{"id":1635,"date":"2020-10-13T01:10:54","date_gmt":"2020-10-12T22:10:54","guid":{"rendered":"https:\/\/sitecenneti.com\/kimya\/?p=1635"},"modified":"2022-07-06T18:05:36","modified_gmt":"2022-07-06T15:05:36","slug":"guclu-etkilesimler","status":"publish","type":"post","link":"https:\/\/sitecenneti.com\/kimya\/tyt-kimya\/kimyasal-turler-arasi-etkilesimler\/guclu-etkilesimler\/","title":{"rendered":"3. G\u00fc\u00e7l\u00fc Etkile\u015fimler"},"content":{"rendered":"<div id=\"toc_container\" class=\"toc_transparent no_bullets\"><p class=\"toc_title\">\u0130&ccedil;indekiler<\/p><ul class=\"toc_list\"><li><a href=\"#Lewis_Elektron_Nokta_Yapisi\">Lewis Elektron Nokta Yap\u0131s\u0131<\/a><ul><li><a href=\"#Noktalar_Nasil_Konulur\">Noktalar Nas\u0131l Konulur?<\/a><ul><li><a href=\"#Ornek\">\u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#Noktalari_Cizgi_ile_Gosterebilirsiniz\">Noktalar\u0131 \u00c7izgi ile G\u00f6sterebilirsiniz<\/a><ul><li><a href=\"#Ornek-2\">\u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#Ilk_20_Atomun_Lewis_Nokta_Yapilari\">\u0130lk 20 Atomun Lewis Nokta Yap\u0131lar\u0131<\/a><\/li><li><a href=\"#Anyonlarin_Lewis_Nokta_Yapisi\">Anyonlar\u0131n Lewis Nokta Yap\u0131s\u0131<\/a><ul><li><a href=\"#Ogretici_Ornek\">\u00d6\u011fretici \u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#Katyonlarin_Lewis_Nokta_Yapisi\">Katyonlar\u0131n Lewis Nokta Yap\u0131s\u0131<\/a><ul><li><a href=\"#Ogretici_Ornek-2\">\u00d6\u011fretici \u00d6rnek:<\/a><\/li><\/ul><\/li><\/ul><\/li><li><a href=\"#Atomlar_Neden_Kimyasal_Baglar_Kurarlar\">Atomlar Neden Kimyasal Ba\u011flar Kurarlar?<\/a><ul><li><ul><li><a href=\"#Ogretici_Ornek-3\">\u00d6\u011fretici \u00d6rnek:<\/a><\/li><\/ul><\/li><\/ul><\/li><li><a href=\"#Iyonik_Bag\">\u0130yonik Ba\u011f<\/a><ul><li><a href=\"#Bohr_Atom_Modeli_Ile_Iyonik_Bagin_Gosterimi\">Bohr Atom Modeli \u0130le \u0130yonik Ba\u011f\u0131n G\u00f6sterimi<\/a><\/li><li><a href=\"#Lewis_Nokta_Yapisi_ile_Iyonik_Bagin_Olusumu\">Lewis Nokta Yap\u0131s\u0131 ile \u0130yonik Ba\u011f\u0131n Olu\u015fumu<\/a><ul><li><a href=\"#Ogretici_Ornek-4\">\u00d6\u011fretici \u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#Caprazlama_Yontemi_ile_Bilesik_Formulu_Bulma\">\u00c7aprazlama Y\u00f6ntemi ile Bile\u015fik Form\u00fcl\u00fc Bulma<\/a><ul><li><a href=\"#Ornek-3\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-4\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-5\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ogretici_Ornek-5\">\u00d6\u011fretici \u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-6\">\u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#Iyonik_Bilesiklerin_Genel_Ozellikleri\">\u0130yonik Bile\u015fiklerin Genel \u00d6zellikleri<\/a><\/li><li><a href=\"#Iyonik_Bagli_Bilesiklerin_Sistematik_Adlandirilmasi\">\u0130yonik Ba\u011fl\u0131 Bile\u015fiklerin Sistematik Adland\u0131r\u0131lmas\u0131<\/a><ul><li><a href=\"#Katyonlar\">Katyonlar<\/a><\/li><li><a href=\"#1_ve_2_Yuklu_Iyonlar\">+1 ve +2 Y\u00fckl\u00fc \u0130yonlar<\/a><\/li><li><a href=\"#3_ve_4_Yuklu_Iyonlar\">+3 ve +4 Y\u00fckl\u00fc \u0130yonlar<\/a><\/li><li><a href=\"#Anyonlar\">Anyonlar<\/a><\/li><li><a href=\"#-1_ve_-2_Yuklu_Iyonlar\">-1 ve -2 Y\u00fckl\u00fc \u0130yonlar<\/a><\/li><li><a href=\"#-3_ve_-4_Yuklu_Iyonlar\">-3 ve -4 Y\u00fckl\u00fc \u0130yonlar<\/a><\/li><li><a href=\"#Iyonik_Bilesiklerin_Sistematik_Adlari\">\u0130yonik Bile\u015fiklerin Sistematik Adlar\u0131<\/a><\/li><\/ul><\/li><\/ul><\/li><li><a href=\"#Kovalent_Bag\">Kovalent Ba\u011f<\/a><ul><li><a href=\"#Ornek-7\">\u00d6rnek:<\/a><\/li><li><a href=\"#Bohr_Atom_Modeli_Ile_Kovalent_Bag_Gosterimi\">Bohr Atom Modeli \u0130le Kovalent Ba\u011f G\u00f6sterimi<\/a><\/li><li><a href=\"#Lewis_Elektron_Nokta_Yapisi_Ile_Kovalent_Bag_Gosterimi\">Lewis Elektron Nokta Yap\u0131s\u0131 \u0130le Kovalent Ba\u011f G\u00f6sterimi<\/a><ul><li><a href=\"#Ogretici_Ornek-6\">\u00d6\u011fretici \u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-8\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-9\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-10\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-11\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-12\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-13\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-14\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-15\">\u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#Tekli_Ikili_ve_Uclu_Kovalent_Baglar\">Tekli, \u0130kili ve \u00dc\u00e7l\u00fc Kovalent Ba\u011flar<\/a><ul><li><a href=\"#Ogretici_Ornek-7\">\u00d6\u011fretici \u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#Polar_8211_Apolar_Kovalent_Bag\">Polar &#8211; Apolar Kovalent Ba\u011f<\/a><ul><li><a href=\"#Apolar_Kovalent_Bag\">Apolar Kovalent Ba\u011f<\/a><\/li><li><a href=\"#Polar_Kovalent_Bag\">Polar Kovalent Ba\u011f<\/a><\/li><li><a href=\"#Ornek-16\">\u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-17\">\u00d6rnek:<\/a><\/li><\/ul><\/li><li><a href=\"#Kovalent_Bagli_Bilesiklerin_Sistematik_Adlandirilmasi\">Kovalent Ba\u011fl\u0131 Bile\u015fiklerin Sistematik Adland\u0131r\u0131lmas\u0131<\/a><ul><li><a href=\"#Ogretici_Ornek-8\">\u00d6\u011fretici \u00d6rnek:<\/a><\/li><li><a href=\"#Ornek-18\">\u00d6rnek:<\/a><\/li><\/ul><\/li><\/ul><\/li><li><a href=\"#III_Metalik_Bag\">III. Metalik Ba\u011f<\/a><ul><li><a href=\"#Ornek-19\">\u00d6rnek:<\/a><\/li><\/ul><\/li><\/ul><\/div>\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube stcnnt-video-banner wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe loading=\"lazy\" title=\"2022 - TYT Kimya - Kimyasal T\u00fcrler Aras\u0131 Etkile\u015fimler - 3. B\u00f6l\u00fcm (I) - Lewis Elektron Nokta Yap\u0131s\u0131\" width=\"1170\" height=\"658\" src=\"https:\/\/www.youtube.com\/embed\/QuYWkWXaqj0?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" allowfullscreen><\/iframe>\n<\/div><figcaption>Kimyasal T\u00fcrler Aras\u0131 Etkile\u015fimler &#8211; G\u00fc\u00e7l\u00fc Etkile\u015fimler 1. B\u00f6l\u00fcm<\/figcaption><\/figure>\n\n\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube stcnnt-video-banner wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe loading=\"lazy\" title=\"2022 TYT - Kimyasal T\u00fcrler Aras\u0131 Etkile\u015fimler - 3. B\u00f6l\u00fcm (II) - G\u00fc\u00e7l\u00fc Etkile\u015fimler - \u0130yonik Ba\u011f\" width=\"1170\" height=\"658\" src=\"https:\/\/www.youtube.com\/embed\/k6vH-SohxXM?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" allowfullscreen><\/iframe>\n<\/div><figcaption>Kimyasal T\u00fcrler Aras\u0131 Etkile\u015fimler &#8211; G\u00fc\u00e7l\u00fc Etkile\u015fimler 2. B\u00f6l\u00fcm<\/figcaption><\/figure>\n\n\n\n<p><strong><em>G\u00fc\u00e7l\u00fc etkile\u015fimler<\/em><\/strong>, zay\u0131f etkile\u015fimlere g\u00f6re kopar\u0131lmas\u0131 daha y\u00fcksek enerji gerektiren ba\u011flard\u0131r.<\/p>\n\n\n\n<ul class=\"wp-block-list\"><li>G\u00fc\u00e7l\u00fc etkile\u015fimleri koparmak i\u00e7in gereken enerji (<strong><em>ba\u011f enerjisi<\/em><\/strong> de denir) genellikle <strong><em>40 kj\/mol veya daha b\u00fcy\u00fckt\u00fcr<\/em><\/strong>.<\/li><li>Zay\u0131f etkile\u015fimlerin ba\u011f enerjileri genellikle 40 kj\/mol de\u011ferinin alt\u0131ndad\u0131r.<\/li><li>G\u00fc\u00e7l\u00fc etkile\u015fimler 3 tanedir:<ol><li>\u0130yonik Ba\u011f<\/li><li>Kovalent Ba\u011f<\/li><li>Metalik Ba\u011f<\/li><\/ol><\/li><li>G\u00fc\u00e7l\u00fc etkile\u015fimlerden:<ul><li><strong><em>\u0130yonik ve kovalent ba\u011fa kimyasal ba\u011flar da denir.<\/em><\/strong><\/li><li>Metalik ba\u011f, g\u00fc\u00e7l\u00fc bir etkile\u015fimdir fakat bir kimyasal ba\u011f olarak ge\u00e7mez.<\/li><\/ul><\/li><\/ul>\n\n\n\n<p class=\"has-background\" style=\"background-color:#f0fffe\">Sevgili \u00f6\u011frencim, g\u00fc\u00e7l\u00fc etkile\u015fimleri anlatmaya ge\u00e7meden \u00f6nce, <strong><em>Lewis Nokta Yap\u0131s\u0131<\/em><\/strong> hakk\u0131nda bilgi vermek istiyorum, \u00e7\u00fcnk\u00fc; Lewis Nokta Yap\u0131lar\u0131, kimyasal ba\u011flar\u0131 daha <strong><em>basit <\/em><\/strong>bir \u015fekilde g\u00f6stermemizi sa\u011flayan yap\u0131lard\u0131r.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><span id=\"Lewis_Elektron_Nokta_Yapisi\">Lewis Elektron Nokta Yap\u0131s\u0131<\/span><\/h2>\n\n\n\n<ul class=\"has-background wp-block-list\" style=\"background-color:#e2f4ff\"><li>&#8220;<strong><em>Lewis Elektron Nokta Yap\u0131s\u0131<\/em><\/strong>&#8221; kavram\u0131;<ul><li>&#8220;<strong><em>Lewis Yap\u0131s\u0131<\/em><\/strong>&#8221; veya<\/li><li>&#8220;<strong><em>Lewis Nokta Yap\u0131s\u0131<\/em><\/strong>&#8221; veya<\/li><li><strong><em>&#8220;Lewis Sembolleri<\/em><\/strong>&#8221; veya<\/li><li>&#8220;<strong><em>Lewis Form\u00fclleri<\/em><\/strong>&#8221; olarak da isimlendirilebilir.<\/li><\/ul><\/li><\/ul>\n\n\n\n<ul class=\"wp-block-list\"><li>Lewis Nokta Yap\u0131s\u0131 (Lewis Elektron Nokta Yap\u0131s\u0131 da denir) demek, bir atomun <strong><em>sembol\u00fcn\u00fcn etraf\u0131na noktalar koymak<\/em><\/strong> demektir.<\/li><\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"600\" height=\"69\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Ikinci-Periyot-Atomlarinin-Lewis-Elektron-Nokta-Yapilari.jpg\" alt=\"2. Periyot Atomlar\u0131n\u0131 Lewis Elektron Nokta Yap\u0131lar\u0131\" class=\"wp-image-2812\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Ikinci-Periyot-Atomlarinin-Lewis-Elektron-Nokta-Yapilari.jpg 600w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Ikinci-Periyot-Atomlarinin-Lewis-Elektron-Nokta-Yapilari-300x35.jpg 300w\" sizes=\"auto, (max-width: 600px) 100vw, 600px\" \/><figcaption>2. Periyot Atomlar\u0131n\u0131n Lewis Elektron Nokta Yap\u0131lar\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<ul class=\"wp-block-list\"><li>Bir atomun b\u00fct\u00fcn <strong><em>kimyasal \u00f6zellikleri, son y\u00f6r\u00fcngesindeki elektronlarda<\/em><\/strong> sakl\u0131d\u0131r.<\/li><li>Bu y\u00fczden, atomlar\u0131n son y\u00f6r\u00fcngesindeki elektronlar \u00e7ok <strong><em>de\u011ferlidir<\/em><\/strong> ve bu y\u00fczden:<ul><li><strong><em>son y\u00f6r\u00fcngedeki<\/em><\/strong> elektronlara de\u011ferlik elektronlar\u0131 denir;<\/li><li>son y\u00f6r\u00fcngedeki elektron say\u0131s\u0131nda da  say\u0131s\u0131na <strong>de\u011ferlik elektron say\u0131s\u0131<\/strong> da denir.<\/li><\/ul><\/li><li>Lewis ad\u0131ndaki kimyac\u0131 bunu fark etmi\u015ftir ve atomun sadece son y\u00f6r\u00fcngesindeki elektronlar\u0131 bilsek bu bize yeter diye d\u00fc\u015f\u00fcnm\u00fc\u015ft\u00fcr.<\/li><li>Lewis, bu ama\u00e7la atomlar\u0131n sembollerinin etraf\u0131na<em> <\/em><strong><em>de\u011ferlik elektron say\u0131lar\u0131 kadar nokta koymu\u015ftur<\/em><\/strong>.<\/li><li><strong><em>Etraf\u0131nda noktalar<\/em><\/strong> olan bu sembollere biz <strong><span class=\"has-inline-color has-luminous-vivid-orange-color\">Lewis Nokta Yap\u0131s\u0131<\/span><\/strong> diyoruz.<\/li><li><a href=\"https:\/\/sitecenneti.com\/kimya\/tyt-kimya\/atom-ve-periyodik-sistem\/3-periyodik-sistem\/#Atomlarda_Elektron_Dagilimi\">Atomlarda Elektron Da\u011f\u0131l\u0131m\u0131<\/a> konusunda, bir atomun son y\u00f6r\u00fcngesinde <strong><em>en fazla 8 elektron<\/em><\/strong> olabilece\u011fini \u00f6\u011frenmi\u015ftik.<ul><li>O zaman, Lewis nokta yap\u0131s\u0131nda da <strong><em>en fazla 8 nokta<\/em><\/strong> olabilir demektir.<\/li><\/ul><\/li><\/ul>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Noktalar_Nasil_Konulur\">Noktalar Nas\u0131l Konulur?<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\"><li>\u00d6nce <a href=\"https:\/\/sitecenneti.com\/kimya\/tyt-kimya\/atom-ve-periyodik-sistem\/3-periyodik-sistem\/#Atomlarda_Elektron_Dagilimi\">atomun elektron da\u011f\u0131l\u0131m\u0131<\/a>n\u0131 yap\u0131p son y\u00f6r\u00fcngesinde ka\u00e7 elektron oldu\u011funu bulaca\u011f\u0131z. Atomun son y\u00f6r\u00fcngesindeki elektron say\u0131s\u0131, Lewis nokta yap\u0131s\u0131ndaki nokta say\u0131s\u0131 demektir.<\/li><li>Noktalar\u0131 koymaya ba\u015flamadan \u00f6nce, atomlar\u0131n sembollerini g\u00f6r\u00fcnmez bir dikd\u00f6rtgen i\u00e7inde hayal edece\u011fiz. Yani sembollerin etraf\u0131nda d\u00f6rt tane kenar\u0131 oldu\u011funu kabul edece\u011fiz.<\/li><li>\u0130lk d\u00f6rt noktay\u0131 bu d\u00f6rt kenar\u0131n her birine birer tane olacak \u015fekilde koyaca\u011f\u0131z. Hangi kenardan ba\u015flayaca\u011f\u0131n\u0131z hi\u00e7 \u00f6nemli de\u011fil.<\/li><li>Be\u015finci nokta ile birlikte art\u0131k kenarlara ikinci noktalar\u0131 koymaya ba\u015flayaca\u011f\u0131z.<\/li><li>A\u015fa\u011f\u0131da, 1 noktadan 8 noktaya kadar, Lewis nokta yap\u0131s\u0131nda kar\u015f\u0131la\u015fabilece\u011fimiz b\u00fct\u00fcn g\u00f6sterimler verilmi\u015ftir.<\/li><\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"600\" height=\"69\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Ikinci-Periyot-Atomlarinin-Lewis-Elektron-Nokta-Yapilari.jpg\" alt=\"2. Periyot Atomlar\u0131n\u0131 Lewis Elektron Nokta Yap\u0131lar\u0131\" class=\"wp-image-2812\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Ikinci-Periyot-Atomlarinin-Lewis-Elektron-Nokta-Yapilari.jpg 600w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Ikinci-Periyot-Atomlarinin-Lewis-Elektron-Nokta-Yapilari-300x35.jpg 300w\" sizes=\"auto, (max-width: 600px) 100vw, 600px\" \/><figcaption>2. Periyot Atomlar\u0131n\u0131 Lewis Elektron Nokta Yap\u0131lar\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<ul class=\"wp-block-list\"><li>N\u00f6t\u00fcr bir atomun, de\u011ferlik elektron say\u0131s\u0131 ka\u00e7 ise, grup numaras\u0131 da oldur.<\/li><li>A\u015fa\u011f\u0131da, 2. periyottaki atomlar\u0131n 1A&#8217;dan 8A&#8217;ya do\u011fru s\u0131rayla Lewis Nokta Yap\u0131lar\u0131 verilmi\u015ftir.<\/li><\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"\u0130kinci Periyot Atomlar\u0131n\u0131n Lewis Nokta Yap\u0131s\u0131\" class=\"wp-image-2771\" width=\"487\" height=\"104\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg 600w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Lewis-Elektron-Nokta-Yapisi-SiteCenneti-300x65.jpg 300w\" sizes=\"auto, (max-width: 487px) 100vw, 487px\" \/><figcaption>2. Periyot Atomlar\u0131n\u0131n Lewis Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p><strong><sub>13<\/sub>X atomunun Lewis elektron nokta yap\u0131s\u0131 a\u015fa\u011fdakilerden hangisindeki gibidir?<\/strong><\/p>\n\n\n\n<p class=\"stcnnt-no-bordered-img\"><img loading=\"lazy\" decoding=\"async\" width=\"400\" height=\"44\" class=\"wp-image-9292\" style=\"width: 400px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Lewsi-Nokta-Yapisi-Soru-Cozumu.jpg\" alt=\"Lewsi-Nokta-Yap\u0131s\u0131-Soru-\u00c7\u00f6z\u00fcm\u00fc\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Lewsi-Nokta-Yapisi-Soru-Cozumu.jpg 400w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Lewsi-Nokta-Yapisi-Soru-Cozumu-300x33.jpg 300w\" sizes=\"auto, (max-width: 400px) 100vw, 400px\" \/><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-huge-font-size\"><strong>A<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>\u00d6nce, <a href=\"https:\/\/sitecenneti.com\/kimya\/tyt-kimya\/atom-ve-periyodik-sistem\/3-periyodik-sistem\/#Atomlarda_Elektron_Dagilimi\">elektron da\u011f\u0131l\u0131m\u0131n\u0131<\/a> yaparak, <sub>13<\/sub>X atomunun son y\u00f6r\u00fcngesinde ka\u00e7 tane elektron var, onu g\u00f6relim. Atomun proton say\u0131s\u0131 13 verilmi\u015f, y\u00fck\u00fc de g\u00f6r\u00fcnm\u00fcyor, demek ki n\u00f6t\u00fcr bir atom, o zaman elektron say\u0131s\u0131 da 13 olmal\u0131d\u0131r. 13 elektron y\u00f6r\u00fcngelere \u015f\u00f6yle da\u011f\u0131l\u0131r:<\/p>\n\n\n\n<p class=\"has-white-color has-luminous-vivid-orange-background-color has-text-color has-background\"><sub>13<\/sub>X<sub>13<\/sub>   )<strong>2e<sup>&#8211;<\/sup><\/strong>    )<strong>8e<sup>&#8211;<\/sup><\/strong>    )<strong>3e<sup>&#8211;<\/sup><\/strong><\/p>\n\n\n\n<p>X atomunun son y\u00f6r\u00fcngesinde 3 elektron vard\u0131r. Demek ki Lewis yap\u0131s\u0131nda sembol\u00fcn\u00fcn etraf\u0131na 3 nokta koymam\u0131z gerekecek. \u00dc\u00e7 nokta d\u00f6rt kenara \u015f\u00f6yle konulur:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"94\" height=\"77\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Lewis-Nokta-Yapisi-2.jpg\" alt=\"Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-1902\"\/><figcaption>3 Noktal\u0131 Lewis Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<p>&#8220;Niye alt kenar bo\u015f kald\u0131?&#8221; diye sorabilirsiniz. Hangi kenar\u0131n bo\u015f kalaca\u011f\u0131 tamamen sizin tercihinize ba\u011fl\u0131d\u0131r. Noktalar\u0131 yerle\u015ftirirken, hangi kenardan ba\u011flayaca\u011f\u0131n\u0131z \u00f6nemli de\u011fildir.<\/p>\n\n\n\n<p><strong>Cevap A \u015f\u0131kk\u0131d\u0131r.