ger\u00e7ek verim, tepkimede olu\u015fan ve elimize ge\u00e7en \u00fcr\u00fcn miktar\u0131d\u0131r.<\/li>\n<\/ul>\n\n\n\n<p>Bir tepkimenin y\u00fczde verimi, \u015fu form\u00fcl ile hesaplan\u0131r:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"350\" height=\"69\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Hesaplamalar-Yuzde-Verim.jpg\" alt=\"Y\u00fczde Verim\" class=\"wp-image-3712\" style=\"width:284px;height:56px\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Hesaplamalar-Yuzde-Verim.jpg 350w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Hesaplamalar-Yuzde-Verim-300x59.jpg 300w\" sizes=\"auto, (max-width: 350px) 100vw, 350px\" \/><figcaption class=\"wp-element-caption\">Y\u00fczde Verim Form\u00fcl\u00fc<\/figcaption><\/figure>\n<\/div>\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#055c39\">Mesela; biz tepkimeden 5 mol madde beklerken, 3 mol olu\u015ftuysa, o tepkime %100 verimle ger\u00e7ekle\u015fmemi\u015ftir. Tepkimenin verimini \u015f\u00f6yle hesaplayabiliriz:<br><br>% verim = ( 3 \/ 5 ) x 100<br>% verim = 60<br><br>Yani tepkime, %60 verimle ger\u00e7ekle\u015fmi\u015ftir.<\/p>\n\n\n\n<p>Tepkimelerin veriminin, %100&#8217;den daha <strong><em>d\u00fc\u015f\u00fck olmas\u0131n\u0131n<\/em><\/strong> \u00e7e\u015fitli <strong><em>nedenleri <\/em><\/strong>olabilir. Bu nedenlerden baz\u0131lar\u0131 a\u015fa\u011f\u0131da s\u0131ralanm\u0131\u015ft\u0131r:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>\u0130stenmeyen ba\u015fka tepkimeler ger\u00e7ekle\u015ferek istenen \u00fcr\u00fcn\u00fcn yan\u0131nda yan \u00fcr\u00fcnler olu\u015fabilir veya olu\u015fan \u00fcr\u00fcnler kendi aralar\u0131nda ba\u015fka tepkimeler verebilir.<\/li>\n\n\n\n<li>Baz\u0131 tepkimeler tersinir (geri d\u00f6nebilir) tepkimedir. Olu\u015fan \u00fcr\u00fcnlerin bir k\u0131sm\u0131 tekrar ba\u015flang\u0131\u00e7taki maddeleri olu\u015fturur.<\/li>\n\n\n\n<li>Sulu \u00e7\u00f6zeltiler gibi baz\u0131 ortamlardan \u00fcr\u00fcn\u00fcn al\u0131nmas\u0131 zordur. \u0130\u015flemler s\u0131ras\u0131nda madde kayb\u0131 olabilir.<\/li>\n\n\n\n<li>Elde edilen \u00fcr\u00fcn\u00fcn saf olmay\u0131\u015f\u0131, safla\u015ft\u0131rma yap\u0131l\u0131rken madde kayb\u0131 olmas\u0131 verimi d\u00fc\u015f\u00fcrebilir.<\/li>\n\n\n\n<li>Kullan\u0131lan sistem veya cihazlardan kaynaklanan hatalar olabilir.<\/li>\n\n\n\n<li>Tepkimenin ger\u00e7ekle\u015fti\u011fi bas\u0131n\u00e7 ve s\u0131cakl\u0131k ko\u015fullar\u0131na ba\u011fl\u0131 olarak maddenin bir k\u0131sm\u0131 tepkimeye girmeyebilir.<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-17\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p>Bir tepkimede hesaplanan teorik verim 8 gramd\u0131r. Ancak elde edilen \u00fcr\u00fcn 6,4 gramd\u0131r.<\/p>\n\n\n\n<p><strong>Buna g\u00f6re, bu tepkimede % verim nedir?<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong>%80<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#055c39\">Biz tepkimeden 8 gram madde beklerken (teorik verim), 6,4 gram olu\u015ftuysa (ger\u00e7ek verim), o tepkime %100 verimle ger\u00e7ekle\u015fmemi\u015ftir. Tepkimenin verimini \u015f\u00f6yle hesaplayabiliriz:<br><br>% verim = ( 6,4 \/ 8 ) x 100<br>% verim = 80<br><br>Yani tepkime, %80 verimle ger\u00e7ekle\u015fmi\u015ftir.