<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Noktalari_Cizgi_ile_Gosterebilirsiniz\">Noktalar\u0131 \u00c7izgi ile G\u00f6sterebilirsiniz<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\"><li>Son olarak, <strong>ayn\u0131 kenara<\/strong> koydu\u011funuz iki noktay\u0131 bir tane k\u0131sa \u00e7izgi olarak (\u2014) g\u00f6sterme hakk\u0131m\u0131z vard\u0131r, istedi\u011fimiz zaman bu hakk\u0131m\u0131z\u0131 kullanabiliriz, bu karar tamamen bize aittir.<ul><li>Kenarlardaki bir \u00e7izgi iki elektron demektir.<\/li><\/ul><\/li><li>A\u015fa\u011f\u0131da, 2. periyottaki atomlar\u0131n 1A&#8217;dan 8A&#8217;ya do\u011fru s\u0131rayla Lewis Nokta Yap\u0131lar\u0131 verilmi\u015ftir. Yukar\u0131dakinden farkl\u0131 olarak, ayn\u0131 kenarlardaki iki nokta bir \u00e7izgi ile g\u00f6sterilmi\u015ftir.<\/li><\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/2-Periyot-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"2. Periyot Atomlar\u0131n\u0131n Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2773\" width=\"482\" height=\"93\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/2-Periyot-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg 600w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/2-Periyot-Lewis-Elektron-Nokta-Yapisi-SiteCenneti-300x58.jpg 300w\" sizes=\"auto, (max-width: 482px) 100vw, 482px\" \/><figcaption>2. Periyot Atomlar\u0131n\u0131n Lewis Elektron Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-2\">\u00d6rnek:<\/span><\/h4>\n\n\n<div class=\"wp-block-image stcnnt-no-bordered-img\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"94\" height=\"77\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Lewis-Nokta-Yapisi-3.jpg\" alt=\"Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-1905\"\/><\/figure>\n<\/div>\n\n\n<p><strong>Yukar\u0131da, temel haline ait Lewis Elektron Nokta Yap\u0131s\u0131 verilen X atomu hakk\u0131nda a\u015fa\u011f\u0131dakilerden hangisi kesinlikle yanl\u0131\u015ft\u0131r?<\/strong><\/p>\n\n\n\n<p>A) De\u011ferlik elektron say\u0131s\u0131 7&#8217;dir.<br>B) 7A grubunda bulunan bir atomdur.<br>C) Bir metal atomudur.<br>D) Tabiatta kat\u0131, s\u0131v\u0131 veya gaz halinde bulunabilir.<br>E) Di\u011fer atomlar ile hem iyonik ba\u011f hem de kovalent ba\u011f kurabilir.<br><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-huge-font-size\"><strong>C<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Atomlar\u0131n Lewis nokta yap\u0131lar\u0131nda, \u00e7izgiler iki elektron demektir.<\/p>\n\n\n\n<p>X atomunun \u00e7evresinde 3 tane \u00e7izgi vard\u0131r. Bu 6 elektron demektir. Bir tane de tek nokta vard\u0131r. Bu da 7. elektrondur.<\/p>\n\n\n\n<p>Lewis yap\u0131s\u0131nda toplamda 7 tane elektron oldu\u011fu i\u00e7in, X atomunun de\u011ferlik elektron say\u0131s\u0131 7&#8217;dir.<\/p>\n\n\n\n<p>Temel halinde de\u011ferlik elektron say\u0131s\u0131 7 olan bir atom \u015fu \u00f6zellikleri ta\u015f\u0131yabilir:<\/p>\n\n\n\n<ul class=\"wp-block-list\"><li>7A grubu atomlar\u0131ndan biridir.<\/li><li>Bir halojendir.<\/li><li>Bir ametaldir<\/li><li>Metal atomlar\u0131 ile iyonik ba\u011flar kurar, ametal atomlar\u0131 ile kovalent ba\u011flar kurar.<\/li><li>Tabiatta X<sub>2<\/sub> \u015feklinde molek\u00fcler yap\u0131da bulunur.<\/li><li>Bile\u015fiklerinde -1 ve +7 aras\u0131nda y\u00fck alabilir.<\/li><li>Tabiatta kat\u0131, s\u0131v\u0131 ya da gaz halinde bulunan bir elementin atomu olabilir.<\/li><\/ul>\n\n\n\n<p>Ama bir metal olamaz.<\/p>\n\n\n\n<p><strong>Bu y\u00fczden cevap C \u015f\u0131kk\u0131d\u0131r.<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Ilk_20_Atomun_Lewis_Nokta_Yapilari\">\u0130lk 20 Atomun Lewis Nokta Yap\u0131lar\u0131<\/span><\/h3>\n\n\n\n<p>A\u015fa\u011f\u0131da, periyodik sistemin ilk 20 atomunun temel hallerine ait Lewis Nokta Yap\u0131lar\u0131 verilmi\u015ftir.<br>Ayn\u0131 grupta bulunan atomlar\u0131n Lewis nokta yap\u0131lar\u0131n\u0131n da ayn\u0131 oldu\u011funa dikkat edin.<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"700\" height=\"538\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Lewsi-Elektron-Nokta-Yapisi-Ilk-20-Element.jpg\" alt=\"\u0130lk 20 Atomun Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-1901\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Lewsi-Elektron-Nokta-Yapisi-Ilk-20-Element.jpg 700w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Lewsi-Elektron-Nokta-Yapisi-Ilk-20-Element-300x231.jpg 300w\" sizes=\"auto, (max-width: 700px) 100vw, 700px\" \/><figcaption>\u0130lk 20 Atomun Lewis Elektron Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Anyonlarin_Lewis_Nokta_Yapisi\">Anyonlar\u0131n Lewis Nokta Yap\u0131s\u0131<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\"><li>Anyonlar; atomlar\u0131n <strong><em>elektron almas\u0131yla<\/em><\/strong> olu\u015fur.<\/li><li><strong><em>Anyonlarda, <\/em><\/strong><em>Lewis Yap\u0131s\u0131n\u0131<\/em> bulmak i\u00e7in:<ol><li>Anyonun elektron say\u0131s\u0131n\u0131 hesaplar\u0131z.<\/li><li>Elektron da\u011f\u0131l\u0131m\u0131n\u0131 yapar\u0131z.<\/li><li>Elektron da\u011f\u0131l\u0131m\u0131nda, son y\u00f6r\u00fcngesine bakarak <em>Lewis Nokta Yap\u0131s\u0131n\u0131<\/em> yazabiliriz.<\/li><\/ol><\/li><\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ogretici_Ornek\">\u00d6\u011fretici \u00d6rnek:<\/span><\/h4>\n\n\n\n<p>Gelin <strong><em><sub>17<\/sub>Cl<sup>&#8211;<\/sup><\/em><\/strong> iyonunun <em>Lewis Nokta Yap\u0131s\u0131n\u0131<\/em> yapal\u0131m:<\/p>\n\n\n\n<ul class=\"wp-block-list\"><li><sub>17<\/sub>Cl<sup>1-<\/sup> iyonunun elektron say\u0131s\u0131 18&#8217;dir.<\/li><li>Lewis Nokta Yap\u0131s\u0131n\u0131 g\u00f6stermek i\u00e7in \u00f6nce bu iyonun elektron da\u011f\u0131l\u0131m\u0131n\u0131 yapal\u0131m:<ul><li><sub>17<\/sub>Cl<sup>-1<\/sup><sub>18<\/sub>   )<strong>2e<sup>&#8211;<\/sup><\/strong>    )<strong>8e<sup>&#8211;<\/sup><\/strong>    )<strong>8e<sup>&#8211;<\/sup><\/strong><\/li><\/ul><\/li><\/ul>\n\n\n\n<ul class=\"wp-block-list\"><li>Bu durumda Cl<sup>&#8211;<\/sup> iyonunun de\u011ferlik elektron say\u0131s\u0131 8&#8217;dir. O zaman Lewis Nokta Yap\u0131s\u0131, 8A atomlar\u0131 gibi 8 noktal\u0131 olmal\u0131d\u0131r:<br><img loading=\"lazy\" decoding=\"async\" width=\"100\" height=\"77\" class=\"wp-image-1911\" style=\"width: 100px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Anyonlarin-Lewis-Nokta-Yapisi.jpg\" alt=\"Cl- Anyonunun Lewis Nokta Yap\u0131s\u0131\"><br>(Y\u00fck ile Lewis nokta yap\u0131s\u0131 kar\u0131\u015fmas\u0131n diye k\u00f6\u015feli parantez kullan\u0131lm\u0131\u015ft\u0131r.)<\/li><\/ul>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Katyonlarin_Lewis_Nokta_Yapisi\">Katyonlar\u0131n Lewis Nokta Yap\u0131s\u0131<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\"><li>Katyonlar, son y\u00f6r\u00fcngelerinden elektron vermi\u015f olan atomlard\u0131r.<\/li><li>Katyonlar bu y\u00fczden pozitif (+) y\u00fckl\u00fcd\u00fcrler.<\/li><li>Bir katyonun Lewis elektron yap\u0131s\u0131n\u0131 yaparken:<ol><li><strong><em>\u00d6nce n\u00f6t\u00fcr (temel) <\/em><\/strong>halinin <strong><em>Lewis yap\u0131s\u0131<\/em><\/strong> bulunur.<\/li><li>Sonra, bu yap\u0131dan, katyonun y\u00fck\u00fc kadar <strong><em>nokta silinir<\/em><\/strong> ve i\u015flem biter.<ul><li>E\u011fer atom, son y\u00f6r\u00fcngesindeki b\u00fct\u00fcn elektronlar\u0131 vermi\u015f ise o zaman Lewis yap\u0131s\u0131nda hi\u00e7 nokta olmayacak demektir.<\/li><\/ul><\/li><\/ol><\/li><\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ogretici_Ornek-2\">\u00d6\u011fretici \u00d6rnek:<\/span><\/h4>\n\n\n\n<p>Gelin <strong><sub>13<\/sub>Al<sup>3+<\/sup><\/strong> (Al\u00fcminyum) katyonunun Lewis Elektron Nokta Yap\u0131s\u0131n\u0131 bulal\u0131m.<\/p>\n\n\n\n<ol class=\"wp-block-list\"><li>\u0130lk ad\u0131m, katyonun temel haline ait Lewis elektron nokta yap\u0131s\u0131n\u0131 bulmakt\u0131r:<ul><li><sub>13<\/sub>Al atomunun n\u00f6t\u00fcr iken elektron da\u011f\u0131l\u0131m\u0131 \u015f\u00f6yledir:<br><sub>13<\/sub>Al<sub>13<\/sub>   )<strong>2e<sup>&#8211;<\/sup><\/strong>    )<strong>8e<sup>&#8211;<\/sup><\/strong>    )<strong>3e<sup>&#8211;<\/sup><\/strong><br><br><\/li><li>De\u011ferlik elektron say\u0131s\u0131 3 oldu\u011fu i\u00e7in Lewis elektron nokta yap\u0131s\u0131 \u015f\u00f6yledir:<br><img loading=\"lazy\" decoding=\"async\" width=\"65\" height=\"51\" class=\"wp-image-1906\" style=\"width: 65px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Lewis-Nokta-Yapisi-4.jpg\" alt=\"N\u00f6t\u00fcr Al Atomunun Lewis Nokta Yap\u0131s\u0131\"><\/li><\/ul><\/li><\/ol>\n\n\n\n<ol class=\"wp-block-list\" start=\"2\"><li>\u015eimdi Al atomunun etraf\u0131ndan 3 nokta silelim: <ul><li> Al atomunun Lewis yap\u0131s\u0131ndan 1 nokta silersek, atom 1 elektron vermi\u015f olur ve Al<sup><strong>+<\/strong><\/sup> iyonuna d\u00f6n\u00fc\u015f\u00fcr:<br><img loading=\"lazy\" decoding=\"async\" width=\"80\" height=\"55\" class=\"wp-image-1907\" style=\"width: 80px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Katyonlarin-Lewis-Nokta-Yapisi.jpg\" alt=\"Al+1 Katyonunun Lewis Elektron Yap\u0131s\u0131\"><br>(K\u00f6\u015feli parantez; y\u00fck ile noktalar kar\u0131\u015fmas\u0131n diye \u00e7izilmi\u015ftir.)<\/li><li>Al<sup>+<\/sup> iyonunun Lewis yap\u0131s\u0131ndan 1 nokta silersek, atom 1 elektron daha vermi\u015f olur ve Al<sup><strong>2+<\/strong><\/sup> iyonuna d\u00f6n\u00fc\u015f\u00fcr:<br><img loading=\"lazy\" decoding=\"async\" width=\"85\" height=\"57\" class=\"wp-image-1908\" style=\"width: 85px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Katyonlarin-Lewis-Nokta-Yapisi-2.jpg\" alt=\"Al2+ Katyonunun Lewis Nokta Yap\u0131s\u0131\"><\/li><li>Al<sup>2+<\/sup> iyonunun Lewis yap\u0131s\u0131ndan 1 nokta silersek, atom 1 elektron daha vermi\u015f olur ve Al<sup><strong>3+<\/strong><\/sup> iyonuna d\u00f6n\u00fc\u015f\u00fcr:<br><img loading=\"lazy\" decoding=\"async\" width=\"85\" height=\"56\" class=\"wp-image-1909\" style=\"width: 85px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Katyonlarin-Lewis-Nokta-Yapisi-3.jpg\" alt=\"Al+3 Katyonunun Lewis Elektron Yap\u0131s\u0131\"><\/li><li>Asl\u0131nda, Al<sup>3+<\/sup> iyonunun Lewis yap\u0131s\u0131nda k\u00f6\u015feli paranteze de gerek yoktur. \u00c7\u00fcnk\u00fc; ortal\u0131kta, iyonun y\u00fck\u00fc ile kar\u0131\u015facak bir nokta yoktur, hepsini verip +3 y\u00fck kazanm\u0131\u015ft\u0131r. Yani \u015fu g\u00f6sterim de bu iyonun Lewis yap\u0131s\u0131d\u0131r asl\u0131nda:<\/li><\/ul><\/li><\/ol>\n\n\n\n<p class=\"has-text-align-center\" style=\"font-size:30px\"><strong>Al<sup>3+<\/sup><\/strong><\/p>\n<\/div><\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><span id=\"Atomlar_Neden_Kimyasal_Baglar_Kurarlar\">Atomlar Neden Kimyasal Ba\u011flar Kurarlar?<\/span><\/h2>\n\n\n\n<ul class=\"wp-block-list\"><li>Kimyasal ba\u011flar\u0131n; iyonik ve kovalent ba\u011flar oldu\u011funu daha \u00f6nce \u00f6\u011frenmi\u015ftik.<\/li><li>Atomlar\u0131n iyonik veya kovalent ba\u011f kurarken, <strong><em>ama\u00e7lar\u0131 kararl\u0131 olmakt\u0131r<\/em><\/strong>.<ul><li><span class=\"has-inline-color has-luminous-vivid-orange-color\"><strong><em>Atomlar\u0131 kararl\u0131 yapan \u015fey, kendilerine an yak\u0131n asal gaz atomunun elektron d\u00fczenine sahip olmakt\u0131r.<\/em><\/strong><\/span><\/li><li>A\u015fa\u011f\u0131da ilk 4 asal gaz\u0131n elektron say\u0131lar\u0131 ve d\u00fczenleri verilmi\u015ftir:<ul><li>He<sub>2<\/sub> &nbsp;&nbsp; <span class=\"has-inline-color has-luminous-vivid-orange-color\">)<strong>2e<sup>&#8211;<\/sup><\/strong><\/span> &nbsp;&nbsp;<\/li><li>Ne<sub>10<\/sub> &nbsp;&nbsp; )<strong>2e<sup>&#8211;<\/sup><\/strong> &nbsp;&nbsp;<span class=\"has-inline-color has-luminous-vivid-orange-color\">)<strong>8e<sup>&#8211;<\/sup><\/strong><\/span> &nbsp;&nbsp;<\/li><li>Ar<sub>18<\/sub> &nbsp;&nbsp; )<strong>2e<sup>&#8211;<\/sup><\/strong> &nbsp;&nbsp;)<strong>8e<sup>&#8211;<\/sup><\/strong> &nbsp;&nbsp;<span class=\"has-inline-color has-luminous-vivid-orange-color\">)<strong>8e<sup>&#8211;<\/sup><\/strong><\/span><\/li><li>Kr<sub>36<\/sub> &nbsp;&nbsp; )<strong>2e<sup>&#8211;<\/sup><\/strong> &nbsp;&nbsp;)<strong>8e<sup>&#8211;<\/sup><\/strong> &nbsp;&nbsp;)1<strong>8e<sup>&#8211;<\/sup><\/strong> &nbsp;&nbsp;<span class=\"has-inline-color has-luminous-vivid-orange-color\">)<strong>8e<sup>&#8211;<\/sup><\/strong><\/span><\/li><\/ul><\/li><li>Dikkat edersek He asal gaz\u0131nda sadece 2 elektron vard\u0131r. Di\u011ferler asal gaz atomlar\u0131n\u0131n de\u011ferlik elektron say\u0131s\u0131 8&#8217;dir.<\/li><\/ul><\/li><li><strong><em>He<\/em><\/strong> soy gaz\u0131na yak\u0131n atomlar, elektron say\u0131lar\u0131 2 (duble) olunca He gibi kararl\u0131 olurlar.<ul><li>Bu kurala <strong><em>dublet<\/em><\/strong> kural\u0131 denir.<\/li><li>2 elektronu olan bir atom dubletini tamamlam\u0131\u015ft\u0131r.<\/li><\/ul><\/li><li>Di\u011fer soy gazlara daha yak\u0131n olan atomlar; <strong><em>son y\u00f6r\u00fcngelerinde 8 (okta) elektron<\/em><\/strong> (<strong><em>oktet<\/em><\/strong>) olunca kararl\u0131 olurlar.<ul><li>Bu kurala <strong><em>oktet kural\u0131<\/em><\/strong> denir.<\/li><li>De\u011ferlik elektron say\u0131s\u0131 8 olan bir atom oktetini tamamlam\u0131\u015ft\u0131r.<\/li><\/ul><\/li><li>\u0130\u015fte, <strong><em>kimyasal ba\u011f kurmak, atomlar\u0131n dublet ve oktetlerini tamamlay\u0131p, kararl\u0131 olmalar\u0131n\u0131 sa\u011flar.<\/em><\/strong><\/li><\/ul>\n\n\n\n<ul class=\"wp-block-list\"><li>Asal gazlar zaten kararl\u0131 olduklar\u0131 i\u00e7in kimyasal ba\u011flar kurmazlar.<\/li><li>Asal gazlar\u0131n elektron d\u00fczenlerinde dublet ve oktet zaten tamamlanm\u0131\u015ft\u0131r.<\/li><\/ul>\n\n\n\n<p class=\"has-text-align-center has-background\" style=\"background-color:#fff2f5\">Oktet ya da dubletini tamamlayan atomlara <strong>kararl\u0131 atomlar<\/strong> denir.<\/p>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ogretici_Ornek-3\">\u00d6\u011fretici \u00d6rnek:<\/span><\/h4>\n\n\n\n<ul class=\"wp-block-list\"><li>A\u015fa\u011f\u0131daki atom ve iyonlar dubletini tamamlam\u0131\u015ft\u0131r:<ul><li><sub>2<\/sub>He<sub>2<\/sub>    &nbsp;&nbsp;)2e<sup>&#8211;<\/sup>    &nbsp;&nbsp;<em>(dubletini tamamlam\u0131\u015f)<\/em><\/li><li><sub>3<\/sub>Li<sup>+<\/sup><sub>2<\/sub>   &nbsp;&nbsp; )2e<sup>&#8211;<\/sup>   &nbsp;&nbsp;<em>(dubletini tamamlam\u0131\u015f)<\/em><\/li><li><sub>1<\/sub>H<sup>&#8211;<\/sup><sub>2<\/sub>    &nbsp;&nbsp; )2e<sup>&#8211;<\/sup>    &nbsp;&nbsp;<em>(dubletini tamamlam\u0131\u015f)<\/em><\/li><\/ul><\/li><\/ul>\n\n\n\n<ul class=\"wp-block-list\"><li>A\u015fa\u011f\u0131daki atom ve iyonlar, oktetini tamamlam\u0131\u015ft\u0131r:<ul><li><sub>20<\/sub>Ca<sub>18<\/sub><sup>2+<\/sup>  &nbsp;&nbsp;<span class=\"has-inline-color has-vivid-red-color\"> <\/span>)<strong>2e<sup>&#8211;<\/sup><\/strong>    &nbsp;&nbsp;)<strong>8e<sup>&#8211;<\/sup><\/strong>    &nbsp;&nbsp;)<strong>8e<sup>&#8211;<\/sup><\/strong>  &nbsp;&nbsp;<em>(oktetini tamamlam\u0131\u015f)<\/em><\/li><li><sub>10<\/sub>Ne<sub>10<\/sub>      &nbsp;&nbsp;<span class=\"has-inline-color has-vivid-red-color\">&nbsp;<\/span>&nbsp;)<strong>2e<sup>&#8211;<\/sup><\/strong> &nbsp;&nbsp;)<strong>8e<sup>&#8211;<\/sup><\/strong> &nbsp;&nbsp;<em>(oktetini tamamlam\u0131\u015f)<\/em><\/li><li><sub>17<\/sub>Cl<sub>18<\/sub><sup>-1<\/sup>    &nbsp;&nbsp;<span class=\"has-inline-color has-vivid-red-color\">&nbsp;&nbsp;<\/span>)<strong>2e<sup>&#8211;<\/sup><\/strong> &nbsp;&nbsp;)<strong>8e<sup>&#8211;<\/sup><\/strong> &nbsp;&nbsp;)<strong>8e<sup>&#8211;<\/sup><\/strong> &nbsp;&nbsp;<em>(oktetini tamamlam\u0131\u015f)<\/em><\/li><\/ul><\/li><\/ul>\n<\/div><\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><span id=\"Iyonik_Bag\">\u0130yonik Ba\u011f<\/span><\/h2>\n\n\n\n<ul class=\"wp-block-list\"><li>\u0130yonik ba\u011f ile iyonik ba\u011fl\u0131 bile\u015fikler olu\u015fur.<\/li><li>\u0130yonik ba\u011f\u0131n kurulu\u015fu ve iyonik ba\u011fl\u0131 bile\u015fi\u011fin olu\u015fumu \u015f\u00f6yle ger\u00e7ekle\u015fir:<ol><li>\u0130yonik ba\u011f her zaman, bir <strong><em>metal <\/em><\/strong>atomu ile bir <strong><em>ametal <\/em><\/strong>atomu <strong><em>aras\u0131nda <\/em><\/strong>kurulur.<ul><li><strong><em>Metal <\/em><\/strong>atomlar\u0131n\u0131n son y\u00f6r\u00fcngesinde genellikle <strong><em>1, 2 veya 3 elektron<\/em><\/strong> vard\u0131r.<\/li><li><strong><em>Ametal <\/em><\/strong>atomlar\u0131n\u0131n son y\u00f6r\u00fcngesinde, genellikle <strong><em>5, 6 ve 7 elektron <\/em><\/strong>vard\u0131r.<\/li><\/ul><\/li><li>\u0130yonik ba\u011f kurulurken atomlar <strong><em>elektron al\u0131\u015f-veri\u015fi<\/em><\/strong> yapar.<ul><li><strong><em>Metal <\/em><\/strong>atomu, son y\u00f6r\u00fcngesindeki b\u00fct\u00fcn <strong><em>elektronlar\u0131 <\/em><\/strong>ametal atomuna <strong><em>verir <\/em><\/strong>ve kararl\u0131 bir katyona d\u00f6n\u00fc\u015f\u00fcr.<\/li><li><strong><em>Ametal <\/em><\/strong>atomu, son y\u00f6r\u00fcngesini tamamen dolduracak kadar <strong><em>elektron al\u0131r <\/em><\/strong>ve kararl\u0131 bir anyona d\u00f6n\u00fc\u015f\u00fcr. <\/li><\/ul><\/li><li>Olu\u015fan katyon ve anyonun y\u00fckleri <strong><em>\u00e7aprazlanarak<\/em><\/strong>, iyonik ba\u011fl\u0131 <em><strong>bile\u015fi\u011fin form\u00fcl\u00fc bulunur<\/strong><\/em>.<\/li><\/ol><\/li><\/ul>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Bohr_Atom_Modeli_Ile_Iyonik_Bagin_Gosterimi\">Bohr Atom Modeli \u0130le \u0130yonik Ba\u011f\u0131n G\u00f6sterimi<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\"><li>Metal ve ametal atomlar\u0131n\u0131 y\u00f6r\u00fcngeleri ile \u00e7izerek, al\u0131nan ve verilen elektron say\u0131s\u0131n\u0131 g\u00f6sterebiliriz.<ul><li>B\u00f6ylede iyonik bir ba\u011f\u0131 da g\u00f6stermi\u015f oluruz.<\/li><li>Bu g\u00f6sterime Bohr Atom Modeli ile g\u00f6sterim denir.<\/li><\/ul><\/li><\/ul>\n\n\n\n<p>A\u015fa\u011f\u0131da <sub>11<\/sub>Na ve <sub>17<\/sub>Cl atomunun iyonik ba\u011f kurarak NaCl bile\u015fi\u011fini nas\u0131l olu\u015fturdu\u011fu g\u00f6sterilmi\u015ftir:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"700\" height=\"154\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Turler-Arasi-Etkilesimler-Iyonik-Bag.jpg\" alt=\"Na ile Cl Aras\u0131ndaki \u0130yonik Ba\u011f\u0131n G\u00f6sterimi\" class=\"wp-image-11336\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Turler-Arasi-Etkilesimler-Iyonik-Bag.jpg 700w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Turler-Arasi-Etkilesimler-Iyonik-Bag-300x66.jpg 300w\" sizes=\"auto, (max-width: 700px) 100vw, 700px\" \/><figcaption>Na ile Cl Aras\u0131ndaki \u0130yonik Ba\u011f\u0131n G\u00f6sterimi<\/figcaption><\/figure>\n<\/div>\n\n\n<ul class=\"wp-block-list\"><li>A\u015fa\u011f\u0131da, Na (Sodyum) metali ve Klor (Cl) ametali aras\u0131nda kurulan iyonik ba\u011f\u0131n sim\u00fclasyonu verilmi\u015ftir:<\/li><\/ul>\n\n\n\n<figure class=\"wp-block-embed aligncenter is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe loading=\"lazy\" title=\"| Ionic Bond | My Inter Academy |\" width=\"1170\" height=\"658\" src=\"https:\/\/www.youtube.com\/embed\/j5M9_qoGKXY?start=26&#038;feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" allowfullscreen><\/iframe>\n<\/div><figcaption>NaCl Bile\u015fi\u011findeki \u0130yonik Ba\u011f\u0131n Olu\u015fumu<\/figcaption><\/figure>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Lewis_Nokta_Yapisi_ile_Iyonik_Bagin_Olusumu\">Lewis Nokta Yap\u0131s\u0131 ile \u0130yonik Ba\u011f\u0131n Olu\u015fumu<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\"><li>\u0130ster iyonik ba\u011f olsun ister kovalent ba\u011f olsun, atomlar\u0131n son y\u00f6r\u00fcngesindeki elektronlar ile kurulur.<\/li><li>Lewis nokta yap\u0131s\u0131ndaki elektronlar da zaten son y\u00f6r\u00fcngedeki elektronlard\u0131r.<ul><li>Bu y\u00fczden iyonik ve kovalent ba\u011flar\u0131 Lewis Yap\u0131lar\u0131 ile g\u00f6stermek daha pratiktir.<\/li><\/ul><\/li><\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ogretici_Ornek-4\">\u00d6\u011fretici \u00d6rnek:<\/span><\/h4>\n\n\n\n<p>Lewis nokta yap\u0131s\u0131 ile \u0130yonik ba\u011f\u0131n kurulumunu ve iyonik bir bile\u015fi\u011fin olu\u015fumunu <sub>11<\/sub>Na ve <sub>17<\/sub>Cl \u00f6rne\u011fi atomlar\u0131n\u0131 ba\u011flayarak g\u00f6sterelim.<\/p>\n\n\n\n<ol class=\"wp-block-list\"><li><strong>Ba\u011flayaca\u011f\u0131m\u0131z atomlar\u0131n t\u00fcr\u00fcne karar veriyoruz<\/strong>: Na ile Cl atomlar\u0131n\u0131n, metal mi ametal mi oldu\u011funu ezberden bilemiyorsak \u015f\u00f6yle anlayabiliriz:<ul><li>Na atomunun proton say\u0131s\u0131 11&#8217;dir.<ul><li>Na atomunun, elektron da\u011f\u0131l\u0131m\u0131 \u015f\u00f6yledir:<br><sub>11<\/sub>Na<sub>11<\/sub> &nbsp;&nbsp; )<strong>2e<sup>&#8211;<\/sup><\/strong> &nbsp;&nbsp;)<strong>8e<sup>&#8211;<\/sup><\/strong> &nbsp;&nbsp;)<strong>1e<sup>&#8211;<\/sup><\/strong><\/li><li>De\u011ferlik elektron say\u0131s\u0131 1 oldu\u011fu i\u00e7in <strong><em>Na atomu bir metaldir<\/em><\/strong>.<\/li><\/ul><\/li><li>Cl atomunun proton say\u0131s\u0131 17&#8217;dir.<ul><li>Cl atomunun elektron da\u011f\u0131l\u0131m\u0131 \u015f\u00f6yledir:<br><sub>17<\/sub>Cl<sub>17<\/sub> &nbsp;&nbsp; )<strong>2e<sup>&#8211;<\/sup><\/strong> &nbsp;&nbsp;)<strong>8e<sup>&#8211;<\/sup><\/strong> &nbsp;&nbsp;)<strong>7e<sup>&#8211;<\/sup><\/strong> &nbsp;&nbsp;(temel haldeki Na atomu)<\/li><li>De\u011ferlik elektron say\u0131s\u0131 7 oldu\u011fu i\u00e7in <strong><em>Cl atomu bir ametaldir.<\/em><\/strong><\/li><\/ul><\/li><\/ul><\/li><li><strong>Ba\u011f\u0131n t\u00fcr\u00fcne karar veriyoruz<\/strong>: Elimizde bir metal bir de ametal atomu varsa bir <strong><em>iyonik ba\u011f kuraca\u011f\u0131z<\/em><\/strong> demektir.<\/li><li>\u015eimdi bu iki atomun <strong><em>Lewis yap\u0131lar\u0131n\u0131<\/em><\/strong> g\u00f6sterelim:<ul><li>Na atomunun Lewis yap\u0131s\u0131 \u015f\u00f6yledir:<br><img loading=\"lazy\" decoding=\"async\" width=\"68\" height=\"54\" class=\"wp-image-1929\" style=\"width: 68px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Lewis-Nokta-Yapisi-Na.jpg\" alt=\"11Na Atomunun Temel Hal Lewis Yap\u0131s\u0131\"><\/li><li>Cl atomunun Lewis yap\u0131s\u0131 da \u015f\u00f6yledir:<br><img loading=\"lazy\" decoding=\"async\" width=\"78\" height=\"83\" class=\"wp-image-1930\" style=\"width: 78px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Lewis-Nokta-Yapisi-Cl.jpg\" alt=\"17Cl Atomunun Temel Hal Lewis Yap\u0131s\u0131\"><\/li><\/ul><\/li><li>S\u0131ra <strong><em>elektron al\u0131\u015f-veri\u015finde<\/em><\/strong>. \u0130yonik ba\u011fda elektron al\u0131\u015f-veri\u015fi her zaman \u015f\u00f6yle olur:<ul><li>Metal son y\u00f6r\u00fcngesindeki b\u00fct\u00fcn elektronlar\u0131 verir, Lewis yap\u0131s\u0131 bo\u015f kal\u0131r.<ul><li>Na metalinin son y\u00f6r\u00fcngesinde 1 tane elektron oldu\u011fundan, bu elektron gidince atom, bile\u015fi\u011finde +1 y\u00fckl\u00fc bir iyona d\u00f6n\u00fc\u015fecektir:<br><img loading=\"lazy\" decoding=\"async\" width=\"58\" height=\"54\" class=\"wp-image-1931\" style=\"width: 58px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Lewis-Nokta-Yapisi-Na-1.jpg\" alt=\"Na+ \u0130yonunun Lewis Nokta Yap\u0131s\u0131\"><\/li><\/ul><\/li><li>Ametal son y\u00f6r\u00fcngesini 8&#8217;e tamamlar ve Lewis yap\u0131s\u0131 fullenir, 8 nokta olur.<ul><li>Cl atomu, 7 elektronunu 8 yapmak i\u00e7in 1 elektron alacak ve -1 y\u00fcklenecektir:<br><img loading=\"lazy\" decoding=\"async\" width=\"90\" height=\"84\" class=\"wp-image-1932\" style=\"width: 90px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Lewis-Nokta-Yapisi-Cl-.jpg\" alt=\"Cl- \u0130yonunun Lewis Nokta Yap\u0131s\u0131\"><\/li><\/ul><\/li><\/ul><ul><li>Art\u0131k, Na<sup>+<\/sup> ve Cl<sup>&#8211;<\/sup> iyonlar\u0131, iyonik ba\u011f ile birle\u015ftiler. Bu y\u00fczden bu iki iyonu, ayr\u0131 ayr\u0131 g\u00f6stermek do\u011fru olmaz. Bu iki iyonun Lewis yap\u0131lar\u0131n\u0131 yan yana yazarsak, NaCl bile\u015fi\u011finin Lewis Nokta Yap\u0131s\u0131n\u0131 g\u00f6stermi\u015f oluruz:<br><img loading=\"lazy\" decoding=\"async\" width=\"150\" height=\"87\" class=\"wp-image-1933\" style=\"width: 150px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Lewis-Nokta-Yapisi-NaCl.jpg\" alt=\"NaCl Bile\u015fi\u011finin Lewis Nokta Yap\u0131s\u0131\"><\/li><\/ul><\/li><\/ol>\n\n\n\n<ul class=\"wp-block-list\"><li>Gelin \u015fimdi, en ba\u015f\u0131ndan en sonuna kadar, NaCl bile\u015fi\u011fini olu\u015fumuna ait anlatt\u0131\u011f\u0131m\u0131z her \u015feyi, bir tepkime denkleminde \u00f6zetleyelim:<\/li><\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"500\" height=\"103\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Lewis-Nokta-Yapisi-NaCl-olusumu.jpg\" alt=\"NaCl Bile\u015fi\u011finin Olu\u015fum Tepkimesi\" class=\"wp-image-1934\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Lewis-Nokta-Yapisi-NaCl-olusumu.jpg 500w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Lewis-Nokta-Yapisi-NaCl-olusumu-300x62.jpg 300w\" sizes=\"auto, (max-width: 500px) 100vw, 500px\" \/><figcaption>NaCl Bile\u015fi\u011finin Olu\u015fum Tepkimesi<\/figcaption><\/figure>\n<\/div><\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Caprazlama_Yontemi_ile_Bilesik_Formulu_Bulma\">\u00c7aprazlama Y\u00f6ntemi ile Bile\u015fik Form\u00fcl\u00fc Bulma<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\"><li>Verilen elektron say\u0131s\u0131 ile al\u0131nan elektron say\u0131s\u0131 e\u015fit olmazsa, bile\u015fi\u011fin form\u00fcl\u00fcn\u00fc bulmak i\u00e7in \u00e7aprazlama i\u015flemi yapar\u0131z.<\/li><li><strong><em>\u00c7aprazlama <\/em><\/strong>y\u00f6ntemi, bir iyonik ba\u011fl\u0131 bile\u015fi\u011fin <strong><em>form\u00fcl\u00fcn\u00fc bulman\u0131n<\/em><\/strong> en <strong><em>kolay yoludur<\/em><\/strong>.<ul><li>\u00c7aprazlama y\u00f6nteminde tek <strong><em>ihtiyac\u0131m\u0131z <\/em><\/strong>olan \u015fey, bile\u015fik kuracak iyonlar\u0131n <strong><em>y\u00fckleridir<\/em><\/strong>.<\/li><li>Y\u00fcklerini biliyorsak basit bir <strong><em>\u00e7aprazlama <\/em><\/strong>i\u015flemi <strong><em>ile form\u00fcl\u00fc <\/em><\/strong>an\u0131nda <strong><em>bulabiliriz<\/em><\/strong>.<\/li><\/ul><\/li><li><strong><em>\u00c7aprazlama i\u015fleminde \u015fu kurallara uyulur:<\/em><\/strong><ol><li>\u00d6nce art\u0131 y\u00fckl\u00fc iyon sonra eksi y\u00fckl\u00fc olacak \u015fekilde iki iyon yan yana yaz\u0131l\u0131r.<\/li><li>Sonra bu iki iyonun y\u00fckleri, kar\u015f\u0131l\u0131kl\u0131 olarak birbirinin sa\u011f alt k\u00f6\u015fesine g\u00f6nderilir.<\/li><li>E\u011fer \u00e7aprazlanan say\u0131lar sadele\u015febiliyorsa sadele\u015ftirilir.<\/li><li>Say\u0131s\u0131 1 olan atomlar\u0131n alt\u0131na 1 yazmak gereksizdir.<ul><li>Mesela; NaCl bile\u015fi\u011finde bir tane Na bir tane de Cl vard\u0131r. Bile\u015fi\u011fin form\u00fcl\u00fcn\u00fc Na<sub>1<\/sub>Cl<sub>1<\/sub> \u015feklinde yazmak gereksizdir.<\/li><\/ul><\/li><\/ol><\/li><\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-3\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p><strong>Mesela, Al<sup>+3<\/sup> ile O<sup>-2<\/sup> iyonlar\u0131n\u0131n bile\u015fi\u011fi a\u015fa\u011f\u0131dakilerden hangisidir?<\/strong><\/p>\n\n\n\n<p>A) Al<sub>2<\/sub>O<br>B) AlO<sub>3<\/sub><br>C) AlO<br>D) Al<sub>3<\/sub>O<sub>2<\/sub><br>E) Al<sub>2<\/sub>O<sub>3<\/sub><br><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-huge-font-size\"><strong>E<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>&#8212; Z\u0131t y\u00fckl\u00fc iki iyonun bir bile\u015fik olu\u015fturur.<br>&#8212; Bile\u015fi\u011fin form\u00fcl\u00fc, iyonlar\u0131n \u00e7aprazlanmas\u0131 ile bulunur.<\/p>\n\n\n\n<p>Hemen \u00e7aprazlayal\u0131m:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Caprazlama.jpg\" alt=\"\u00c7aprazlama Y\u00f6ntemi\" class=\"wp-image-1938\" width=\"367\" height=\"86\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Caprazlama.jpg 368w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Caprazlama-300x70.jpg 300w\" sizes=\"auto, (max-width: 367px) 100vw, 367px\" \/><figcaption>\u00c7aprazlama Y\u00f6ntemi ile Al<sub>2<\/sub>O<sub>3<\/sub> Bile\u015fi\u011fi<\/figcaption><\/figure>\n<\/div>\n\n\n<p>G\u00f6r\u00fcld\u00fc\u011f\u00fc gibi, sonu\u00e7, <strong>Al<sub>2<\/sub>O<sub>3<\/sub><\/strong> bile\u015fi\u011fidir.<\/p>\n\n\n\n<p><strong>Bu y\u00fczden cevap C \u015f\u0131kk\u0131d\u0131r.<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<p> <\/p>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-4\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p><strong>Pb<sup>4+<\/sup> ve O<sup>2-<\/sup> iyonlar\u0131 ile a\u015fa\u011f\u0131daki bile\u015fiklerden hangisine aittir?<\/strong><\/p>\n\n\n\n<p>A) PbO<sub>2<\/sub><br>B) Pb<sub>2<\/sub>O<sub>4<\/sub><br>C) Pb<sub>2<\/sub>O<br>D) PbO<br>E) Pb<sub>4<\/sub>O<sub>2<\/sub><br><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-huge-font-size\"><strong>A<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Verilen iyonlar\u0131 \u00e7aprazlarsak hangi bile\u015fikten geldikleri de ortaya \u00e7\u0131kar:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Caprazlama-PbO2.jpg\" alt=\"Pb4+ ve O2- \u0130yonlar\u0131n\u0131n \u00c7aprazlanma \u0130\u015flemi\" class=\"wp-image-1939\" width=\"373\" height=\"168\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Caprazlama-PbO2.jpg 471w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Caprazlama-PbO2-300x135.jpg 300w\" sizes=\"auto, (max-width: 373px) 100vw, 373px\" \/><figcaption>Pb<sup>4+<\/sup> ve O<sup>2-<\/sup> \u0130yonlar\u0131n\u0131n \u00c7aprazlanma \u0130\u015flemi<\/figcaption><\/figure>\n<\/div>\n\n\n<p>Pb<sup>4+<\/sup> ve O<sup>2-<\/sup> iyonlar\u0131 ile olu\u015facak bile\u015fi\u011fin form\u00fcl\u00fc, <strong>PbO<sub>2<\/sub><\/strong>&#8216;dir.<\/p>\n\n\n\n<p><strong>Bu y\u00fczden cevap A \u015f\u0131kk\u0131d\u0131r.<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-5\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p><strong>Ca<sup>2+<\/sup> ve Sn<sup>4+<\/sup> iyonlar\u0131 aras\u0131nda kurulacak bile\u015fi\u011fin form\u00fcl\u00fc a\u015fa\u011f\u0131dakilerden hangisi olmal\u0131d\u0131r?<\/strong><\/p>\n\n\n\n<p>A) CaSn<sub>2<\/sub><br>B) Ca<sub>2<\/sub>Sn<sub>4<\/sub><br>C) CaSn<sub>4<\/sub><br>D) Ca<sub>2<\/sub>Sn<br>E) Bile\u015fik olu\u015fmaz.<br><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-huge-font-size\"><strong>E<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>&#8212; Bu iyonlar\u0131n ikisi de katyondur, pozitif y\u00fckl\u00fcd\u00fcr.<br>&#8212; Ayn\u0131 y\u00fckler birbirini iter.<br>&#8212; Bu y\u00fczden, iki katyonu yan yana getirip siz birle\u015fin ve beraber tak\u0131l\u0131n demek m\u00fcmk\u00fcn de\u011fildir, yan yana duramazlar.<br>&#8212; K\u0131sacas\u0131 iki katyon bile\u015fik olu\u015fturmaz.<br>&#8212; \u0130kisi de anyon olsayd\u0131 yine ayn\u0131 \u015feyleri s\u00f6ylerdik.<\/p>\n\n\n\n<p><strong>Bu y\u00fczden cevap E \u015f\u0131kk\u0131d\u0131r.<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ogretici_Ornek-5\">\u00d6\u011fretici \u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-text-align-left has-white-background-color has-background\"><strong><sub>20<\/sub>Ca (Kalsiyum) ve <sub>7<\/sub>N (Azot) aras\u0131nda kurulacak bile\u015fi\u011fin form\u00fcl\u00fcn\u00fc bulal\u0131m:<\/strong><\/p>\n\n\n\n<ol class=\"wp-block-list\"><li>\u00d6nce, atomlar\u0131n, bile\u015fik kurmadan \u00f6nce (temel halde iken) son y\u00f6r\u00fcngelerine bir g\u00f6z atmam\u0131z gerekiyor. Bunun i\u00e7in, ikisinin de elektron da\u011f\u0131l\u0131mlar\u0131n\u0131 yapmal\u0131y\u0131z:<ul><li><strong><em><sub>20<\/sub>Ca<sub>20<\/sub>  &nbsp;&nbsp;)2e<sup>&#8211;<\/sup>  &nbsp;&nbsp;)8e<sup>&#8211;<\/sup> &nbsp;&nbsp;)8e<sup>&#8211;<\/sup> &nbsp;&nbsp;)2e<sup>&#8211;<\/sup><\/em><\/strong>  (Temel hal)<ul><li>Temel haline bakt\u0131\u011f\u0131m\u0131zda, Ca atomunun son y\u00f6r\u00fcngesinde 2 elektron g\u00f6r\u00fcyoruz.<\/li><li>Bu da demek oluyor ki; bu atom, 2A grubunda ya\u015fayan bir metal atomudur<\/li><li>\u0130yonik ba\u011f yaparken 2 elektron verir ve b\u00f6ylece oktetini tamamlar.<\/li><li>2 elektron verece\u011fi i\u00e7in Ca, bile\u015fi\u011finde +2 y\u00fckl\u00fc olacak demektir.<\/li><\/ul><\/li><li><strong><em><sub>7<\/sub>N<sub>7<\/sub>  &nbsp;&nbsp;)2e<sup>&#8211;<\/sup>  &nbsp;&nbsp;)5e<sup>&#8211;<\/sup> <\/em><\/strong> (Temel hal)<ul><li>Temel haline bakt\u0131\u011f\u0131m\u0131zda, N atomunun son y\u00f6r\u00fcngesinde 5 elektron g\u00f6r\u00fcyoruz.<\/li><li>Bu da demek oluyor ki; bu atom, 5A grubunda ya\u015fayan bir ametal atomudur.<\/li><li>\u0130yonik ba\u011f yaparken 3 elektron al\u0131r ve son y\u00f6r\u00fcngesini 8 yapar; b\u00f6ylece oktetini tamamlar.<\/li><li>3 elektron alaca\u011f\u0131 i\u00e7in N, bile\u015fi\u011finde -3 y\u00fckl\u00fc olacak demektir.<\/li><\/ul><\/li><\/ul><\/li><li>Sonu\u00e7ta anlad\u0131k ki, atomlardan biri metal, di\u011feri ametaldir.<ul><li>O zaman kurulacak bile\u015fik iyonik bir bile\u015fiktir ve y\u00fckler \u00e7aprazlanarak bile\u015fi\u011fin form\u00fcl\u00fc bulunabilir.<\/li><\/ul><\/li><li>Yine anlad\u0131k ki; bu bile\u015fikte, Ca<sup>2+<\/sup> y\u00fckl\u00fc, N<sup>3-<\/sup> y\u00fckl\u00fc olmal\u0131d\u0131r.