<\/p>\n\n\n\n<p><em>Cevap: %80<\/em><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group stcnnt-yazi-ici-reklam\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p>Bu bir reklamd\u0131r:<\/p>\n\n\n\n<script async=\"\" src=\"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\"><\/script>\n<ins class=\"adsbygoogle\" style=\"display:block; text-align:center;\" data-ad-layout=\"in-article\" data-ad-format=\"fluid\" data-ad-client=\"ca-pub-6366953309324763\" data-ad-slot=\"9738116384\"><\/ins>\n<script>\n     (adsbygoogle = window.adsbygoogle || []).push({});\n<\/script>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-18\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-white-color has-vivid-red-background-color has-text-color has-background\" style=\"font-size:18px\">Ca<sub>(k)<\/sub> + 2HCI<sub>(suda)<\/sub> \u2192 CaCl<sub>2(suda)<\/sub> + H<sub>2(g)<\/sub><\/p>\n\n\n\n<p>Yukar\u0131daki tepkimeye g\u00f6re, Ca ve yeterince HCI\u02bcin tepkimesinden, normal ko\u015fullarda 33,6 L H<sub>2<\/sub> gaz\u0131 olu\u015fmaktad\u0131r.<\/p>\n\n\n\n<p><strong>Tepkimenin %75 verimle ger\u00e7ekle\u015fti\u011fi bilindi\u011fine g\u00f6re, ba\u015flang\u0131\u00e7ta kullan\u0131lan Ca k\u00fctlesi ka\u00e7 gramd\u0131r? (Ca:40 g\/mol)<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong>80 gram<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#41484e\">Normal ko\u015fullarda 33,6 Litre H2 gaz\u0131n\u0131n mol say\u0131s\u0131:<br>n = V \/ 22,4<br>n = 33,6 \/ 22,4<br>n = 1,5 mol<br><br>Katsay\u0131lara bakarsak, Ca ile H<sub>2<\/sub>&#8216;nin katsay\u0131lar\u0131n\u0131 e\u015fit oldu\u011funu g\u00f6r\u00fcr\u00fcz. Bu durumda; 1,5 mol H<sub>2<\/sub> gaz\u0131 i\u00e7in 1,5 mol Ca metali tepkimeye girmi\u015ftir.<br><br>Tepkime %75 verimle ger\u00e7ekle\u015fiyor yani; Ca metalinin %75&#8242; harcan\u0131yor. O zaman ba\u015flang\u0131\u00e7taki Ca metalinin mol say\u0131s\u0131:<br>100 de 75 ise<br>n molde 1,5 mol<br><br>Do\u011fru orant\u0131dan:<br>n . 75 = 100 . 1,5<br>n = 2 mol Ca metali<br><br>2 mol Ca metalinin k\u00fctlesi:<br>m = n . M<sub>A<\/sub><br>m = 2 . 40<br>m = 80 gram<\/p>\n\n\n\n<p><em>Cevap: 80 gram<\/em><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group stcnnt-yazi-ici-reklam\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p>Bu bir reklamd\u0131r:<\/p>\n\n\n\n<script async=\"\" src=\"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\"><\/script>\n<ins class=\"adsbygoogle\" style=\"display:block; text-align:center;\" data-ad-layout=\"in-article\" data-ad-format=\"fluid\" data-ad-client=\"ca-pub-6366953309324763\" data-ad-slot=\"9738116384\"><\/ins>\n<script>\n     (adsbygoogle = window.adsbygoogle || []).push({});\n<\/script>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-19\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p>16 gram k\u00fck\u00fcrt (S) yand\u0131\u011f\u0131nda, NK\u2019da 8,96 litre SO<sub>2<\/sub> elde ediliyor.<\/p>\n\n\n\n<p><strong>Tepkimenin y\u00fczde verimi ka\u00e7t\u0131r? (S: 32 g\/mol)<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong>%75<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Yanmak demek O<sub>2<\/sub> ile tepkimeye girmek demektir. K\u00fck\u00fcrt\u00fcn yanma tepkimesi, denkle\u015fmi\u015f haliyle, \u015f\u00f6yle olmal\u0131d\u0131r:<\/p>\n\n\n\n<p class=\"has-white-color has-vivid-red-background-color has-text-color has-background\" style=\"font-size:18px\">S<sub>(k)<\/sub> + O<sub>2(g)<\/sub> \u2192 