<ul><li>O zaman bu iyonlar\u0131n olu\u015fturaca\u011f\u0131 bile\u015fi\u011fin form\u00fcl\u00fc (Ca<sub>3<\/sub>N<sub>2<\/sub>), \u00e7aprazlama ile basit\u00e7e bulunabilir:<\/li><\/ul><\/li><\/ol>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Caprazlama-Ca3N2.jpg\" alt=\"Ca2+ ve N3- \u0130yonlar\u0131n\u0131n \u00c7aprazlanmas\u0131\" class=\"wp-image-1942\" width=\"318\" height=\"65\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Caprazlama-Ca3N2.jpg 367w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Caprazlama-Ca3N2-300x61.jpg 300w\" sizes=\"auto, (max-width: 318px) 100vw, 318px\" \/><figcaption>Ca<sup>2+<\/sup> ve N<sup>3-<\/sup> \u0130yonlar\u0131n\u0131n \u00c7aprazlanmas\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<p><\/p>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-6\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p><strong><sub>11<\/sub>Na (Sodyum) ile <sub>16<\/sub>S (K\u00fck\u00fcrt) aras\u0131nda kurulacak bile\u015fi\u011fin form\u00fcl\u00fcn\u00fc ve bu bile\u015fi\u011fin Lewis Nokta Yap\u0131s\u0131n\u0131 g\u00f6steriniz.<\/strong><br><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center\">Bile\u015fi\u011fin form\u00fcl\u00fc: <strong>Na<sub>2<\/sub>S<\/strong><\/p>\n\n\n\n<p><\/p>\n\n\n\n<p class=\"has-text-align-center\">Bile\u015fi\u011fin Lewis Nokta Yap\u0131s\u0131:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Na2S-Lewis-Nokta-Yapisi.jpg\" alt=\"Na2S Bile\u015fi\u011finin Lewsi Nokta Yap\u0131s\u0131\" class=\"wp-image-1945\" width=\"219\" height=\"121\"\/><figcaption>Na<sub>2<\/sub>S Bile\u015fi\u011finin Lewis Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div><\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Bile\u015fi\u011fin form\u00fcl\u00fcn\u00fc \u00e7aprazlama ile bulal\u0131m. Form\u00fcl\u00fcne barak da Lewis yap\u0131s\u0131n\u0131 \u00e7izelim.<\/p>\n\n\n\n<p>\u00c7aprazlama i\u00e7in atomlar\u0131n temel haline bak\u0131p alacaklar\u0131 y\u00fckleri bulmam\u0131z laz\u0131m:<\/p>\n\n\n\n<p class=\"has-white-color has-luminous-vivid-orange-background-color has-text-color has-background\" style=\"font-size:18px\"><sub>11<\/sub>Na<sub>11<\/sub>  &nbsp;&nbsp;)2e<sup>&#8211;<\/sup>  &nbsp;&nbsp;)8e<sup>&#8211;<\/sup> &nbsp;&nbsp;)1e<sup>&#8211;<\/sup>  (Temel hal)<\/p>\n\n\n\n<p>Sodyumun temel halde iken, de\u011ferlik elektron say\u0131s\u0131 1&#8217;mi\u015f. Demek ki bu atom bir metaldir. \u0130yonik ba\u011f yaparken de +1 y\u00fck al\u0131r.<\/p>\n\n\n\n<p class=\"has-white-color has-luminous-vivid-orange-background-color has-text-color has-background\" style=\"font-size:18px\"><sub>16<\/sub>S<sub>16<\/sub>  &nbsp;&nbsp;)2e<sup>&#8211;<\/sup>  &nbsp;&nbsp;)8e<sup>&#8211;<\/sup> &nbsp;&nbsp;)6e<sup>&#8211;<\/sup>  (Temel hal)<\/p>\n\n\n\n<p>K\u00fck\u00fcrt atomunun temel halde, de\u011ferlik elektron say\u0131s\u0131 6&#8217;ym\u0131\u015f. Demek ki bu atom bir ametaldir. \u0130yonik ba\u011f yaparken de -2 y\u00fck al\u0131r.<\/p>\n\n\n\n<p>Demek ki elimizde bir metal bir de ametal atomu var. \u0130yonik ba\u011f yaparken y\u00fckleri s\u0131ras\u0131yla Na<sup>+<\/sup> ve S<sup>2-<\/sup> oluyor.<\/p>\n\n\n\n<p>Na<sup>+<\/sup> ve S<sup>2-<\/sup> iyonlar\u0131n\u0131 \u00e7aprazlarsak, Na<sub>2<\/sub>S form\u00fcl\u00fcn\u00fc elde ederiz.<\/p>\n\n\n\n<p>\u015eimdi, s\u0131ra geldi, Na<sub>2<\/sub>S bile\u015fi\u011finin Lewis Nokta Yap\u0131s\u0131n\u0131 yapmaya. \u0130yonik bile\u015fiklerin Lewis yap\u0131s\u0131n\u0131 yapmakta bir zorluk yok. Bile\u015fikteki iyonlar\u0131n Lewis Yap\u0131lar\u0131n\u0131 ayr\u0131 ayr\u0131 g\u00f6stermemiz yeterli oluyor. Yani iki tane Na<sup>+ <\/sup>ve bir tane S<sup>2-<\/sup> iyonunun Lewis yap\u0131lar\u0131n\u0131 yan yana yazaca\u011f\u0131z. (Ortaya S<sub>2-<\/sub> iyonunu kayaca\u011f\u0131z. Genelde say\u0131s\u0131 az olan ortada, \u00e7ok olan iyonlar da onun etraf\u0131nda olur.)<\/p>\n\n\n\n<p>Sodyum, +1 y\u00fck al\u0131rken son y\u00f6r\u00fcngesini bitirdi\u011fi i\u00e7in Lewis yap\u0131s\u0131nda nokta olmayacak. (\u0130yonik bile\u015fiklerdeki b\u00fct\u00fcn metallerin Lewis yap\u0131lar\u0131 hep b\u00f6yle olur.)<\/p>\n\n\n\n<p>K\u00fck\u00fcrt de, son y\u00f6r\u00fcngesini fulledi\u011fi i\u00e7in, Lewis yap\u0131s\u0131 tam dolu olacak. (\u0130yonik bile\u015fiklerdeki b\u00fct\u00fcn ametallerin Lewis yap\u0131lar\u0131 hep b\u00f6yle olur.)<\/p>\n\n\n\n<p>Sonu\u00e7ta, bile\u015fi\u011fin Lewis yap\u0131s\u0131 \u015f\u00f6yle olacakt\u0131r:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Na2S-Lewis-Nokta-Yapisi.jpg\" alt=\"Na2S Bile\u015fi\u011finin Lewsi Nokta Yap\u0131s\u0131\" class=\"wp-image-1945\" width=\"219\" height=\"121\"\/><figcaption>Na<sub>2<\/sub>S Bile\u015fi\u011finin Lewis Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div><\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group has-background\" style=\"background-color:#e5f0f8\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<p><strong>MERAKLISINA<\/strong><\/p>\n\n\n\n<p>Yukar\u0131da, \u00e7aprazlama ile buldu\u011fumuz Na<sub>2<\/sub>S form\u00fcl\u00fcn\u00fc, Lewis yap\u0131lar\u0131 ile de bulamak istersek, a\u015fa\u011f\u0131daki tepkimeyi yazmam\u0131z yeterli olacakt\u0131r:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"575\" height=\"121\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Na2S-Lewis-Nokta-Yapisi-2.jpg\" alt=\"Na2S Bile\u015fi\u011finin Lewis Nokta Yap\u0131s\u0131\" class=\"wp-image-1946\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Na2S-Lewis-Nokta-Yapisi-2.jpg 575w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/Na2S-Lewis-Nokta-Yapisi-2-300x63.jpg 300w\" sizes=\"auto, (max-width: 575px) 100vw, 575px\" \/><figcaption>Na<sub>2<\/sub>S Bile\u015fi\u011finin Lewis Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div><\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Iyonik_Bilesiklerin_Genel_Ozellikleri\">\u0130yonik Bile\u015fiklerin Genel \u00d6zellikleri<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\"><li>\u0130yonik bile\u015fikler, iyonik ba\u011f ile olu\u015fur.<\/li><li>\u0130yonik bile\u015fikler, metal ile ametal elementlerinin iyonik ba\u011f kurmas\u0131 ile olu\u015fur.<\/li><li>\u0130yonik ba\u011f en sa\u011flam kimyasal ba\u011fd\u0131r. Bu y\u00fczden iyonik bile\u015fiklerin erime ve kaynama noktalar\u0131n y\u00fcksektir.<\/li><li>\u0130yonik ba\u011f, en sa\u011flam kimyasal ba\u011f oldu\u011fu i\u00e7in, iyonik bile\u015fikler tabiatta kat\u0131 halde bulunurlar.<\/li><li>\u0130yonik bile\u015fikler, suda iyonlar\u0131na ayr\u0131\u015farak \u00e7\u00f6z\u00fcn\u00fcrler. Bu y\u00fczden iyonik bile\u015fiklerin sulu \u00e7\u00f6zeltileri elektrik ak\u0131m\u0131n\u0131 iletir yani elektrolit \u00e7\u00f6zeltilerdir.<\/li><\/ul>\n\n\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-4-3 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe loading=\"lazy\" title=\"How Water Dissolves Salt\" width=\"1170\" height=\"878\" src=\"https:\/\/www.youtube.com\/embed\/xdedxfhcpWo?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" allowfullscreen><\/iframe>\n<\/div><figcaption>NaCl (Yemek Tuzu) Bile\u015fi\u011finin Suda \u0130yonlar\u0131na Ayr\u0131\u015farak \u00c7\u00f6z\u00fcnmesi<\/figcaption><\/figure>\n\n\n\n<ul class=\"wp-block-list\"><li>\u0130yonik bile\u015fikler kat\u0131 halde iken, kristallerden meydana gelirler. Kristaller, atom ya da iyonlar\u0131n d\u00fczg\u00fcn bir \u015fekilde istiflenmesiyle olu\u015fur.<\/li><\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"300\" height=\"287\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/09\/NaCl-yemek-tuzu-kristali.jpg\" alt=\"NaCl (Yemek Tuzu) Kristali\" class=\"wp-image-1857\"\/><figcaption>NaCl (Yemek Tuzu) Bile\u015fi\u011finin Kristali<\/figcaption><\/figure>\n<\/div>\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Iyonik_Bagli_Bilesiklerin_Sistematik_Adlandirilmasi\">\u0130yonik Ba\u011fl\u0131 Bile\u015fiklerin Sistematik Adland\u0131r\u0131lmas\u0131<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\"><li>\u0130yonik bile\u015fiklerin <strong><em>sistematik adland\u0131r\u0131lmas\u0131<\/em><\/strong> demek, b\u00fct\u00fcn d\u00fcnyada kabul edilen ve her kimyac\u0131n\u0131n bildi\u011fi, <strong><em>bilimsel adland\u0131rmalar<\/em><\/strong> demektir.<\/li><li>\u0130yonik bile\u015fiklerin form\u00fcllerinde, \u00f6nce bir <strong><em>katyon <\/em><\/strong>sonra da bir <strong><em>anyon <\/em><\/strong>vard\u0131r.<\/li><li>Katyon ve anyonun <strong><em>y\u00fck\u00fc<\/em><\/strong>, \u00e7aprazlama ile birbirinin alt\u0131na inmi\u015ftir ve <strong><em>g\u00f6r\u00fcnmez<\/em><\/strong>. A\u015fa\u011f\u0131da, bu duruma baz\u0131 \u00f6rnekler verilmi\u015ftir. Mesela:<ul><li><strong>NaCl bile\u015fi\u011fi:<\/strong><ul><li><strong>Na<sup>+<\/sup> ve Cl<sup>&#8211;<\/sup> iyonlar\u0131ndan olu\u015fmu\u015ftur.<\/strong><\/li><\/ul><\/li><li><strong>CaCl<sub>2<\/sub> bile\u015fi\u011fi:<\/strong><ul><li><strong>Ca<sup>2+<\/sup> ve Cl<sup>&#8211;<\/sup> iyonlar\u0131ndan olu\u015fmu\u015ftur.<\/strong><\/li><\/ul><\/li><li><strong>PbO bile\u015fi\u011fi:<\/strong><ul><li><strong>Pb<sup>2+<\/sup> ve O<sup>2-<\/sup> iyonlar\u0131ndan olu\u015fur.<\/strong><\/li><\/ul><\/li><li><strong>PbO<sub>2<\/sub> bile\u015fi\u011fi:<\/strong><ul><li><strong>Pb<sup>4+<\/sup> ve O<sup>2-<\/sup> iyonlar\u0131ndan olu\u015fur.<\/strong><\/li><\/ul><\/li><\/ul><\/li><li>\u0130yonik bile\u015fiklerin ad\u0131n\u0131 s\u00f6yleyebilmek i\u00e7in, katyon ve anyonlar\u0131n ad\u0131n\u0131 bilmek gerekir.<\/li><\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><span id=\"Katyonlar\">Katyonlar<\/span><\/h4>\n\n\n\n<ul class=\"wp-block-list\"><li>Katyonlar &#8220;+&#8221; y\u00fckl\u00fc iyonlard\u0131r.<\/li><li>Katyonlar, genellikle, bile\u015fik form\u00fcllerinin ba\u015f\u0131nda bulunur.<\/li><li>Katyonlar\u0131n isimleri genellikle n\u00f6t\u00fcr atomu ile ayn\u0131d\u0131r.<\/li><\/ul>\n\n\n\n<p>A\u015fa\u011f\u0131da, iyonik bile\u015fiklerde kar\u015f\u0131m\u0131za \u00e7\u0131kabilecek katyonlar ve isimleri verilmi\u015ftir:<\/p>\n\n\n\n<h4 class=\"has-text-align-left wp-block-heading\"><span id=\"1_ve_2_Yuklu_Iyonlar\">+1 ve +2 Y\u00fckl\u00fc \u0130yonlar<\/span><\/h4>\n\n\n\n<table class=\"table table-dark\">\n\t<thead>\n\t\t<tr>\n\t\t\t<th scope=\"col\">Katyon<\/th>\n\t\t\t<th scope=\"col\">Ad\u0131<\/th>\n<th scope=\"col\">Katyon<\/th>\n\t\t\t<th scope=\"col\">Ad\u0131<\/th>\n\t\t<\/tr>\n\t<\/thead>\n\t<tbody>\n\t\t<tr>\n\t\t\t<td>H<sup>+<\/sup><\/td>\n\t\t\t<td>Hidrojen<\/td>\n<td>Be<sup>2+<\/sup><\/td>\n\t\t\t<td>Berilyum<\/td>\n\n\t\t<\/tr>\n\t\t<tr>\n\t\t\t<td>Li<sup>+<\/sup><\/td>\n\t\t\t<td>Lityum<\/td>\n<td>Mg<sup>2+<\/sup><\/td>\n\t\t\t<td>Magnezyum<\/td>\n\t\t<\/tr>\n\t\t<tr>\n\t\t\t<td>Na<sup>+<\/sup><\/td>\n\t\t\t<td>Sodyum<\/td>\n<td>Ca<sup>2+<\/sup><\/td>\n\t\t\t<td>Kalsiyum<\/td>\n\t\t<\/tr>\n\t\t<tr>\n\t\t\t<td>K<sup>+<\/sup><\/td>\n\t\t\t<td>Potasyum<\/td>\n<td>Ba<sup>2+<\/sup><\/td>\n\t\t\t<td>Baryum<\/td>\n\t\t<\/tr>\n\t\t<tr>\n\t\t\t<td>Hg<sup>+<\/sup><\/td>\n\t\t\t<td>C\u0131va(I)<\/td>\n<td>Hg<sup>2+<\/sup><\/td>\n\t\t\t<td>C\u0131va(II)<\/td>\n\t\t<\/tr>\n\t\t<tr>\n\t\t\t<td>Cu<sup>+<\/sup><\/td>\n\t\t\t<td>Bak\u0131r(I)<\/td>\n<td>Cu<sup>2+<\/sup><\/td>\n\t\t\t<td>Bak\u0131r(II)<\/td>\n\t\t<\/tr>\n\t\t<tr>\n\t\t\t<td>Ag<sup>+<\/sup><\/td>\n\t\t\t<td>G\u00fcm\u00fc\u015f<\/td>\n<td>Fe<sup>2+<\/sup><\/td>\n\t\t\t<td>Demir(II)<\/td>\n\t\t<\/tr>\n\t\t<tr>\n\t\t\t<td>NH<sub>4<\/sub><sup>+<\/sup><\/td>\n\t\t\t<td>Amonyum<\/td>\n<td>Pb<sup>2+<\/sup><\/td>\n\t\t\t<td>Kur\u015fun(II)<\/td>\n\t\t<\/tr>\n\t\t<tr>\n\t\t\t<td>H<sub>3<\/sub>O<sup>+<\/sup><\/td>\n\t\t\t<td>Hidronyum<\/td>\n<td>Sn<sup>2+<\/sup><\/td>\n\t\t\t<td>Kalay(II)<\/td>\n\t\t<\/tr>\n\t\t<tr>\n\t\t\t<td><\/td>\n\t\t\t<td><\/td>\n<td>Co<sup>2+<\/sup><\/td>\n\t\t\t<td>Kobalt(II)<\/td>\n\t\t<\/tr>\n\t<\/tbody>\n<\/table>\n\n\n\n<h4 class=\"has-text-align-left wp-block-heading\"><span id=\"3_ve_4_Yuklu_Iyonlar\">+3 ve +4 Y\u00fckl\u00fc \u0130yonlar<\/span><\/h4>\n\n\n\n<table class=\"table table-dark\">\n\t<thead>\n\t\t<tr>\n\t\t\t<th scope=\"col\">Katyon<\/th>\n\t\t\t<th scope=\"col\">Ad\u0131<\/th>\n<th scope=\"col\">Katyon<\/th>\n\t\t\t<th scope=\"col\">Ad\u0131<\/th>\n\t\t<\/tr>\n\t<\/thead>\n\t<tbody>\n\t\t<tr>\n\t\t\t<td>Al<sup>3+<\/sup><\/td>\n\t\t\t<td>Al\u00fcminyum<\/td>\n<td>Pb<sup>4+<\/sup><\/td>\n\t\t\t<td>Kur\u015fun(IV)<\/td>\n\t\t<\/tr>\n\t\t<tr>\n\t\t\t<td>Fe<sup>3+<\/sup><\/td>\n\t\t\t<td>Demir(III)<\/td>\n<td>Sn<sup>4+<\/sup><\/td>\n\t\t\t<td>Kalay(IV)<\/td>\n\t\t<\/tr>\n\t\t<tr>\n\t\t\t<td>Co<sup>3+<\/sup><\/td>\n\t\t\t<td>Kobalt(III)<\/td>\n<td><\/td>\n<td><\/td>\n\t\t<\/tr>\n\t<\/tbody>\n<\/table>\n\n\n\n<p class=\"has-background\" style=\"background-color:#fcf2ff\"><strong>D\u0130KKAT<\/strong>:<br>Baz\u0131 metallerin isminin sonunda y\u00fck\u00fc de s\u00f6ylenir:<br><br>Fe<sup>2+<\/sup> : Demir (II)<br>Fe<sup>3+<\/sup> : Demir (III)<br><br>Bu metaller, bile\u015fiklerinde birden fazla y\u00fck alabilen metallerdir. Bu y\u00fczden, metalin o bile\u015fikte hangi y\u00fckte oldu\u011funu belirtmek i\u00e7in, ismi ve y\u00fck\u00fc birlikte s\u00f6ylenir.<br><br>B\u00f6yle metallerin, bile\u015fikteki y\u00fck\u00fcn\u00fc g\u00f6rmek i\u00e7in, \u00e7aprazlama ile kar\u015f\u0131ya g\u00f6nderdi\u011fi say\u0131ya dikkat etmemiz gerekir:<br><br>FeCl<sub><span style=\"color:#ffed46\" class=\"has-inline-color\">2<\/span><\/sub> bile\u015fi\u011findeki demir : Fe<sup><span style=\"color:#f7f46f\" class=\"has-inline-color\">2<\/span>+<\/sup> (Demir-II-)<br>FeCl<sub><span style=\"color:#fff065\" class=\"has-inline-color\">3<\/span><\/sub> bile\u015fi\u011findeki demir : Fe<sup><span style=\"color:#f5e874\" class=\"has-inline-color\">3<\/span>+<\/sup> (Demir-III-)<br>PbO bile\u015fi\u011findeki kur\u015fun : Pb<sup>2+<\/sup> (Kur\u015fun-II-)<br>PbO<sub>2<\/sub> bile\u015fi\u011findeki kur\u015fun : Pb<sup>4+<\/sup> (Kur\u015fun-IV-)<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><span id=\"Anyonlar\">Anyonlar<\/span><\/h4>\n\n\n\n<ul class=\"wp-block-list\"><li>Anyonlar &#8220;-&#8221; y\u00fckl\u00fc iyonlard\u0131r.<\/li><li>Anyonlar, genellikle bile\u015fik <strong><em>form\u00fcllerinin sonunda bulunur.<\/em><\/strong><\/li><li>Anyonlar\u0131n <strong><em>isimleri genellikle n\u00f6t\u00fcr atomlar\u0131ndan farkl\u0131d\u0131r<\/em><\/strong>.<ul><li>Ametaller, anyon olarak okunurken genellikle isimlerinin sonuna <strong><em>&#8220;-\u00fcr&#8221;<\/em><\/strong> eki al\u0131rlar:<ul><li>F<sup>&#8211;<\/sup>: Flor\u00fcr<\/li><li>Cl<sup>&#8211;<\/sup>: Klor\u00fcr<\/li><li>Br<sup>&#8211;<\/sup>: Brom\u00fcr<\/li><li>I<sup>&#8211;<\/sup>: \u0130yod\u00fcr<\/li><li>O<sup>2-<\/sup>: Oksit<\/li><li>S<sup>2-<\/sup>: S\u00fclf\u00fcr<\/li><li>N<sup>3-<\/sup>: Nitr\u00fcr<\/li><li>P<sup>3-<\/sup>: Fosf\u00fcr<\/li><li>C<sup>4-<\/sup>: Karb\u00fcr<\/li><\/ul><\/li><\/ul><\/li><\/ul>\n\n\n\n<p>A\u015fa\u011f\u0131da, iyonik bile\u015fiklerde kar\u015f\u0131m\u0131za \u00e7\u0131kabilecek anyonlar ve isimleri verilmi\u015ftir:<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><span id=\"-1_ve_-2_Yuklu_Iyonlar\">-1 ve -2 Y\u00fckl\u00fc \u0130yonlar<\/span><\/h4>\n\n\n\n<table class=\"table table-dark\">\n\t<thead>\n\t\t<tr>\n\t\t\t<th scope=\"col\">Anyon<\/th>\n\t\t\t<th scope=\"col\">Ad\u0131<\/th>\n<th scope=\"col\">Anyon<\/th>\n\t\t\t<th scope=\"col\">Ad\u0131<\/th>\n\t\t<\/tr>\n\t<\/thead>\n\t<tbody>\n\t\t<tr>\n\t\t\t<td>H<sup>&#8211;<\/sup><\/td>\n\t\t\t<td>Hidr\u00fcr<\/td>\n<td>O<sup>2-<\/sup><\/td>\n\t\t\t<td>Oksit<\/td>\n\t\t<\/tr>\n\t\t<tr>\n\t\t\t<td>F<sup>&#8211;<\/sup><\/td>\n\t\t\t<td>Flor\u00fcr<\/td>\n<td>S<sup>2-<\/sup><\/td>\n\t\t\t<td>S\u00fclf\u00fcr<\/td>\n\t\t<\/tr>\n\t\t<tr>\n\t\t\t<td>Cl<sup>&#8211;<\/sup><\/td>\n\t\t\t<td>Klor\u00fcr<\/td>\n<td>CO<sub>3<\/sub><sup>2-<\/sup><\/td>\n\t\t\t<td>Karbonat<\/td>\n\t\t<\/tr>\n\t\t<tr>\n\t\t\t<td>Br<sup>&#8211;<\/sup><\/td>\n\t\t\t<td>Brom\u00fcr<\/td>\n<td>SO<sub>4<\/sub><sup>2-<\/sup><\/td>\n\t\t\t<td>S\u00fclfat<\/td>\n\t\t<\/tr>\n\t\t<tr>\n\t\t\t<td>I<sup>&#8211;<\/sup><\/td>\n\t\t\t<td>\u0130yod\u00fcr<\/td>\n<td>SO<sub>3<\/sub><sup>2-<\/sup><\/td>\n\t\t\t<td>S\u00fclfit<\/td>\n\t\t<\/tr>\n\t\t<tr>\n\t\t\t<td>OH<sup>&#8211;<\/sup><\/td>\n\t\t\t<td>Hidroksit (Hidroksil)<\/td>\n<td>MnO<sub>4<\/sub><sup>2-<\/sup><\/td>\n\t\t\t<td>Manganat<\/td>\n\t\t<\/tr>\n\t\t<tr>\n\t\t\t<td>CN<sup>&#8211;<\/sup><\/td>\n\t\t\t<td>Siyan\u00fcr<\/td>\n<td><\/td>\n<td><\/td>\n\t\t<\/tr>\n\t\t<tr>\n\t\t\t<td>NO<sub>3<\/sub><sup>&#8211;<\/sup><\/td>\n\t\t\t<td>Nitrat<\/td>\n<td><\/td>\n<td><\/td>\n\t\t<\/tr>\n\t\t<tr>\n\t\t\t<td>CH<sub>3<\/sub>COO<sup>&#8211;<\/sup><\/td>\n\t\t\t<td>Asetat<\/td>\n<td><\/td>\n<td><\/td>\n\t\t<\/tr>\n\t\t<tr>\n\t\t\t<td>MnO<sub>4<\/sub><sup>&#8211;<\/sup><\/td>\n\t\t\t<td>Permanganat<\/td>\n<td><\/td>\n<td><\/td>\n\t\t<\/tr>\n\t\t<tr>\n\t\t\t<td>HCO<sub>3<\/sub><sup>&#8211;<\/sup><\/td>\n\t\t\t<td>Bikarbonat<\/td>\n<td><\/td>\n<td><\/td>\n\t\t<\/tr>\n\t\t<tr>\n\t\t\t<td>HSO<sub>4<\/sub><sup>&#8211;<\/sup><\/td>\n\t\t\t<td>Bis\u00fclfat<\/td>\n<td><\/td>\n<td><\/td>\n\t\t<\/tr>\n\t\t<tr>\n\t\t\t<td>HSO<sub>3<\/sub><sup>&#8211;<\/sup><\/td>\n\t\t\t<td>Bis\u00fclfit<\/td>\n<td><\/td>\n<td><\/td>\n\t\t<\/tr>\n\t<\/tbody>\n<\/table>\n\n\n\n<h4 class=\"wp-block-heading\"><span id=\"-3_ve_-4_Yuklu_Iyonlar\">-3 ve -4 Y\u00fckl\u00fc \u0130yonlar<\/span><\/h4>\n\n\n\n<table class=\"table table-dark\">\n\t<thead>\n\t\t<tr>\n\t\t\t<th scope=\"col\">Anyon<\/th>\n\t\t\t<th scope=\"col\">Ad\u0131<\/th>\n<th scope=\"col\">Anyon<\/th>\n\t\t\t<th scope=\"col\">Ad\u0131<\/th>\n\t\t<\/tr>\n\t<\/thead>\n\t<tbody>\n\t\t<tr>\n\t\t\t<td>N<sup>3-<\/sup><\/td>\n\t\t\t<td>Nitr\u00fcr<\/td>\n<td>C<sup>4-<\/sup><\/td>\n\t\t\t<td>Karb\u00fcr<\/td>\n\t\t<\/tr>\n\t\t<tr>\n\t\t\t<td>P<sup>3-<\/sup><\/td>\n\t\t\t<td>Fosf\u00fcr<\/td>\n<td><\/td>\n<td><\/td>\n\t\t<\/tr>\n\t\t<tr>\n\t\t\t<td>PO<sub>4<\/sub><sup>3-<\/sup><\/td>\n\t\t\t<td>Fosfat<\/td>\n<td><\/td>\n<td><\/td>\n\t\t<\/tr>\n\t<\/tbody>\n<\/table>\n\n\n\n<h4 class=\"wp-block-heading\"><span id=\"Iyonik_Bilesiklerin_Sistematik_Adlari\">\u0130yonik Bile\u015fiklerin Sistematik Adlar\u0131<\/span><\/h4>\n\n\n\n<ul class=\"wp-block-list\"><li>\u0130yonik bile\u015fikleri <strong><em>okurken<\/em><\/strong>, <strong><em>yapmam\u0131z gereken<\/em><\/strong> tek \u015fey:<ul><li>bile\u015fikte g\u00f6rd\u00fc\u011f\u00fcm\u00fcz <strong><em>katyon ve anyonlar\u0131 s\u0131rayla okumakt\u0131r<\/em><\/strong>.<\/li><\/ul><\/li><li>Bu y\u00fczden \u00f6ncelikle, biraz <strong><em>ezber <\/em><\/strong>yaparak, iyonik bile\u015fiklerde kar\u015f\u0131m\u0131za \u00e7\u0131kabilecek <strong><em>anyon ve katyonlar\u0131 \u00f6\u011frenmemiz gerekiyor<\/em><\/strong>.<\/li><\/ul>\n\n\n\n<p>A\u015fa\u011f\u0131da, iyonik ba\u011f\u0131l\u0131 baz\u0131 bile\u015fiklerin sistematik adlar\u0131 verilmi\u015ftir:<\/p>\n\n\n\n<ul class=\"wp-block-list\"><li><strong>Na<span class=\"has-inline-color has-vivid-purple-color\">Cl<\/span> : Sodyum <span class=\"has-inline-color has-vivid-purple-color\">klor\u00fcr<\/span><\/strong><\/li><li><strong>Na<span class=\"has-inline-color has-vivid-purple-color\">NO<sub>3<\/sub><\/span> : Sodyum <span class=\"has-inline-color has-vivid-purple-color\">nitrat<\/span><\/strong><\/li><li><strong>Pb<span class=\"has-inline-color has-vivid-purple-color\">O<\/span> : Kur\u015fun(II) <span class=\"has-inline-color has-vivid-purple-color\">oksit<\/span><\/strong><\/li><li><strong>NH<sub>4<\/sub><span class=\"has-inline-color has-vivid-purple-color\">NO<sub>3<\/sub><\/span> : Amonyum <span class=\"has-inline-color has-vivid-purple-color\">nitrat<\/span><\/strong><\/li><li><strong>Ca<span class=\"has-inline-color has-vivid-purple-color\">CO<sub>3<\/sub><\/span> : Kalsiyum <span class=\"has-inline-color has-vivid-purple-color\">karbonat<\/span><\/strong><\/li><li><strong>Mg<span class=\"has-inline-color has-vivid-purple-color\">H<sub>2<\/sub> <\/span>: Magnezyum <span class=\"has-inline-color has-vivid-purple-color\">hidr\u00fcr<\/span><\/strong><\/li><li><strong>Hg<sub>2<\/sub><span class=\"has-inline-color has-vivid-purple-color\">O<\/span> : C\u0131va(I) <span class=\"has-inline-color has-vivid-purple-color\">oksit<\/span><\/strong><\/li><li><strong>Ba<span class=\"has-inline-color has-vivid-purple-color\">SO<sub>4<\/sub><\/span> : Baryum <span class=\"has-inline-color has-vivid-purple-color\">s\u00fclfat<\/span><\/strong><\/li><li><strong>Ca(<span class=\"has-inline-color has-vivid-purple-color\">OH<\/span>)<sub>2<\/sub> : Kalsiyum <span class=\"has-inline-color has-vivid-purple-color\">hidroksit<\/span><\/strong><\/li><li><strong>Al<sub>4<\/sub><span class=\"has-inline-color has-vivid-purple-color\">C<\/span><sub>3<\/sub> : Al\u00fcminyum <span class=\"has-inline-color has-vivid-purple-color\">karb\u00fcr<\/span><\/strong><\/li><li><strong>Ca(<span class=\"has-inline-color has-vivid-purple-color\">NO<sub>3<\/sub><\/span>)<sub>2<\/sub> : Kalsiyum <span class=\"has-inline-color has-vivid-purple-color\">nitrat<\/span><\/strong><\/li><li><strong>Ba<sub>3<\/sub>(<span class=\"has-inline-color has-vivid-purple-color\">PO<sub>4<\/sub><\/span>)<sub>2<\/sub> : Baryum <span class=\"has-inline-color has-vivid-purple-color\">fosfat<\/span><\/strong><\/li><li><strong>Pb<span class=\"has-inline-color has-vivid-purple-color\">I<\/span><sub>2<\/sub> : Kur\u015fun(II) <span class=\"has-inline-color has-vivid-purple-color\">iyod\u00fcr<\/span><\/strong><\/li><li><strong>Fe<sub>2<\/sub>(<span class=\"has-inline-color has-vivid-purple-color\">SO<sub>4<\/sub><\/span>)<sub>3<\/sub> : Demir(III) <span class=\"has-inline-color has-vivid-purple-color\">s\u00fclfat<\/span><\/strong><\/li><li><strong>Fe<span class=\"has-inline-color has-vivid-purple-color\">SO<sub>4<\/sub> <\/span>: Demir(II) <span class=\"has-inline-color has-vivid-purple-color\">s\u00fclfat<\/span><\/strong><\/li><\/ul>\n\n\n\n<h2 class=\"wp-block-heading\"><span id=\"Kovalent_Bag\">Kovalent Ba\u011f<\/span><\/h2>\n\n\n\n<ul class=\"wp-block-list\"><li><strong><em>G\u00fc\u00e7l\u00fc etkile\u015fimlerin<\/em><\/strong> ikincisi kovalent ba\u011fd\u0131r.<\/li><li>Kovalent ba\u011f, <strong><em>ametaller aras\u0131nda kurulur<\/em><\/strong>.<\/li><li><strong><em>Ametal <\/em><\/strong>atomlar\u0131 <strong><em>son y\u00f6r\u00fcngelerinde<\/em><\/strong> genellikle; <strong><em>5, 6 veya 7<\/em><\/strong> tane <strong><em>elektron <\/em><\/strong>bulundururlar.<\/li><li>\u0130ki ametal atomu birer elektronunu ortakla\u015fa kullan\u0131nca, <strong><em>1 kovalent ba\u011f kurulmu\u015f olur.<\/em><\/strong><ul><li>Her <strong><em>kovalent ba\u011f<\/em><\/strong>, <strong><em>2 elektronun<\/em><\/strong> ortakla\u015fa kullan\u0131lmas\u0131 ile <strong><em>olu\u015fur<\/em><\/strong>.<\/li><li>2 elektron <strong><em>1 \u00e7izgi <\/em><\/strong>olarak g\u00f6sterilebildi\u011fi i\u00e7in, kovalent ba\u011flar, atomlar\u0131n aras\u0131nda ve birer k\u0131sa \u00e7izgi <strong><em>olarak g\u00f6sterilir<\/em><\/strong>.<\/li><li>Ametal atomlar\u0131n\u0131n, kovalent ba\u011f kurmak i\u00e7in, ortakla\u015fa kulland\u0131klar\u0131 elektronlar, <strong><em>son y\u00f6r\u00fcngelerindeki elektronlard\u0131r<\/em><\/strong>.<\/li><\/ul><\/li><\/ul>\n\n\n\n<ul class=\"wp-block-list\"><li>Kovalent ba\u011f kurarken, ametal atomlar\u0131, kar\u015f\u0131l\u0131kl\u0131 olarak birer <strong><em>elektronunu ortakla\u015fa kullan\u0131rlar<\/em><\/strong>.<ul><li><strong><span class=\"has-inline-color has-luminous-vivid-orange-color\">Bir ametal atomu, <em>son y\u00f6r\u00fcngesini fullemek i\u00e7in<\/em> (8 elektron olmas\u0131 i\u00e7in) <em>ka\u00e7 tane elektrona ihtiya\u00e7 duyuyorsa<\/em> o kadar say\u0131da elektronunu ortakla\u015fa kullan\u0131r ve kovalent ba\u011f kurar.<\/span><\/strong><br>(Hidrojen bu kural\u0131n istisnas\u0131d\u0131r. Hidrojen atomu 1 tane kovalent ba\u011f kurar.)<\/li><\/ul><\/li><\/ul>\n\n\n\n<ul class=\"wp-block-list\"><li><strong><em>Kovalent ba\u011f<\/em><\/strong> ile birbirine ba\u011flanm\u0131\u015f atom toplulu\u011funa <strong><em>molek\u00fcl denir.<\/em><\/strong><\/li><li><strong><em>Ayn\u0131 atomlar<\/em><\/strong> kovalent ba\u011f kurarsa <strong><em>element molek\u00fcl\u00fc<\/em><\/strong>, <strong><em>farkl\u0131 atomlar<\/em><\/strong> kovalent ba\u011f kurarsa <strong><em>bile\u015fik molek\u00fcl\u00fc olu\u015fur.<\/em><\/strong><\/li><\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h3 class=\"wp-block-heading\"><span id=\"Ornek-7\">\u00d6rnek:<\/span><\/h3>\n\n\n\n<div class=\"wp-block-columns has-white-background-color has-background is-layout-flex wp-container-core-columns-is-layout-9d6595d7 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\" style=\"flex-basis:33.34%\">\n<p>I) H<sub>2<\/sub><br>II) H<sub>2<\/sub>O<\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\" style=\"flex-basis:33.34%\">\n<p>III) CO<sub>2<\/sub><br>IV) Cl<sub>2<\/sub><\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\" style=\"flex-basis:33.33%\">\n<p>V) O<sub>3<\/sub><br>VI) NH<sub>3<\/sub><\/p>\n<\/div>\n<\/div>\n\n\n\n<p><strong>Yukar\u0131da verilen molek\u00fclleri element ve bile\u015fik molek\u00fcl\u00fc olarak s\u0131n\u0131fland\u0131r\u0131n\u0131z.<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(106,41,92,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<ul class=\"wp-block-list\"><li>Ayn\u0131 atomlar\u0131n molek\u00fclleri element molek\u00fclleridir:<ul><li>I)<strong>H<sub>2<\/sub><\/strong><\/li><li>IV) <strong>Cl<sub>2<\/sub><\/strong><\/li><li>V) <strong>O<sub>3<\/sub><\/strong><\/li><\/ul><\/li><li>Farkl\u0131 atomlar\u0131n molek\u00fcller bile\u015fik molek\u00fclleridir:<ul><li>II) <strong>H<sub>2<\/sub>O<\/strong><\/li><li>III) <strong>CO<sub>2<\/sub><\/strong><\/li><li>VI) <strong>NH<sub>3<\/sub><\/strong><\/li><\/ul><\/li><\/ul>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Bohr_Atom_Modeli_Ile_Kovalent_Bag_Gosterimi\">Bohr Atom Modeli \u0130le Kovalent Ba\u011f G\u00f6sterimi<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\"><li>Bohr Atom Modeline ile kovalent ba\u011f\u0131 g\u00f6sterirken \u015fu kurallara uyulur:<ul><li>Atomlar y\u00f6r\u00fcngeleri ile \u00e7izilirler,<\/li><li>Atomlar\u0131n son y\u00f6r\u00fcngeleri kesi\u015ftirilir.<\/li><li>Kesi\u015fim b\u00f6lgelerine ortakla\u015fa kullan\u0131lan elektronlar konulur.<\/li><\/ul><\/li><\/ul>\n\n\n\n<p>A\u015fa\u011f\u0131da baz\u0131 kovalent ba\u011flar\u0131n olu\u015fumu g\u00f6sterilmi\u015ftir:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"596\" height=\"126\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Turler-Arasi-Etkilesimler-Kovalent-Bag-Hidrojen.jpg\" alt=\"Kovalent Ba\u011f \u0130le H2 Olu\u015fumu\" class=\"wp-image-11372\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Turler-Arasi-Etkilesimler-Kovalent-Bag-Hidrojen.jpg 596w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Turler-Arasi-Etkilesimler-Kovalent-Bag-Hidrojen-300x63.jpg 300w\" sizes=\"auto, (max-width: 596px) 100vw, 596px\" \/><figcaption>Kovalent Ba\u011f \u0130le H<sub>2<\/sub> Olu\u015fumu<\/figcaption><\/figure>\n<\/div>\n\n\n<p>Kovalent ba\u011f ile su molek\u00fcl\u00fcn\u00fcn olu\u015fumu:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Turler-Arasi-Etkilesimler-Kovalent-Bag-Su.jpg\" alt=\"Kovalent Ba\u011f ile H2O Olu\u015fumu\" class=\"wp-image-11373\" width=\"581\" height=\"247\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Turler-Arasi-Etkilesimler-Kovalent-Bag-Su.jpg 628w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Turler-Arasi-Etkilesimler-Kovalent-Bag-Su-300x128.jpg 300w\" sizes=\"auto, (max-width: 581px) 100vw, 581px\" \/><figcaption>Kovalent Ba\u011f ile H<sub>2<\/sub>O Olu\u015fumu<\/figcaption><\/figure>\n<\/div>\n\n\n<p>Kovalent ba\u011f ile O2 molek\u00fcl\u00fcn\u00fcn olu\u015fumu:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"700\" height=\"192\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Turler-Arasi-Etkilesimler-Kovalent-Bag-Oksijen.jpg\" alt=\"Kovalent Ba\u011f ile O2 Olu\u015fumu\" class=\"wp-image-11374\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Turler-Arasi-Etkilesimler-Kovalent-Bag-Oksijen.jpg 700w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Turler-Arasi-Etkilesimler-Kovalent-Bag-Oksijen-300x82.jpg 300w\" sizes=\"auto, (max-width: 700px) 100vw, 700px\" \/><figcaption>Kovalent Ba\u011f ile O<sub>2<\/sub> Olu\u015fumu<\/figcaption><\/figure>\n<\/div>\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Lewis_Elektron_Nokta_Yapisi_Ile_Kovalent_Bag_Gosterimi\">Lewis Elektron Nokta Yap\u0131s\u0131 \u0130le Kovalent Ba\u011f G\u00f6sterimi<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\"><li>Ametal atomlar\u0131, Lewis Yap\u0131lar\u0131ndaki yaln\u0131z elektronlar\u0131 kadar kovalent ba\u011f kurmak ister.<ul><li>Lewis Elektron Nokta Yap\u0131s\u0131 ile kovalent ba\u011f kurarken, yapmam\u0131z gereken tek \u015fey, yaln\u0131z elektronlar\u0131 kar\u015f\u0131l\u0131kl\u0131 olarak e\u015fle\u015ftirmektir. (Kimse yaln\u0131z kalmas\u0131n.)<\/li><li><strong><em>\u0130ki atom, birer yaln\u0131z elektronunu ortaya koyar ve 1 adet kovalent ba\u011f kurulmu\u015f olur.<\/em><\/strong><\/li><li>Her kovalent ba\u011f, bir \u00e7ift elektron demektir.<\/li><li>Her kovalent ba\u011f bir \u00e7izgi ile g\u00f6sterilebilir.<\/li><\/ul><\/li><\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ogretici_Ornek-6\">\u00d6\u011fretici \u00d6rnek:<\/span><\/h4>\n\n\n\n<p>Gelin <sub>1<\/sub>H ve <sub>17<\/sub>Cl atomlar\u0131n\u0131n nas\u0131l ba\u011fland\u0131\u011f\u0131n\u0131 Lewis yap\u0131lar\u0131 ile a\u015fama a\u015fama g\u00f6sterelim.<\/p>\n\n\n\n<ol class=\"wp-block-list\"><li><strong>Ba\u011flayaca\u011f\u0131m\u0131z atomlar\u0131n t\u00fcr\u00fcne karar veriyoruz<\/strong>: H ile Cl atomlar\u0131n\u0131n, metal mi ametal mi oldu\u011funu ezberden bilemiyorsak \u015f\u00f6yle anlayabiliriz:<ul><li>H atomunun proton say\u0131s\u0131 1&#8217;dir.<ul><li>H atomunun, elektron da\u011f\u0131l\u0131m\u0131 \u015f\u00f6yledir:<br><sub>1<\/sub>H<sub>1<\/sub> &nbsp;&nbsp;)<strong>1e<sup>&#8211;<\/sup><\/strong><\/li><li><strong><em>H atomu bir metaldir<\/em><\/strong>. <em>(H de\u011ferlik elektron say\u0131s\u0131 1 olan tek ametaldir.)<\/em><\/li><\/ul><\/li><li>Cl atomunun proton say\u0131s\u0131 17&#8217;dir.<ul><li>Cl atomunun elektron da\u011f\u0131l\u0131m\u0131 \u015f\u00f6yledir:<br><sub>17<\/sub>Cl<sub>17<\/sub> &nbsp;&nbsp; )<strong>2e<sup>&#8211;<\/sup><\/strong> &nbsp;&nbsp;)<strong>8e<sup>&#8211;<\/sup><\/strong> &nbsp;&nbsp;)<strong>7e<sup>&#8211;<\/sup><\/strong> &nbsp;&nbsp;(temel haldeki Na atomu)<\/li><li>De\u011ferlik elektron say\u0131s\u0131 7 oldu\u011fu i\u00e7in <strong><em>Cl atomu bir ametaldir.<\/em><\/strong><\/li><\/ul><\/li><\/ul><\/li><li><strong>Ba\u011f\u0131n t\u00fcr\u00fcne karar veriyoruz<\/strong>: Elimizde iki tane ametal atomu varsa bir <strong><em>kovalent ba\u011f kuraca\u011f\u0131z<\/em><\/strong> demektir.<\/li><li>\u015eimdi bu iki atomun <strong><em>Lewis yap\u0131lar\u0131n\u0131<\/em><\/strong> g\u00f6sterelim:<ul><li>H atomunun Lewis yap\u0131s\u0131 \u015f\u00f6yledir:<br><img loading=\"lazy\" decoding=\"async\" width=\"40\" height=\"38\" class=\"wp-image-2653\" style=\"width: 40px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Hidrojen-Lewis-Elektron-Nokta-Yapisi.jpg\" alt=\"Hidrojen Atomunun Lewis Elektron Nokta Yap\u0131s\u0131\"><\/li><li>Cl atomunun Lewis yap\u0131s\u0131 da \u015f\u00f6yledir:<br><img loading=\"lazy\" decoding=\"async\" width=\"50\" height=\"52\" class=\"wp-image-2654\" style=\"width: 50px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Klor-Lewis-Elektron-Nokta-Yapisi.jpg\" alt=\"Klor Atomunun Lewis Elektron Nokta Yap\u0131s\u0131\"><\/li><\/ul><\/li><li>S\u0131ra <strong><em>elektron ortakla\u015fmas\u0131nda<\/em><\/strong>. Kovalent ba\u011fda yaln\u0131z elektronlar kar\u015f\u0131l\u0131kl\u0131 olarak e\u015fle\u015ftirilir:<ul><li>Cl atomunun, 1 tane yaln\u0131z noktas\u0131 vard\u0131r ve kovalent ba\u011f kurarken bu elektronu payla\u015f\u0131r.<\/li><li>H atomunun da 1 tane yaln\u0131z noktas\u0131 vard\u0131r ve kovalent ba\u011f kurarken bu elektronu payla\u015f\u0131r.<br><img loading=\"lazy\" decoding=\"async\" width=\"120\" height=\"100\" class=\"wp-image-2658\" style=\"width: 120px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/HCl-Lewis-Elektron-Nokta-Yapisi.jpg\" alt=\"HCl Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131\"><\/li><li>Ayn\u0131 molek\u00fcl\u00fc \u015f\u00f6yle de g\u00f6sterebiliriz:<br><img loading=\"lazy\" decoding=\"async\" width=\"150\" height=\"102\" class=\"wp-image-2660\" style=\"width: 150px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/HCl-Lewis-Elektron-Nokta-Yapisi-2.jpg\" alt=\"HCl Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131\"><\/li><\/ul><\/li><\/ol>\n\n\n\n<ul class=\"wp-block-list\"><li>Hidrojen ve Klor atomlar\u0131n\u0131n, kovalent ba\u011f kurarak HCl molek\u00fcl\u00fcn\u00fc olu\u015fturmas\u0131 olay\u0131n\u0131, \u015f\u00f6yle bir tepkime denklemi ile de g\u00f6sterebiliriz:<\/li><\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"537\" height=\"100\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kovalent-bag-Lewis-ELektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"Lewis Elektron Nokta Yap\u0131s\u0131 ile Kovalent Ba\u011f\" class=\"wp-image-2705\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kovalent-bag-Lewis-ELektron-Nokta-Yapisi-SiteCenneti.jpg 537w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kovalent-bag-Lewis-ELektron-Nokta-Yapisi-SiteCenneti-300x56.jpg 300w\" sizes=\"auto, (max-width: 537px) 100vw, 537px\" \/><figcaption>Lewis Elektron Nokta Yap\u0131s\u0131 ile Kovalent Ba\u011f<\/figcaption><\/figure>\n<\/div>\n\n\n<ul class=\"wp-block-list\"><li>Yukar\u0131da verilen tepkime, \u015fu \u015fekilde de yaz\u0131labilir:<\/li><\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"592\" height=\"114\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kovalent-bag-Lewis-ELektron-Nokta-Yapisi-SiteCenneti-2.jpg\" alt=\"Lewis Elektron Nokta Yap\u0131s\u0131 ile Kovalent Ba\u011f\" class=\"wp-image-2706\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kovalent-bag-Lewis-ELektron-Nokta-Yapisi-SiteCenneti-2.jpg 592w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kovalent-bag-Lewis-ELektron-Nokta-Yapisi-SiteCenneti-2-300x58.jpg 300w\" sizes=\"auto, (max-width: 592px) 100vw, 592px\" \/><figcaption>Lewis Elektron Nokta Yap\u0131s\u0131 ile Kovalent Ba\u011f<\/figcaption><\/figure>\n<\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-8\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p><strong>Cl<sub>2<\/sub> molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131n\u0131 g\u00f6steriniz. (<sub>17<\/sub>Cl)<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center\"><strong><em>Cl<sub>2<\/sub> molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131 a\u015fa\u011f\u0131dakilerin ikisi de olabilir:<\/em><\/strong><\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"200\" height=\"94\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Cl2-Molekulunun-Lewis-Elektron-Nokta-Yapisi-2-SiteCenneti.jpg\" alt=\"Cl2 Molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131\" class=\"wp-image-2766\"\/><figcaption>Cl<sub>2<\/sub> Molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div>\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"200\" height=\"96\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Cl2-Molekulunun-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"Cl2 Molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131\" class=\"wp-image-2764\"\/><figcaption>Cl<sub>2<\/sub> Molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div><\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Kor (Cl) atomu bir ametaldir ve kovalent ba\u011f kurarak Cl<sub>2<\/sub> molek\u00fcl\u00fcn\u00fc olu\u015fturur.