SO<sub>2(suda)<\/sub><\/p>\n\n\n\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#343c43\">\u00d6nce, 16 gram K\u00fck\u00fcrtten beklenen SO2 gaz\u0131n\u0131n normal \u015fartlardaki hacmini bulal\u0131m:<br><br>16 g S&#8217;nin mol say\u0131s\u0131:<br>n = m \/ M<sub>A<\/sub><br>n = 16 \/ 32<br>n = 0,5 mol<br><br>Katsay\u0131lar\u0131 ayn\u0131 oldu\u011fu i\u00e7in, 0,5 mol S elementinden, 0,5 mol SO<sub>2<\/sub> gaz\u0131 olu\u015fur. 0,5 mol SO2 gaz\u0131n\u0131n normal ko\u015fullardaki hacmi:<br>V = n . 22,4<br>V = 0,2 . 22,4<br>V = 4,48 L (Teorik verim)<br><br>Soruda verilene g\u00f6re, tepkimeden elde edilen SO<sub>2<\/sub> hacmi:<br>V = 3,36 L (Ger\u00e7ek verim)<br><br>Tepkimenin % verimi:<br><img loading=\"lazy\" decoding=\"async\" width=\"250\" height=\"49\" class=\"wp-image-3712\" style=\"width: 250px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Hesaplamalar-Yuzde-Verim.jpg\" alt=\"Y\u00fczde Verim\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Hesaplamalar-Yuzde-Verim.jpg 350w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Hesaplamalar-Yuzde-Verim-300x59.jpg 300w\" sizes=\"auto, (max-width: 250px) 100vw, 250px\" \/><br>% verim = ( 3,36 \/ 4,48 ) x 100<br>% verim = ( 3 \/ 4 ) x 100<br>% verim = 75<\/p>\n\n\n\n<p><em>Cevap: %75<\/em><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"7_Saf_Olmayan_Madde_Sorulari\">7. Saf Olmayan Madde Sorular\u0131<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Tabiatta <strong><em>saf madde<\/em><\/strong> bulmak olduk\u00e7a <strong><em>zordur<\/em><\/strong>. Laboratuvarlarda kullan\u0131lan maddelerin bile neredeyse hepsi, %100 saf de\u011fildir.\n<ul class=\"wp-block-list\">\n<li>Mesela; laboratuvar ortam\u0131nda, raf\u0131ndan indirip, 40 gram Ca (Kalsiyum) metali tartt\u0131n\u0131z. B\u00fcy\u00fck ihtimal, tartt\u0131\u011f\u0131n\u0131z Ca metalinin i\u00e7inde 1-2 gram <strong><em>ba\u015fka maddeler de vard\u0131r<\/em><\/strong>.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Bir maddenin i\u00e7ine kar\u0131\u015fm\u0131\u015f ba\u015fka maddelere <strong>safs\u0131zl\u0131k <\/strong>denir.<\/li>\n\n\n\n<li>Safs\u0131zl\u0131\u011f\u0131ndan dolay\u0131, 40 gram sand\u0131\u011f\u0131n\u0131z Ca metali ile ger\u00e7ekle\u015ftirdi\u011finiz tepkimede, olu\u015facak \u00fcr\u00fcnler, tam da 40 gram Ca metalinden <strong><em>beklenen kadar olmayacakt\u0131r<\/em><\/strong>.<\/li>\n\n\n\n<li>Bir maddenin, <strong><em>safl\u0131k <\/em><\/strong>miktar\u0131, <strong><em>y\u00fczde <\/em><\/strong>olarak verilir.\n<ul class=\"wp-block-list\">\n<li>Mesela, <strong><em>safl\u0131\u011f\u0131 %80<\/em><\/strong> olan Ca metalinden, <strong><em>100 gram<\/em><\/strong> tartarsan\u0131z, tartt\u0131\u011f\u0131n\u0131z Ca metalinin <strong><em>20 gram\u0131 ba\u015fka maddeler<\/em><\/strong>, 80 gram\u0131 ger\u00e7ekten Ca metalidir.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-20\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-white-color has-vivid-red-background-color has-text-color has-background\" style=\"font-size:18px\">MgCO<sub>3(k)<\/sub> \u2192 MgO<sub>(k)<\/sub> + CO<sub>2(g)<\/sub><\/p>\n\n\n\n<p>%50 safl\u0131kta MgCO<sub>3<\/sub> i\u00e7eren 42 graml\u0131k bir kar\u0131\u015f\u0131m, yukar\u0131daki tepkimeye g\u00f6re ayr\u0131\u015f\u0131yor.