<\/p>\n\n\n\n<p>Cl<sub>2<\/sub> molek\u00fcl\u00fcn\u00fcn Lewis yap\u0131s\u0131 i\u00e7in, \u00f6nce Cl atomunun temel hallerinin elektron da\u011f\u0131l\u0131m\u0131na bakal\u0131m:<\/p>\n\n\n\n<p class=\"has-white-color has-vivid-red-background-color has-text-color has-background\"><sub>17<\/sub>Cl<sub>17<\/sub> : )2e<sup>&#8211;<\/sup> )8e<sup>&#8211;<\/sup> <strong>)7e<sup>&#8211;<\/sup><\/strong><\/p>\n\n\n\n<p>De\u011ferlik elektron say\u0131s\u0131 (son y\u00f6r\u00fcngedeki elektron say\u0131s\u0131 da denir) 7 oldu\u011fu i\u00e7in Cl atomunun temel halinin Lewis Nokta Yap\u0131s\u0131 \u015f\u00f6yle olacakt\u0131r:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Klor-Lewis-Elektron-Nokta-Yapisi.jpg\" alt=\"Klor Atomunun Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2654\" width=\"83\" height=\"87\"\/><\/figure>\n<\/div>\n\n\n<p>G\u00f6r\u00fcyoruz ki Cl atomunun 1 tane yaln\u0131z elektronu var. Bu y\u00fczden bu atom bir tane kovalent ba\u011f kurabilecektir. Bu durumda iki tane Cl atomu \u015fu \u015fekilde ba\u011flanacakt\u0131r:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"200\" height=\"94\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Cl2-Molekulunun-Lewis-Elektron-Nokta-Yapisi-2-SiteCenneti.jpg\" alt=\"Cl2 Molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131\" class=\"wp-image-2766\"\/><figcaption>Cl<sub>2<\/sub> Molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<p>Ayn\u0131 kenardaki iki noktay\u0131 bir \u00e7izgi olarak g\u00f6sterme hakk\u0131m\u0131z\u0131 kullan\u0131rsak, Cl<sub>2<\/sub> molek\u00fcl\u00fcn\u00fcn Lewis yap\u0131s\u0131 \u015f\u00f6yle olacakt\u0131r:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"200\" height=\"96\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Cl2-Molekulunun-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"Cl2 Molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131\" class=\"wp-image-2764\"\/><figcaption>Cl<sub>2<\/sub> Molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-9\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p><strong>H<sub>2<\/sub>O molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131n\u0131 g\u00f6steriniz. (<sub>1<\/sub>H, <sub>8<\/sub>O)<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center\"><strong><em>H<sub>2<\/sub>O bile\u015fi\u011finin Lewis Nokta Yap\u0131s\u0131 a\u015fa\u011f\u0131dakilerin ikisi de olabilir:<\/em><\/strong><\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"157\" height=\"160\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/H2O-Lewis-Elektron-Nokta-Yapisi-SiteCenneti-2.jpg\" alt=\"Su Molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131\" class=\"wp-image-2717\"\/><figcaption>Su Molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<p class=\"has-text-align-left\">Veya, \u00e7ift noktay\u0131 bir \u00e7izgi olarak g\u00f6sterme hakk\u0131m\u0131z\u0131 kullan\u0131rsak, ayn\u0131 molek\u00fcl\u00fcn Lewis yap\u0131s\u0131n\u0131 \u015f\u00f6yle de g\u00f6sterebiliriz:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/H2O-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"H2O Molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131\" class=\"wp-image-2719\" width=\"136\" height=\"141\"\/><figcaption>H2O Molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div><\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Hidrojen (H) ve Oksijen (O) atomlar\u0131 birer ametaldir ve kovalent ba\u011f kurarak H<sub>2<\/sub>O molek\u00fcl\u00fcn\u00fc olu\u015ftururlar.<\/p>\n\n\n\n<p>H<sub>2<\/sub>O molek\u00fcl\u00fcn\u00fcn Lewis yap\u0131s\u0131 i\u00e7in, \u00f6nce Hidrojen (H) ve Oksijen (O) atomlar\u0131n\u0131n temel hallerinin elektron da\u011f\u0131l\u0131m\u0131na bakal\u0131m:<\/p>\n\n\n\n<p class=\"has-white-color has-vivid-red-background-color has-text-color has-background\"><sub>1<\/sub>H<sub>1<\/sub> : <strong>)1e-<\/strong><br><br><sub>8<\/sub>O<sub>8<\/sub> : )2e<sup>&#8211;<\/sup> <strong>)6e<sup>&#8211;<\/sup><\/strong><\/p>\n\n\n\n<p> Bu atomlar\u0131n temel hallerinin Lewis Yap\u0131lar\u0131n\u0131 yazal\u0131m:<\/p>\n\n\n\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-9d6595d7 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\"><div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"69\" height=\"79\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Hidrojen-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"Hidrojen Atomunun Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2711\"\/><\/figure>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\"><div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"95\" height=\"97\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Oksijen-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"Oksijen Atomunun Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2712\"\/><\/figure>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\"><div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"110\" height=\"100\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Oksijen-Lewis-Elektron-Nokta-Yapisi-SiteCenneti-2.jpg\" alt=\"Oksijen Atomunun Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2713\"\/><\/figure>\n<\/div><\/div>\n<\/div>\n\n\n\n<p>G\u00f6r\u00fcyoruz ki Hidrojen atomunda 1 tane yaln\u0131z elektron var, yani 1 tane ba\u011f kurmak isteyecek; Oksijen atomunda ise 2 tane yaln\u0131z elektron var yani Oksijen 2 tane kovalent ba\u011f kurmak isteyecektir. O zaman 1 tane Oksijen atomu ile 2 Hidrojen atomunu ba\u011flarsak herkes iste\u011fini ger\u00e7ekle\u015ftirmi\u015f olur:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"157\" height=\"160\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/H2O-Lewis-Elektron-Nokta-Yapisi-SiteCenneti-2.jpg\" alt=\"Su Molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131\" class=\"wp-image-2717\"\/><figcaption>Su Molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<p>Veya, \u00e7ift noktay\u0131 bir \u00e7izgi olarak g\u00f6sterme hakk\u0131m\u0131z\u0131 kullan\u0131rsak, ayn\u0131 molek\u00fcl\u00fcn Lewis yap\u0131s\u0131n\u0131 \u015f\u00f6yle de g\u00f6sterebiliriz:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/H2O-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"H2O Molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131\" class=\"wp-image-2719\" width=\"136\" height=\"141\"\/><figcaption>H2O Molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-10\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p><strong>CH<sub>4<\/sub> molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131n\u0131 g\u00f6steriniz. (<sub>1<\/sub>H, <sub>6<\/sub>C)<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center\"><strong><em>CH<sub>4<\/sub> molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131:<\/em><\/strong><\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/CH4-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"CH4 Molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131\" class=\"wp-image-2724\" width=\"248\" height=\"261\"\/><figcaption>CH<sub>4<\/sub> Molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div><\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Karbon (C) ve Hidrojen (H) atomlar\u0131 birer ametaldir ve kovalent ba\u011f kurarak H<sub>2<\/sub>O molek\u00fcl\u00fcn\u00fc olu\u015ftururlar.<\/p>\n\n\n\n<p>CH<sub>4<\/sub> molek\u00fcl\u00fcn\u00fcn Lewis yap\u0131s\u0131 i\u00e7in, \u00f6nce Karbon (C) ve Hidrojen (H) atomlar\u0131n\u0131n temel hallerinin elektron da\u011f\u0131l\u0131m\u0131na bakal\u0131m:<\/p>\n\n\n\n<p class=\"has-white-color has-vivid-red-background-color has-text-color has-background\"><sub>1<\/sub>H<sub>1<\/sub> : <strong>)1e-<\/strong><br><br><sub>6<\/sub>C<sub>6<\/sub> : )2e<sup>&#8211;<\/sup> <strong>)4e<sup>&#8211;<\/sup><\/strong><\/p>\n\n\n\n<p> Bu atomlar\u0131n temel hallerinin Lewis Yap\u0131lar\u0131n\u0131 yazal\u0131m:<\/p>\n\n\n\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-9d6595d7 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\"><div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"69\" height=\"79\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Hidrojen-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"Hidrojen Atomunun Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2711\"\/><\/figure>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\"><div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"95\" height=\"99\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/C-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"Karbon Atomunun Lewis Nokta Yap\u0131s\u0131\" class=\"wp-image-2723\"\/><\/figure>\n<\/div><\/div>\n<\/div>\n\n\n\n<p>G\u00f6r\u00fcyoruz ki Hidrojen atomunda 1 tane yaln\u0131z elektron var, yani 1 tane ba\u011f kurmak isteyecek; Karbon atomunda ise 4 tane yaln\u0131z elektron var yani 4 tane kovalent ba\u011f kurmak isteyecektir. O zaman 1 tane Karbon atomu ile 4 Hidrojen atomunu ba\u011flarsak herkes iste\u011fini ger\u00e7ekle\u015ftirmi\u015f olur:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/CH4-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"CH4 Molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131\" class=\"wp-image-2724\" width=\"248\" height=\"261\"\/><figcaption>CH<sub>4<\/sub> Molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-11\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p><strong>CH<sub>4<\/sub> molek\u00fcl\u00fcn\u00fcn atomlar\u0131ndan olu\u015fumunu g\u00f6steren tepkime denklemini Lewis Elektron Nokta Yap\u0131s\u0131n\u0131 ile g\u00f6steriniz. (<sub>1<\/sub>H, <sub>6<\/sub>C)<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center\"><strong>C ve H atomlar\u0131n\u0131n <em>CH<sub>4<\/sub> molek\u00fcl\u00fcn\u00fc olu\u015fturmas\u0131 tepkimesinin Lewis Nokta Yap\u0131s\u0131:<\/em><\/strong><\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/CH4-Lewis-Elektron-Nokta-Yapisi-SiteCenneti-2.jpg\" alt=\"CH4 Molek\u00fcl\u00fcn\u00fcn Olu\u015fum Tepkimesi\" class=\"wp-image-2727\" width=\"340\" height=\"142\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/CH4-Lewis-Elektron-Nokta-Yapisi-SiteCenneti-2.jpg 400w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/CH4-Lewis-Elektron-Nokta-Yapisi-SiteCenneti-2-300x125.jpg 300w\" sizes=\"auto, (max-width: 340px) 100vw, 340px\" \/><figcaption>CH<sub>4<\/sub> Molek\u00fcl\u00fcn\u00fcn Olu\u015fum Tepkimesi<\/figcaption><\/figure>\n<\/div><\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>CH4 molek\u00fcl\u00fcn\u00fc olu\u015fturmak i\u00e7in 4 tane H atomu ile 1 tane C atomunun kovalent ba\u011f kurmas\u0131 gerekmektedir. Bu olay\u0131n tepkime denklemi \u015f\u00f6yledir:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/CH4-Lewis-Elektron-Nokta-Yapisi-SiteCenneti-2.jpg\" alt=\"CH4 Molek\u00fcl\u00fcn\u00fcn Olu\u015fum Tepkimesi\" class=\"wp-image-2727\" width=\"340\" height=\"142\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/CH4-Lewis-Elektron-Nokta-Yapisi-SiteCenneti-2.jpg 400w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/CH4-Lewis-Elektron-Nokta-Yapisi-SiteCenneti-2-300x125.jpg 300w\" sizes=\"auto, (max-width: 340px) 100vw, 340px\" \/><figcaption>CH<sub>4<\/sub> Molek\u00fcl\u00fcn\u00fcn Olu\u015fum Tepkimesi<\/figcaption><\/figure>\n<\/div>\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-12\">\u00d6rnek:<\/span><\/h4>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Lewis-Elektron-Nokta-Yapisi-SiteCenneti-2.jpg\" alt=\"Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2730\" width=\"194\" height=\"66\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Lewis-Elektron-Nokta-Yapisi-SiteCenneti-2.jpg 343w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Lewis-Elektron-Nokta-Yapisi-SiteCenneti-2-300x102.jpg 300w\" sizes=\"auto, (max-width: 194px) 100vw, 194px\" \/><\/figure>\n<\/div>\n\n\n<p>Yukar\u0131da Hidrojen (H), Azot (N) ve Flor (F) atomlar\u0131n\u0131n temel hallerine ait Lewis Elektron Nokta Yap\u0131lar\u0131 verilmi\u015ftir.<\/p>\n\n\n\n<p><strong>Buna g\u00f6re H<sub>2<\/sub>, N<sub>2<\/sub> ve F<sub>2<\/sub> molek\u00fcllerinin Lewis Yap\u0131lar\u0131n\u0131 g\u00f6steriniz.<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center\"><strong><em>H<sub>2<\/sub> molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131 \u015f\u00f6yledir:<\/em><\/strong><\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/H2-molekulu-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"H2 Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2731\" width=\"125\" height=\"61\"\/><figcaption>H2 Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<p class=\"has-text-align-center\"><strong><em>N<sub>2<\/sub> molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131 \u015f\u00f6yledir:<\/em><\/strong><\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/N2-molekulu-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"N2 Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2732\" width=\"121\" height=\"63\"\/><figcaption>N2 Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<p class=\"has-text-align-center\"><strong><em>F<sub>2<\/sub> molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131 \u015f\u00f6yledir:<\/em><\/strong><\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/F2-molekulu-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"F2 Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2733\" width=\"141\" height=\"79\"\/><figcaption>F2 Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div><\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Hidrojen, Azot ve Flor atomlar\u0131 ametaldir. Bu y\u00fczden birbirleri ile kovalent ba\u011flar kurarlar.<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Lewis-Elektron-Nokta-Yapisi-SiteCenneti-2.jpg\" alt=\"Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2730\" width=\"199\" height=\"68\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Lewis-Elektron-Nokta-Yapisi-SiteCenneti-2.jpg 343w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Lewis-Elektron-Nokta-Yapisi-SiteCenneti-2-300x102.jpg 300w\" sizes=\"auto, (max-width: 199px) 100vw, 199px\" \/><\/figure>\n<\/div>\n\n\n<p>Lewis yap\u0131lar\u0131ndaki yaln\u0131z noktalara bakt\u0131\u011f\u0131m\u0131zda, Hidrojenin 1 tane, Azotun 3 tane, Florun da 1 tane kovalent ba\u011f kurabildi\u011fini anlar\u0131z.