<\/p>\n\n\n\n<p><strong>Tepkimede ka\u00e7 gram MgO olu\u015ftu\u011funu ve olu\u015fan CO<sub>2<\/sub> gaz\u0131n\u0131n, NK\u2019daki hacmini hesaplay\u0131n\u0131z. (C: 12 g\/mol, O: 16 g\/mol, Mg: 24 g\/mol)<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-medium-font-size\"><strong>10 g MgO<br>5,6 L CO<sub>2<\/sub><\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\" data-transition=\"fade\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-white-color has-text-color has-background\" style=\"background-color:#31393f\">%50 safl\u0131kta demek, yar\u0131s\u0131 ba\u015fka madde demektir. O zaman; %50 safl\u0131ktaki 42 gram MgCO<sub>3<\/sub> kar\u0131\u015f\u0131m\u0131nda:<br><br>m<sub>MgCO3<\/sub> = (50\/100) . 42<br>m<sub>MgCO3<\/sub> = 21<br><br>gram MgCO<sub>3<\/sub> vard\u0131r.<br><br>21 gram MgCO<sub>3<\/sub> kat\u0131s\u0131n\u0131n mol say\u0131s\u0131:<br>M<sub>A<\/sub> = 24 + 12 + (3.16)<br>M<sub>A<\/sub> = 36 + 48<br>M<sub>A<\/sub> = 84 g\/mol<br><br>n = m \/ M<sub>A<\/sub><br>n = 21 \/ 84<br>n = 0,25 mol MgCO<sub>3<\/sub><br><br>Tepkimedeki b\u00fct\u00fcn katsay\u0131lar e\u015fittir. Bu y\u00fczden 0,25 mol MgCO<sub>3<\/sub> bile\u015fi\u011finden:<br>0,25 mol MgO kat\u0131s\u0131,<br>0,25 mol CO<sub>2<\/sub> gaz\u0131 olu\u015fur.<br><br>0,25 mol MgO kat\u0131s\u0131\u0131n k\u00fctlesi:<br>MA = 24 + 16 = 40<br>m = n . M<sub>A<\/sub><br>m = 0,25 . 40<br>m = 10 gram<br><br>0,25 mol CO<sub>2<\/sub> gaz\u0131n\u0131n, normal ko\u015fullardaki (NK) hacmi:<br>V = n . 22,4<br>V = 0,25 . 22,4<br>V = 5,6 L<\/p>\n\n\n\n<p><em>Cevap: 10 g MgO; 5,6 L CO<sub>2<\/sub><\/em><\/p>\n\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group stcnnt-yazi-ici-reklam\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p>Bu bir reklamd\u0131r:<\/p>\n\n\n\n<script async=\"\" src=\"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\"><\/script>\n<ins class=\"adsbygoogle\" style=\"display:block; text-align:center;\" data-ad-layout=\"in-article\" data-ad-format=\"fluid\" data-ad-client=\"ca-pub-6366953309324763\" data-ad-slot=\"9738116384\"><\/ins>\n<script>\n     (adsbygoogle = window.adsbygoogle || []).push({});\n<\/script>\n<\/div><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Kimyasal Tepkimelerde Hesaplamalar konusu, TYT seviyesinde ve sade bir dille anlat\u0131lm\u0131\u015ft\u0131r.<\/p>\n","protected":false},"author":1,"featured_media":3404,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[222],"tags":[136],"class_list":["post-3402","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-kimyanin-temel-kanunlari-ve-kimyasal-hesaplamalar","tag-kimyasal-tepkimelerde-hesaplamalar"],"_links":{"self":[{"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/posts\/3402","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/comments?post=3402"}],"version-history":[{"count":3,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/posts\/3402\/revisions"}],"predecessor-version":[{"id":32908,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/posts\/3402\/revisions\/32908"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/media\/3404"}],"wp:attachment":[{"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/media?parent=3402"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/categories?post=3402"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/tags?post=3402"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}