<\/p>\n\n\n\n<p>Bu durumda H<sub>2<\/sub> molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131 \u015f\u00f6yle olacakt\u0131r:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/H2-molekulu-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"H2 Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2731\" width=\"125\" height=\"61\"\/><figcaption>H2 Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<p>N<sub>2<\/sub> molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131 \u015f\u00f6yle olacakt\u0131r:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/N2-molekulu-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"N2 Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2732\" width=\"121\" height=\"63\"\/><figcaption>N2 Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<p>F<sub>2<\/sub> molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131 \u015f\u00f6yle olacakt\u0131r:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/F2-molekulu-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"F2 Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2733\" width=\"141\" height=\"79\"\/><figcaption>F2 Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-13\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p><strong>O<sub>2<\/sub> (Oksijen) molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131n\u0131 g\u00f6steriniz. (<sub>8<\/sub>O)<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center\"><strong><em>O<sub>2<\/sub> molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131 \u015f\u00f6yledir:<\/em><\/strong><\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/O2-molekulu-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"O2 Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2735\" width=\"145\" height=\"73\"\/><figcaption>O2 Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div><\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Oksijen (O) atomu bir ametal atomudur. Bu y\u00fczden, Oksijen atomlar\u0131 aras\u0131nda kovalent ba\u011f kurulur.<\/p>\n\n\n\n<p>Oksijen atomunun elektron dizilimine bakal\u0131m:<\/p>\n\n\n\n<p class=\"has-white-color has-vivid-red-background-color has-text-color has-background\" style=\"font-size:18px\"><sub>8<\/sub>O<sub>8<\/sub> : )2e<sup>&#8211;<\/sup> <strong>)6e<sup>&#8211;<\/sup><\/strong><\/p>\n\n\n\n<p>Oksijen atomunun Lewis Yap\u0131s\u0131nda 6 tane elektron olmal\u0131d\u0131r:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Oksijen-Lewis-Elektron-Nokta-Yapisi-SiteCenneti-2.jpg\" alt=\"Oksijen Atomunun Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2713\" width=\"96\" height=\"87\"\/><figcaption>Oksijen Atomunun Lewis Elektron Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<p>Lewis Yap\u0131s\u0131ndaki yaln\u0131z 2 elektrondan anl\u0131yoruz ki Oksijen atomlar\u0131 2 tane kovalent ba\u011f kurmak istiyor. Buna g\u00f6re O<sub>2<\/sub> molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131 \u015f\u00f6yle olacakt\u0131r:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/O2-molekulu-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"O2 Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2735\" width=\"145\" height=\"73\"\/><figcaption>O2 Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<p><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-14\">\u00d6rnek:<\/span><\/h4>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/NH3-molekulu-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"NH3 Molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131\" class=\"wp-image-2741\" width=\"125\" height=\"89\"\/><\/figure>\n<\/div>\n\n\n<p>Yukar\u0131da, NH<sub>3<\/sub> (Amonyak) molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131 verilmi\u015ftir.<\/p>\n\n\n\n<p><strong>Bu yap\u0131ya bakarak, Azot (N) atomunun temel haline ait Lewis yap\u0131s\u0131n\u0131 ve grup numaras\u0131n\u0131 bulunuz.<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center\"><strong><em>N atomunun Lewis Yap\u0131s\u0131:<\/em><\/strong><\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/N-atomu-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"N Atomunun Lewis Nokta Yap\u0131s\u0131\" class=\"wp-image-2742\" width=\"86\" height=\"80\"\/><figcaption>N Atomunun Lewis Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<p class=\"has-text-align-center\"><strong><em>N atomu 5A grubunda bulunur.<\/em><\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p> <\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/NH3-molekulu-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"NH3 Molek\u00fcl\u00fcn\u00fcn Lewis Nokta Yap\u0131s\u0131\" class=\"wp-image-2741\" width=\"136\" height=\"97\"\/><\/figure>\n<\/div>\n\n\n<p>Molek\u00fcle bakt\u0131\u011f\u0131m\u0131zda, N atomunun 3 tane kovalent ba\u011f yapt\u0131\u011f\u0131n\u0131, ba\u011fa kat\u0131lmayan 1 \u00e7ift elektronu oldu\u011funu g\u00f6r\u00fcr\u00fcz. N atomu, 3 tane kovalent ba\u011f\u0131n her birinde 1 tane elektron kullanm\u0131\u015f olmal\u0131d\u0131r veya ba\u011f yapmadan \u00f6nce, N atomunun 3 tane yaln\u0131z elektronu olmal\u0131d\u0131r. Bu durumda, N atomunun temel halinin Lewis yap\u0131s\u0131 \u015f\u00f6yle olmal\u0131d\u0131r:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/N-atomu-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"N Atomunun Lewis Nokta Yap\u0131s\u0131\" class=\"wp-image-2742\" width=\"86\" height=\"80\"\/><figcaption>N Atomunun Lewis Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<p>Lewis yap\u0131s\u0131ndaki her bir nokta, 1 elektron demek, her bir \u00e7izgi de 2 elektron demektir. Bu durumda, N atomunun Lewis yap\u0131s\u0131nda 5 elektron bulunur, yani de\u011ferlik elektron say\u0131s\u0131 5&#8217;tir, yani N atomu 5A grubunda bulunur.<\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-15\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p><strong>CO<sub>2<\/sub> (Karbon dioksit) molek\u00fcl\u00fcn\u00fcn, Lewis Elektron Nokta Yap\u0131s\u0131n\u0131 g\u00f6steriniz. (<sub>6<\/sub>C, <sub>8<\/sub>O)<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center\"><strong><em>CO<sub>2<\/sub> molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131 \u015f\u00f6yle olmal\u0131d\u0131r:<\/em><\/strong><\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/CO2-Molekulunun-Lewis-Elektron-Nokta-Yapisi-2-SiteCenneti.jpg\" alt=\"CO2 Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2769\" width=\"214\" height=\"74\"\/><figcaption>CO<sub>2<\/sub> Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div><\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p> C ve O atomlar\u0131, ametal atomlar\u0131d\u0131r. Aralar\u0131ndaki ba\u011f kovalent ba\u011f olmal\u0131d\u0131r.<\/p>\n\n\n\n<p>C ve O atomlar\u0131n\u0131n temel hallerine ait elektron da\u011f\u0131l\u0131mlar\u0131 \u015f\u00f6yledir:<\/p>\n\n\n\n<p class=\"has-white-color has-vivid-red-background-color has-text-color has-background\" style=\"font-size:18px\"><sub>6<\/sub>C<sub>6<\/sub> : )2e<sup>&#8211;<\/sup> <strong>)4e<sup>&#8211;<\/sup><\/strong><br><sub>8<\/sub>O<sub>8<\/sub> : )2e<sup>&#8211;<\/sup> <strong>)6e<sup>&#8211;<\/sup><\/strong><\/p>\n\n\n\n<p>Bu iki ametalin temel hallerine ait Lewis Yap\u0131lar\u0131 \u015f\u00f6yle olmal\u0131d\u0131r:<\/p>\n\n\n\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-9d6595d7 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\"><div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"95\" height=\"99\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/C-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"Karbon Atomunun Lewis Nokta Yap\u0131s\u0131\" class=\"wp-image-2723\"\/><figcaption>Karbon Atomunun Lewis Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\"><div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"110\" height=\"100\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Oksijen-Lewis-Elektron-Nokta-Yapisi-SiteCenneti-2.jpg\" alt=\"Oksijen Atomunun Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2713\"\/><figcaption>Oksijen Atomunun Lewis Elektron Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div><\/div>\n<\/div>\n\n\n\n<p>Lewis yap\u0131lar\u0131ndan anl\u0131yoruz ki, C atomu 4 tane kovalent ba\u011f, oksijen atomu da 2 tane kovalent ba\u011f kurabilmektedir. Bu durumda CO<sub>2<\/sub> molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131 \u015f\u00f6yle olmal\u0131d\u0131r:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/CO2-Molekulunun-Lewis-Elektron-Nokta-Yapisi-2-SiteCenneti.jpg\" alt=\"CO2 Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2769\" width=\"214\" height=\"74\"\/><figcaption>CO<sub>2<\/sub> Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131<\/figcaption><\/figure>\n<\/div>\n\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe loading=\"lazy\" title=\"Mastering Chemical Bonding: Explained with 3D Animation\" width=\"1170\" height=\"658\" src=\"https:\/\/www.youtube.com\/embed\/g-tE6MN-wrE?start=275&#038;feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" allowfullscreen><\/iframe>\n<\/div><figcaption>CO<sub>2<\/sub> Bile\u015fi\u011findeki Kovalent Ba\u011f\u0131n Olu\u015fumu<\/figcaption><\/figure>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Tekli_Ikili_ve_Uclu_Kovalent_Baglar\">Tekli, \u0130kili ve \u00dc\u00e7l\u00fc Kovalent Ba\u011flar<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\"><li>\u0130ki ametal atomu aras\u0131nda, kar\u015f\u0131l\u0131kl\u0131 birer elektron payla\u015f\u0131m\u0131 ile <strong><em>1 tane kovalent ba\u011f<\/em><\/strong> kurulursa, tekli kovalent ba\u011f olu\u015fur.<ul><li>A\u015fa\u011f\u0131da, H<sub>2<\/sub> molek\u00fcl\u00fcnde bulunan tekli kovalent ba\u011f\u0131 g\u00f6r\u00fcyorsunuz:<\/li><\/ul><\/li><\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/H2-molekulu-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"H2 Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2731\" width=\"127\" height=\"62\"\/><figcaption>Tekli Kovalent Ba\u011f<\/figcaption><\/figure>\n<\/div>\n\n\n<ul class=\"wp-block-list\"><li>\u0130ki ametal atomu aras\u0131nda, kar\u015f\u0131l\u0131kl\u0131 <strong><em>iki\u015fer elektron payla\u015f\u0131m\u0131<\/em><\/strong> ile 2 tane kovalent ba\u011f kurulursa, <strong><em>ikili kovalent ba\u011f olu\u015fur.<\/em><\/strong><ul><li>A\u015fa\u011f\u0131da, O<sub>2<\/sub> molek\u00fcl\u00fcnde bulunan ikili kovalent ba\u011f\u0131 g\u00f6r\u00fcyorsunuz:<\/li><\/ul><\/li><\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/O2-molekulu-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"O2 Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2735\" width=\"163\" height=\"82\"\/><figcaption>\u0130kili Kovalent Ba\u011f<\/figcaption><\/figure>\n<\/div>\n\n\n<ul class=\"wp-block-list\"><li>\u0130ki ametal atomu aras\u0131nda, kar\u015f\u0131l\u0131kl\u0131 <strong><em>\u00fc\u00e7er elektron payla\u015f\u0131m\u0131<\/em><\/strong> ile 3 tane kovalent ba\u011f kurulursa, <strong><em>\u00fc\u00e7l\u00fc kovalent ba\u011f olu\u015fur.<\/em><\/strong><ul><li>A\u015fa\u011f\u0131da, N<sub>2<\/sub> molek\u00fcl\u00fcnde bulunan \u00fc\u00e7l\u00fc kovalent ba\u011f\u0131 g\u00f6r\u00fcyorsunuz:<\/li><\/ul><\/li><\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/N2-molekulu-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"N2 Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2732\" width=\"143\" height=\"74\"\/><figcaption>\u00dc\u00e7l\u00fc Kovalent Ba\u011f<\/figcaption><\/figure>\n<\/div>\n\n\n<p class=\"has-background\" style=\"background-color:#eaf7ff\">\u0130kili ve \u00fc\u00e7l\u00fc kovalent ba\u011flara <strong>\u00e7oklu kovalent ba\u011f<\/strong> da denir.<\/p>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ogretici_Ornek-7\">\u00d6\u011fretici \u00d6rnek:<\/span><\/h4>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/N2-molekulu-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"N2 Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2732\" width=\"143\" height=\"74\"\/><\/figure>\n<\/div>\n\n\n<p>Yukar\u0131da Lewis form\u00fcl\u00fc verilen N<sub>2<\/sub> molek\u00fcl\u00fc i\u00e7in, \u015fu bilgiler do\u011frudur:<\/p>\n\n\n\n<ul class=\"wp-block-list\"><li>Ortaklanm\u0131\u015f (kovalent ba\u011f kurmu\u015f) elektron \u00e7ifti say\u0131s\u0131: 3<\/li><li>Ortaklanmam\u0131\u015f elektron \u00e7ifti say\u0131s\u0131: 2<\/li><li>Ortaklanm\u0131\u015f elektron say\u0131s\u0131: 6<\/li><li>Ortaklanmam\u0131\u015f elektron say\u0131s\u0131: 4<\/li><\/ul>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Polar_8211_Apolar_Kovalent_Bag\">Polar &#8211; Apolar Kovalent Ba\u011f<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\"><li><strong><em>Polar <\/em><\/strong>kelimesi, &#8220;<strong><em>kutuplu<\/em><\/strong>&#8221; demektir.<\/li><li>Polar kovalent ba\u011flar, t\u0131pk\u0131 bir <strong><em>m\u0131knat\u0131s gibi<\/em><\/strong> kutuplar\u0131 olan ba\u011flard\u0131r.<\/li><li><strong><em>Apolar <\/em><\/strong>kelimesi &#8220;<strong><em>kutupsuz<\/em><\/strong>&#8221; demektir.<\/li><li><strong><em>Apolar kovalent ba\u011flar, kutuplar\u0131 olmayan ba\u011flard\u0131r.<\/em><\/strong><\/li><\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><span id=\"Apolar_Kovalent_Bag\">Apolar Kovalent Ba\u011f<\/span><\/h4>\n\n\n\n<ul class=\"wp-block-list\"><li><strong><em>Ayn\u0131 atomlar<\/em><\/strong> aras\u0131nda kurulan kovalent ba\u011flar <em><strong>apolar<\/strong> <\/em>kovalent ba\u011flard\u0131r.<\/li><\/ul>\n\n\n\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-9d6595d7 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\"><div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"143\" height=\"70\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/H2-molekulu-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"H2 Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2731\"\/><figcaption>1 Tane Apolar Kovalent Ba\u011f<\/figcaption><\/figure>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\"><div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/O2-molekulu-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"O2 Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2735\" width=\"156\" height=\"78\"\/><figcaption>2 Tane Apolar Kovalent Ba\u011f<\/figcaption><\/figure>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\"><div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/N2-molekulu-Lewis-Elektron-Nokta-Yapisi-SiteCenneti.jpg\" alt=\"N2 Molek\u00fcl\u00fcn\u00fcn Lewis Elektron Nokta Yap\u0131s\u0131\" class=\"wp-image-2732\" width=\"141\" height=\"73\"\/><figcaption>3 Tane Apolar Kovalent Ba\u011f<\/figcaption><\/figure>\n<\/div><\/div>\n<\/div>\n\n\n\n<ul class=\"wp-block-list\"><li>Yukar\u0131da verilen molek\u00fcllerde, ayn\u0131 atomlar aras\u0131nda kuruldu\u011fu i\u00e7in kovalent ba\u011flar\u0131n hepsi apolard\u0131r.<\/li><\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><span id=\"Polar_Kovalent_Bag\">Polar Kovalent Ba\u011f<\/span><\/h4>\n\n\n\n<ul class=\"wp-block-list\"><li><strong><em>Farkl\u0131 atomlar<\/em><\/strong> aras\u0131nda kurulan kovalent ba\u011flar <em><strong>polar<\/strong> <\/em>kovalent ba\u011flard\u0131r.<\/li><\/ul>\n\n\n\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-9d6595d7 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\"><div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Polar-Kovalent-Baglar-SiteCenneti.jpg\" alt=\"Polar Kovalent Ba\u011f\" class=\"wp-image-2757\" width=\"-61\" height=\"-44\"\/><figcaption>3 Tane Polar Kovalent Ba\u011f<\/figcaption><\/figure>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\"><div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Polar-Kovalent-Baglar-HCl-SiteCenneti.jpg\" alt=\"Polar Kovalent Ba\u011f\" class=\"wp-image-2758\" width=\"-27\" height=\"-13\"\/><figcaption>1 Tane Polar Kovalent Ba\u011f<\/figcaption><\/figure>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\"><div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"266\" height=\"261\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Turler-Arasi-Etkilesimler-Polar-Kovalent-Bag-Metan-CH4.jpg\" alt=\"Polar Kovalent Ba\u011flar\" class=\"wp-image-11405\"\/><figcaption>4 Tane Polar Kovalent Ba\u011flar<\/figcaption><\/figure>\n<\/div><\/div>\n<\/div>\n\n\n\n<ul class=\"wp-block-list\"><li>Yukar\u0131da g\u00f6sterilen kovalent ba\u011flara dikkat edersek, hepsinde, kovalent ba\u011f\u0131n iki taraf\u0131nda <strong><em>farkl\u0131 ametal atomlar\u0131<\/em><\/strong> vard\u0131r.<ul><li>Bu y\u00fczden, bu kovalent ba\u011flar\u0131n hepsi <strong><em>polar <\/em><\/strong>kovalent ba\u011flard\u0131r.<\/li><\/ul><\/li><\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-16\">\u00d6rnek:<\/span><\/h4>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Polar-Apolar-Kovalent-Baglar-SiteCenneti.jpg\" alt=\"Polar ve Apolar Kovalent Ba\u011flar\" class=\"wp-image-2761\" width=\"268\" height=\"165\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Polar-Apolar-Kovalent-Baglar-SiteCenneti.jpg 443w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Polar-Apolar-Kovalent-Baglar-SiteCenneti-300x185.jpg 300w\" sizes=\"auto, (max-width: 268px) 100vw, 268px\" \/><\/figure>\n<\/div>\n\n\n<p>Yukar\u0131da verilen molek\u00fclde, kovalent ba\u011flar numaralar ile etiketlenmi\u015ftir. <\/p>\n\n\n\n<p><strong>Buna g\u00f6re bu kovalent ba\u011flar\u0131 polar ve apolar olarak s\u0131n\u0131fland\u0131r\u0131n\u0131z.<\/strong><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-background\" style=\"background-color:#c9efff\"><strong>Polar kovalent ba\u011flar: 1, 2, 5, 7, 8, 9<br>Apolar kovalent ba\u011flar: 3, 4, 6<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p><\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Polar-Apolar-Kovalent-Baglar-SiteCenneti.jpg\" alt=\"Polar ve Apolar Kovalent Ba\u011flar\" class=\"wp-image-2761\" width=\"268\" height=\"165\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Polar-Apolar-Kovalent-Baglar-SiteCenneti.jpg 443w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Polar-Apolar-Kovalent-Baglar-SiteCenneti-300x185.jpg 300w\" sizes=\"auto, (max-width: 268px) 100vw, 268px\" \/><\/figure>\n<\/div>\n\n\n<ul class=\"wp-block-list\"><li><strong><em>Farkl\u0131 <\/em><\/strong>atomlar aras\u0131ndaki kovalent ba\u011flar <strong><em>polar<\/em><\/strong> kovalent ba\u011flard\u0131r:<ul><li><strong>Polar kovalent ba\u011flar: 1, 2, 5, 7, 8, 9<\/strong><\/li><\/ul><\/li><li><strong><em>Ayn\u0131 <\/em><\/strong>atomlar aras\u0131ndaki kovalent ba\u011flar <strong><em>apolar <\/em><\/strong>kovalent ba\u011flard\u0131r:<ul><li><strong>Apolar kovalent ba\u011flar: 3, 4, 6<\/strong><\/li><\/ul><\/li><\/ul>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-17\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<p class=\"has-text-align-center\"><img loading=\"lazy\" decoding=\"async\" width=\"300\" height=\"397\" class=\"wp-image-11410\" style=\"width: 300px;\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Turler-Arasi-Etkilesimler-Polar-Apolar-Kovalent-Bag-Soru-Cozumu.jpg\" alt=\"Polar - Apolar Kovalent Ba\u011flar\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Turler-Arasi-Etkilesimler-Polar-Apolar-Kovalent-Bag-Soru-Cozumu.jpg 300w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Kimyasal-Turler-Arasi-Etkilesimler-Polar-Apolar-Kovalent-Bag-Soru-Cozumu-227x300.jpg 227w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/p>\n\n\n\n<p>\u015eevket, kimya dersinde, performans \u00f6devi olarak yukar\u0131daki tabloyu haz\u0131rlam\u0131\u015ft\u0131r. \u00d6\u011fretmeni, tabloda bir molek\u00fcl\u00fcn &#8220;Atomlar aras\u0131 ba\u011f\u0131n polarl\u0131\u011f\u0131\/apolarl\u0131\u011f\u0131&#8221; bilgisinin yanl\u0131\u015f oldu\u011funu s\u00f6ylemi\u015ftir.<\/p>\n\n\n\n<p><strong>Buna g\u00f6re \u00f6\u011fretmenin bahsetti\u011fi hata hangi molek\u00fcldedir?<\/strong><\/p>\n\n\n\n<p>A) O<sub>2<\/sub><br>B) N<sub>2<\/sub><br>C) CO<sub>2<\/sub><br>D) NH<sub>3<\/sub><br>E) CH<sub>4<\/sub><\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-large-font-size\"><strong>D<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>Kovalent ba\u011f\u0131n iki taraf\u0131nda da ayn\u0131 atomlar varsa, apolar kovalent ba\u011f olur, farkl\u0131 atomlar varsa polar kovalent ba\u011f olur.<\/p>\n\n\n\n<p>Buna g\u00f6re NH<sub>3<\/sub> molek\u00fcl\u00fcndeki kovalent ba\u011flar, N-H ba\u011flar\u0131d\u0131r ve polar kovalent ba\u011flard\u0131r. Fakat, \u015eevket tabloda bu ba\u011flara apolar demi\u015ftir.<\/p>\n\n\n\n<p><em>Cevap D \u015f\u0131kk\u0131d\u0131r.<\/em><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h3 class=\"wp-block-heading\"><span id=\"Kovalent_Bagli_Bilesiklerin_Sistematik_Adlandirilmasi\">Kovalent Ba\u011fl\u0131 Bile\u015fiklerin Sistematik Adland\u0131r\u0131lmas\u0131<\/span><\/h3>\n\n\n\n<ul class=\"wp-block-list\"><li>Kovalent ba\u011fl\u0131 bile\u015fikler adland\u0131r\u0131l\u0131rken, bile\u015fik <strong><em>form\u00fcl\u00fcndeki say\u0131lar da s\u00f6ylenir.<\/em><\/strong><ul><li>Fakat bu say\u0131lar T\u00fcrk\u00e7e de\u011fil <strong><em>Latince <\/em><\/strong>s\u00f6ylenir.<\/li><\/ul><\/li><li>Kovalent ba\u011fl\u0131 bile\u015fikleri adland\u0131rabilmek i\u00e7in, <strong><em>Latince 10&#8217;a kadar<\/em><\/strong> bilmek gerekir. Bu say\u0131lar a\u015fa\u011f\u0131da verilmi\u015ftir.<\/li><\/ul>\n\n\n\n<div class=\"wp-block-columns has-background is-layout-flex wp-container-core-columns-is-layout-9d6595d7 wp-block-columns-is-layout-flex\" style=\"background-color:#e8f6ff\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p>1: Mono<br>2: Di<br>3: Tri<\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p>4: Tetra<br>5: Penta<br>6: Hekza<\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p>7: Hepta<br>8: Okta<\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p>9: Nona<br>10: Deka<\/p>\n<\/div>\n<\/div>\n\n\n\n<ul class=\"wp-block-list\"><li><strong><em>Ametallerin<\/em><\/strong>, bile\u015fi\u011fin ba\u015f\u0131nda ve sonunda iken isimleri farkl\u0131d\u0131r:<ul><li><span class=\"has-inline-color has-luminous-vivid-orange-color\">Bile\u015fi\u011fin <strong><em>ba\u015f\u0131nda iken<\/em><\/strong> ametaller, bildi\u011fimiz <strong><em>isimleri ile<\/em><\/strong> adland\u0131r\u0131l\u0131r<\/span>.<\/li><li><span class=\"has-inline-color has-luminous-vivid-orange-color\">Bile\u015fi\u011fin <strong><em>sonunda iken<\/em><\/strong> isimlerine genellikle <strong>&#8220;<em>-\u00fcr&#8221; eki eklenir<\/em><\/strong>.<\/span> A\u015fa\u011f\u0131da, ametallerin <strong><em>bile\u015fi\u011fin sonunda iken<\/em><\/strong> isimleri verilmi\u015ftir:<\/li><\/ul><\/li><\/ul>\n\n\n\n<div class=\"wp-block-columns has-background is-layout-flex wp-container-core-columns-is-layout-9d6595d7 wp-block-columns-is-layout-flex\" style=\"background-color:#e0fffd\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p>H: Hidr\u00fcr<br>C: Karb\u00fcr<br>N: Nitr\u00fcr<\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p>O: Oksit<br>F: Flor\u00fcr<br>Cl: Klor\u00fcr<\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p>Br: Brom\u00fcr<br>I: \u0130yod\u00fcr<br>Se: Selen\u00fcr<\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p>P: Forf\u00fcr<br>S: S\u00fclf\u00fcr<br><\/p>\n<\/div>\n<\/div>\n\n\n\n<ul class=\"wp-block-list\"><li>Kovalent bile\u015fi\u011fin ismini s\u00f6ylerken;<ul><li><strong><em>\u00f6nce <\/em><\/strong>ametalin <strong><em>ad\u0131 <\/em><\/strong>s\u00f6ylenir,<\/li><li><strong><em>sonra <\/em><\/strong>Latince olarak <strong><em>say\u0131s\u0131 <\/em><\/strong>s\u00f6ylenir.<\/li><\/ul><\/li><li>Bile\u015fikteki <strong><em>ilk ametalin<\/em><\/strong> say\u0131s\u0131 <strong><em>1<\/em><\/strong> ise, bu say\u0131 <strong><em>s\u00f6ylenmez<\/em><\/strong>, sadece ametalin ad\u0131 s\u00f6ylenir.<\/li><\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ogretici_Ornek-8\">\u00d6\u011fretici \u00d6rnek:<\/span><\/h4>\n\n\n\n<p><strong>A\u015fa\u011f\u0131da, baz\u0131 kovalent ba\u011fl\u0131 bile\u015fiklerin form\u00fclleri ve sistematik isimleri verilmi\u015ftir:<\/strong><\/p>\n\n\n\n<p class=\"has-white-background-color has-background\"><strong>H<sub>2<\/sub><span class=\"has-inline-color has-vivid-purple-color\">O<\/span> : Dihidrojen <span class=\"has-inline-color has-vivid-purple-color\">monooksit<\/span><br>N<sub>2<\/sub><span class=\"has-inline-color has-vivid-purple-color\">O<sub>5<\/sub><\/span> : Diazot <span class=\"has-inline-color has-vivid-purple-color\">pentaoksit<\/span><\/strong><br><strong>N<span class=\"has-inline-color has-vivid-purple-color\">F<sub>3<\/sub><\/span> : Azot <span class=\"has-inline-color has-vivid-purple-color\">triflor\u00fcr<\/span><br>C<span class=\"has-inline-color has-vivid-purple-color\">O<sub>2<\/sub><\/span> : Karbon <span class=\"has-inline-color has-vivid-purple-color\">dioksit<\/span><br>C<span class=\"has-inline-color has-vivid-purple-color\">O<\/span> : Karbon <span class=\"has-inline-color has-vivid-purple-color\">monooksit<\/span><br>S<span class=\"has-inline-color has-vivid-purple-color\">O<sub>2<\/sub><\/span> : K\u00fck\u00fcrt <span class=\"has-inline-color has-vivid-purple-color\">dioksit<\/span><br>C<span class=\"has-inline-color has-vivid-purple-color\">Cl<sub>4<\/sub><\/span> : Karbon <span class=\"has-inline-color has-vivid-purple-color\">tetraklor\u00fcr<\/span><br>C<span class=\"has-inline-color has-vivid-purple-color\">F<sub>4<\/sub><\/span> : Karbon <span class=\"has-inline-color has-vivid-purple-color\">tetraflor\u00fcr<\/span><br>P<span class=\"has-inline-color has-vivid-purple-color\">Cl<sub>3<\/sub><\/span> : Fosfor <span class=\"has-inline-color has-vivid-purple-color\">triklor\u00fcr<\/span><\/strong><\/p>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h4 class=\"wp-block-heading\"><span id=\"Ornek-18\">\u00d6rnek:<\/span><\/h4>\n\n\n\n<div class=\"wp-block-columns has-white-background-color has-background is-layout-flex wp-container-core-columns-is-layout-9d6595d7 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p>I. N<sub>2<\/sub>O<sub>4<\/sub><br>II. SF<sub>6<\/sub><\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p>III. P<sub>4<\/sub>S<sub>3<\/sub><br>IV. PCl<sub>5<\/sub><\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p>V. H<sub>2<\/sub>S<\/p>\n<\/div>\n<\/div>\n\n\n\n<p>Serkan&#8217;\u0131n kimya s\u0131nav\u0131nda, yukar\u0131daki bile\u015fiklerin sistematik ad\u0131 sorulmu\u015ftur. Soruda, her bir bile\u015fi\u011fin do\u011fru ad\u0131 3 puan de\u011ferindedir. Serkan, bu soruyu a\u015fa\u011f\u0131daki gibi cevapland\u0131rarak 12 puan alm\u0131\u015ft\u0131r.<\/p>\n\n\n\n<p><strong>Buna g\u00f6re, \u00f6\u011fretmeni Serkan&#8217;\u0131n hangi cevab\u0131ndan puan k\u0131rm\u0131\u015ft\u0131r?<\/strong><\/p>\n\n\n\n<p>A) N<sub>2<\/sub>O<sub>4<\/sub> : Diazot tetraoksit<br>B) SF<sub>6<\/sub> : K\u00fck\u00fcrt hekzaflor\u00fcr<br>C) P<sub>4<\/sub>S<sub>3<\/sub> : Tetrafosfor tris\u00fclf\u00fcr<br>D) PCl<sub>5<\/sub> : Fosfor pentaklor\u00fcr<br>E) H<sub>2<\/sub>S : Dihidrojen monok\u00fck\u00fcrt<\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-large-font-size\"><strong>E<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p>H<sub>2<\/sub>S bile\u015fi\u011finin sistematik ad\u0131 \u015f\u00f6yledir:<br><strong><em>H<sub>2<\/sub>S : Dihidrojen monos\u00fclf\u00fcr<\/em><\/strong><\/p>\n\n\n\n<p>Serkan, H<sub>2<\/sub>S bile\u015fi\u011fine,<br><em>Dihidrojen monok\u00fck\u00fcrt<\/em><br>diyerek yanl\u0131\u015f bir cevap vermi\u015ftir.<\/p>\n\n\n\n<p><em>Cevap E \u015f\u0131kk\u0131d\u0131r.<\/em><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><span id=\"III_Metalik_Bag\">III. Metalik Ba\u011f<\/span><\/h2>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"500\" height=\"125\" src=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Metalik-Bag-SiteCenneti.jpg\" alt=\"Metalik Ba\u011f ve Elektron Denizi\" class=\"wp-image-2791\" srcset=\"https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Metalik-Bag-SiteCenneti.jpg 500w, https:\/\/sitecenneti.com\/kimya\/wp-content\/uploads\/sites\/16\/2020\/10\/Metalik-Bag-SiteCenneti-300x75.jpg 300w\" sizes=\"auto, (max-width: 500px) 100vw, 500px\" \/><figcaption>Metalik Ba\u011f ve Elektron Denizi<\/figcaption><\/figure>\n<\/div>\n\n\n<ul class=\"wp-block-list\"><li>G\u00fc\u00e7l\u00fc etkile\u015fimlerden \u00fc\u00e7\u00fcnc\u00fcs\u00fc ve sonuncusu metalik ba\u011fd\u0131r.<\/li><li>Metalik ba\u011f; g\u00fc\u00e7l\u00fc olmas\u0131na ra\u011fmen bir <strong><em>kimyasal ba\u011f de\u011fildir<\/em><\/strong>.<\/li><li><strong><em>Metallerin<\/em><\/strong>, <strong><em>de\u011ferlik elektronlar\u0131<\/em><\/strong>, \u00e7ok <strong><em>zay\u0131f ba\u011fl\u0131d\u0131r<\/em><\/strong>.<ul><li>Hatta, bazen atomlar\u0131n\u0131 terk edip kom\u015fu atomun son y\u00f6r\u00fcngesine bile ge\u00e7ebilirler, veya<\/li><li>atomlar\u0131n\u0131 terk edip ortal\u0131kta bo\u015f bo\u015f dolanabilirler.<\/li><\/ul><\/li><li>Bu y\u00fczden, bu ba\u015f\u0131bo\u015f <strong><em>de\u011ferlik elektronlar\u0131<\/em><\/strong>, metal atomlar\u0131 aras\u0131nda bir <strong><span class=\"has-inline-color has-luminous-vivid-orange-color\">elektron denizi<\/span><\/strong> olu\u015ftururlar.<ul><li><strong><em>Elektron denizinde<\/em><\/strong>, atomlar\u0131n\u0131 terk eden elektronlar, atomlar\u0131n katyon haline ge\u00e7mesine sebep olur.<\/li><\/ul><\/li><li>Bu <strong><em>elektron denizi<\/em><\/strong>, metal atomlar\u0131 aras\u0131nda, <strong><em>g\u00fc\u00e7l\u00fc<\/em><\/strong> bir ba\u011f kurulmas\u0131na sebep olur.<ul><li>\u0130\u015fte bu \u015fekilde kurulan ba\u011fa <strong><span class=\"has-inline-color has-luminous-vivid-orange-color\">metalik ba\u011f<\/span><\/strong> denir.<\/li><\/ul><\/li><li>De\u011ferlik elektron say\u0131s\u0131 artt\u0131k\u00e7a, genellikle, metalik ba\u011f\u0131n kuvveti artar.<\/li><\/ul>\n\n\n\n<ul class=\"wp-block-list\"><li><strong>Metalik ba\u011f sayesinde, metaller \u015fu \u00f6zellikleri ta\u015f\u0131rlar:<\/strong><ul><li><strong>Is\u0131 ve elektri\u011fi iletirler.<\/strong><\/li><li><strong>Y\u00fczeyleri parlakt\u0131r.<\/strong><\/li><li><strong>Tel ve levha h\u00e2line getirilebilirler.<\/strong><\/li><li><strong>Esnektirler, d\u00f6v\u00fclebilir ve \u015fekillendirilebilirler.<\/strong><\/li><\/ul><\/li><\/ul>\n\n\n\n<div class=\"wp-block-group\"><div class=\"wp-block-group__inner-container is-layout-flow wp-block-group-is-layout-flow\">\n<h3 class=\"wp-block-heading\"><span id=\"Ornek-19\">\u00d6rnek:<\/span><\/h3>\n\n\n\n<p>Muzaffer hoca s\u0131n\u0131fa: &#8220;Metalik ba\u011f ile ilgili olarak 5 tane c\u00fcmle kuraca\u011f\u0131m fakat bir tanesi yanl\u0131\u015f olacak. Yanl\u0131\u015f\u0131 bulan \u00f6\u011frenciye, s\u0131f\u0131r bir iPhone 12 hediye edece\u011fim&#8221; demi\u015ftir.<\/p>\n\n\n\n<p>Muzaffer hoca, bunu dedikten sonra a\u015fa\u011f\u0131daki c\u00fcmleleri kurmu\u015f ve \u00f6d\u00fcl\u00fc de Ya\u011fmur alm\u0131\u015ft\u0131r.<\/p>\n\n\n\n<p><strong>Buna g\u00f6re Ya\u011fmur hangi c\u00fcmlenin yanl\u0131\u015f oldu\u011funu s\u00f6ylemi\u015ftir?<\/strong><\/p>\n\n\n\n<p>A) Metal atomlar\u0131 aras\u0131nda olu\u015fan g\u00fc\u00e7l\u00fc bir ba\u011fd\u0131r.<br>B) Etkile\u015fimler, katyonlar ve anyonlar aras\u0131nda kurulur.<br>C) Metalik ba\u011f sayesinde, metallerin y\u00fczeyi parlakt\u0131r.<br>D) Ba\u011f\u0131n sebebi serbest hareket eden de\u011ferlik elektronlar\u0131d\u0131r.<br>E) De\u011ferlik elektronlar\u0131n\u0131n say\u0131s\u0131 artt\u0131k\u00e7a metalik ba\u011f kuvveti artar.<\/p>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(41,106,54,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">Cevab\u0131 g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.75)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">Cevap<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<p class=\"has-text-align-center has-large-font-size\"><strong>B<\/strong><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n\n\n\n<div class=\"wp-block-bod-modal-block bod-block-popup align-left\"><button type=\"button\" style=\"background-color:rgba(132,77,77,1);color:#ffffff\" class=\"bod-block-popup-trigger type_btn bod-btn\">\u00c7\u00f6z\u00fcm\u00fc g\u00f6ster<\/button><div style=\"background-color:rgba(0,0,0,0.69)\" class=\"bod-block-popup-overlay\" data-disabled-overlay-close=\"false\" data-disabled-escape-close=\"false\"><\/div><div role=\"dialog\" aria-modal=\"false\" aria-labelledby=\"\" aria-describedby=\"\" class=\"bod-block-popup-wrap undefined\"><div style=\"background-color:#ffffff;border-radius:10px \" class=\"bod-block-popup size-m\"><div id=\"\" style=\"background-color:#ffffff;text-align:left\" class=\"bod-modal-title\"><h2 style=\"color:#000000\">\u00d6rne\u011fin \u00e7\u00f6z\u00fcm\u00fc:<\/h2><\/div> <div id=\"\" class=\"bod-modal-content\">\n<ul class=\"wp-block-list\"><li>Metalik ba\u011f, metal atomlar\u0131 aras\u0131nda kurulur.<\/li><li>Anyon ve katyonlar aras\u0131nda kurulan ba\u011fa iyonik ba\u011f denir. Bu y\u00fczden B \u015f\u0131kk\u0131 yanl\u0131\u015ft\u0131r.<\/li><\/ul>\n\n\n\n<p><em>Cevap B \u015f\u0131kk\u0131d\u0131r.<\/em><\/p>\n<\/div> <\/div> <div class=\"bod-block-popup-closer\"><\/div><\/div><\/div>\n<\/div><\/div>\n","protected":false},"excerpt":{"rendered":"<p>G\u00fc\u00e7l\u00fc etkile\u015fimler, kopar\u0131lmas\u0131 zor olan ba\u011flard\u0131r. G\u00fc\u00e7l\u00fc etkile\u015fimleri koparmak i\u00e7in gereken enerji (ba\u011f enerjisi de denir) genellikle 40 kj\/mol veya daha b\u00fcy\u00fckt\u00fcr. Zay\u0131f etkile\u015fimlerin ba\u011f enerjileri genellikle bu de\u011ferin alt\u0131ndad\u0131r.<\/p>\n","protected":false},"author":1,"featured_media":1857,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[93],"tags":[116,117,118,119],"class_list":["post-1635","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-kimyasal-turler-arasi-etkilesimler","tag-guclu-etkilesimler","tag-iyonik-bag","tag-kovalent-bag","tag-metalik-bag"],"_links":{"self":[{"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/posts\/1635","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/comments?post=1635"}],"version-history":[{"count":4,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/posts\/1635\/revisions"}],"predecessor-version":[{"id":22841,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/posts\/1635\/revisions\/22841"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/media\/1857"}],"wp:attachment":[{"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/media?parent=1635"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/categories?post=1635"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/sitecenneti.com\/kimya\/wp-json\/wp\/v2\/tags?post=1635"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}